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D. R. WiltonECE Dept.
ECE 6382 ECE 6382
Functions of a Complex Variable as Mappings
8/24/10
A Function of a Complex Variable as a MappingA Function of a Complex Variable as a Mapping
w f z
z w
A function of a complex variable, , is usually viewed
as a from the complex to the complex plane.mapping
z
z
x
yw
u
vw
w f z
Simple Mappings: TranslationsSimple Mappings: Translations
a
w a z
Translation:
where is a complex constant.
z
z
x
yw
u
vww za
a
z
z
a .
The mapping translates every point in the plane
by the "vector"
Simple Mappings: RotationsSimple Mappings: Rotations
ii i iw e z e re re
Rotation:
where is a constant. real
z . The mapping rotates every point in
the plane through an angle
z
z
x
yw
u
v
w
iw e z
z
Simple Mappings: DilationsSimple Mappings: Dilations
( )i iw az a re ar e
a
Dilation (stretching) :
where is a constant. real
arg
z z
a
z A A A
A
The mapping magnifies the magnitude of a point
in the complex plane by a factor .
Multiplying by a number is equivalent to
stretching it by a factor
rotatin
complex
and arg Ag it through an angle
z
z
x
y w
u
v
ww za
z
Simple Mappings: InversionsSimple Mappings: Inversions
1 1 i
ie
wz rre
Inversion:
Inversions have a "circle preserving" property, i.e., circles
always map to circles (straight lines are "circles" of infinite radius).
Points the unit circle map to points the unit ciroutside inside cle
and vice versa.
0z x iy
Re0x
01 x
1
1 z
Im
0z x iy The straight line maps to a circle
z
Re
Im
11 z
Inversion circle -preserving property
Inversion – Line-to-Circle PropertyInversion – Line-to-Circle Property
0z x iy
Re0x
01 x
1
1 z
Im
0
002 2 2
0
02 2 2 20 0
1
1 2
1 2
z x iy
z* x iyw u iv x y
z x yz
x yu v
x y x y
y
u x
v
( is a constant, is a parameter)
To prove the straight line maps to a circle :
, ,
merely parameterizes the line, so eliminate it :
0 0 3
3 2
x v, yy u
v
Substituting from into 0x v
2
02 2
2 00
u ux vuux v
xu
2 2 2 20 0
22 2 2 2 2 20 0 0 0 0
222
0
0 0
12 01
2 0
1 12 4
1 12 2
0
u,v ,
x
x
x x
.u x v x
u x ux v x ux v x
u v
Eq. of circle of radius ,
centered at
Rearranging,
or
Re01 x
0x1 z
Im
Inversion – Line-to-Circle Property, cont’dInversion – Line-to-Circle Property, cont’d
1 1
i
ii
z e z z d it ,
w eze z
Multiplying by rotates the line by the angle
but the circle is rotated in the direct on:
iopposite
Re
d
1 z
Im z
1 d
Re1 dd
1 z
Imz d it
z d it , t ,
x d .
is the equation of vertical line
passing through on the x - axis
( ), < <
1 1< <
i
i
z
z e d it t
z
w e , tz d it
Since every straight line in the - plane may be
represented as
-
via the transformation
every straight line in the plane is mapped into
a circle
Simple Mappings: Inversions, cont’dSimple Mappings: Inversions, cont’d
1 1 i
ie
wz rre
Geometrical construction of the inversion
1w
z
w
u
v
w
z
1
z
x
y
z
w
u
v
w
A General Linear Transformation (Mapping) Is a A General Linear Transformation (Mapping) Is a Combination of Translation, Rotation, and DilationCombination of Translation, Rotation, and Dilation
Arg Arg i Bi B iw A Bz A B e re A B r e
A ,B
rotation
dilation
translation
Linear transformation:
where are complex constants .
z
z
x
y w
u
v
w
w A Bz B z
A
Arg B
A General A General BilinearBilinear Transformation (Mapping) Is a Succession Transformation (Mapping) Is a Succession of Translations, Rotations, Dilations, and Inversionsof Translations, Rotations, Dilations, and Inversions
0
A Bzw
C DzA,B,C,D
D ,
A BC D B D C DzA Bz A BC Dw B D
C Dz C Dz C Dz
f C D ,
Bilinear (Fractional or Mobius) transformation:
where are complex constants .
Note that if
If we let (translation, dilation, rota
A BC Dg
A Bzw B D g f z
C Dz
tion)
and (inversion, dilation, rotation)
then the Mobius transformation may be written as
which is just a sequence of translations, dilations, rotations, and an inversion
Sinc
z
w
e each transformation preserves circles, bilinear transformations also
have the circle -preserving property : circles in the plane are mapped into circles in
the plane, with straight lines included as circles of infinite radius.
Bilinear Transformation Example: The Smith ChartBilinear Transformation Example: The Smith Chart
0
0
Zz r jx Z R jX
Z
Z
Let where is the impedance at a
point on a transmission line of characteristic impedance and
is the generalized reflection coefficient
0
0
1 1
1 1
Z Z z z
Z Z z z
or simply
at poi nt
.
