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Circuit de priza trifazat
I= P
√3∗U l∗cosφ∗η= 6000
√3∗400∗0.8∗0.8=13.5 A
1. Calea de curent: conductor de cupru cu izolatie PVC „FY”:
Alegere: {In≤ Ima(¿18 A)nca=4
smin=2.5mm2
|¿>solutie5 FY 2.5
2. Tub de protectie PEL
Alegere: {smin=2.5mm2
n=5|¿>solutie PEL17.9
3. Elemente de protectie disjunctor
Alegere: {ID≤ Ima(18 A)ID≥ I n(13.5)
|¿>solutie ID=16 A 4 P /16 A
Circuit de priza joasa tensiune
I 230=SU f
=400230
=1.7 A
1. Comutator bipolar I c≥ I230→Solutie I c=6 A
2. Elemente de protectie disjunctor
Alegere ID≥ I230|¿>solutie I D=2 A 2P /2 A
I 24=SU j
=40024
=16.7 A
3. Calea de curent: conductor de cupru cu izolatie PVC „FY”:
Alegere: {I24≤ Ima(¿24 A )nca=2
smin=2.5mm2
|¿>solutie2FY 2.5
4. Tub de protectie PEL
Alegere: {smin=2.5mm2
n=2|¿>solutie PEL12.7
5. Elemente de protectie disjunctor
Alegere: {ID≤ Ima(24 A)ID≥ I n(16.7)
|¿>solutie I D=20 A P+N /20 A
Circuit priza monofazata
I n=P
U f∗cosφ= 2000230∗0.8
=10.87 A
1. Calea de curent: conductor de cupru cu izolatie PVC „FY”:
Alegere: {In≤kIma(¿24∗0.8=19.2 A)nca=2
smin=2.5mm2
k=0.8
|¿>solutie3FY 2.5
2. Tub de protectie PEL
Alegere: {smin=2.5mm2
nca=3|¿>solutiePEL16.1
3. Elemente de protectie disjunctor
Alegere: {ID≤ Ima∗kID≥ I n
|¿> ID=16 A solutie2 P/16 A
Circuit motor 2.2kw
I n=P
√3∗U l∗cosφ∗η= 2200
√3∗400∗0.855∗0.79=4.7 A
1. Calea de curent: conductor de cupru cu izolatie PVC „FY”:
Alegere: {In≤ Ima(¿14 A)nca=3
smin=1.5mm2
|¿>solutie4 FY 1.5
Verificarea la densitatea de curent
J=IP
s=
k P∗I n
s=6.5∗4.7
1.5=20.4 A /mm2<34 A /mm2
2. Tub de protectie PEL
Alegere: {smin=1.5mm2
n=4|¿>solutie PEL12.7
3. Releu termic -TSA
Alegere:{ I n=4.7 AI r=In
0.6∗I s≤ I r≤ I s
I FRT=20 A
→ I s=6 A→solutie TSA10 /6 A
4. Contactor TCAAlegere: I c≥ I n (4.7 A )→solutieTCA 6
IFc=20 A
5. Siguranta fuzibila
Alegere :{IF> I n(5 A)
I F≥IP
k=
k P∗I n
2.5=6.5∗4.7
2.5=12.2 A
IF≤3∗Ima (42 A )I F≤ IF RT
(20 A )I F≤ IFC (20 A)
→solutie3LF 25/16 A
Circuit motor 3kw
I n=P
√3∗U l∗cosφ∗η= 3000
√3∗400∗0.86∗0.8=6.3 A
1. Calea de curent: conductor de cupru cu izolatie PVC „FY”:
