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Yoonchan Jeong School of Electrical Engineering, Seoul National University
Tel: +82 (0)2 880 1623, Fax: +82 (0)2 873 9953 Email: [email protected]
Electromagnetics: Antenna Patterns and Antenna Parameters
Thin Linear Antennas Antenna Arrays
(11-3, 11-4, 11-5)
D. K. Cheng, Field and Wave Electromagnetics, 2nd ed., Addison-Wesley, 1989.
Radiation Pattern or Antenna Pattern
Relative far-zone field strength at a fixed distance from an antenna:
→ E-plane pattern:
→ H-plane pattern:
D. K. Cheng, Field and Wave Electromagnetics, 2nd ed., Addison-Wesley, 1989.
Herzian dipole: Far fields:
θβπ
β
φ sin4
=
−
ReIdljH
Rj
θβηπ
β
θ sin4 0
=
−
ReIdljE
Rj
1/2 >>= λπβ RR
θθ sin=→ ENormalized
22 zxxE+
=→ θ
22
2
21
21
=+
±→ zx
E-plane pattern:
H-plane pattern:
2/sin
πθθ θ=
=→ ENormalized
Normalized field strength vs θ for a constant φ
Normalized field strength vs φ for θ = π/2
2 1=
θE
D. K. Cheng, Field and Wave Electromagnetics, 2nd ed., Addison-Wesley, 1989.
Antenna Patterns
Typical H-plane radiation patterns:
3
D. K. Cheng, Field and Wave Electromagnetics, 2nd ed., Addison-Wesley, 1989.
Antenna Parameters (1)
1. Bandwidth (Width of the main beam):
2. Sidelobe levels:
A typical H-plane radiation pattern:
3. Directivity: avPRU 2=→ Radiation intensity (time-averaged power per unit solid angle):
→ Total time-average power radiated: Ω=⋅= ∫∫ dUdP avr sP
→ Directive gain: av
D UUG ),(),( φθφθ =
→ Directivity: av
max
UUD =
∫ ∫= π π
φθθφθ
π2
0 0
2
2
sin),(
4
ddE
Emax
4
→ Angular width between the half-power or −3-dB points (occasionally, −10-dB points)
→ Typically, −40-dB required for radar applications
πφθ
4/),(
rPU
=π
φθ4/),(
Ω=∫ dU
U
π4/max
rPU
=
Time-average Poynting vector
Antenna Parameters (2)
6. Radiation resistance:
4. Power gain:
π4/max
iP P
UG = lri PPP +=←
Total input power
Radiated power
Power loss (Ohmic, structural, etc.)
5. Radiation efficiency:
i
rr P
P=η
rr RIP 2
21
=
7. Loss resistance: ll RIP 2
21
=
5
DGp=
π4/max
rPU
=av
max
UUD =←
D. K. Cheng, Field and Wave Electromagnetics, 2nd ed., Addison-Wesley, 1989.
Current distribution:
)(sin)( zhIzI m −=→ β
Recall: Hertzian dipole
θβπ
β
φ sin4
=
−
ReIdljH
Rj
θβηπ
β
θ sin4 0
=
−
ReIdljE
Rj
)1/2( >>= λπβ RR
θβηπ
ηβ
φθ sin4 00
′
==→′−
ReIdzjdHdE
Rj
( ) 2/122 cos2 θRzzRR −+=′←
∫−− −≅=→
h
h
zjRjm dzezheR
IjHE θββφθ β
πθβηη cos0
0 )(sin4
sin
[ ]∫−− +−=
h
h
Rjm dzzjzzheR
Ij )cossin()coscos()(sin4
sin0 θβθββπ
θβη β
∫ −= − hRjm dzzzheR
Ij0
0 )coscos()(sin2
sin θββπ
θβη β6
Far fields:
Thin Linear Antennas (1)
Elemental contribution
θcoszR −≅
Why?
Why?
Thin Linear Antennas (2)
∫ −≅=→ − hRjm dzzzheR
IjHE0
00 )coscos()(sin
2sin θββ
πθβηη β
φθ
)(60 θβ FeRIj Rjm −=
θβθβθ
sincos)coscos()( hhF −
=←← Pattern function
D. K. Cheng, Field and Wave Electromagnetics, 2nd ed., Addison-Wesley, 1989.
hhλπβ 2
=→
7
Far fields:
Radiation pattern: Zero radiation
Zero radiation
Why?
