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Prof. Dr.-Ing. Joachim Gnther
Technisches Zeichnen
Ergnzungen zum Skript:
- Kegelbemaung
Seite 2
Version 1.3
Technisches Zeichnen 2014
Kegelbemaung
7
0
2
100
Seite 3
Kegelverhltnis C
D
d
l
2tan2
dDC
Seite 4
D =
d =
l = 100
2:1100:50100
2070
C
Seite 6
Aufgabe Kegelbemaung
1
60
a) 150
b) 140
c) 110
d) 60
e) 10
Heimarbeit
Kegelwinkel
fr a)
D=160 d=150
e)
D=160 d=10
zeichnerisch
und rechnerisch
bestimmen
50
C = ?
a)
b)
c)
d)
Seite 7
berechnen
rechnerisch /
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1 Systematic feedback (recursive) encoders G’(D) = [1,(1 + D 2 )/(1 + D + D 2 ),(1 + D)/(1 + D + D 2 ) ] Infinite impulse response (not polynomial) Easier
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![1 Systematic feedback (recursive) encoders G’(D) = [1,(1 + D 2 )/(1 + D + D 2 ),(1 + D)/(1 + D + D 2 ) ] Infinite impulse response (not polynomial) Easier](https://img.dokumen.tips/doc/110x75/56649e8f5503460f94b93c30/1-systematic-feedback-recursive-encoders-gd-11-d-2-1-d-.jpg)
![信号処理 - 北海道大学sdm0.5 1 t[] x (t)-d/2 0 d/2 2 sinc /2 sin /2 2 0 2 1 d d d d X d X d t d t x t のフーリエ変換 は フーリエ 変換 振幅スペクトル （d](https://img.dokumen.tips/doc/110x75/5eda76c8b3745412b5716294/c-oee-05-1-t-x-t-d2-0-d2-2-sinc-2-sin-2-2-0-2.jpg)
![d d·· ]ectlve 2)](https://img.dokumen.tips/doc/110x75/6261f85aedcadf7e3f08dbdf/d-d-ectlve-2.jpg)