Alegere: {In≤ Ima(¿14 A)nca=3
smin=1.5mm2
|¿>solutie4 FY 1.5
Verificarea la densitatea de curent
J=IP
s=
k P∗I n
s=6.5∗6.3
1.5=27.3 A /mm2<34 A /mm2
2. Tub de protectie PEL
Alegere: {smin=1.5mm2
n=4|¿>solutie PEL12.7
3. Releu termic -TSA
Alegere:{ I n=6.3 AI r=In
0.6∗I s≤ I r≤ I s
I FRT=35 A
→ I s=10 A→solutie TSA10/10 A
4. Contactor TCAAlegere: I c≥ I n (6.3 A ) →solutie TCA 10
IFc=35 A
5. Siguranta fuzibila
Alegere :{IF> I n(7.8 A)
I F≥IP
k=
k P∗I n
2.5=6.5∗6.3
2.5=16.38 A
IF≤3∗Ima (42 A )IF≤ IF RT
(35 A )IF ≤ IFC (35 A)
→solutie3 LF25 /25 A
Circuit motor 11kw
I n=P
√3∗U l∗cosφ∗η= 11000
√3∗400∗0.87∗0.86=21.2 A
1. Calea de curent: conductor de cupru cu izolatie PVC „FY”:
Alegere: {In≤ Ima(¿34 A)nca=3
smin=6mm2
|¿>solutie4 FY 6
Verificarea la densitatea de curent
J=IP
s=
k P∗I n
s=7∗21.2
6=24.7 A /mm2<34 A /mm2
2. Tub de protectie PEL
Alegere: {smin=6mm2
n=4|¿>solutiePEL20
3. Releu termic -TSA
Alegere:{ I n=21.2 AI r=In
0.6∗I s≤ I r≤ I s
I FRT=80 A
→ I s=10 A→solutie TSA32/25 A
4. Contactor TCAAlegere: I c≥ I n (21.7 A )→solutie TCA 32
IFc=100 A
5. Siguranta fuzibila
Alegere :{IF> I n(21.7)
I F≥IP
k=
k P∗I n
2.5=7∗21.2
2=74.2 A
IF≤3∗Ima (102 A )IF≤ IF RT
(80 A )IF≤ IFC (100 A)
→solutie3 LF100/80 A
CALCULUL COLOANELOR TABLOURILOR DE FORTA SECUNDARE
COLOANA TGF - TAM
Functioneaza simultan circuitele : m11, m12, m14, f17
m11(2.2kw){ ¿=4.7 Asinφ=0.515 m12(2.2kw){ ¿=4.7 A
sinφ=0.515 m14(11kw){ ¿=21.2 Asinφ=0.65 f17
{ ¿=1.7 Asinφ=0.6
Ia=ΣInk x cosφk=[2x(4.7x0.855)]+(21.2x0.87)+(1.7x0.8)=27.84A
Ir=ΣInk x sinφk=[2x(4.7x0.515)]+(21.2x0.65)+(1.7x0.6)=19.64A
In=√¿a2+¿ r2=√27.842+19.642=34.07A
1. Calea de curent: conductor de cupru cu izolatie PVC PY:
Alegere: {In≤ Ima(¿ 45 A )nca=4
smin=2.5mm2|¿>solutie5FY 10
s=10mm2
2. Tub de protectie din PEL
Alegere: {s❑=10mm2
nca=5|¿>PEL34.2
3. Intreruptor parghie tripolar IP III Ir>Ic =>IPIII 100/504. Disjunctor
Alegere: {ID≤ Ima(45 A)ID≥ Ic
|¿>solutie ID=80 A
COLOANA TGF - TAT
Functioneaza simultan circuitele : m21, m23, m24, f25
m21(2.2kw){ ¿=4.7 Asinφ=0.515 m23(3kw){ ¿=6.3 A
sinφ=0.651 m24(11kw){ ¿=21.2 Asinφ=0.65 f25
