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Circuit de priza trifazat I= P 3U l cosφη = 6000 34000.80.8 =13.5 A 1. Calea de curent: conductor de cupru cu izolatie PVC „FY”: Alegere: { I n ≤I ma ( ¿ 18 A ) n ca =4 s min =2.5 mm 2 | ¿ >solutie 5 FY 2.5 2. Tub de protectie PEL Alegere: { s min =2.5 mm 2 n=5 |¿ >solutie PEL 17.9 3. Elemente de protectie disjunctor Alegere: { I D ≤I ma ( 18 A ) I D ≥I n ( 13.5 ) | ¿ >solutie I D =16 A 4 P / 16 A Circuit de priza joasa tensiune I 230 = S U f = 400 230 =1.7 A 1. Comutator bipolar I c ≥I 230 → SolutieI c =6 A 2. Elemente de protectie disjunctor Alegere I D ≥I 230 | ¿ >solutie I D =2 A 2 P/ 2 A I 24 = S U j = 400 24 = 16.7 A 3. Calea de curent: conductor de cupru cu izolatie PVC „FY”:

Calculul Circuitelor de Forta

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Page 1: Calculul Circuitelor de Forta

Circuit de priza trifazat

I= P

√3∗U l∗cosφ∗η= 6000

√3∗400∗0.8∗0.8=13.5 A

1. Calea de curent: conductor de cupru cu izolatie PVC „FY”:

Alegere: {In≤ Ima(¿18 A)nca=4

smin=2.5mm2

|¿>solutie5 FY 2.5

2. Tub de protectie PEL

Alegere: {smin=2.5mm2

n=5|¿>solutie PEL17.9

3. Elemente de protectie disjunctor

Alegere: {ID≤ Ima(18 A)ID≥ I n(13.5)

|¿>solutie ID=16 A 4 P /16 A

Circuit de priza joasa tensiune

I 230=SU f

=400230

=1.7 A

1. Comutator bipolar I c≥ I230→Solutie I c=6 A

2. Elemente de protectie disjunctor

Alegere ID≥ I230|¿>solutie I D=2 A 2P /2 A

I 24=SU j

=40024

=16.7 A

3. Calea de curent: conductor de cupru cu izolatie PVC „FY”:

Alegere: {I24≤ Ima(¿24 A )nca=2

smin=2.5mm2

|¿>solutie2FY 2.5

Page 2: Calculul Circuitelor de Forta

4. Tub de protectie PEL

Alegere: {smin=2.5mm2

n=2|¿>solutie PEL12.7

5. Elemente de protectie disjunctor

Alegere: {ID≤ Ima(24 A)ID≥ I n(16.7)

|¿>solutie I D=20 A P+N /20 A

Circuit priza monofazata

I n=P

U f∗cosφ= 2000230∗0.8

=10.87 A

1. Calea de curent: conductor de cupru cu izolatie PVC „FY”:

Alegere: {In≤kIma(¿24∗0.8=19.2 A)nca=2

smin=2.5mm2

k=0.8

|¿>solutie3FY 2.5

2. Tub de protectie PEL

Alegere: {smin=2.5mm2

nca=3|¿>solutiePEL16.1

3. Elemente de protectie disjunctor

Alegere: {ID≤ Ima∗kID≥ I n

|¿> ID=16 A solutie2 P/16 A

Circuit motor 2.2kw

I n=P

√3∗U l∗cosφ∗η= 2200

√3∗400∗0.855∗0.79=4.7 A

Page 3: Calculul Circuitelor de Forta

1. Calea de curent: conductor de cupru cu izolatie PVC „FY”:

Alegere: {In≤ Ima(¿14 A)nca=3

smin=1.5mm2

|¿>solutie4 FY 1.5

Verificarea la densitatea de curent

J=IP

s=

k P∗I n

s=6.5∗4.7

1.5=20.4 A /mm2<34 A /mm2

2. Tub de protectie PEL

Alegere: {smin=1.5mm2

n=4|¿>solutie PEL12.7

3. Releu termic -TSA

Alegere:{ I n=4.7 AI r=In

0.6∗I s≤ I r≤ I s

I FRT=20 A

→ I s=6 A→solutie TSA10 /6 A

4. Contactor TCAAlegere: I c≥ I n (4.7 A )→solutieTCA 6

IFc=20 A

5. Siguranta fuzibila

Page 4: Calculul Circuitelor de Forta

Alegere :{IF> I n(5 A)

