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3/25/15 1 COST APPROACH MARKET ANALYSIS FEASIBILITY HIGHEST & BEST USE 63 Cost Cost, Feasibility, Market & HBU – graded areas ! The cost approach: Theory & concepts ! Land valuation ! External obsolescence ! Market analysis: Subdivision ! Market analysis ! Functional obsolescence ! Reconciliation ! Market analysis: Shopping centers ! Market analysis: Office buildings ! Total & physical depreciation ! HBU decisions ! HBU applications 64 Cost COST APPROACH: THEORY & CONCEPTS 65 Cost

COST APPROACH - Ted Whitmer · Reconciliation ! ... is not the difference between cost and value, but is a cost, ... Cost 72 Cost Approach Inconsistencies! The age of the

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3/25/15

1

COST APPROACH

MARKET ANALYSIS FEASIBILITY

HIGHEST & BEST USE

63 Cost

Cost, Feasibility, Market & HBU – graded areas !  The cost approach:

Theory & concepts !  Land valuation !  External

obsolescence !  Market analysis:

Subdivision !  Market analysis !  Functional

obsolescence

!  Reconciliation !  Market analysis:

Shopping centers !  Market analysis:

Office buildings !  Total & physical

depreciation !  HBU decisions !  HBU applications

64 Cost

COST APPROACH: THEORY & CONCEPTS

65 Cost

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Why Do Appraisers Hate the Cost Approach? !  Do we have to do a breakdown method for

depreciation? !  Does the market consider cost? !  Can you add the value of the land to the

value of the improvements? !  Is it because it is not developed properly in

courses?

66 Cost

Cost Approach Reliability

!  The cost approach is applicable when the improvements are new & when the improvements are older!

Reliability

Age of Property

High

Low

New Old

67 Cost

Cost Approach !  Reproduction Cost

!  Exact copy !  Can it be done with

even a 5 year old house? What about HVAC?

!  Does this relate to market value definition?

!  Replacement Cost !  Same utility !  Only cost of functional

superadequate items are different than for reproduction cost. Therefore, it is a modified Reproduction cost.

!  It does not build the building that is appraised 68 Cost

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3

Profit (Entrepreneurial Incentive) in the Cost Approach

!  Sale price minus cost, excluding profit? !  Is it what it would take to build improvements

as one of the agents of production? !  Land !  Labor !  Capital !  Profit or coordination

!  Is it only in the improvements? !  What about churches & owner-occupied

buildings? 69 Cost

Cost Approach Considerations ! The four agents of production are

land, labor, capital and coordination. This applies to any goods or services. The cost approach expresses the four agents. The value of the land + direct & indirect costs (labor & capital) and profit (coordination) are elements of cost. Profit, in the cost approach, is not the difference between cost and value, but is a cost, & should always be included.

! Newer texts set forth only three agents of production. Coordination or profit is a labor cost.

! The cost approach builds to the date of appraisal. The income approach discounts to the date of appraisal. The profit in the income approach is not the same as profit in the cost approach.

! Profit can be derived and even applied as a percentage of direct costs, direct & indirect costs, or direct, indirect costs and land value. However, the profit or coordination is only attributable to the improvements. If the improvements are destroyed, the profit is all lost.

70 Cost

Misconceptions About the Cost Approach

!  It sets the upper limit of value !  Investors do not consider the cost approach !  You cannot reflect leased fee or leasehold

valuations !  It should be independent of the income & sales

comparison approaches !  It is most useful for special purpose properties !  It is not useful for older properties

71 Cost

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Cost Approach Inconsistencies !  The cost does not

match with the quality of the improvements

!  The multipliers and other adjustments are not properly applied

!  Lease-up costs are not accounted for

!  The cost is not as of the appraisal date

!  The cost manuals do not reflect current costs from the local market (even after all adjustments)

!  Soft costs are omitted because the owner built with a small loan or all cash

!  Profit is not included

72 Cost

Cost Approach Inconsistencies !  The age of the

improvements is not consistent with !  previous renovations !  the age of improvements

in the area !  the condition of the

improvements !  after considering all

curables

!  Curables do not have profit or sufficient profit built into the estimate (when appropriate)

!  Depreciation is inconsistent with highest & best use as vacant (and land value)

!  Cost is not consistent with time line

73 Cost

Cost Approach Inconsistencies !  Appraising on the time line - soft & hard costs reflect

stage of completion? Date correct?

As Is

As Complete, But Not Stable Occupancy

As Complete & Stable Occupancy

Could Be Land Value

The Shell Of a Building Occupied & Finished Building

Land value

Hard cost to shell

Soft cost to shell

Land value

Hard cost to shell & finish

Soft cost to shell & finish & lease-up (marketing, commissions, tenant improvements)

74 Cost

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Cost Approach Inconsistencies

!  If leasehold estate or leased fee, is there a bottom-line or other adjustment?

!  Are site improvements in the land and the cost?

!  Overall, does the age of the improvements, the functionality and market justify the adjustment from cost expressed by the depreciation?

75 Cost

Special Purpose Property !  Definition: Economically,

suitable for only one use !  Therefore, use value is

appropriate? !  Therefore, cost approach

the default?

76 Cost

Bottom Line Adjustments !  A cost approach results in a fee simple value without

adjustments. If the appraisal is to estimate another interest such as leased fee or leasehold estate, then an adjustment is necessary.

!  Use bottom-line adjustments for the present worth of

excess rent (add) or present worth of below market rent (subtract). This is a market rent equivalency adjustment.

!  Use bottom-line adjustments for intangibles or personal

property. 77 Cost

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LAND VALUATION

78 Cost

Land Valuation Four Acceptable Methods

! Sales Comparison ! Allocation ! Extraction ! Income Approach

!  Ground Rent Capitalization

!  Land Residual

!  Subdivision 79 Cost

Unit v. Element of Comparison Unit of Comparison

!  Convenient way to look at price

!  Whole property !  Per square foot

!  Of land area !  Of buildable area

!  Per front foot !  Residential !  Lake front !  Other

Element of Comparison !  Factors that cause prices to

vary (our adjustments) !  At date of sale

!  Property rights !  Financing !  Conditions of sale !  Expenditures made shortly

after time of sale !  Market conditions !  At date of appraisal

!  Location !  Physical !  Use !  Economic !  Non-realty

80 Cost

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Allocation

!  The percentage (%) of total value to land value !  Is common in residential lots !  Is useful as a rule of thumb

!  Example: !  A house sold for $200,000 in a new neighborhood & the lot

was sold for $40,000. Therefore, the land value is 20% of a total house sale price.

81 Cost

Extraction !  Is also called Abstraction. It is the sale

price less contributory building value to result in a dollar ($) value for the land. !  It is used in areas with older buildings or

buildings representing interim uses. !  Example:

!  An older property sold for $500,000 & the buyer gave the building $50,000 in value. Therefore, the land is worth $450,000.

82 Cost

Ground Rent Capitalization

!  Is an income approach to valuing land. !  Is useful with leased land along highways, downtown areas, or

other commercial areas !  You should not state in a report: �Because the subject in vacant

land, an income approach is not applicable.�

!  Example !  A site was leased for a restaurant for $5 PSF absolute net

for 25 years to a fast food chain. Rates of return for similar leases are 11% - 13%. The value of the site is approximately $45 PSF.

83 Cost

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Land Residual !  The following must be known for a land

residual !  Building value !  Building capitalization rate !  Land capitalization rate !  Estimated NOI

!  Example: !  A drug store is to be constructed for $2,000,000, inclusive of

profit. The market requires a 9% return on investment for buildings and 8% for land. What can be paid for a site if the net operating income is expected to be $270,000/year?

!  Answer: ($270,000 - $180,000)/.08 = $1,125,000 84

I R V B 9% 2,000,000 L 8% T 270,000

Cost

Subdivision !  To develop land value:

!  Estimate retail sales !  Estimate absorption period !  Deduct expenses !  Deduct all development costs !  Discount at rate of return

!  The above procedure results in how much one could pay for land.

!  To value a subdivision, only costs to complete would be deducted. By deducting all costs above, vacant land value results.

85 Cost

TOTAL & PHYSICAL DEPRECIATION

86 Cost

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87 Cost

Depreciation !  Some buildings depreciate significantly at first and

others at the end of the economic life

Vo = 100% of cost

Vo = 0% of cost

Vo as a % of cost

Age of property

A

B

C

88 Cost

Depreciation for a Corporate Headquarters, Many Special Use Properties & Many Houses !  Vo is less than 100% of cost at construction

Vo = 100% of cost

Vo = 0% of cost

Vo as a % of Cost

Age of Property

Obsolescence due to �overimprovement� or due to use of market value definition

89 Cost

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Likely Depreciation of Improvements Over Time

!  You must determine where an improvement is in relation to the deferred maintenance.