{ ¿=1.7 Asinφ=0.6
Ia=ΣInk x cosφk=(4.7x0.855)+(6.3x0.86)+(21.2x0.87)+(1.7x0.8)=29.24A
Ir=ΣInk x sinφk=(4.7x0.515)+(6.3x0.651)+(21.2x0.65)+(1.7x0.6)=21.32A
In=√¿a2+¿ r2=√29.242+21.322=36.18A
1. Calea de curent: conductor de cupru cu izolatie PVC PY:
Alegere: {In≤ Ima(¿ 45 A )nca=4
smin=2.5mm2|¿>solutie5FY 10
s=10mm2
2. Tub de protectie din PEL
Alegere: {s❑=10mm2
nca=5|¿>PEL34.2
3. Intreruptor parghie tripolar IP III Ir>Ic =>IPIII 100/504. Disjunctor
Alegere: {ID≤ Ima(45 A)ID≥ Ic
|¿>solutie ID=80 A
COLOANA TGF - TCV
Functioneaza simultan circuitele : m31, m33, f34, f35
m31(2.2kw){ ¿=4.7 Asinφ=0.515 m33(11kw){ ¿=21.2 A
sinφ=0.65 f34(24 v){ ¿=1.7 Asinφ=0.6 f35{¿=10.87 A
sinφ=0.6
Ia=ΣInk x cosφk=(4.7x0.855)+(21.2x0.87)+(1.7x0.8)+(10.87x0.8)=32.51A
Ir=ΣInk x sinφk=(4.7x0.515)+(21.2x0.65)+(1.7x0.6)+(10.87x0.6)=23.74A
In=√¿a2+¿ r2=√32.512+23.742=40.25A
1. Calea de curent: conductor de cupru cu izolatie PVC PY:
Alegere: {In≤ Ima(¿76 A)nca=4
smin=2.5mm2|¿>solutie3 FY 25+2FY 16
s=25mm2
2. Tub de protectie din PEL
Alegere: {s❑=25mm2
nca=5|¿>PEL 44
3. Intreruptor parghie tripolar IP III Ir>Ic =>IPIII 100/504. Disjunctor
Alegere: {ID≤ Ima(76 A)ID≥ I c
|¿>solutie I D=100 A
COLOANA TGF - TCT
Functioneaza simultan circuitele : m41, m43, f44, f45
m41(2.2kw){ ¿=4.7 Asinφ=0.515 m43(11kw){ ¿=21.2 A
sinφ=0.65 f44(24 v){ ¿=1.7 Asinφ=0.6 f45{¿=10.87 A
sinφ=0.6
Ia=ΣInk x cosφk=(4.7x0.855)+(21.2x0.87)+(1.7x0.8)+(10.87x0.8)=32.51A
Ir=ΣInk x sinφk=(4.7x0.515)+(21.2x0.65)+(1.7x0.6)+(10.87x0.6)=23.74A
In=√¿a2+¿ r2=√32.512+23.742=40.25A
1. Calea de curent: conductor de cupru cu izolatie PVC PY:
Alegere: {In≤ Ima(¿76 A)nca=4
smin=2.5mm2|¿>solutie3 FY 25+2FY 16
s=25mm2
2. Tub de protectie din PEL
Alegere: {s❑=25mm2
nca=5|¿>PEL 44
3. Intreruptor parghie tripolar IP III Ir>Ic =>IPIII 100/504. Disjunctor
Alegere: {ID≤ Ima(76 A)ID≥ I c
|¿>solutie I D=100 A
COLOANA TGF - TSH
Functioneaza simultan circuitele : m51, m52, m53, f58
m55(11kw ){ ¿=21.2 Asinφ=0.65 m52(2.2kw){ ¿=4.7 A
sinφ=0.515 m53(2.2kw){ ¿=4.7 Asinφ=0.515 f58
{ ¿=1.7 Asinφ=0.6
