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Electric Charges, Forces, and Fields. Electric Charges. Electric charge is a basic property of matter Two basic charges Positive and Negative Each having an absolute value of 1.6 x 10 -19 Coulombs Experiments have shown that Like signed charges repel each other - PowerPoint PPT Presentation
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Fall 2008Lecture 1-1Physics 231
Electric Charges,Forces, and
Fields
Fall 2008Lecture 1-2Physics 231
Electric ChargesElectric charge is a basic property of matterTwo basic charges
Positive and Negative
Each having an absolute value of 1.6 x 10-19 Coulombs
Experiments have shown thatLike signed charges repel each otherUnlike signed charges attract each other
For an isolated system, the net charge of the system remains constant
Charge Conservation
Fall 2008Lecture 1-3Physics 231
Two basics type of materials
ConductorsMaterials, such as metals, that allow the free
movement of charges
InsulatorsMaterials, such as rubber and glass, that don’t
allow the free movement of charges
Fall 2008Lecture 1-4Physics 231
Coulomb’s LawCoulomb found that the electric force between
two charged objects is
Proportional to the product of the charges on the objects, and
Inversely proportional to the separation of the objects squared
2
21
r
qqkF
k being a proportionality constant, having a value of 8.988 x 109 Nm2/c2
Fall 2008Lecture 1-5Physics 231
Electric Force
12221
12 r̂r
qqkF
This gives the force on charged object 2 due to charged object 1
The direction of the force is either parallel or antiparallel to this unit vector depending upon the relative signs of the charges
12r̂ is a unit vector pointing from object 1 to object 2
As with all forces, the electric force is a Vector
So we rewrite Coulomb’s Law as
q2q1
Fall 2008Lecture 1-6Physics 231
Electric ForceThe force acting on each charged object has the same magnitude - but acting in opposite
directions
(Newton’s Third Law)2112 FF
Fall 2008Lecture 1-7Physics 231
Example 1A charged ball Q1 is fixed to a horizontal surface
as shown. When another massive charged ball Q2 is brought near, it achieves an equilibrium position at a distance d12 directly above Q1.
When Q1 is replaced by a different charged ball Q3, Q2 achieves an equilibrium position at a distance d23 (< d12) directly above Q3.
For 1a and 1b which is the correct answer
1a: A) The charge of Q3 has the same sign of the charge of Q1
B) The charge of Q3 has the opposite sign as the charge of Q1
C) Cannot determine the relative signs of the charges of Q3 & Q1
1b: A) The magnitude of charge Q3 < the magnitude of charge Q1
B) The magnitude of charge Q3 > the magnitude of charge Q1
C) Cannot determine relative magnitudes of charges of Q3 & Q1
Q2
Q1
gd12
Q2
d23
Q3
Fall 2008Lecture 1-8Physics 231
• To be in equilibrium, the total force on Q2 must be zero.• The only other known force acting on Q2 is its weight.• Therefore, in both cases, the electrical force on Q2 must be directed
upward to cancel its weight.• Therefore, the sign of Q3 must be the SAME as the sign of Q1
A charged ball Q1 is fixed to a horizontal surface as shown. When another massive charged ball Q2 is brought near, it achieves an equilibrium position at a distance d12 directly above Q1.
When Q1 is replaced by a different charged ball Q3, Q2 achieves an equilibrium position at a distance d23 (< d12) directly above Q3.
1a: A) The charge of Q3 has the same sign of the charge of Q1
B) The charge of Q3 has the opposite sign as the charge of Q1
C) Cannot determine the relative signs of the charges of Q3 & Q1
Q2
Q1
gd12
Q2
d23
Q3
Example 1
Fall 2008Lecture 1-9Physics 231
• The electrical force on Q2 must be the same in both cases … it just cancels the weight of Q2
• Since d23 < d12 , the charge of Q3 must be SMALLER than the charge of Q1 so that the total electrical force can be the same!!
A charged ball Q1 is fixed to a horizontal surface as shown. When another massive charged ball Q2 is brought near, it achieves an equilibrium position at a distance d12 directly above Q1.
When Q1 is replaced by a different charged ball Q3, Q2 achieves an equilibrium position at a distance d23 (< d12) directly above Q3.