Vo = 100% of cost

Vo = 0% of cost

Vo as a % of Cost

Age of Property

If no $ is spent

Average over long period of time

Money spent on curables over time

90 Cost

Depreciation With Renovation !  This assumes the renovation costs were

reasonable. Note the life is extended. Vo = 100% of cost

Vo = 0% of cost

Vo as a % of Cost

Age of Property

Average over a long period of time

Renovation

New depreciation line

91 Cost

Depreciation Of Components !  Not all components of a building depreciate over the

same life

Vo = 100% of cost

Vo = 0% of cost

Vo as a % of Cost

Age of Property

�Skeletal Structure� or total physical life

Items that last 50% of total life

Items that last <50% of total life

Economic Life of all improvements

92 Cost

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Depreciation on the other Approaches – Income

!  Curable !  (1) Run the income, vacancy, expenses and

develop the cap rate as though there is nothing that needs to be done. This overstates the value until the next step

!  (2) Deduct the amount of curable from the indicated value. You bring over line 3A, not the depreciation estimate in the cost approach!

!  Note: The curable depreciation may have a profit component. Also, you do this procedure because the economic test that determined the item or items considered were economically justified to cure, replace, etc. as of the appraisal date.

93 Cost

Depreciation on the other Approaches – Income

!  Incurable !  Run the income, vacancy, expenses and develop

the cap rate as the property is. It has already been determined that whatever may decrease rents, increase vacancy, increase expenses or raise the cap rate is not economically justified to spend money.

94 Cost

Depreciation on the other Approaches – Sales

!  Curable !  It depends…

"  If you add all deferred maintenance or curables to your sales before adjusting, then you will conduct your adjustment process as though there is no deferred maintenance or curables with the subject. At the end after determining a value as though nothing needs to be done with the subject you would deduct all of line 3A.

"  If you do not add all curable items to your sales, in the adjustment process you would adjust the difference between the curables in the comparables and the subject.

95 Cost

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Depreciation on the other Approaches – Sales

!  Incurable !  You can adjust the comparables for the incurable

functional obsolescence (line 3B) !  You can analyze the sales as though there is no

functional obsolescence, then bottom-line line 3B !  Sometimes all the comparables have the same

functional obsolescence as the subject. In this case, you would not have to adjust any obsolescence.

!  Sometimes the comparables have some degree of the same functional obsolescence. You deduct the difference.

!  E.G. You are appraising an old warehouse with a low eave height. All your comps have the same eave height.

96 Cost

Handling Depreciation in other Approaches

97

Income Sales Incurable Do nothing. The income

approach will be conducted as though nothing will be cured. Incurable obsolescence shows up in 1.  Decreased income 2.  Decreased occupancy 3.  Increased expenses 4.  Increased Ro

Choices: 1.  Run sales as though

there is no incurable obsolescence & deduct it as a line item.

2.  If sales have the same incurable obsolescence, do nothing.

3.  Adjust for the difference in incurable obsolescence

Cost

Handling Depreciation in other Approaches

98

Income Sales Curable Run the income approach as

if there is no deferred maintenance or curable items. (As though all is cured). Then deduct line 3A.

Two choices: 1.  Add all deferred

maintenance & curable items in your sales & analyze the subject as though there are no curable items (the subject is without deferred maintenance, etc.). Then deduct line 3A.

2.  Adjust for the difference in curables & deferred maintenance items

Cost

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FUNCTIONAL OBSOLESCENCE

99 Cost

Format

!  Line 1 Cost of item !  Line 2 Physical depreciation charged !  Line 3 [Go with lower & cross out larger]

!  A If curable !  B If incurable

!  Line 4 Value of correct item

100 Cost

Format !  Line 1 Zero if not in property !  Line 2 If line one is zero, so is this !  Line 3 Sometimes you don’t get a choice

!  A If curable (Include profit) !  B If incurable

!  Line 4 Use the value & not the cost unless that is all you have

If there is surplus land, put the value of the site in line one & the land value needed for the size of site in line 4 & subtract.

101 Cost

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Considerations !  Functional obsolescence is “in” the

buildings but is a result of poor layout, outdated fixtures, poor design, ugly colors, etc.

!  Functional obsolescence is sometimes a rational expense… !  Corporate headquarters !  A swimming pool !  Tenant finish !  Etc.

102 Cost

EXTERNAL OBSOLESCENCE

103 Cost

External Obsolescence

!  Two major categories of external obsolescence… !  Economic – Poor market

!  This is typically short-term & discounted with a yield rate, not capitalized with a Ro

!  Environmental – Next to something that causes loss !  This may be estimated using direct capitalization if the

loss will go on for an undetermined time

104 Cost

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External Obsolescence

!  The total loss from external obsolescence must be allocated between land & building. The total external obsolescence is that attributable to the building. !  Total loss/Ro – loss to land !  Total loss from external reasons x building/value

ratio [This usually doesn’t work but if it is the only information you get, use it.]

!  PV of loss from yield capitalization – loss to land

105 Cost

External Obsolescence

!  External obsolescence as a % is computed on physically & functionally depreciated cost !  Cost = $1,000,000 !  Physical depreciation = $100,000 !  Functional obsolescence = $200,000 !  External obsolescence = $350,000 !  % external obsolescence =

$350,000/($1,000,000 – 100,000 – 200,000) = 50%

106 Cost

MARKET ANALYSIS - SUBDIVISIONS

107 Cost

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Subdivision Analysis

!  Capture – The percentage of the market the subdivision is expected to achieve

!  Absorption – Number of units sold per some time period, such as per month, per quarter, per year.

!  Projecting Units – Population increase divided by average household size x % to category (owned or rental) x % in value range of subject x capture rate

108 Cost

Subdivision Analysis

COMPONENTS OF AN AVERAGE LOT PRICE IN A SUBDIVISION Return to: "On" Capital Return on equity capital

Return on debt capital Ongoing Management expense or Management Profit Line (To make the investment a hands off investment) All Expenses Marketing expenses Commissions Closing expenses of sale Overhead Other expenses All Costs Costs of infrastructure Costs of offsite improvements Prorated cost of amenities Raw Land Cost Underlying raw land value THE SUM OF THE ABOVE IS THE AVERAGE LOT PRICE THAT RETURNS ALL EXPENSES, COSTS, RETURN ON CAPITAL, UNDERLYING LAND VALUE, COSTS OF AMENITIES AS WELL AS THE PRORATED LAND COSTS TO THE AMENITIES TO THE AVERAGE LOT. NOTE: THE RETURN "OF" IS IN THE RETURN OF EXPENSES, COSTS AND UNDERLYING LAND VALUE.

Cost

Copyright Ted Whitmer. All rights reserved.

17 Cost

109 Cost

Absorption

110

Absorption A subdivision has 100 proposed lots that will sell for $40,000/lot. The lot represents approximately 25% of total home value. Qualify at 2 times household income with income ranging from $25,000 to $200,000 per family. Given a supply of 300 lots competing with the subject and 1,000 new families in the next year. How many months should it take to absorb the subject, assuming 20% of the families qualify for the subject price range, and the subject is in an average competitive position? Capture rate = % of total potential market absorbed in the subject = lots in subject sold per period ÷ total lots in market Absorption = total families per time period moving into area x % in subject price range x capture rate 100 families X 20% qualify = 200 lots per year 300 lots existing + 100 proposed = 400 lots Subject capture rate = 100/400 = 25% Absorption = 200 X 25% = 50 lots per year Sell Out = 100 lots/ 50 lots = 2 years

Calculation of Feasible Rents Feasible rents are a function of cost and rate of return. In its simplest form a project is feasible when the income generated produces the required return on cost. The cost includes direct, indirect and profit as well as land cost. The rate of return is either to a particular investor, class of investors or the market in general. Overall rates from sales of existing buildings can be used for indications of return rates. However, if the properties are older the range of rates may be on the higher end of the rates that should be used for analysis of a proposed project, unless there are indications of risk that make the project higher risk than with an existing property. There are two examples of feasible rent calculations following. One is for a property that leases 90% of gross building area and the other for a property that can lease 100% of gross building area. Another example of calculation of feasible rents with different rates of increase to various components is included.

Cost

Copyright Ted Whitmer. All rights reserved.

