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• Conceptual Challenge, p. 107.
Section 3-4 Relative motion
• Objectives1. Describe situations in terms of frame of
reference.2. Solve problems involving relative velocity.
Checking Your References
Relative Motion
and
2-D Kinematics
How would Homer know that he is hurtling
through interstellar space if his speed were
constant?Without a window, he wouldn’t!
All of the Laws of Motion apply within his FRAME of REFERENCE
Do you feel like you are motionless right now?
ALL Motion is RELATIVE!
The only way to define motion is by changing position… The question is changing position relative to WHAT?!?
You are moving at about 1000 miles per hour relative to thecenter of the Earth!
The Earth is hurtling around the Sun at over66,000 miles per hour!
MORE MOTION!!!
Example #1• A train is moving east at 25 meters per second.
A man on the train gets up and walks toward the front at 2 meters per second.
• How fast is he going?– Depends on what we want to relate his speed to!!!
• +2 m/s (relative to a fixed point on the train)• +27 m/s (relative to a fixed point on the Earth)
vtrain = +25 m/svperson = +2 m/s
Example #2• A passenger on a 747 that is traveling
east at 230 meters per second walks toward the lavatory at the rear of the airplane at 1.5 meters per second.
• How fast is the passenger moving?– Again, depends on how you look at it!
• -1.5 m/s (relative to a fixed point in the 747)• +228.5 m/s (relative to a fixed point on the Earth)
Non-Parallel Vectors• What happens to the aircraft’s forward
speed when the wind changes direction?
vthrust
No wind – planemoves with velocity
that comes from engines
vwind
Wind in same directionas plane – adds to overall
velocity!
Wind is still giving the planeextra speed, but is also
pushing it SOUTH.
Wind is now NOT having anyeffect on forward movement,
but pushes plane SOUTH.
Wind is now slowing the plane somewhat AND pushing it
SOUTH.
Wind is now working againstthe aircraft thrust, slowing itdown, but causing no drift.
Perpendicular Kinematics
• Critical variable in multi dimensional problems is TIME.
• We must consider each dimension SEPARATELY, using TIME as the only crossover VARIABLE.
Example• A swimmer moving at 0.5
meters per second swims across a 200 meter wide river.
200 m
vs = 0.5 m/sHow long will it take the swimmer
to get across?
t
dv t = 400 s
t =0
The time to cross is unaffected! Theswimmer still arrives on the other bank
in 400 seconds. What IS different?
• Now, assume that as the swimmer moves ACROSS the river, a current pushes him DOWNSTREAM at 0.1 meter per second.
vc= 0.1 m/s
The arrival POINT will be shifted DOWNSTREAM!
• A motorboat traveling 4 m/s, East encounters a current traveling 3.0 m/s, North.
1. What is the resultant velocity of the motorboat?
2. If the width of the river is 80 meters wide, then how much time does it take the boat to travel shore to shore?
3. What distance downstream does the boat reach the opposite shore?
practice• A motorboat traveling 4 m/s, East encounters a
current traveling 7.0 m/s, North.1. What is the resultant velocity of the motorboat? 2. If the width of the river is 80 meters wide, then how
much time does it take the boat to travel shore to shore?
3. What distance downstream does the boat reach the opposite shore?
4 m/s7 m/s d = ?
80 m
Class work
• Page 108 – sample problem 3F• Page 109 – practice 3F