1b: A) The magnitude of charge Q3 < the magnitude of charge Q1
B) The magnitude of charge Q3 > the magnitude of charge Q1
C) Cannot determine relative magnitudes of charges of Q3 & Q1
Q2
Q1
gd12
Q2
d23
Q3
Example 1
Fall 2008Lecture 1-10Physics 231
More Than Two Charges
q
q1
q2
qqF1
qqF2
netF
If q1 were the only other charge, we would know the force on q due to q1 - qqF
1
If q2 were the only other charge, we would know the force on q due to q2 - qqF
2
Given charges q, q1, and q2
What is the net force if both charges are present?
The net force is given by the Superposition Principle
21 FFFnet
Fall 2008Lecture 1-11Physics 231
What are the directions of the forces acting on q1?
Fall 2008Lecture 1-12Physics 231
Superposition of ForcesIf there are more than two charged objects
interacting with each other
The net force on any one of the charged objects is
The vector sum of the individual Coulomb forces on that charged object
ji
rr
qkqF ijij
ijj ˆ2
Fall 2008Lecture 1-13Physics 231
Example Twoqo, q1, and q2 are all point charges where qo = -1C, q1 = 3C, and q2 = 4C
What are F0x and F0y ?
yFxFF ˆsinˆcos 202020
20
02
r
xx cos
20
20
r
yy sin
x (cm)
y (cm)
1 2 3 4 5
4
3
2
1
qo
q2q1
210
1010
r
qqkF yFF ˆ1010
220
2020
r
qqkF
202020 rFF ˆ
2010 FF
and calculate to Need
What is the force acting on qo?
We have that 20100 FFF
Decompose into its x and y components
20F
Fall 2008Lecture 1-14Physics 231
Example Two - Continued
10F
Now add the components of and to find and xF0 yF020F
cos200 FF x
xxx FFF 20100
010 xF
X-direction:
yyy FFF 20100
sin20100 FFF y
Y-direction:x (cm)
y (cm)
1 2 3 4 5
4
3
2
1
qo
q2q1
20F
10F
0F
Fall 2008Lecture 1-15Physics 231
Example Two - Continued
N52.110 xF N64.380 yF
N32.4020
200 yx FFFThe magnitude of is0F
Putting in the numbers . . .
cm310 r cm520 r
8.0cos
N4.1420 FN3010 F
We then get for the components
At an angle given by
40.73)52.11/64.38(tantan 100
1 xy FF
x (cm)
y (cm)
1 2 3 4 5
4
3
2
1
qo
q2q1
20F
10F
0F
Fall 2008Lecture 1-16Physics 231
Note on constants
k is in reality defined in terms of a more fundamental constant, known as the permittivity of free space.
2
212
0
0
C 10854.8
4
1
Nmxwith
k
Fall 2008Lecture 1-17Physics 231
Electric Field
The Electric Force is like the Gravitational Force
Action at a Distance
The electric force can be thought of as being mediated by an electric field.
Fall 2008Lecture 1-18Physics 231
What is a Field?
A Field is something that can be defined anywhere in space
A field represents some physical quantity (e.g., temperature, wind speed, force)
It can be a scalar field (e.g., Temperature field)
It can be a vector field (e.g., Electric field)
It can be a “tensor” field (e.g., Space-time curvature)
Fall 2008Lecture 1-19Physics 231
7782
8368
5566
8375 80
9091
7571
80
72
84
73
82
8892
77
8888
7364
A Scalar Field
A scalar field is a map of a quantity that has only a magnitude, such as temperature
Fall 2008Lecture 1-20Physics 231
77
82
8368
5566
8375 80
9091
7571
80
72
84
73
57
8892
77
5688
7364
A Vector Field
A vector field is a map of a quantity that is a vector, a quantity having both magnitude and direction, such as wind
Fall 2008Lecture 1-21Physics 231
Electric Field
We say that when a charged object is put at a point in space,
The charged object sets up an Electric Field throughout the space surrounding the charged object
It is this field that then exerts a force on another charged object
Fall 2008Lecture 1-22Physics 231
Electric FieldLike the electric force,
the electric field is also a vector
If there is an electric force acting on an object having a charge qo, then the electric field at that point is given by
0q
FE
(with the sign of q0 included)
Fall 2008Lecture 1-23Physics 231
Electric Field
The force on a positively charged object is in the same direction as the electric field at that point,
While the force on a negative test charge is in the opposite direction as the electric field at the point
Fall 2008Lecture 1-24Physics 231
Electric Field
A positive charge sets up an electric field pointing away from the charge
A negative charge sets up an electric field pointing towards the charge
Fall 2008Lecture 1-25Physics 231
Electric Field
rr
qkE ˆ
2
The electric field of a point charge can then be shown to be given by
ji
rrqk ij
ij
ijj qF ˆ2
Earlier we saw that the force on a charged object is given by
The term in parentheses remains the same if we change the charge on the object at the point in question
The quantity in the parentheses can be thought of as the electric field at the point where the test object is placed
Fall 2008Lecture 1-26Physics 231
Electric Field
As with the electric force, if there are several charged objects, the net electric field at a given point is given by the vector sum of the individual electric fields
i
iEE
Fall 2008Lecture 1-27Physics 231
Electric Field
rr
dqkE ˆ
2
If we have a continuous charge distribution the summation becomes an integral
Fall 2008Lecture 1-28Physics 231
Hints
1) Look for and exploit symmetries in the problem.