57 Cost

1,000

Cost

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Subdivision Analysis !  Qualifying

!  Income = $100,000 !  % for PITI = 28% !  Income for housing =

100,000 x 28% = $28,000

!  % for taxes & insurance = 25% of principal & interest. Therefore, 28,000/1.25 = $22,400

!  There is $22,400/12 = $1,867 for principal & interest

!  Mortgage: I = 6% & N = 360 months

!  You would run this across income strata to see what expected growth in population would qualify in subdivision 111

N I PV PMT FV 360 6/12 [311,400] -1,867

Cost

Subdivision Analysis – For vacant land

!  Project sell out period !  Project retail values !  Project expenses !  Project all costs !  Discount to PV with

high Yo

!  Relationships… !  Lot value to raw land value

per acre !  Lot value to projected home

value (allocation) !  Lot value = Land value per

acre/density per acre + cost per lot + profit per lot

112 Cost

Subdivision Analysis – Across Phases !  As you move down

the time-line the Yo decreases

!  When using the cost approach, build in costs that are spent

!  When conducting an income approach, deduct costs not yet spent

!  If you do rentals, use rental rates and qualify by % income to rentals instead of calculate payments

!  If no capture rate is suggested and there are four competing subdivisions (including the subject), go with a 25% capture

113 Cost

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Time Line – Cost Approach

114

Highest Yo Yo lower than vacant

Lowest Yo

Probably no direct costs spent. Could be on utilities to site.

Add direct costs spent to phase I for infrastructure, entry, etc.

Add costs spent to get to phase II

Soft costs spent on planning, approvals, marketing, etc.

Soft costs of approvals, marketing, etc.

Profit minimal Add profit down the time line

Most profit

Deduct lots sold over time if appraising an existing improved subdivision. If all the subdivision is proposed, you would not deduct lot sales.

Cost

115

COMMON RATIOS & MULTIPLIERS - EXAMPLE Population in area 50,000 Employment in area 30,000 Basic employment in area 10,000 Employment in mining 3,600 Mining in country 5% Forecast basic employment change 5,000 e (Local employment % in industry) = 3,600 / 30,000 = 12% E (National employment % in industry) = 5% (given) Location quotient (mining) = 12% / 5% = 2.40 EB multiplier (Total employment / basic employment) = 30,000 / 10,000 = 3 % of basic employees in industry = (2.40 - 1) / 2.40 = 58.3% PE ratio (Population to employment) = 50,000 / 30,000 = 1.67

Forecasting: Total employment: 5,000 x 3 = 15,000 Total population: 15,000 x 1.67 = 25,050 Note: 1. Basic employment x EB multiplier x PE ratio = Population (This can be used for change in basic employment as well as point in time analysis). 2. Forecast population = Forecast employment growth x PE ratio

SUBDIVISION LOTS (Also homes, apartments, duplexes, mobile homes, timeshare, condos, etc.)

Keys: 1. Population change per year or quarter, etc. 2. % to live in property type (e.g. mobile homes, single-family, etc.) 3. Monthly payments (inclusive of taxes & insurance) 4. % of households that can afford 5. Factor in current supply 6. Factor in competitive position of subject 7. Capture rate

Problem: Population increase: 1997 to 2002 = 35,000 persons Median household income: $35,000

25% ± $5,000 of median ; 50% ± $15,000 of median ; 75% ± $25,000 of median Average household size: 2.75 persons % single-family units: 60% Existing supply homes: 500 units Existing supply of home under construction: 100 units Existing single-family lots: 750 lots Typical lot value as % of total value: 22% Capture of subject subdivision: 20% of the market Proposed subdivision: 400 lots from $20,000 to $35,000/lot Mortgage terms: i = 8%, n = 360 months, LTV = 90%, Qualify at 28% total PITI Taxes are based on $20 per 1,000 of value and insurance on .75% of total home value

Cost

Copyright Ted Whitmer. All rights reserved.

44 Cost

Cost

116

Solution Housing units demanded: 35,000 ÷ 2.75 x 60% = 7,636 single family units Housing units per year: 7,636 ÷ 5 years = 1,527 per year City wide supply: 500 + 100 + 750 = 1,350 lots & houses Duration of supply: 1,350 / 1,527 = .88 years, or 10.6 months Home prices in subject: 20,000 / .22 to 35,000 / .22 = $90,900 to $159,000 Incomes to qualify: [90,900 x 90% x .0881* + (90,900 x .0275**)] /.28 = $34,700 (R) [159,000 x 90% x .0881* + (159,000 x .0275**)] /.28 = $60,600(R) * Rm = 360 N, 8 ÷ 12 I, -1 PV, solve PMT x 12 (.0881) ** Taxes are 2% & insurance .75% of value = 2.75% % who qualify: The median income is $35,000 and 75% of the population is within $25,000 of the median income, or $10,000 to $60,000. Therefore, 1/2 of 75% is from $10,000 to $35,000 & 1/2 is from $35,000 to $60,000. This translates to 75% divided by 2, or 37.5% of the population is in the range of the subject home value. Lots/homes demanded: 1,527 per year x .375 = 572 units per year Capture rate: 20% Absorption: 572 x 20% = 114 lots per year Sellout: 400 lots ÷ 114 = 3.5 years Variations: 1. If the market study is for apartments, etc. (rental units), then instead of mortgage

payments, look at affordability and rental payments that will be made. 2. Also look for % owner vs. renter, & possibly further segmentation based upon type of

subject property (e.g. high amenity apartments, extended care facilities, etc. 3. The problem above gives the capture rate (20%) for the subject. You may be asked to

make a judgment call on the test based upon competitive supply.

Cost

Copyright Ted Whitmer. All rights reserved.

45 Cost

Cost

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MARKET ANALYSIS

117 Cost

Market Analysis – Urban Structures

! Concentric Zone ! 5 zones – ripple effect ! PVI – peak value intersection

! Sector or Wedge Model ! Multiple Nuclei ! Axial Growth (Radial corridor)

118 Cost

Market Analysis – Levels of Market Study

119 Cost

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Market Analysis !  Productivity analysis What a site can be used for.

Look at physical, economic and functional characteristics. !  Situs – The sum total externalities as it relates to a specific

site. !  Linkages (1) transportation (2) utility

!  Linkage components: (1) Route, (2) Access, (3) Travel mode, (bus, car, rail, etc.) (4) Route orientation (inward to subject, outward or dual directional)

!  Externalities (1) Neighborhood (2) Linkage

!  Employment (1) service (2) basic

!  Economic base – brings $ into an area and exports goods or services. 120 Cost

Market Analysis 1. Local employment % in industry

e = Local employment in industry / Total local employment

2. National employment % in industry E = National employment in industry / Total national employment

3. Location quotient (If >1, then the industry is basic and

imports money & exports goods or services) LQ = e / E

4. Percentage of basic employees

(LQ - 1.0) / LQ = % of basic employees in industry

121 Cost

Market Analysis

5. Number of basic employees Total employs in industry x % of basic

6. EB multiplier (Employment to basic employment)

Total employment / Basic employment Basic employment x EB multiplier = Total employment

7. Population/employment ratio (PE)

Total population / Total employment 8. To forecast total population

Forecast total employment x PE ratio

122 Cost

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Market Analysis 9. To forecast total employment

Forecast basic employment x EB multiplier = Forecast total employment

10. Total employment

Basic + non-basic = total employment 11. m = Number of jobs created by a basic job

Non-basic employment / Basic employment 12. Population multiplier = reciprocal of % population in

workforce

123 Cost

Market Analysis – Demand

124 Cost

When the Market Softens

!  Feasible rent will exceed market rent & market rent will decline at a rapid rate

!  Land values will dive & decrease at a faster rate than will buildings !  The highest & best use of land will change from �office� to �hold for future office development�

!  Land will be a negative carry with a risky reversion pushed out. The mechanics of discounting can cause land to be worth 1/2 in one day what it was the day before.

125 Cost

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Market analysis – shopping centers

126 Cost

Shopping Centers

127

!  Population change in area !  Population change/average household (HH) size =

households !  Income per household !  % of household income to retail sales !  Average sales PSF !  Income for retail divided by average sales PSF = Net

space !  Net space/(1 – frictional vacancy) = Space Needed for

population growth !  Residual demand is after accounting for existing supply

Cost

Shopping Centers

128

!  Central place theory (CPT) – geographical concept that explains the number, size and location of retail of most goods and services relative to the local population.