Re
Im1
1
z
z
For an interpretation of mobius transformations as projections on a sphere, seehttp://www.youtube.com/watch?v=JX3VmDgiFnY
zr
jx
The Squaring TransformationThe Squaring Transformation
2 2 2iw f z z r e
x
yz
z
z
w
u
v
w
z w
z w
The transformation maps the -plane into the -plane
The entire -plane covers the -plane twice
The transformation is said to be
half entire
many - to - one
Another Mapping of the Squaring Another Mapping of the Squaring TransformationTransformation
2 2 2iw f z z r e
Re
Im
1 2 3
3
2
1
9
4
1
90o
180o
270o
360o
-180o-270o
-360o 0o
-90o
Re
Im
2z
The Square Root TransformationThe Square Root Transformation
21 1
2 2 2 0 1ki
w f z z r e , k ,
w
u
v
w
z w
The transformation maps the entire -plane into one half of the -plane
The transformation is said to be The inverse of the square
function (i.e., the square root function) is
one - to - many.
no . t unique
wx
yz
z
top sheet
bottom sheet
3
Connecting the Two Sheets at a Branch Cut to Form a Connecting the Two Sheets at a Branch Cut to Form a Riemann SurfaceRiemann Surface
21 1
2 2 2 0 1ki
w f z z r e , k ,
bottom sheet
branch point
branch cut
arg
arg
z
If we agree to limit to one sheet, never crossing the branch cut,
the inverse is unique. Physics usually dictates the branch choice and cut.
The two sheets shown may be defined as
1)
arg 3
z
z
(principal branch)
2)
x
yz
z
3
Only at a branch point are multiple cycles encircling the point required to return to the starting value
top sheet
The Branch Cut Allows Us to Map the Square Root FunctionThe Branch Cut Allows Us to Map the Square Root Function
1 122 2 10
i kw f z z r e , k , ,
Re
Im
1 2 3
3
2
11
22.5o
45o
67.5o
90o
-45o-67.5o
-90o 0o
2
3
-22.5o
top sheet, k = 0
Re
Im
1 2 3
3
2
11
202.5o
225o
247.5o
270o
135o
90o 180o
2
3
157.5o
bottom sheet , k = 1
112.5o
Re
Im1
2z
Constant Constant uu and and vv Contours are Orthogonal Contours are Orthogonal z x, y u x, y v x, y
u uˆ ˆux y
v vˆvx y
x y
x
Consider contours in the plane on which the real quantities and
are constant.
The directions normal to these contours are along the gradient direction :
ˆ
u u u uˆ ˆ ˆ
vˆ ˆ ˆv u
y xˆ ˆu v
x y xx yy
u
y
x y x y x y x y
The gradients, and therefore the contours, are orthogonal (perpendicular) by the C. R. conditions : C.R. cond's
0u u u u
y x y x
x
yz
u
constantu
constantv
v
u
vw
Mappings of Analytic Functions are Mappings of Analytic Functions are ConformalConformal (Angle-Preserving) (Angle-Preserving)
1 2
0 0 00
C C z x iy
w u iv
f z w f z
Consider a pair of intersecting paths in the plane mapped
onto the plane.
If at the intersection of their mapping, then the angles
between the intersecting c
,
,
onto
1 0 1 1 0 1 1 1
2 0 2 2 0 2 2 2
2 1 2 1
2 1
Arg Arg Arg
Arg Arg Arg
Arg Arg Arg Arg
0
w f z z w f z z , z C
w f z z w f z z , z C
w w z z
z , z ,
urs are preserved:
along
along
The approximation improves as with
2 1
2 1
Arg Arg
Arg Arg
z z
w w
and the above approximation yielding
u
v
w 1C
2C0w
x
y
z1C
2C
0z
0
2
0
Arg
0
0
Arg0
0
2 0 0
Arg Arg Arg 2Argz
z
z
f z
w f z z z
w f z z z z; f
w z z z
The condition below is
needed since is !
E.g., consider at :
since ,
indeterminant
Constant |Constant |w|w| and Arg and Arg ww Contours are also Contours are also Orthogonal Orthogonal
1
iw Re R
z f w z
If the constant and contours are orthogonal.
If is a mapping back to (a branch of) the plane,
the mapping preserves the orthogonality.
-45o
Re
Im
1 2 3
3
2
11
22.5o
45o
67.5o
90o
-67.5o
-90o 0o
2
3
-22.5o
z
12f z z Magnitude, phase plot of :
w
u
v
The Logarithm FunctionThe Logarithm Function2 ln
2 1 2
z z i k
z
w e e z w
w z e w
z z i k k , ,
Since , the inverse function cannot be unique.
I.e., given , is the complex number such that . But this
number cannot be unique, since , ,
has the propalso
2
( 2 )2 2
ln
ln 2 0 1 2
ln 2 0 1 2
z z i k z
i v ki w w i k u iv i k u
u
e e e w
w z w
z z e e e e e e
z e u z , v k , k , , ,
w u iv z i k , k , , ,
erty that .
Let . To evaluate , note that we have
so that
and hence
which has 0z a branch point with an infinite number of branches.
x
yz
x
y
Infinite # of sheetsBranch cut
Branch point
Riemann surface for the log function
Arbitrary Powers of Complex NumbersArbitrary Powers of Complex Numbers
ln
ln 2ln
ln
0
Since ,
also has an infinite number of values (branches), unless integer for some ,
i.e., unless is real ( ) and rational. r i i
z z
a z ai ka a z
z e e
z e e
ak k
a a i a a
x
y
x
yz
Infinite # of sheetsBranch cut
Branch point
Riemann surfaces for za