I F≥IP

k=

k P∗I n

2.5=6.5∗4.7

2.5=12.2 A

IF≤3∗Ima (42 A )I F≤ IF RT

(20 A )I F≤ IFC (20 A)

→solutie3LF 25/16 A

Circuit motor 3kw

I n=P

√3∗U l∗cosφ∗η= 3000

√3∗400∗0.86∗0.8=6.3 A

1. Calea de curent: conductor de cupru cu izolatie PVC „FY”:

Alegere: {In≤ Ima(¿14 A)nca=3

smin=1.5mm2

|¿>solutie4 FY 1.5

Verificarea la densitatea de curent

J=IP

s=

k P∗I n

s=6.5∗6.3

1.5=27.3 A /mm2<34 A /mm2

2. Tub de protectie PEL

Alegere: {smin=1.5mm2

n=4|¿>solutie PEL12.7

3. Releu termic -TSA

Page 5: Calculul Circuitelor de Forta

Alegere:{ I n=6.3 AI r=In

0.6∗I s≤ I r≤ I s

I FRT=35 A

→ I s=10 A→solutie TSA10/10 A

4. Contactor TCAAlegere: I c≥ I n (6.3 A ) →solutie TCA 10

IFc=35 A

5. Siguranta fuzibila

Alegere :{IF> I n(7.8 A)

I F≥IP

k=

k P∗I n

2.5=6.5∗6.3

2.5=16.38 A

IF≤3∗Ima (42 A )IF≤ IF RT

(35 A )IF ≤ IFC (35 A)

→solutie3 LF25 /25 A

Circuit motor 11kw

I n=P

√3∗U l∗cosφ∗η= 11000

√3∗400∗0.87∗0.86=21.2 A

1. Calea de curent: conductor de cupru cu izolatie PVC „FY”:

Page 6: Calculul Circuitelor de Forta

Alegere: {In≤ Ima(¿34 A)nca=3

smin=6mm2

|¿>solutie4 FY 6

Verificarea la densitatea de curent

J=IP

s=

k P∗I n

s=7∗21.2

6=24.7 A /mm2<34 A /mm2

2. Tub de protectie PEL

Alegere: {smin=6mm2

n=4|¿>solutiePEL20

3. Releu termic -TSA

Alegere:{ I n=21.2 AI r=In

0.6∗I s≤ I r≤ I s

I FRT=80 A

→ I s=10 A→solutie TSA32/25 A

4. Contactor TCAAlegere: I c≥ I n (21.7 A )→solutie TCA 32

IFc=100 A

5. Siguranta fuzibila

Alegere :{IF> I n(21.7)

I F≥IP

k=

k P∗I n

2.5=7∗21.2

2=74.2 A

IF≤3∗Ima (102 A )IF≤ IF RT

(80 A )IF≤ IFC (100 A)