!  Threshold population – the minimum people needed !  Two main goods & services

!  1. Higher-order – (cars, jewelry, etc.) need high threshold !  2. Lower-order – (food, clothes, etc.) need lower threshold

!  Market standard !  Characteristics expected by local acceptance

!  Property rating grid !  Site, parking, topography building improvements, tenant mix,

legal !  Purpose is to identify the competitive differential (subject vs.

competitors) Cost

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Shopping Centers

129

!  Retail market area – Area of consistent draw !  Primary – 70 to 80% of market !  Secondary – 15 to 20% of market !  Tertiary – Any remaining market share

!  Leakage– Loss of retail to other areas !  Reilly’s gravitational model– Predicts where one will

likely shop between centers !  Distance has a greater affect than size !  MAB = T / (1 + √Sa / Sb)

!  MAB = Market area boundary !  T = Travel time !  Sa = Size of store a !  Sb = Size of store b

Cost

Shopping Centers TYPE TENANT SIZE MARKET

Convenience Not anchored, convenience goods

< 30,000 Less than 5 minutes

Neighborhood Convenience + personal services

30,000 to 150,000 & 4-10 Acres

5-10 minutes & 1-1.5 miles with 5,000-40,000 people

Community Convenience + personal services + shopper goods

100,000 to 300,000 & 10-30 acres

10-20 minutes & 3-6 miles with 40,000-150,000people

Regional Convenience + personal services + shopper goods & general merchandise

300,000 to 1M & 30 acres & one or more dept stores

20 minutes & 5-10 miles with 150,000-400,000 people

Super Regional General merchandise + apparel + furniture + home furnishings + services

>800,000 & at least 3 dept stores of at least 100,000

30minutes & 10-35 miles with >500,000 people

Specialty/theme Boutiques, crafts, gourmet foods, etc.

Same as neighborhood & community

Same as regional

Lifestyle Upscale home furnishings, women’s fashion, restaurants, etc.

300,000 to 500,000 Same as regional

Power Minimum of 3, but usually 5+ anchors & few small

Open-air > 250,000 all large 15 miles & 20 minutes & 400,000-500,000 people

Off-price outlet & discount Name brand, wholesale, outlet 60,000 to 400,000 Same as super regional

Strip Convenience, quick-service restaurant, car, service

Varies Neighborhood

Highway Motels, restaurants, truck, etc. Varies Passing motorists 130 Cost

131

8. To forecast total population Forecast total employment x PE ratio 9. To forecast total employment Forecast basic employment x EB multiplier = Forecast total employment 10. Total employment Basic + nonbasic employment = total employment 11. m = Number of jobs created by a basic job Nonbasic employment / Basic employment 12. Population multiplier = reciprocal of % population in workforce Estimating demand - future in an area

� Retail 1. � in households in market area 2. x average household income 3. x % of income for retail 4. divided by sales psf per year

� Office 1. � in office employees over given period 2. x sf of office per employee 3. x capture rate of submarket

� Housing 1. � in households in area (population divided by persons per household) 2. + demolitions 3. - (actual - normal vacancies) 4. - (actual - normal units under construction)

Existing buildings and demand

� Existing Shopping Center Market Analysis Process

Step 1 � in households in market area Step 2 Delineate the market area Step 3 Forecast demand A. 4cast households B. Est. mean/median income & total income C. % household income spent on retail D. % of retail in subject type property E. Repeat above for secondary market F. Determine total demand in market G. Est SF by dividing F by sales PSF H. Adjust for vacancy (add) Step 4 Measure competitive supply Step 5 Analyze market equilibrium/disequilibrium Step 6 Forecast subject capture

Cost

Copyright Ted Whitmer. All rights reserved.

42 Cost

Cost

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Example

RETAIL Keys: 1. Households 2. Average household income 3. % income spent on retail 4. % spent in subject type 5. % retention 6. Sales required psf 7. Less existing supply 8. Less forecast supply 9. Residual demand

Problem Households: Change of 1000 over the next 5 years (Currently 10,000) Average household income: $35,000 % spent taxes 25% % spent on nonretail 45% (housing, medical, insurance & professional, services, recreation, savings) % of retail sales by subject type 20% % retention of sales in primary mkt 80% (Note: on the test this may be expressed as 20% leakage) % supportable in secondary mkt 15% (of primary) Sales required psf subject type $250 Frictional vacancy 5% Existing retail space 250,000 sf (20% in subject type) Under construction 50,000 sf (25% in subject type) Permitted 40,000 sf (15% in subject type)

Solution 1. Total income = 11,000 x $35,000 = $385,000,000 2. Retail sales potential = $385,000,000 x (1 - 25% - 45%) = $115,500,000 3. Retail sales by subject type = $115,500,000 x 20% = $23,100,000 4. Sales retention = $23,100,000 x 80% = $18,480,000 5. Primary sales sf required = $18,480,000 / $250 psf = 73,920 sf 6. Plus: Secondary sales = 73,920 x 1.15 = 85,008 sf 7. Plus: Frictional vacancy = 85,008 / (1 - 5%) = 89,482 sf 8. Less: Existing, U.C., proposed = 250,000x20% + 50,000x25% + 40,000x15% = 68,500 sf 9. Shortage of space (next 5 years) = 89,482 sf - 68,500 = 20,982 sf

OFFICE & INDUSTRIAL Keys: 1. Employment 2. % of employment in office 3. Average sf per employee 4. Capture by subject area 5. Capture by subject property class (A, B, etc.) 6. Add existing, under construction (U.C.), proposed 7. Calculate residual demand

Cost

Copyright Ted Whitmer. All rights reserved.

46 Cost

132 Cost

Example

133

RETAIL Keys: 1. Households 2. Average household income 3. % income spent on retail 4. % spent in subject type 5. % retention 6. Sales required psf 7. Less existing supply 8. Less forecast supply 9. Residual demand

Problem Households: Change of 1000 over the next 5 years (Currently 10,000) Average household income: $35,000 % spent taxes 25% % spent on nonretail 45% (housing, medical, insurance & professional, services, recreation, savings) % of retail sales by subject type 20% % retention of sales in primary mkt 80% (Note: on the test this may be expressed as 20% leakage) % supportable in secondary mkt 15% (of primary) Sales required psf subject type $250 Frictional vacancy 5% Existing retail space 250,000 sf (20% in subject type) Under construction 50,000 sf (25% in subject type) Permitted 40,000 sf (15% in subject type)

Solution 1. Total income = 11,000 x $35,000 = $385,000,000 2. Retail sales potential = $385,000,000 x (1 - 25% - 45%) = $115,500,000 3. Retail sales by subject type = $115,500,000 x 20% = $23,100,000 4. Sales retention = $23,100,000 x 80% = $18,480,000 5. Primary sales sf required = $18,480,000 / $250 psf = 73,920 sf 6. Plus: Secondary sales = 73,920 x 1.15 = 85,008 sf 7. Plus: Frictional vacancy = 85,008 / (1 - 5%) = 89,482 sf 8. Less: Existing, U.C., proposed = 250,000x20% + 50,000x25% + 40,000x15% = 68,500 sf 9. Shortage of space (next 5 years) = 89,482 sf - 68,500 = 20,982 sf

OFFICE & INDUSTRIAL Keys: 1. Employment 2. % of employment in office 3. Average sf per employee 4. Capture by subject area 5. Capture by subject property class (A, B, etc.) 6. Add existing, under construction (U.C.), proposed 7. Calculate residual demand

Cost

Copyright Ted Whitmer. All rights reserved.

46 Cost

Cost

Market analysis – office buildings

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Office & Industrial

135

!  1. Employment !  Basic !  Service

!  2. % employment in office translated to # in office !  3. Office space per employee !  4. Employees in office x office space per employee =

Space needed for growth !  5. Line 4/(1- frictional vacancy) = Total space

needed !  6. Residual demand is after accounting for supply

Cost

136

Problem: Employment Currently 50,000 Population Expected growth in population over next 4 years is 20,000 persons PE ratio 1.75 to 1 Percent of employees in office 20% Total office in city 1,000,000 sf Total Class B in city 550,000 sf Total office in submarket 100,000 Occupancy 75% in submarket Total Class B in submarket 50,000 sf Occupancy in Class B 80% Frictional vacancy 5% Average space per employee 225 sf Est. capture by subject area 25% Est. % class demand 50% Office U.C., proposed Class B 25,000 sf

Solution: 1. Total employment growth = 20,000 / 1.75 = 11,429 2. Total occupying office = 11,429 x 20% = 2,286 persons 3. Office demand = 2,286 persons x 225 sf per person = 514,350 sf 4. Capture in subject market = 514,350 x 25% = 128,588 sf 5. Total demand for Class B in market = 128,588 sf x 50% / (1-5%) = 67,678 sf 6. Less: Existing, UC, proposed = (50,000 sf x 20% vacant) + 25,000 sf = 35,000 sf 7. Residual demand = 67,678 - 35,000 = 32,678 sf needed Variations: 1. There may not be a frictional vacancy given. Compute demand without making up a vacancy.

Cost

Copyright Ted Whitmer. All rights reserved.