2) Choose variables for integration carefully.
3) Check limiting conditions for appropriate result
Fall 2008Lecture 1-29Physics 231
Electric FieldRing of Charge
Fall 2008Lecture 1-30Physics 231
Electric FieldLine of Charge
Fall 2008Lecture 1-31Physics 231
Two equal, but opposite charges are placed on the x axis. The positive charge is placed at x = -5 m and the negative charge is placed at x = +5m as shown in the figure above.
1) What is the direction of the electric field at point A?
a) up b) down c) left d) right e) zero
2) What is the direction of the electric field at point B?
a) up b) down c) left d) right e) zero
Example 3
Fall 2008Lecture 1-32Physics 231
Example 4Two charges, Q1 and Q2, fixed along the x-axis asshown produce an electric field, E, at a point(x,y) = (0,d) which is directed along the negativey-axis.
Which of the following is true?
Q2Q1
(c) E
Q2Q1
(b)
E
Q2Q1 x
y
Ed
(a) Both charges Q1 and Q2 are positive
(b) Both charges Q1 and Q2 are negative
(c) The charges Q1 and Q2 have opposite signs
E
Q2Q1
(a)
Fall 2008Lecture 1-33Physics 231
Electric Field Lines
Possible to map out the electric field in a region of spaceAn imaginary line that at any given point has its tangent being in the direction of the electric field at that point
The spacing, density, of lines is related to the magnitude of the electric field at that point
Fall 2008Lecture 1-34Physics 231
Electric Field Lines
At any given point, there can be only one field line
The electric field has a unique direction at any given point
Electric Field Lines
Begin on Positive Charges
End on Negative Charges
Fall 2008Lecture 1-35Physics 231
Electric Field Lines
Fall 2008Lecture 1-36Physics 231
Electric Dipole
An electric dipole is a pair of point charges having equal magnitude but opposite sign that are separated by a distance d.
Two questions concerning dipoles:1) What are the forces and torques acting on a dipole when placed in an external electric field?2) What does the electric field of a dipole look like?
Fall 2008Lecture 1-37Physics 231
Force on a DipoleGiven a uniform external field
Then since the charges are of equal magnitude, the force on each charge has the same value
However the forces are in opposite directions!
Therefore the net force on the dipole is
Fnet = 0
Fall 2008Lecture 1-38Physics 231
Torque on a Dipole
The individual forces acting on the dipole may not necessarily be acting along the same line.
If this is the case, then there will be a torque acting on the dipole, causing the dipole to rotate.
Fall 2008Lecture 1-39Physics 231
Torque on a Dipole
Edq
The torque is then given by = qE dsin
d is a vector pointing from the negative charge to the positive charge
Fall 2008Lecture 1-40Physics 231
Potential Energy of a Dipole
Given a dipole in an external field:
Dipole will rotate due to torque
Electric field will do work
The work done is the negative of the change in potential energy of the dipole
The potential energy can be shown to be
EdqU
Fall 2008Lecture 1-41Physics 231
Electric Field of a Dipole