→solutie3 LF100/80 A

Page 7: Calculul Circuitelor de Forta

CALCULUL COLOANELOR TABLOURILOR DE FORTA SECUNDARE

COLOANA TGF - TAM

Functioneaza simultan circuitele : m11, m12, m14, f17

m11(2.2kw){ ¿=4.7 Asinφ=0.515 m12(2.2kw){ ¿=4.7 A

sinφ=0.515 m14(11kw){ ¿=21.2 Asinφ=0.65 f17

{ ¿=1.7 Asinφ=0.6

Ia=ΣInk x cosφk=[2x(4.7x0.855)]+(21.2x0.87)+(1.7x0.8)=27.84A

Ir=ΣInk x sinφk=[2x(4.7x0.515)]+(21.2x0.65)+(1.7x0.6)=19.64A

In=√¿a2+¿ r2=√27.842+19.642=34.07A

1. Calea de curent: conductor de cupru cu izolatie PVC PY:

Alegere: {In≤ Ima(¿ 45 A )nca=4

smin=2.5mm2|¿>solutie5FY 10

s=10mm2

2. Tub de protectie din PEL

Alegere: {s❑=10mm2

nca=5|¿>PEL34.2

3. Intreruptor parghie tripolar IP III Ir>Ic =>IPIII 100/504. Disjunctor

Alegere: {ID≤ Ima(45 A)ID≥ Ic

|¿>solutie ID=80 A

COLOANA TGF - TAT

Functioneaza simultan circuitele : m21, m23, m24, f25

m21(2.2kw){ ¿=4.7 Asinφ=0.515 m23(3kw){ ¿=6.3 A

sinφ=0.651 m24(11kw){ ¿=21.2 Asinφ=0.65 f25

{ ¿=1.7 Asinφ=0.6

Ia=ΣInk x cosφk=(4.7x0.855)+(6.3x0.86)+(21.2x0.87)+(1.7x0.8)=29.24A

Page 8: Calculul Circuitelor de Forta

Ir=ΣInk x sinφk=(4.7x0.515)+(6.3x0.651)+(21.2x0.65)+(1.7x0.6)=21.32A

In=√¿a2+¿ r2=√29.242+21.322=36.18A

1. Calea de curent: conductor de cupru cu izolatie PVC PY:

Alegere: {In≤ Ima(¿ 45 A )nca=4

smin=2.5mm2|¿>solutie5FY 10

s=10mm2

2. Tub de protectie din PEL

Alegere: {s❑=10mm2

nca=5|¿>PEL34.2

3. Intreruptor parghie tripolar IP III Ir>Ic =>IPIII 100/504. Disjunctor

Alegere: {ID≤ Ima(45 A)ID≥ Ic

|¿>solutie ID=80 A

COLOANA TGF - TCV

Functioneaza simultan circuitele : m31, m33, f34, f35

m31(2.2kw){ ¿=4.7 Asinφ=0.515 m33(11kw){ ¿=21.2 A

sinφ=0.65 f34(24 v){ ¿=1.7 Asinφ=0.6 f35{¿=10.87 A

sinφ=0.6

Ia=ΣInk x cosφk=(4.7x0.855)+(21.2x0.87)+(1.7x0.8)+(10.87x0.8)=32.51A

Ir=ΣInk x sinφk=(4.7x0.515)+(21.2x0.65)+(1.7x0.6)+(10.87x0.6)=23.74A

In=√¿a2+¿ r2=√32.512+23.742=40.25A

1. Calea de curent: conductor de cupru cu izolatie PVC PY:

Alegere: {In≤ Ima(¿76 A)nca=4

smin=2.5mm2|¿>solutie3 FY 25+2FY 16

s=25mm2

2. Tub de protectie din PEL

Alegere: {s❑=25mm2

nca=5|¿>PEL 44

3. Intreruptor parghie tripolar IP III Ir>Ic =>IPIII 100/504. Disjunctor

Page 9: Calculul Circuitelor de Forta

Alegere: {ID≤ Ima(76 A)ID≥ I c

|¿>solutie I D=100 A

COLOANA TGF - TCT

Functioneaza simultan circuitele : m41, m43, f44, f45

m41(2.2kw){ ¿=4.7 Asinφ=0.515 m43(11kw){ ¿=21.2 A

sinφ=0.65 f44(24 v){ ¿=1.7 Asinφ=0.6 f45{¿=10.87 A

sinφ=0.6

Ia=ΣInk x cosφk=(4.7x0.855)+(21.2x0.87)+(1.7x0.8)+(10.87x0.8)=32.51A

Ir=ΣInk x sinφk=(4.7x0.515)+(21.2x0.65)+(1.7x0.6)+(10.87x0.6)=23.74A

In=√¿a2+¿ r2=√32.512+23.742=40.25A

1. Calea de curent: conductor de cupru cu izolatie PVC PY:

Alegere: {In≤ Ima(¿76 A)nca=4

smin=2.5mm2|¿>solutie3 FY 25+2FY 16

s=25mm2