47 Cost

Cost

137

Problem: Employment Currently 50,000 Population Expected growth in population over next 4 years is 20,000 persons PE ratio 1.75 to 1 Percent of employees in office 20% Total office in city 1,000,000 sf Total Class B in city 550,000 sf Total office in submarket 100,000 Occupancy 75% in submarket Total Class B in submarket 50,000 sf Occupancy in Class B 80% Frictional vacancy 5% Average space per employee 225 sf Est. capture by subject area 25% Est. % class demand 50% Office U.C., proposed Class B 25,000 sf

Solution: 1. Total employment growth = 20,000 / 1.75 = 11,429 2. Total occupying office = 11,429 x 20% = 2,286 persons 3. Office demand = 2,286 persons x 225 sf per person = 514,350 sf 4. Capture in subject market = 514,350 x 25% = 128,588 sf 5. Total demand for Class B in market = 128,588 sf x 50% / (1-5%) = 67,678 sf 6. Less: Existing, UC, proposed = (50,000 sf x 20% vacant) + 25,000 sf = 35,000 sf 7. Residual demand = 67,678 - 35,000 = 32,678 sf needed Variations: 1. There may not be a frictional vacancy given. Compute demand without making up a vacancy.

Cost

Copyright Ted Whitmer. All rights reserved.

47 Cost

Cost

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HIGHEST & BEST USE DECISIONS

138 Cost

How much building can you get on the site problem… !  Lot 500’ (frontage) x 400’ (depth) !  Building: 2-story !  Parking: Five spaces per 1,000 SF of rentable & need 350 SF per

space. Rentable to gross is 90%. !  Setbacks– Cannot build on the setbacks parking or building.

!  40’ front !  20’ back !  10’ one side & 15’ the other side

!  Green areas – In addition to setback areas !  10% of building size !  15% of total site size

!  Retention (detention) area – 10% of site area (total)

139 Cost

Solution !  (475x340) – [(15% green +

10% retention) x 500x400] = 1/2x + (x.90/1000 x 5 x 350) + .10x

!  161,500 – 50,000 = .5x + 1.575x + .10x

!  111,500 = 2.175x

!  X = 111,500/2.175 = 51,264 SF

!  Parking: 51,264 x .90/1000 x 5 = 231spaces

140

500’

400’

40’

20’

15’ 10’

475’

340’

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Highest & Best Use

! Tests – Measured in dollars not rate of return !  Physical !  Legal !  Financially feasible !  Maximally productive

141 Cost

Highest & Best Use

! Can have negative values ! Must report your analysis of HBU,

not just summarize your HBU ! Value in use must be consistent.

You don�t predetermine the use, then value the site under HBU (churches may be an exception)

142 Cost

Highest & Best Use

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HIGHEST & BEST USE APPLICATIONS

144 Cost

Highest & Best Use Tests

! Demolish or not to demolish !  Steps

!  Value of land if vacant !  Value of property if continue use & do not

demolish !  Subtract: If the cost to demolish is greater, then

do not demolish. If the cost to demolish is less, then demolish.

145 Cost

Highest & Best Use Tests

! Renovate or not renovate !  Steps

!  Value the property as though renovated !  Value of property if continue use & do not

renovate !  Subtract: If the cost to renovate is greater, then do

not renovate. If the cost to renovate is less, then renovate.

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Feasibility

147 Cost

Breakeven point

!  Point at which EGI = debt service + expenses !  To derive occupancy:

!  BE occupancy = (OE + DS)/annual rent per unit !  �Unit� can be an apartment unit, SF, cubic ft,

etc.

148 Cost

Breakeven ratio

!  It is used to determine the margin of safety that exists until CF = 0 !  DCR = 1 !  Re = 0

!  BER = (OE + DS) / PGI !  It results in a % occupancy to break even

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Feasible Rent Calculation

!  Cost x Ro = Io needed !  Io + Expenses = EGI needed !  EGI divided by (1 – vacancy) = PGI needed

150 Cost

Feasibility

151 Cost

Feasibility

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Feasibility

153 Cost

When Market Rent Exceeds Feasible Rent (Good Market Conditions for Building)

!  If the rental rates in the market exceed the feasible rental rate, then one, two, three or all of the following will happen… !  land values will increase at a very rapid rate (land

owners will take their cut of the market) !  improvement costs will increase (subs will take their

cut) !  there will be continued construction (developers will be

smiling) !  rates could increase and this would cause costs to

increase, slowing building (the Federal Reserve gets involved)

154 Cost

RECONCILIATION

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PROBLEMS

156 Cost

Physical Depreciation

157

!  RCN = $2,000,000 !  Needs painted $25,000

!  Age is 5 & remaining life is 45 years !  What is total physical depreciation?

Item Cost Age Life % Total Carpet 75,000 5 7 HVAC 100,000 5 12

Roof 200,000 5 15

Other 250,000 5 8

Total

Cost

Physical Depreciation

158

!  RCN = $2,000,000 !  Needs painted $25,000

!  Incurable LL: (2,000,000 – 25,000 – 625,000) (5/50) = $135,000

!  Age is 5 & remaining life is 45 years !  What is total physical depreciation? !  $25,000 + 318,155 + 135,000 = $478,155

Item Cost Age Life % Total Carpet 75,000 5 7 71.43 $53,571 HVAC 100,000 5 12 41.67 41,667 Roof 200,000 5 15 33.33 66,667 Other 250,000 5 8 62.50 156,250 Total 625,000 318,155

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Reilly’s Gravitational Model

!  There is a 13 minute travel time between two stores with Store A having 300,000 SF and store B having 250,000 SF. What is the market area boundary?

159 Cost

Reilly’s Gravitational Model !  There is a 13 minute travel time between two stores with Store A having

300,000 SF and store B having 250,000 SF. What is the market area boundary? !  MAB = T / (1 + √Sa / Sb)

!  MAB = Market area boundary !  T = Travel time !  Sa = Size of store a !  Sb = Size of store b

!  MAB = 13/ (1 + √300/250) = 13/ (1 + 1.09545) = 6.204 minutes from store B.

160 Cost

Problems 1. A parking lot will be built with concrete that will cost $1.50 PSF for labor, $75 per cubic yard for concrete, and $1.00 PSF for forms and rebar. Assume the parking lot is 200 feet by 150 feet and will be poured 5.5 inches thick. What is the cost of the parking lot per square foot? a. $2.50 PSF b. $3.25 PSF c. $3.75 PSF d. $4.00 PSF 2. A market has 100,000 SF of office available for lease, 150,000 SF being added, 20,000 scheduled to be demolished and total office space is 1,000,000. Assume stabilized vacancy at 5%, what is residual demand in this market? a. 0 SF b. 56,500 SF c. 180,000 SF d. Cannot determine from the information given

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Problems 3. NOI = $0. Taxes are $2,000, insurance is $1,000 and maintenance is $2,000 per year. The taxes are broken into $1,500 for the land and $500 per year for the building. Ro = .12. Assume the land is worth $125,000, but is not developable until a road is completed in the area in two years and a change of zoning form R-1 to C-2 is achieved. The change in zoning is likely prior to the road being completed. Demolition of the building will cost $15,000. What is the value of the improvements? a. $0 b. -$12,000 c. -$15,000 d. -$30,000 4. In the above example, what is the highest and best use of the property? a. Commercial b. Residential c. To hold for future commercial development d. Research and development

162 Cost

Problems 5. What has the most affect on apartment leasing? a. Household size b. Population change c. Employment change d. Students 6. There is an announcement that a company will employ 150 employees and sell computer keyboards to a distributor located in another state. The company will build a building of 50,000 SF of office, manufacturing and storage area. The expectations are that 400 more jobs will result because this company. Assume that the growth will result in a need for more office with a market that has 5,000 SF in excess of what is needed for typical frictional vacancy. Average employment in office is 180 SF per employee and 18% of the growth is expected to be in employment that needs office. What is the residual office demand after the company locates in the market? a. 7,960 SF b. 12,960 SF c. 15,820 SF d. 17,820 SF

163 Cost

Problems 7. What is the likely growth in population from the company locating in this market? a. 550 persons b. 1,100 persons c. 2,200 persons d. 3,300 persons 8. What is the classification of the 150, 400 and 550 employees in problem 6? a. Basic, ancillary, total b. Basic, service, total c. Service, basic, total d. Service, additional, speculative 9. A property has above market leases. How would you adjust for this feature in the cost approach? a. You would not, the cost approach values fee simple interests b. You would add the present value of the excess rent as a bottom-line item c. You would subtract the present value of the excess rent as a bottom-line item d. You would add the difference between the leasehold and leased fee values as a bottom-line item

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Problems Answer questions 10 – 13 based upon the following information. Office building 1: Built within the last two years for $1,000,000 total construction costs and with a land value of $275,000. The building is 13,000 SF and the land is 52,000 SF. Office building 2: Built within the last year for $1,200,000 total construction costs and with a land value of $380,000. The building is 15,100 SF and the land area is 75,000 SF. Office building 3: Built within the last three years for $1,400,000 total construction costs and with a land value of $380,000. The building is 19,000 SF and the land area is 78,000 SF. Office building 4:Built within the last year for $1,150,000 total construction costs and with a land value of $375,000. The building is 15,000 SF and the land area is 63,000 SF. Assume all sites have a highest and best use with office development.