Half-Wave Dipole (1)
θβθβθ
sincos)coscos()( hhF −
=E-plane Pattern function:
For a half-wave dipole: 2//2 πλπβ ==→ hh2/2 λ=h
[ ]
=→ −
θθπβ
θ sincos)2/(cos60 Rjm e
RIjE
[ ]
=→ −
θθπ
πβ
φ sincos)2/(cos
2Rjm e
RjIH
Far-zone fields:
Time-average Poynting vector: [ ] 2
2
2
sincos)2/(cos15
21
== ∗
θθπ
πφθ RIHEP m
av
Total power radiated:
∫ ∫=π π
φθθ2
0 0
2 sin ddRPP avr
[ ]∫=π
θθ
θπ0
22
sincos)2/(cos30 dIm
254.36 mI≅8
D. K. Cheng, Field and Wave Electromagnetics, 2nd ed., Addison-Wesley, 1989.
Radiation resistance: )(1.732
2 Ω==m
rr I
PR
Half-Wave Dipole (2)
Directivity: )2/(2
max πθ == avPRU
π4/max
rPUD =→
Half-power bandwidth: [ ]
= −
θθπβ
θ sincos)2/(cos60 Rjm e
RIjE
[ ]2
1sin
cos)2/(cos=→
θθπ 78≈→ FWHMθ
What about the total impedance?
rrr jXRZ +=For the impedance matching, the dipole length should be slightly shorter than λ/4!
9
[ ] 2
2
2
sincos)2/(cos15
=←
θθπ
πRIP m
av
254.36 mr IP ≅←
215mI
π=
64.154.36
60==
rr RIP 2
21
=←
Quarter-Wave Monopole
D. K. Cheng, Field and Wave Electromagnetics, 2nd ed., Addison-Wesley, 1989.
Recall: Image method ← Radiation limited into the upper half-space!
)54.36(21 2
mr IP ×=→
Total power radiated:
Radiation resistance:
)(54.3622 Ω==→m
rr I
PR
Directivity: 64.1
2/===→
πr
max
av
max
PU
UUD
10
For HW DP
Recall: Electromagnetic Waves (RF/MW)
+Q
−Q
z θ
O dl
R
×
E
H aR
A Hertzian dipole
λ/4
λ/4
Half-wave dipole antenna
λ/4
Quarter-wave Monopole antenna
c = fλ
Speed of EM wave
Frequency
Wavelength λ/4 = 3×108 / 2.4×109 / 4 ≈ 0.031 m
Conducting ground
WiFi router (f = 2.4 GHz)
11
Antenna Arrays
Two-element arrays:
D. K. Cheng, Field and Wave Electromagnetics, 2nd ed., Addison-Wesley, 1989.
00
0
),(R
eFEERj
m
β
φθ−
=
11
1
),(ReeFEE
Rjj
m
βξ
φθ−
=
Total electric field:
+=+=
−−
1010
10
),(Ree
ReFEEEE
RjjRj
m
βξβ
φθ φθ cossin01 dRR −≅←
)1(),( cossin
0
0 ξφθββφθ jdjRjm eee
RFEE +=→ −
= −
2cos2),( 2/
0
0ψφθ ψβ jRj
m eeR
FEξφθβψ +=← cossind
2cos),(2
0
ψφθFREE m=→
Element factor
Array factor
12
)1(),(0
0
ψβφθ jRjm ee
RFE += −
Initial phase difference
Why?
Multi-Element Parallel Dipole Arrays
D. K. Cheng, Field and Wave Electromagnetics, 2nd ed., Addison-Wesley, 1989.
For two parallel half-wave dipoles:
2cos),(2
0
ψφθFREE m=
2cos
sin]cos)2/cos[(2
0
ψθ
θπREm=
)cos(21cos
2cos)( ξφβψψ +== dA
→ Normalized array factor:
2/πθ =←
D. K. Cheng, Field and Wave Electromagnetics, 2nd ed., Addison-Wesley, 1989.
Arrays of equal magnitude and a uniform progressive phase shift: ψψψψ )1(211)( −+⋅⋅⋅+++= Njjj eee
NA
ξφβψ +=← cosd
ψ
ψ
ψ j
jN
ee
NA
−−
=→111)(
)2/sin()2/sin(1
ψψN
N=
2/πθ =←
13
Why zero? θ
βθβθsin
cos)coscos()( hhF −=←
→ Broadside or endfire?
ξφθβψ +=← cossind