Edexcel GCSE Physics 2011 Topics P3.2 and P3.3 test 13_14 with mark scheme

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  • 8/18/2019 Edexcel GCSE Physics 2011 Topics P3.2 and P3.3 test 13_14 with mark scheme

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    Part A

    Part A 2

    FORMULAE

    You may find theses formulae useful

     

         

      

      

     

     

    The relationship between focal length, object and image distance

        

     

     

    current = number of particles per second × charge on each particle  I  = N  × q

    kinetic energy = electronic charge × accelerating potential difference

            

    momentum = mass × velocity  p = m × v

           

      

    The relationship between temperature and volume for a gas      

     

     

    The relationship between volume and pressure for a gas V 1  P 1 = V 2  P 2 

    The relationship between the volume, pressure and temperature for a gas   

     

       

     

     

     

      

    Do not forget to include units in all your answers.

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    1. (a) The diagram shows a human eye.

    (i) Label part X. [1] 

    (ii) State the names of two parts of the eye that focus the light. [2]

     _____________________________________________________________________  

     _____________________________________________________________________  

    (b) A bright object is placed 47 cm away from a lens as shown in the diagram. A real image of the bright object is seen on a screen which is 20 cm away from the lens asshown.

    Calculate the focal length of the lens. [3] 

    Focal length = __________  

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    *(c) Long sight and short sight are two defects of vision.

    Explain how long sight and short sight are different from normal sight and how one of thesedefects can be corrected. [6] 

     _______________________________________________________________________

     _______________________________________________________________________  

     _______________________________________________________________________  

     _______________________________________________________________________  

     _______________________________________________________________________  

     _______________________________________________________________________

     _______________________________________________________________________  

     _______________________________________________________________________  

     _______________________________________________________________________  

     _______________________________________________________________________  

     _______________________________________________________________________

     _______________________________________________________________________  

     _______________________________________________________________________  

     _______________________________________________________________________  

     _______________________________________________________________________  

    [Total for Question 1 = 12 marks]

    2. The potential difference between the filament and metal target in an X-ray tube is 40 kV.The charge on an electron is 1.6 × 10 –19 C and its mass is 9.1 × 10 –31 kg.

    Calculate the speed of an electron as it reaches the target. [3]

    speed of electron = __________  

    [Total for Question 2 = 3 marks]

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    3. The diagram shows X-rays being produced when fast moving electrons hit a metal target.

    (i) Complete the sentence by putting a cross ( ) in the box next to your answer.The X-rays that have most energy have the [1]

    A  greatest massB  highest frequencyC  highest speedD  longest wavelength

    (ii) Complete the sentence by putting a cross ( ) in the box next to your answer.Electrons travel to the target because it is [1] 

    A  magnetisedB  negatively chargedC  neutral

    D  positively charged

    (iii) Explain what is meant by thermionic emission.  [2]

     _______________________________________________________________________

     _______________________________________________________________________  

    (iv) Suggest why there must be a vacuum in the glass tube. [1]

     _______________________________________________________________________

     _______________________________________________________________________

    [Total for Question 3 = 5 marks]

    [Total for Part A = 20 marks]

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    Part B

    Part B 1

    Surname Name

    American Academy LarnacaYear 5 Physics

    Semester 2 Test 1 

    Unit P3 Applications of Physics

    Topic P1.1  Radiation in treatment and medicineTopic P1.2  X-rays and ECGs

    Topic P1.2  Production, uses and risks of ionising

    radiation and radioactive sources

    Part B Time: 20 minutes

    The total marks for this part is 20.

    The total marks for the paper is 40.

    The marks for each question are shown in square brackets.Use this as a guide as to how much time to spend on each question.

    Questions labelled with an asterisk (*) are ones where the quality of your written

    communication will be assessed.You should take particular care with your spelling and grammar, as well as theclarity of expression, on these questions.

    Answer the questions in the spaces provided.There may be more space than you need.

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    Part B

    Part B 2

    FORMULAE

    You may find theses formulae useful

     

         

      

      

     

     

    The relationship between focal length, object and image distance

        

     

     

    current = number of particles per second × charge on each particle  I  = N  × q

    kinetic energy = electronic charge × accelerating potential difference

            

    momentum = mass × velocity  p = m × v

           

      

    The relationship between temperature and volume for a gas      

     

     

    The relationship between volume and pressure for a gas V 1  P 1 = V 2  P 2 

    The relationship between the volume, pressure and temperature for a gas   

     

       

     

     

     

      

    Do not forget to include units in all your answers.

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    1. The diagram shows light from a point source, S, spreading out as it gets further from S.

    The intensity of light passing through the surface which is 1 m from S is 2.5 W/m2.

    (i) Complete the sentence by putting a cross ( ) in the box next to your answer.The intensity of light, in W/m2, passing through the surface which is 2 m from S is [1] 

    A  2.5 ÷ 2B  2.5 ÷ 4C  2.5 × 2D  2.5 × 4

    (ii) Calculate the power of the light passing through the surface which is 1m from S. [2] 

    power = __________  

    [Total for Question 1 = 3 marks]

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    3. 

    Gell-Mann proposed the existence of quarks to explain the large numbers of particles that werebeing discovered.