2. Tub de protectie din PEL

Alegere: {s❑=25mm2

nca=5|¿>PEL 44

3. Intreruptor parghie tripolar IP III Ir>Ic =>IPIII 100/504. Disjunctor

Alegere: {ID≤ Ima(76 A)ID≥ I c

|¿>solutie I D=100 A

COLOANA TGF - TSH

Functioneaza simultan circuitele : m51, m52, m53, f58

m55(11kw ){ ¿=21.2 Asinφ=0.65 m52(2.2kw){ ¿=4.7 A

sinφ=0.515 m53(2.2kw){ ¿=4.7 Asinφ=0.515 f58

{ ¿=1.7 Asinφ=0.6

Ia=ΣInk x cosφk=[2x(4.7x0.855)]+(21.2x0.87)+(1.7x0.8)=27.84A

Ir=ΣInk x sinφk=[2x(4.7x0.515)]+(21.2x0.65)+(1.7x0.6)=19.64A

Page 10: Calculul Circuitelor de Forta

In=√¿a2+¿ r2=√27.842+19.642=34.07A

1. Calea de curent: conductor de cupru cu izolatie PVC PY:

Alegere: {In≤ Ima(¿ 45 A )nca=4

smin=2.5mm2|¿>solutie5FY 10

s=10mm2

2. Tub de protectie din PEL

Alegere: {s❑=10mm2

nca=5|¿>PEL34.2

3. Intreruptor parghie tripolar IP III Ir>Ic =>IPIII 100/504. Disjunctor

Alegere: {ID≤ Ima(45 A)ID≥ Ic

|¿>solutie ID=80 A

DIMENSIONARE COLOANA GENERALA LUMINA

TGL-PT

Ia=cs ΣInaj=0.7 x ((6x36.89)+15.06)=165.48 A

Ir=cs ΣInrj =0.7 x((6x21.87)+4.95)=95.39 A

Page 11: Calculul Circuitelor de Forta

Cs=0.5…0.8=>se allege cs=0.7

In=√¿a2+¿ r2=√165.482+95.392=191 A

1. Calea de curent: conductor de cupru :

Alegere: {In≤ Ima(¿230 A)nca=4

s=70mm2

¿

2.Intreruptor parghie tripolar IP III Ir>Ic =630/300 A

3.Disjunctor

Alegere: {ID≤ Ima(230 A)ID≥ I c

|¿>solutie ID=200 A

DIMENSIONARE COLOANA GENERALA FORTA

TF-PT

Ia=cs ΣInaj=0.7 x (27.84+29.24+32.51+32.51+27.84)=82 A

Ir=cs ΣInrj =0.7 x(19.64+21.32+23.74+23.74+19.64)=75.65 A

Cs=0.5…0.8=>se allege cs=0.7

In=√¿a2+¿ r2=√822+75.652=111.57 A

1. Calea de curent: conductor de cupru :

Alegere: {In≤ Ima(¿185 A)nca=4

s=50mm2

¿

2.Intreruptor parghie tripolar IP III Ir>Ic =350/175 A

Page 12: Calculul Circuitelor de Forta

3.Disjunctor

Alegere: {ID≤ Ima(185 A)I D≥ I c

|¿>solutie ID=160 A

CALCULUL PIERDERILOR DE TENSIUNE

LUMINA:

ΔU1%:=> 100

γ∗Uf 2*ΣPi∗ljsj =

2∗10054∗2302*¿=0.61

ΔU2%:=> 100

γ∗U 2*P∗ls =

100

54∗4002*21436∗27

25 =0.26

ΔU3%: 100γ∗U 2*Pi∗ls =

100

54∗4002*139004∗100

70 =2.29

ΔU= ΔU1+ ΔU2+ ΔU3=0.61+0.26+2.29=3.16% < 8%

Page 13: Calculul Circuitelor de Forta

FORTA:

ΔU1%:=> Rp= 100

γ∗U 2*P∗ls =

100

54∗4002*89448∗11.66

6 =2.011

P=√3∗U∗Ip∗cosφ=√3∗400∗148.4∗0.87=89448

=>Rn== 100

γ∗U 2*Pe∗l

s =100

54∗4002*12790.7∗11.66

10 =0.28

P=Piη

=110000.86

=12790.7

ΔU2%:=> Rp= 100

γ∗U 2*P∗ls =

100

54∗4002*89448∗25.08

6 =2.59

P=√3∗U∗Ip∗cosφ=√3∗400∗148.4∗0.87=89448

=>Rn= 100

γ∗U 2*Pe∗l

s =100

54∗4002*20535.8∗25.08

10 =0.596

P=√3∗U∗¿∗cosφ=√3∗400∗34.07∗0.87=20535.8

ΔU3%: 100γ∗U 2*Pi∗ls =

100

54∗4002*20535.8∗100

50 =0.48

ΔURP= ΔU1RP+ ΔU2

RP+ ΔU3=2.011+2.59+0.48=5.081% < 17%

Page 14: Calculul Circuitelor de Forta

ΔURN= ΔU1RN+ ΔU2

RN+ ΔU3=0.28+0.596+0.48=1.36% < 10%