10. Which of the above is likely to have an irregular site? a. Office building 1 b. Office building 2 c. Office building 3 d. Office building 4

165 Cost

Problems 11. Which building is likely to have the highest rent PSF? a. Office building 1 b. Office building 2 c. Office building 3 d. Office building 4 12. If all leased for the same rental PSF, which building likely has functional obsolescence? a. Office building 1 b. Office building 2 c. Office building 3 d. Office building 4 13. What is the increase in land value in the above office sites? a. 4% per year b. 7% per year c. 9% per year d. 11% per year 166 Cost

Problems

14. A building has a component that cost $125,000 if in new construction and is 10% depreciated. A high quality component would cost $150,000 in new construction and $275,000 to add. There is no salvage value to the existing component. The expenses increase $11,000 per year because of the inferior component and the rate to the building is .11. What is the amount of functional obsolescence? a. $0 b. $50,000 c. $62,500 d. $175,000 15. Which of the following is true? a. The cost approach sets the upper limit of value. b. The cost approach is used for fee simple valuations only. c. The cost approach is the best approach for special purpose properties. d. The cost approach is best used with very old properties.

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Problems 16. A retail property leases in a strip center for $25 PSF and percentage rents of

6% with a natural break. Vacancy in the retail center is overall at 5%. What would the rent be PSF if sales were $400 PSF per year? a. $24 PSF b. $25 PSF c. $25 + $24 PSF d. $25 / (1 - .05) PSF 17. Of the following, which is likely to have the highest sales PSF? a. Restaurants b. Jewelry c. Footwear d. Apparel 18. Which of the following is likely to have the highest turn ratio? a. Grocery b. Jewelry c. Footwear d. Gifts

168 Cost

Problems

19. If the footprint coverage on the site is 1 to 4 and a 3-story building has a footprint of 15,000 SF, what is the FAR? a. 45,000/60,000 b. 60,000/45,000 c. 15,000/60,000 d. 60,000/15,000

20. A property has land worth $500,000. The improvements will be demolished in one year for $25,000. The improvements are being used for storage and generate enough income to off-set expenses. The NOI is zero. Assume the property would be developed today except the lease for the storage encumbers the property. What is the value of the property including the improvements. a. $450,000 b. $475,000 c. $500,000 d. $525,000 169 Cost

Problem Solutions

1. A parking lot will be built with concrete that will cost $1.50 PSF for labor, $75 per cubic yard for concrete, and $1.00 PSF for forms and rebar. Assume the parking lot is 200 feet by 150 feet and will be poured 5.5 inches thick. What is the cost of the parking lot per square foot? a. $2.50 PSF b. $3.25 PSF c. $3.75 PSF d. $4.00 PSF (1.50 + 1.00) x 200 x 150 = $75,000.00 75 x 200/3 x 150/3 x 5.5/36 = 38,194.44 Total Cost $113,194.44 Cost PSF: $113,194.44/(200 x 150) $3.77

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Problem Solutions

2. A market has 100,000 SF of office available for lease, 150,000 SF being added, 20,000 scheduled to be demolished and total office space is 1,000,000. Assume stabilized vacancy at 5%, what is residual demand in this market? a. 0 SF b. 56,500 SF c. 180,000 SF d. Cannot determine from the information given

Frictional vacancy needed: (1,000,000 + 150,000 – 20,000) x 5% = 56,500 SF Vacancy in market = 100,000, therefore there is no residual demand, but excess space of 43,500 SF. 171 Cost

Problem Solutions 3. NOI = $0. Taxes are $2,000, insurance is $1,000 and maintenance is $2,000 per

year. The taxes are broken into $1,500 for the land and $500 per year for the building. Ro = .12. Assume the land is worth $125,000, but is not developable until a road is completed in the area in two years and a change of zoning form R-1 to C-2 is achieved. The change in zoning is likely prior to the road being completed. Demolition of the building will cost $15,000. What is the value of the improvements? a. $0 b. -$12,000 c. -$15,000 d. -$30,000 When NOI is $0 and there is an interim use, the improvements are at least offsetting taxes, some insurance and some property upkeep (mowing, etc.). Therefore, the improvements would not be demolished until the new improvements can be built. The improvements contribute $1,500 x 2 years, but cost $15,000 to remove. Therefore, the improvements are worth at least a -$12,000. Note the property would be more valuable as totally vacant.

172 Cost

Problem Solutions 4. In the above example, what is the highest and best use of the property?

a. Commercial b. Residential c. To hold for future commercial development d. Research and development

The highest and best use is not necessarily what is currently zoned. Many appraisers use the zoning of a property as the highest & best use and ignore the possibility of change of zoning that would result in a higher value. The market can pay a premium for the possibility of a zoning change even if it is remote so long as the potential higher value is considerably greater than the value as currently zoned.

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Problem Solutions 5. What has the most affect on apartment leasing?

a. Household size b. Population change c. Employment change d. Students

The major components of housing demand study are population, household size and income levels. Population change is the best answer.

174 Cost

Problem Solutions 6. There is an announcement that a company will employ 150 employees and sell computer

keyboards to a distributor located in another state. The company will build a building of 50,000 SF of office, manufacturing and storage area. The expectations are that 400 additional jobs will result over the 150 employees because this company. Assume that the growth will result in a need for more office with a market that has 5,000 SF in excess of what is needed for typical frictional vacancy. Average employment in office is 180 SF per employee and 18% of the growth is expected to be in employment that needs office. What is the residual office demand after the company locates in the market? a. 7,960 SF b. 12,960 SF c. 15,820 SF d. 17,820 SF

Note that the basic employer of 150 employees will build their own building. The problem requires translating the 400 jobs into potential residual demand. The office need is (400 x 18% x 180)/(1 – frictional vacancy). Note that frictional vacancy is not given. Ignoring the frictional vacancy there will be a need for 12,960 SF. There is a need for 12,960 less the 5,000 in excess, or 7,960 plus what would be needed for the frictional vacancy. Answer (a) is the best answer.

175 Cost

Problem Solutions 7. What is the likely growth in population from the company locating in this market?

a. 550 persons b.1,100 persons c. 2,200 persons d. 3,300 persons Approximately 48% of Americans are employed. There are one working spouse families, children and retired that do not work. Therefore, the ratio is about 2:1 population to employment. 8. What is the classification of the 150, 400 and 550 employees in problem 6? a. Basic, ancillary, total b. Basic, service, total [All employment is basic + service] c. Service, basic, total d. Service, additional, speculative

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Problem Solutions 9. A property has above market leases. How would you adjust for this feature in the

cost approach? a. You would not, the cost approach values fee simple interests b. You would add the present value of the excess rent as a bottom-line item c. You would subtract the present value of the excess rent as a bottom-line item d. You would add the difference between the leasehold and leased fee values as a bottom-line item There are many bottom-line items that may be deducted or added for a cost approach to reflect the problem that is a appraised. If the problem is to appraise a business, the appraiser may add the value of personal property and business value to the cost approach. This is a possible USPAP problem. An appraiser cannot simply add the component parts of a value together. An appraiser may reflect a value that is not market value in fee simple by making adjustments to the cost approach. Theoretically, the cost approach without adjustment reflects a fee simple value. Any difference in fee simple would be a bottom-line addition or deduction.

177 Cost

Problem Solutions

10. Which of the above is likely to have an irregular site? a. Office building 1 b. Office building 2 c. Office building 3 d. Office building 4 The land-to-building ratio is highest with building 2. 11. Which building is likely to have the highest rent

PSF? a. Office building 1 b. Office building 2 c. Office building 3 d. Office building 4 The newest and highest cost PSF is building 2.

!  12. If all leased for the same rental PSF, which building

likely has functional obsolescence? a. Office building 1 b. Office building 2 c. Office building 3 d. Office building 4 If all had the same rental rate PSF, the highest cost

would most likely have the functional obsolescence.

13. What is the increase in land value in the above office

sites? a. 4% per year b. 7% per year c. 9% per year d.11% per year The oldest building site was $20 PSF of building area,

then the next $21.15 and the newer buildings site cost was about $25 PSF. The prices went up $5 over 2 years or 25%/2 = 12.5%. Therefore, (d) is the best answer.