    +2/3 -1/3

    U d

    c s

    t b

    a)  The Ω0 is a baryon with quark composition ccs.

    i) What is the similarity between the neutron and the Ω0? [1]

     _____________________________________________________________________

    ii) How do the neutron and Ω0 differ? [1]

     _____________________________________________________________________

    b) At CERN the LHC accelerates protons to very high energies and collides them.

    i) How are the protons kept moving in a circle? [2]

     _____________________________________________________________________

     _____________________________________________________________________

    ii) What is the purpose of such experiments? [2]

     _____________________________________________________________________

     _____________________________________________________________________iii) Suggest why it was so difficult to observe hadrons comprising the b quark. [1]

     _____________________________________________________________________

    [Total for Question 3 = 7 marks]

    [Total for Part B = 20 marks]

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    Mark schemePart A

    Answer   Acceptableanswers 

    Mark 

    1(a)(i) iris

    allow anyrecognisable

    spelling (1) 1(a)(ii)  In either order

    • cornea (1)

    • lens (1)

    aqueous humourvitreous humourallow anyrecognisablespelling

    (2) 

    1(b)  substitution (1) 1/f =1/47 + 1/20transposition or  evaluation of 1/f (1)0.071 evaluationof f (1) 14 (cm)

    numbers that rounddown to 14 give fullmarks for the

    correct answer, noworking (3) 

    Indicative Content  Mark 

    *1(c)  QWC  An explanationincluding some ofthe following points

    • normal eyeimage forms onretina

    • for alldistances of

    objects• short sight

    • (clear) image ofa distant objectforms inside theeye / in front ofretina

    • corrected usingdiverging lens

    • diverging the

    light / makes imagedistance longer

    • long sight

    • (clear) image ofnear object forms"beyond" the retina

    • corrected usingconverging lens

    • converging thelight / makes imagedistance smaller

    Other methods ofcorrection include

    • contact lenseswhich change the (6) 

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    curvature of thecornea

    • laser correctionchanges curvatureof cornea

    Level  0  No rewardable content

    1  1 - 2  • a limited explanation of both long and

    short sight OR either long or short sightand how it is corrected eg long-sightedpeople cannot see near objects and thiscan be corrected by convex lenses

    • the answer communicates ideas usingsimple language and uses limitedscientific terminology

    • spelling, punctuation and grammarare used with limited accuracy

    2  3 - 4  • a simple explanation of both long and

    short sight AND either how one iscorrected or detail of image formation eg,longsighted people cannot see nearobjects but short sighted people cannotsee distant objects because the imageforms in front of retina.

    • the answer communicates ideasshowing some evidence of clarity andorganisation and uses scientificterminology appropriately

    • spelling, punctuation and grammar

    are used with some accuracy3  5 - 6  • a detailed explanation including both

    long and short sight AND how one iscorrected AND detail of image formationeg long – eyeball too short so image ofnearby object is beyond the retina,short-sighted people cannot see distantobjects, which can be corrected byconcave lenses

    • the answer communicates ideas

    clearly and coherently uses a range ofscientific terminology accurately

    • spelling, punctuation and grammarare used with few errors

    Answer   Acceptableanswers 

    Mark 

    2 transposition2 × e × V/ m = v2 (1)substitutionv2 = 2 × 1.6 × 10-19 × 40 000/9.1 × 10-31 

    (1)evaluation of v1.2 × 108 (m/s) (1)

    Either orderignore powers often untilevaluation givefull marks for

    correct answer, noworkingaccept 1.19 ×108  (3) 

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     Answer   Acceptable

    answers Mark 

    3(i)  B  highestfrequency (1) 

    (ii)  D  positivelycharged

    (1) 

    (iii)  an explanationlinking:

    • (when) thefilament isheated/very hot(1)with one of:

    • electronsescape (haveenough energy) (1)

    • electronsescape from the

    surface (1)

    cathode / metal (forfilament) released accept boil offIGNORE produces/ emits

    (2) (iv)  a suggestion that

    electrons do notreach target

    otherwise electronscollide with (air)particles electronsare absorbedelectrons ioniseair stops electronsreaching target (1) 

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    Part B

    Answer   Acceptableanswers 

    Mark 

    1(i)  B 2.5 ÷ 4 (1) 

    1(ii)  eitherP = 2.5 × 0.2or2.5 = P / 0.2 (1) 0.5(W) (1)

    give full marks forcorrect answer, noworking

    (2) 

    2(a)(i)  A electron (1) 

    2(a) (ii)  suggestion toinclude two of

    • β- is antimatter(1)

    • β- will annihilateany e it meets (1)

    • β-

    almost certainto meet matter  (1)

    IGNOREreferences toionisation/particlesize

    (2) 

    2(b)  A gammaradiation (1) 

    2(c)(i)    or

      (1)

      (1) (2) 

    2(c)(ii)  uud (1)

      or

      (1)

      (1) (3) 

    3(a)(i) both neutral (1) (1)

    3(a)(ii) Ω0 more massivethan n (1) (1)

    3(b)(i)  magnetic field (1)force towardscentre (1) (2)

    3(b)(ii) Two from:[lost] KE of p’s (1)creates mass/

    particles (1)to confirmpredictions/theories (1) (2)

    3(b)(iii) b verymassive/hugeenergy required (1)