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Chapter 3 - Interest
and EquivalenceClick here for Streaming Audio To
Accompany Presentation (optional)
EGR 403 Capital Allocation Theory
Dr. Phillip R. Rosenkrantz
Industrial & Manufacturing Engineering Department
Cal Poly Pomona
http://video.csupomona.edu/PRRosenkrant/EGR403Lecture-05.asxhttp://video.csupomona.edu/PRRosenkrant/EGR403Lecture-05.asxhttp://video.csupomona.edu/PRRosenkrant/EGR403Lecture-05.asxhttp://video.csupomona.edu/PRRosenkrant/EGR403Lecture-05.asx7/31/2019 egr403_sv5_chapter3 (1)
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EGR 403 - Cal Poly Pomona - SA5 2
EGR 403 - The Big Picture Framework:Accounting& Breakeven Analysis
Time-value of money concepts - Ch. 3, 4
Analysis methods
Ch. 5 - Present Worth
Ch. 6 - Annual Worth
Ch. 7, 8 - Rate of Return (incremental analysis)
Ch. 9 - Benefit Cost Ratio & other techniques
Refining the analysis
Ch. 10, 11 - Depreciation & Taxes
Ch. 12 - Replacement Analysis
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Economic Decision Components
Where economic decisions are immediate we needto consider: amount of expenditure
taxes
Where economic decisions occur over aconsiderable period of time we need to also
consider the consequences of: interest inflation
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Computing Cash Flows
Cash flows have:
Costs (disbursements) a negative number
Benefits (receipts) a positive number
Example 3-1
End of
Year Cash flow
0 (1,000.00)$
1 580.00$
2 580.00$
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Time Value of Money
Money has value Money can be leased or rented
Thepayment is called interest If you put $100 in a bank at 9% interest for one time
period you will receive back your original $100 plus $9
Original amount to be returned = $100
Interest to be returned = $100 x .09 = $9
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Simple Interest
Interest that is computed only on the original
sum or principal
Total interest earned = I = P i n , where:
P = present sum of money, or principal (example:
$1000)
i = interest rate (10% interest is a .10 interest rate)
n = number of periods (years) (example: n = 2 years)
I = $1000 x .10/period x 2 periods = $200
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Future Value of a Loan With
Simple Interest Amount of money due at the end of a loan
F = P + P i n or F = P (1 + i n )
Where,
F = future value
F = $1000 (1 + .10 x 2) = $1200
Simple interest is not used today
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Compound Interest Over Time
If you loaned a friendmoney for short period
of time the difference
between simple and
compound interest is
negligible.
If you loaned a friend
money for a long period
of time the difference
between simple andcompound interest may
amount to a considerable
difference.
P n i% F
1000 1 10% $1,100.00
1000 2 10% $1,210.001000 3 10% $1,331.00
1000 10 10% $2,593.74
1000 20 10% $6,727.50
1000 30 10% $17,449.40
1000 40 10% $45,259.26
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Nominal and Effective Interest
Interest rates are normally given on an annual basis withagreement on how often compounding will occur (e.g., monthly,
quarterly, annually, continuous).
Nominal interest rate /year ( r )the annual interest rate w/o
considering the effect of any compounding (e.g., r = 12%).
Interest rate /period ( i )the nominal interest rate /year
divided by the number of interest compounding periods (e.g.,
monthly compounding: i = 12% / 12 months/year = 1%).
Effective interest rate /year ( ieffor APR )the annual interest
rate taking into account the effect of the multiple compounding
periods in the year. (e.g., as shown later, r = 12% compounded
monthly is equivalent to 12.68% year compounded yearly.