Ia=ΣInk x cosφk=[2x(4.7x0.855)]+(21.2x0.87)+(1.7x0.8)=27.84A
Ir=ΣInk x sinφk=[2x(4.7x0.515)]+(21.2x0.65)+(1.7x0.6)=19.64A
In=√¿a2+¿ r2=√27.842+19.642=34.07A
1. Calea de curent: conductor de cupru cu izolatie PVC PY:
Alegere: {In≤ Ima(¿ 45 A )nca=4
smin=2.5mm2|¿>solutie5FY 10
s=10mm2
2. Tub de protectie din PEL
Alegere: {s❑=10mm2
nca=5|¿>PEL34.2
3. Intreruptor parghie tripolar IP III Ir>Ic =>IPIII 100/504. Disjunctor
Alegere: {ID≤ Ima(45 A)ID≥ Ic
|¿>solutie ID=80 A
DIMENSIONARE COLOANA GENERALA LUMINA
TGL-PT
Ia=cs ΣInaj=0.7 x ((6x36.89)+15.06)=165.48 A
Ir=cs ΣInrj =0.7 x((6x21.87)+4.95)=95.39 A
Cs=0.5…0.8=>se allege cs=0.7
In=√¿a2+¿ r2=√165.482+95.392=191 A
1. Calea de curent: conductor de cupru :
Alegere: {In≤ Ima(¿230 A)nca=4
s=70mm2
¿
2.Intreruptor parghie tripolar IP III Ir>Ic =630/300 A
3.Disjunctor
Alegere: {ID≤ Ima(230 A)ID≥ I c
|¿>solutie ID=200 A
DIMENSIONARE COLOANA GENERALA FORTA
TF-PT
Ia=cs ΣInaj=0.7 x (27.84+29.24+32.51+32.51+27.84)=82 A
Ir=cs ΣInrj =0.7 x(19.64+21.32+23.74+23.74+19.64)=75.65 A
Cs=0.5…0.8=>se allege cs=0.7
In=√¿a2+¿ r2=√822+75.652=111.57 A
1. Calea de curent: conductor de cupru :
Alegere: {In≤ Ima(¿185 A)nca=4
s=50mm2
¿
2.Intreruptor parghie tripolar IP III Ir>Ic =350/175 A
3.Disjunctor
Alegere: {ID≤ Ima(185 A)I D≥ I c
|¿>solutie ID=160 A
CALCULUL PIERDERILOR DE TENSIUNE
LUMINA:
ΔU1%:=> 100
γ∗Uf 2*ΣPi∗ljsj =
2∗10054∗2302*¿=0.61
ΔU2%:=> 100
γ∗U 2*P∗ls =
100
54∗4002*21436∗27
25 =0.26
ΔU3%: 100γ∗U 2*Pi∗ls =
100
54∗4002*139004∗100
70 =2.29
ΔU= ΔU1+ ΔU2+ ΔU3=0.61+0.26+2.29=3.16% < 8%
FORTA:
ΔU1%:=> Rp= 100
γ∗U 2*P∗ls =
100
54∗4002*89448∗11.66
6 =2.011
P=√3∗U∗Ip∗cosφ=√3∗400∗148.4∗0.87=89448
=>Rn== 100
γ∗U 2*Pe∗l
s =100
54∗4002*12790.7∗11.66
10 =0.28
P=Piη
=110000.86
=12790.7
ΔU2%:=> Rp= 100
γ∗U 2*P∗ls =
100
54∗4002*89448∗25.08
6 =2.59
P=√3∗U∗Ip∗cosφ=√3∗400∗148.4∗0.87=89448
=>Rn= 100
γ∗U 2*Pe∗l
s =100
54∗4002*20535.8∗25.08
10 =0.596
P=√3∗U∗¿∗cosφ=√3∗400∗34.07∗0.87=20535.8
ΔU3%: 100γ∗U 2*Pi∗ls =
100
54∗4002*20535.8∗100
50 =0.48
ΔURP= ΔU1RP+ ΔU2
RP+ ΔU3=2.011+2.59+0.48=5.081% < 17%
ΔURN= ΔU1RN+ ΔU2
RN+ ΔU3=0.28+0.596+0.48=1.36% < 10%