178

Building LTB Ratio Cost PSF Land PSF (of Building)

Total Cost

1 (2 years) 4.00:1 $76.93 $21.15 $98.08 2 (1 year) 4.97:1 $79.47 $25.16 $104.63 3 (3 years) 4.11:1 $73.68 $20.00 $93.68 4 (1 year) 4.20:1 $76.67 $25.00 $101.67

Cost

Problem Solutions

14. A building has a component that cost $125,000 if in new construction and is 10% depreciated. The correct component would cost $150,000 in new construction and $275,000 to add. There is no salvage value to the existing component. Because of the existing component, the expenses increase $11,000 per year and the rate to the building is .11. What is the amount of functional obsolescence? a. $0 b. $50,000 c. $62,500 d. $175,000 3B. $11,000/.11 = $100,000 15. Which of the following is true? a. The cost approach sets the upper limit of value. b. The cost approach is used for fee simple valuations only. c. The cost approach is the best approach for special purpose properties. d. The cost approach is best used with very old properties. This represents the best answer. Answer (d) could also be correct because a property with a large land value to total value ratio would result in a cost approach that is useful.

179

1 $125,000

2 (-) ($12,500)

3A (+) $275,000

3B (+) $100,000

4 (-) ($150,000)

TOTAL $62,500

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Problem Solutions 16. A retail property leases in a strip center for $25 PSF and percentage rents of 6% with a

natural break. Vacancy in the retail center is overall at 5%. What would the rent be PSF if sales were $400 PSF per year? a. $24 PSF b. $25 PSF c. $25 + $24 PSF d. $25 / (1 - .05) PSF

Natural break: $25/.06 = $416.67 PSF of sales. At $400, the tenant would pay the base rate. 17. Of the following, which is likely to have the highest sales PSF? a. Restaurants b. Jewelry c. Footwear d. Apparel 18. Which of the following is likely to have the highest turn ratio? a. Grocery b. Jewelry c. Footwear d. Gifts

180

It would either be jewelry or food. Regional malls report jewelry as the highest sales PSF.

Grocery has the highest turn because of perishable items and because the average good is the least.

Cost

Problem Solutions

19. If the footprint coverage on the site is 1 to 4 and a 3-story building has a footprint of 15,000 SF, what is the FAR? a. 45,000/60,000 b. 60,000/45,000 c. 15,000/60,000 d. 60,000/15.000 If is (3 x 15,000)/(4 x 15,000), or 45,000/60,000 Note: The footprint ratio has to have the building being the smaller of the two numbers in the ratio. There is 4 parts land for 1 part building footprint.

20. A property has land worth $500,000. The improvements will be demolished in one year for $25,000. The improvements are being used for storage and generate enough income to off-set expenses. The NOI is zero. Assume the property would be developed today except the lease for the storage encumbers the property. What is the value of the property including the improvements. a. $450,000 b. $475,000 c. $500,000 d. $525,000 $500,000 – 25,000 + offset for carrying some land costs – delay for development because of the encumbrance of the lease. Therefore, either $450,000 or $475,000. Because of risk and delay, (a) is the best answer.

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Depreciation Problems

182

Reproduction Cost $1,000,000 Physical Curable: Paint $10,000 & Appliance replacements = $20,000 Short-lived items Total cost = $100,000 Depreciation = $45,000 Actual age =10 years & remaining physical life = 40 years Obsolescence concerns: (Assume all items below are in physical incurable long-lived) 1. Curable, requiring an addition. Example - Needs a sprinkler system (new fire code), cost to add =$45,000. Cost in new construction if the building was being built new = $25,000. 2. Curable, requiring substitution. Example - A playground area needs to be replaced with a volleyball court area. (Change of tenant mix). The playground cost $10,000. It will cost $2,000 to take away, there is $500 in salvage value for the equipment, and the volleyball court area will cost $1,000 to build. Net rents will increase enough to justify. 3. Curable, super adequacy. Example - A swimming pool cost $30,000 in new construction, would cost $4,000 to fill and landscape over it, adds $500 to expenses each year (Ro = 11%), and adds nothing to rents or occupancy. There is $250 in salvage value to the pool equipment.

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4. No functional, but there is a rent loss - Net income could be increased $4,000 if a recreation building were built for a cost of $50,000, including exercise equipment. The building would have cost $48,000 if built during original construction, as of the date of the appraisal. (This is the example of no functional obsolescence, see calculations following). 5. Incurable, deficiency (item not in the building) - The apartment could use an elevator for the second floor. Rents are affected, net $5,000 per year. The elevator would have cost $30,000 if the property was being built, but would cost $70,000 to add to the existing structure. 6. Incurable, deficiency (item in the building) - The club room has inadequate air-conditioning and therefore does not rent for parties as much as other rec rooms in the area. The lost income is $600 per year, the existing A/C unit cost $3,000 in new construction and would currently cost $10,000 to replace and redo the duct system. The proper A/C unit in new construction would have cost $5,000. 7. Incurable, superadequacy - The apartments have covered parking that cost $34,000 in new construction. The income is affected, net $2,000 per year (positively). The cost to tear down the covered parking would be $10,000.

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8. Incurable, superadequacy - The apartments also have hallways that are too large, compared to market standards and cost $5,000 more in new construction than smaller hallways. In addition, the extra utility bills and maintenance contribute $1,100 in expenses per year over and above what smaller hallways would cost. 9. External - The market is soft and net income is depressed $20,000. The market is expected to recover fully in 5 years. The Ro = 10% and Y = 14%. Assume a land-to-value ratio of 20% and that the land value is depressed $40,000 because of the poor market. 10. External - The apartments are next to an industrial plant and the net rents are affected $3,500 per year. The land is losing $35,000 in value because of its proximity to the plant.

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185

Physical curable = $30,000 Physical incurable short-lived = $45,000 Physical incurable long-lived ($1,000,000 - 30,000 - 100,000) x 10/50 = $174,000

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1. Functional curable, requiring an addition Line Description Notes $

1 Cost of existing item

There is no sprinkler in the cost approach, so there is no cost in line 1

$0

2 (-) Less: Physical Depreciation

When line 1 is $0, then line 2 will be zero.

$0

3A (+) or

Cost to Cure This is the cost of adding a sprinkler system to an existing building.

$45,000

3B (+) Cost if Incurable There is no information given but the system will be installed.

No info

4 (-) Value of “correct” item

This is the cost to install the sprinkler in a new building being built as of the date of the appraisal.

- $25,000

Depreciation This turns out to be the excess cost to add a sprinkler system in an existing building versus building it into a new building.

$20,000

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2. Functional curable, requiring an substitution - Playground Line Description Notes $

1 Cost of existing item

Cost of playground, but there is a change of tenant mix.

$10,000

2 (-) Less: Physical Depreciation

$10,000 x 10/50 - $2,000

3A (+) or

Cost to Cure $2,000 to remove the playground - $500 salvage costs + $1,000 to add a volleyball court

$2,500

3B (+) Cost if Incurable No info

4 (-) Value of “correct” item

The cost (value?) of a volleyball court if being built in new construction. It probably would not be much different than the $1,000 given. If it was, I would use less than the $1,000.

- $1,000

Depreciation $9,500 Cost

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3. Curable, superadequacy - Pool Line Description Notes $

1 Cost of existing item

$30,000

2 (-) Less: Physical Depreciation

$30,000 x 10/50 - $6,000

3A (+) or

Cost to Cure $4,000 to fill - $250 salvage for equipment

$3,750

3B (+) Cost if Incurable $500/.11 = $4,545 PV of expenses if not filled in

$4,545

4 (-) Value of “correct” item

- $0

Depreciation $27,750

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4. No obsolescence. Recreational Building? (This problem exists when an item that is being considered is not in the building and the added value is less than the cost.) Line Description Notes $

1 Cost of existing item

No item in cost. There is no recreational building

$0

2 (-) Less: Physical Depreciation

-$0

3A (+) or

Cost to Cure The cost to build a recreational building

$50,000

3B (+) Cost if Incurable This is the lost income if no building is built ($4,000/.11 = $36,364)

$36,364

4 (-) Value of “correct” item

This is the cost of a recreational building if being built in new construction

- $48,000

Depreciation It is easy to see that the rec building would be a poor decision if built even in new construction. The value is less than the cost.

Negative

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5. Functional Incurable Deficiency, not in building. Elevator Line Description Notes $

1 Cost of existing item

There is no elevator and thus no cost in RCN

$0

2 (-) Less: Physical Depreciation

-$0

3A (+) or

Cost to Cure $70,000

3B (+) Cost if Incurable $5,000/.11 = $45,455 $45,455

4 (-) Value of “correct” item

This is the cost of putting in an elevator while a building is being built.