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Interest Rates (contd)
We use i for the periodic interest rate Nominal interest rate = r (an annual rate)
Number of compounding periods/year = m
r = i * m, and i = r / m
Let r = .12 (or 12%)
Interest Period m = interest periods /
year
i = interest rate / period
Annual 1 .12Quarter 4 .03
Month 12 .01
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Plan 1 Equal annual
principal paymentsYear Balance P i Payment
1 5000 1000 500 1500
2 4000 1000 400 1400
3 3000 1000 300 1300
4 2000 1000 200 1200
5 1000 1000 100 1100
6500
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Plan 2Annual interest + balloon
payment of principalYear Balance P i Payment
1 5000 500 500
2 5000 500 500
3 5000 500 500
4 5000 500 500
5 5000 5000 500 500
7500
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Plan 3Equal annual payments
(installments)Year Balance P i Payment
1 5000.00 819.00 500.00 1319
2 4181.00 900.90 418.10 1319
3 3280.10 990.99 328.01 1319
4 2289.11 1090.09 228.91 1319
5 1199.02 1199.10 119.90 1319
6595
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Plan 4Principal & interest at
end of the loanYear Balance P i Payment
1 5000 0 500 0
2 5500 0 550 0
3 6050 0 605 0
4 6655 0 665.50 0
5 7320.50 0 732.05 8052.55
8052.55
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Which plan would you choose?
Total Principal + Interest Paid
Plan 1 = $6500
Plan 2 = $7500
Plan 3 = $6595
Plan 4 = $8052.55
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Equivalence
When an organization is indifferent as to whether
it has a present sum of money now or, with
interest the assurance of some other sum of money
in the future, or a series of future sums of money,we say that the present sum of money is
equivalentto the future sum or series of future
sums.
Each of the four repayment plans are equivalent
because each repays $5000 at the same 10% interest rate.
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To further illustrate this concept, given the choice
of these two plans which would you choose?
$7000$6200Total
540010805
40011604
40012403
40013202
$400$14001
Plan 2Plan 1Year
To make a choice the cash flows must be
altered so a comparison may be made.
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Technique of Equivalence
Determine a single equivalent value at apoint in time for plan 1.
Determine a single equivalent value at apoint in time for plan 2.
Both at the same interest rate
Judge the relative attractiveness of the two
alternatives from the comparable equivalentvalues. You will learn a number of methods
for finding comparable equivalent values.
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Analysis Methods that Compare
Equivalent Values Present Worth Analysis (Ch. 5) - Find the equivalent value of
cash flows at time 0.
Annual Worth Analysis (Ch. 6) - Find the equivalent annual
worth of all cash flows.
Rate of Return Analysis (Ch. 7, 8) - Compare the interest rate
(ROR) of each alternatives cash flows to a minimum value you
will accept.
Future Worth Analysis (Ch. 9) - Find the equivalent value of
cash flows at time in the future.
Benefit/Cost Ratio (Ch. 9) - Use equivalent values of cash flows
to form ratios that can be easily analyzed.
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Interest Formulas To understand equivalence the underlying
interest formulas must be analyzed. We willstart with Single Payment interest formulas.
Notation:
i = Interest rate per interest period.
n = Number of interest periods.
P = Present sum of money (Present worth, PV).
F = Future sum of money (Future worth, FV).
If you know any three of the above variables
you can find the fourth one.
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For example, given F, P, and n, find
the interest rate (i) or ROR
Principal outstanding over time (P)
Amount repaid (F) at n future periods from now
We know F, P, and n and want to find the interest rate
that makes them equivalent:
If F = P (1 + i)n
Then i = (F/P)1/n - 1
This value of i is theRate Of Return or ROR for
investing the amount P to earn the future sum F
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Cash Flow Diagrams We use cash flow
diagrams to helporganize the data for
each alternative.
Down arrow -
disbursement cash flow Up arrow - Income cash
flow
n = number of
compounding periodsin the problem
i = interest rate/period
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Notation for
Calculating a Future Value
Formula:
F=P(1+i)n is the
single payment compound amount factor.
Functional notation:
F=P(F/P, i, n) F = 5000(F/P, 6%, 10)
F =P(F/P) which is dimensionally correct.
Find the factor values in the tables in the
back of the text.
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Using the Functional Notation and
Tables to Find the Factor Values
F = 5000(F/P, 6%, 10)
To use the tables:
Step 1: Find the page with the 6% tableStep 2: Find the F/P column
Step 3: Go down the F/P column to n = 10
The Factor shown is 1.791, therefore:F = 5000 (1.791) = $8955
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Notation for
Calculating a Present Value P=F(1/1+i)n=F(1+i)-n is the
single payment present worth factor
Functional notation:
P=F(P/F, i, n) P=5000(P/F, 6%, 10)
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Example: P=F(P/F, i, n)
F = $1000, i = 0.10, n = 5, P = ?
Using notation: P = F(P/F, 10%, 5)= $1000(.6209) = $620.90