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1
EKT 441
MICROWAVE COMMUNICATIONS
MICROWAVE FILTERS
2
INTRODUCTION What is a Microwave filter ? Circuit that controls the frequency response at a certain
point in a microwave system
provides perfect transmission of signal for frequencies in
a certain passband region
infinite attenuation for frequencies in the stopband region
Attenuation/dB
0
1
3
10
20
30
40 2
Attenuation/dB
0
c
3
10
20
30
40
3
FILTER DESIGN METHODS
Filter Design Methods
Two types of commonly used design methods:
- Image Parameter Method
- Insertion Loss Method
•Image parameter method yields a usable filter
Filters designed using the image parameter method consist of a
cascade of simpler two port filter sections to provide the desired cutoff frequencies and attenuation characteristics but do not allow the
specification of a particular frequency response over the complete operating range. Thus, although the procedure is relatively simple, the
design of filters by the image parameter method often must be iterated
many times to achieve the desired results.
Filter Design by The Insertion Loss Method
4
The perfect filter would have zero insertion loss in the pass-
band, infinite attenuation in the stop-band, and a linear
phase response in the pass-band.
Filter Design by The Insertion Loss Method
5
6
Filter Design by The Insertion Loss Method
7
Filter Design by The Insertion Loss Method
8
Practical filter response:
Maximally flat:
• also called the binomial or Butterworth response,
• is optimum in the sense that it provides the flattest possible
passband response for a given filter complexity.
N
c
LR kP
21
– frequency of filter
c – cutoff frequency of filter N – order of filter
Equal ripple also known as Chebyshev.
- sharper cutoff
221 NLR TkP
Filter Design by The Insertion Loss Method
9
Filter Design by The Insertion Loss Method
• The insertion loss method (ILM) allows a systematic way to design
and synthesize a filter with various frequency response.
• Design usually begins by designing a normalized low-pass
prototype (LPP). The LPP is a low-pass filter with source and load
resistance of 1 and cutoff frequency of 1 Radian/s.
• Impedance transformation and frequency scaling are then applied
to denormalize the LPP and synthesize different type of filters with
different cutoff frequencies.
10
THE INSERTION LOSS METHOD
Low pass filter prototype, N = 2
Low Pass Filter Prototype
11
= 1.4142
12
THE INSERTION LOSS METHOD
Ladder circuit for low pass filter prototypes and their element definitions. (a)
begin with shunt element. (b) begin with series element.
Low Pass Filter Prototype – Ladder Circuit
For an arbitrary number of elements N.
13
THE INSERTION LOSS METHOD
g0 = generator resistance, generator conductance.
gk = inductance for series inductors, capacitance for shunt
capacitors. (k=1 to N)
gN+1 = load resistance if gN is a shunt capacitor, load
conductance if gN is a series inductor.
14
THE INSERTION LOSS METHOD
Element values for maximally flat LPF prototypes
15
THE INSERTION LOSS METHOD
Attenuation versus normalized frequency for maximally flat filter prototypes.
Low Pass Filter Prototype – Maximally Flat
To determine the order (size) of the filter. Is usually determined by the
specification of the insertion loss at some frequency in the stopband of the
filter.
16
THE INSERTION LOSS METHOD
221 NLR TkP
For an equal ripple low pass filter with a cutoff frequency ωc =
The power loss ratio is:
Low Pass Filter Prototype – Equal Ripple
17
THE INSERTION LOSS METHOD
Element values for equal ripple LPF prototypes (0.5 dB ripple level)
18
THE INSERTION LOSS METHOD
Element values for equal ripple LPF prototypes (3.0 dB ripple level).
19
THE INSERTION LOSS METHOD
Attenuation versus normalized frequency for equal-ripple filter prototypes.
