Design loads on floor beams and columns

The floor shown below with an overall depth of 225 mm is to be designed to carry an imposed load of 3 kN m^-2 plusfloor finishes and ceiling loads of 1 kN m^-2. Calculate the design loads acting on beams B1C1, B2C2 and B1B3 andcolumns B1 and C1. Assume that all the column heights are 3 m and that the beam and column weights are 70 and60 kg m^-1 run respectively.

Floor Depth, d 225

Imposed Load, Pi 3 2

Ceiling Loads, PCL 1 2

Unit Steel Beam Mass,

Unit Steel Column Mass,

Column Height, H 3

WB 70

WC 60

Length of beam B1-C1, LBC1 6

Length of beam B2-C2, LBC2 6

Length of beam B1-B3, LB1B3 6

Unit Mass of Concrete, WCC 2400 3

Acc. Due to Gravity, =9.807 2

Unit Weight of Materials

Concrete Slab

PCC =WCC d 5.296 10

3 2

Steel Beams

PB =WB 686.466

Steel Columns

PC =WC 588.399

Loading

SlabSlab dead Load, gks =+PCC PCL 6.296 2

Slab imposed Load, qks =Pi 3 2

Ultimate Slab Load, US =+1.4 gks 1.6 qks 13.614 2B

Beam

UB =1.4 PB 0.961 Ultimate Beam Load,

Column

Ultimate Beam Load, UC =1.4 PC 0.824

Loading

B1-C1

PBC1 =+ 1.5 6 US UB 6 128.291

RB1 =PBC1

264.145

RC1 =PBC1

264.145

B2-C2

PBC2 =+ 3 6 US UB 6 250.815

RB2 =PBC2

2125.408

RC2 =PBC2

2125.408

B1-B3

PB1B3 =++ UB 6 1.5 6 US RB2 253.698 RB2

RB1a =PB1B3

2126.849

RB1B3 =PB1B3

2126.849

Column B1

Design Load On Column B1, PCB1 +++RB1 RB1a 1.47 UC 3

=PCB1 194.936

Design Load On Column C1, PCC1 ++RC1 66.33 2.52

=PCC1 132.995