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CU06997 Fluid Dynamics
Flow in pipes and closed conduits 4.5 Turbulent flow (page 100-111)
4.6 Local head losses (page 112-116)
4.7 Partially full pipes (page 116-121)
1
Culvert, no upstream and downstream
velocity
1
Culvert, with upstream and downstream
velocity
1
Culvert, no upstream and downstream
velocity
2 [m] 2g
uξΔΗ
2
culvertculvertculvert
21
2
222
2
111
22 H
g
uzy
g
uzy
P1 P2
Friction loss, Darcy Weisbach
R
Lf
4
2
Inlet and outlet loss [intree en uitree verlies]
2
11
i
1o
µ=contraction coëfficiënt (bv 0,6) [1]
2
Outlet los
3,0u 5,0u
2
Loss at a (open) valve [klep]
Loss at a non-return valve
[terugslag klep]
0,2 and 0,1 Between
1 elyapproximat
2
Head (energy) loss strategy
[m] 2g
uξΔΗ
2
[m] 2g
u)ξξξ(ΔΗ
2
.....21total
[m]2g
uξ
2g
uξ
2g
uξΔΗ
2
.......
2
22
2
11total
If velocity does not change
2
Head (energy) loss culvert
2
11
i
1oR
Lf
4
[m] 2g
u)ξξξ(ΔΗ
2
culvertoficulvert 2
Submerged Culvert 1 [Volledig gevuld]
2g
uξΔΗ
2
ctottot
....)ξξξ( ofi tot
2
11
i
R
lf
4
1o
∆𝐻𝑡𝑜𝑡 = Total Head Loss Culvert [m]
𝜉𝑡𝑜𝑡 = Sum of Loss coefficients [1]
𝑢𝑐 = Mean Fluid Velocity Culvert [m/s]
𝜉𝑖 = Loss coefficient due to contraction [1]
𝜉𝑤 = Loss coefficient due to friction [1]
𝜉𝑜 = Loss coefficient due to outlet [1]
𝜇 = Contraction coefficient [1]
𝑔 = earths gravity [m/s2]
𝜆 = Friction coefficient [1]
R = Hydraulic Radius [m]
𝑙 = Length between the Head Loss [m] 2
Submerged Culvert 2
totcHgAmq 2
tot
m
1
2b
2g
uξΔΗ
2
ctottot
𝑄 = 𝑢 ∙ 𝐴
Submerged Culvert 2
totcHgAmq 2
tot
m
1
q = Flow rate Culvert [m3/s]
𝑚 = Discharge coefficient [m]
𝐴 = Wetted Area Culvert [m2]
∆𝐻𝑡𝑜𝑡 = Total Head Loss Culvert [m]
𝜉𝑡𝑜𝑡 = Sum of Loss coefficients [1]
𝑔 = earths gravity [m/s2]
2b
Culvert, no upstream and downstream
velocity
3
∆y=∆H
Difference in water level = Difference in total head
Culvert, with upstream and downstream
velocity
3
∆y≠∆H
Difference in water level ≠ Difference in total head
Culvert, with upstream and downstream
velocity
3
21
2
222
2
111
22 H
g
uzy
g
uzy
[m] 2g
uξΔΗ
2
culvertculvertculvert
P1 P2
Exercise 1 culvert
•Difference in waterlevel 1 m
•Dimensions culvert 2 x 2 m
•μ=0,6 and λ = 0,022
•Calculate Q and draw the H and y line
Discharge culvert
Exercise 2 culvert
•Difference in waterlevel 1 m
•Dimensions culvert 2 x 2 m
•μ=0,6 and λ = 0,022
•u upstream = 0,5 m/s, u downstream = 0,2 m/s
•Calculate Q and draw the H and y line