- $30,000

Depreciation This is what the rest of the building is losing because there is no elevator to serve it.

$15,455

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6. Functional Incurable Deficiency, in building. HVAC Line Description Notes $

1 Cost of existing item

$3,000

2 (-) Less: Physical Depreciation

$3,000 x 10/50 = $600 -$600

3A (+) or

Cost to Cure This is the cost to put in the proper unit in an existing building.

$10,000

3B (+) Cost if Incurable $600/.11 = $5,455 $5,455

4 (-) Value of “correct” item

This is the value of the correct item. Sometimes, costs are cut during construction & the rest of the building loses without the proper component.

- $5,000

Depreciation $2,855

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7. Functional Incurable Superadequacy. Covered Parking.

Line Description Notes $ 1 Cost of existing

item $34,000

2 (-) Less: Physical Depreciation

$34,000 x 10/50 = $6,800 -$6,800

3A (+) or

Cost to Cure This is the cost to remove the covered parking. One would not remove items that contribute to value.

$10,000

3B (+) Cost if Incurable $2,000/.11 = $18,182. This is not a loss but a gain. Note, however the value is less than the cost. Also notice this is a negative depreciation (a negative negative is a positive.

-$18,182

4 (-) Value of “correct” item

The $18,182 could go in line 4 as opposed to line 3B. The math would be the same.

Depreciation $9,018 Cost

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8. Functional Incurable Superadequacy. Large Hallways.

Line Description Notes $ 1 Cost of existing

item Note that here we are using the excess cost of the item, not the total hallway cost.

$5,000

2 (-) Less: Physical Depreciation

$5,000 x 10/50 = $1,000 -$1,000

3A (+) or

Cost to Cure No information, but it seems likely one would not narrow hallways.

3B (+) Cost if Incurable $1,100/.11 = $10,000 $10,000

4 (-) Value of “correct” item Depreciation $14,000

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9. External Obsolescence. Soft Market. The rent loss in one year is $20,000. Even if the loss stays at $20,000 for 5 years, the most the loss would be is 5 x $20,000 = $100,000 to the total property, including the land. The loss to land is $40,000, so the most the loss could be is $100,000 - $40,000 = $60,000 to the improvements. If the loss declines as the market recovers the loss will be less than $60,000. If the loss is as follows: $20,000; $17,500; $15,000; $10,000; $5,000 the PV is approximately $60,000, and $60,000 - $40,000 is $20,000. Therefore, there is not much loss to the improvements. Moral of the Story: Don’t capitalize a short-term loss or gain (e.g. tax abatement) with a Ro.

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10. External Obsolescence. Environmental Problem? The rent loss, total, is $3,500/.10 = $35,000. The loss to the land is $35,000. Therefore, the loss to the building is $35,000 – 35,000 = $0. This is common. Sites have different values in the same Highest & Best Use categories because the higher valued sites produce higher rents and the lower valued sites produce lower rents.

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Problem – Also, which would cost the least to build?

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25. Which neighborhood is primarily industrial? a. 1 b. 2 c. 3 d. 4 26. Which neighborhood has a regional shopping center? a. 1 b. 2 c. 3 d. 4 27. Which neighborhood is a downtown CBD? a. 1 b. 2 c. 3

d. 4 Answer 28 & 29 based upon the following: Assume the following have the same area in square feet. A B C D 28. Which of the following would have the least perimeter? a. A b. B c. C

d. D 29. Which of the following would have the most perimeter? a. A b. B c. C

d. D 30. A property that is 50 years old has a remaining economic life of 5 years. There is sufficient data to establish

a reliable land value. Which of the following statements is most true? a. A cost approach is not reliable because of significant depreciation. b. A cost approach would be reliable because of the well established land value. c. An income approach would appear to be most useful. d. Only the sales comparison approach is applicable to this appraisal. 31. Land that is not salable but is in excess of what is needed for a particular building size is which of the

following? a. excess b. surplus c. outside storage d. industrial

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Copyright Ted Whitmer. All rights reserved.

112 Cost

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Problem – Also, which would cost the least to build?

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25. Which neighborhood is primarily industrial? a. 1 b. 2 c. 3 d. 4 26. Which neighborhood has a regional shopping center? a. 1 b. 2 c. 3 d. 4 27. Which neighborhood is a downtown CBD? a. 1 b. 2 c. 3

d. 4 Answer 28 & 29 based upon the following: Assume the following have the same area in square feet. A B C D 28. Which of the following would have the least perimeter? a. A b. B c. C

d. D 29. Which of the following would have the most perimeter? a. A b. B c. C

d. D 30. A property that is 50 years old has a remaining economic life of 5 years. There is sufficient data to establish

a reliable land value. Which of the following statements is most true? a. A cost approach is not reliable because of significant depreciation. b. A cost approach would be reliable because of the well established land value. c. An income approach would appear to be most useful. d. Only the sales comparison approach is applicable to this appraisal. 31. Land that is not salable but is in excess of what is needed for a particular building size is which of the

following? a. excess b. surplus c. outside storage d. industrial

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112 Cost

A has the least perimeter.

D would have the most perimeter.

A would probably cost the most to build and C the least. Note that houses are often built as rectangles. A square house would have greater load requirements in the roof.

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11. Refer to problem 10. What would the functional obsolescence be if the cost to cure was $90,000 instead of the $150,000?

a. $115,385 b. $145,000 c. $170,385

d. $295,385 e.

Answer 12 - 14 based on the following graph: The subject is a 10 year old office building with functional obsolescence in a soft market. LINE C REPRESENTS THE RELATIONSHIP OF % OF VALUE AND AGE CONSIDERING A SOFT MARKET.

EITHER LINE A OR B REPRESENTS JUST PHYSICAL DEPRECIATION, AND EITHER LINE A OR B REPRESENTS FUNCTIONAL OBSOLESCENCE IN A BUILDING.

Value 100%

90% A

80%

70% B

60%

50% C

40%

30%

20%

10%

0% 0 5 10 15 20 25 30 35 40 45 Age 12. What does line A represent? a. Depreciation from cost new (time 0) to the end of the life of the building b. Physical depreciation from cost new (time 0) to the end of the life of the building c. Functional obsolescence from cost new (time 0) to the end of the life of the building d. External obsolescence from cost new (time 0) to the end of the life of the building 13. What does line B represent? a. Depreciation from cost new (time 0) to the end of the life of the building b. Physical depreciation from cost new (time 0) to the end of the life of the building c. Functional obsolescence from cost new (time 0) to the end of the life of the building d. External obsolescence from cost new (time 0) to the end of the life of the building

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Copyright Ted Whitmer. All rights reserved.

109 Cost

198

What percentage functional, physical & external obsolescence does a 20 year old building have?

Cost

11. Refer to problem 10. What would the functional obsolescence be if the cost to cure was $90,000 instead of the $150,000?

a. $115,385 b. $145,000 c. $170,385

d. $295,385 e.

Answer 12 - 14 based on the following graph: The subject is a 10 year old office building with functional obsolescence in a soft market. LINE C REPRESENTS THE RELATIONSHIP OF % OF VALUE AND AGE CONSIDERING A SOFT MARKET.

EITHER LINE A OR B REPRESENTS JUST PHYSICAL DEPRECIATION, AND EITHER LINE A OR B REPRESENTS FUNCTIONAL OBSOLESCENCE IN A BUILDING.

Value 100%

90% A

80%

70% B

60%

50% C

40%

30%

20%

10%

0% 0 5 10 15 20 25 30 35 40 45 Age 12. What does line A represent? a. Depreciation from cost new (time 0) to the end of the life of the building b. Physical depreciation from cost new (time 0) to the end of the life of the building c. Functional obsolescence from cost new (time 0) to the end of the life of the building d. External obsolescence from cost new (time 0) to the end of the life of the building 13. What does line B represent? a. Depreciation from cost new (time 0) to the end of the life of the building b. Physical depreciation from cost new (time 0) to the end of the life of the building c. Functional obsolescence from cost new (time 0) to the end of the life of the building d. External obsolescence from cost new (time 0) to the end of the life of the building

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Copyright Ted Whitmer. All rights reserved.

109 Cost

199

What percentage functional, physical & external obsolescence does a 20 year old building have?

Physical = 50% Physical & functional = 60%, therefore functional is 10% of cost new. All depreciation is about 75%. (The good is 25%) External as a % is after physical & functional. The loss is 15%/40% = 37.5% of physically & functionally depreciated cost.

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END OF THE COST APPROACH

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