(0.5 dB ripple level)
20
THE INSERTION LOSS METHOD
Attenuation versus normalized frequency for equal-ripple filter prototypes
(3.0 dB ripple level)
Scaling
and TRANSFORMATIONS
21
Scaling
22
23
= 1.4142
Example 1: LPF
24
LL
s
RRR
RR
R
CC
LRL
0
'
0
'
0
'
0
'
Low Pass Filter Prototype – Impedance Scaling
25
'
'
kk
c
k
kk
c
k
CjCjjB
LjLjjX
The new element values of the prototype filter:
c
Frequency scaling for the low pass filter:
26
The new element values are given by:
kk
kk
CC
LL
'
'
c
c
27
finally
The new element values are given by:
c
kk
c
kk
R
CC
LRL
0
'
0'
28
= 1.4142
Example 1: LPF
TRANSFORMATIONS
29
Low-pass to high-pass transformation
31
FILTER TRANSFORMATIONS
c
Low pass to high pass transformation
The frequency substitution:
kc
k
kc
k
C
RL
LRC
0'
0
' 1
The new component values are given by:
33
BANDPASS & BANDSTOP
TRANSFORMATIONS
0
0
0
012
0 1
0
12
210
Where,
The center frequency is:
Low pass to Bandpass transformation
34
BANDPASS & BANDSTOP
TRANSFORMATIONS
k
k
kk
LC
LL
0
'
0
'
The series inductor, Lk, is transformed to a series LC circuit with
element values:
The shunt capacitor, Ck, is transformed to
a shunt LC circuit with element values:
0
'
0
'
kk
k
k
CC
CL
[8.22a]
[8.22b]
0
12
210
35
BANDPASS & BANDSTOP
TRANSFORMATIONS
1
0
0
0
12
210
Where,
The center frequency is:
Low pass to Bandstop transformation
36
BANDPASS & BANDSTOP
TRANSFORMATIONS
k
k
kk
LC
LL
0
'
0
'
1
The series inductor, Lk, is transformed to a parallel LC circuit with
element values:
The shunt capacitor, Ck, is transformed to a series LC circuit with
element values:
0
'
0
' 1
kk
k
k
CC
CL
37
BANDPASS & BANDSTOP
TRANSFORMATIONS
38
EXAMPLE 5.1 Example 2:
Design a maximally flat low pass filter with a cutoff
freq of 2 GHz, impedance of 50 Ω, and at least 15 dB
insertion loss at 3 GHz. Compute and compare with
an equal-ripple (3.0 dB ripple) having the same order.
39
EXAMPLE 5.1 (Cont)
Solution:
First find the order of the maximally flat filter to satisfy the
insertion loss specification at 3 GHz.
We can find the normalized freq by using: 5.012
31
c
40 618.0
618.1
0.2
618.1
618.0
5
4
3
2
1
g
g
g
g
g
41
EXAMPLE 5.1 (Cont)
The ladder diagram of the LPF prototype to be used is as follow:
LL
s
RRR
RR
R
CC
LRL
0
'
0
'
0
'
0
'
C3 C5
L2 L4
C1
cR
gC
0
11
c
gRL
20
2
cR
gC
0
33
c
gRL
40
4
cR
gC
0
55
42
EXAMPLE 5.1 (Cont)
984.0
102250
618.09
0
11
cR
gC
438.6
1022
618.1509
202
c
gRL
183.3
102250
00.29
0
3
3
cR
gC
438.6
1022
618.1509
404
c
gRL
984.0
102250
618.09
0
55
cR
gC
pF
nH
pF
nH
pF
LPF prototype for maximally flat filter
43
EXAMPLE 5.1 (Cont)
541.5
102250
4817.39
0
11
cR
gC
031.3
1022
7618.0509
202
c
gRL
223.7
102250
5381.49
0
33
cR
gC
031.3
1022
7618.0509
404
c
gRL
541.5
102250
4817.39
0
55
cR
gC
pF
nH
pF
nH
pF
4817.3
7618.0
5381.4
7618.0
4817.3
5
4
3
2
1
g
g
g
g
g
LPF prototype for equal ripple filter:
44
EXAMPLE 5.2 Example:
Design a band pass filter having a 0.5 dB
equal-ripple response, with N = 3. The center
frequency is 1 GHz, the bandwidth is 10%,
and the impedance is 50 Ω.
45
EXAMPLE 5.2 (Cont)
Solution: The low pass filter (LPF) prototype ladder diagram is
shown as follow:
LRg
Lg
Cg
Lg
000.1
5963.1
0967.1
5963.1
4
33
2
1
2
1
46
EXAMPLE 5.2 (Cont)
Transforming the LPF prototype to the BPF prototype
= 0.1 N = 3 = 1 GHz
47
48
EXAMPLE 5.2 (Cont)
pF
LZC 199.0
5963.1102250
1.0'
9100
1
nH
ZLL 0.127
1.01012
505963.1'
9
0
1
1
0
pF
Z
CC 91.34
50)1.0(1012
0967.1'
900
22
nH
C
ZL 726.0
0967.11012
501.0'
920
02
49
EXAMPLE 5.2 (Cont)
pF
LZC 199.0
5963.1102250
1.0'
9300
3
nH
ZLL 0.127
1.01012
505963.1'
9
0
3 03
Thank you