Bessel 3

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    Bessels Differentialequation

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    In this lecture we discuss Bessels

    Differential Equation. We also study

    properties of Bessels functions, which are

    solutions of Bessels equation. We first

    review the definition and properties of the

    celebrated Gamma function (which is also

    called the extended factorial function).

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    http://discovery.bits-

    pilani.ac.in/discipline/math/msr/index.html

    You may view my lecture slides in the

    following site.

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    Gamma Function (x)

    This is easily one of the most importantfunctions in Mathematics.

    Definition: For each real no x > 0, the

    improper integral

    dtte

    xt 1

    0

    converges and its value is denoted by (x).

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    (x + 1) = x(x) --- (Proved byIntegrating by parts)

    (1) = 1 -- (immediate from the definition)

    (n + 1) = n ! For all positive integers n

    (follows from the first two properties; thusthe Gamma function is also referred to as

    the extended factorial function)

    Properties of the Gamma function (x)

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    ( ) (1 ) ( not an integer)sin

    x x xx

    We now extend the definition of(x) for

    negative numbersx as follows:

    If -1

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    Thus we have extended the definition of(x)

    for -1

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    Proceeding like this, we define (x) for all

    negative numbersx which are not negativeintegers. We also note that for allx (not a

    negative integer),

    ( 1) ( )x x x

    1 ( 1)x x x

    And so on.

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    We note that ifx is a positive integer,

    (x + 1) =x(x) =x (x-1)(x1)

    = ..

    =x!We now define for all numbersx (not a

    negative integer),

    ! ( 1)x x

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    We also note for future reference that

    ! ( 1)( 2)..( )

    ( )!

    x x x x n

    x n

    wherex is NOT a negative integer.

    The next slide shows the graph of theGamma function.

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    The second order homogeneous l.d.e.

    2 2 2

    ( ) 0x y xy x p y wherep is anonnegative constant, is called as

    the Bessels differential equation of orderp.

    2

    1( )

    xP x

    x x Here and

    2 2 2

    2 2( )( ) 1x p pQ x x x are analytic at all

    points exceptx = 0.

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    Hencex = 0 is the only singular point. As

    ( ) ( ) 1p x xP x 2 2 2

    ( ) ( )q x x Q x x p

    andare both analytic atx = 0,x = 0 is a regular

    singular point.

    ( 1) (0) (0) 0m m p m q

    i.e. 2( 1) 0m m m p or2 2 0m p

    Hence the exponents are m =

    The indicial equation is

    p, -p.

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    Hence corresponding to the bigger exponent

    m=p, there always exists a Frobenius Series

    solution

    00

    ( 0)p nnn

    y x a x a

    00

    ( 0)p nnn

    a x a

    1

    0

    ( ) p nnn

    y p n a x

    2

    0

    ( )( 1) p nnn

    y p n p n a x

    Hence

    Substituting fory,y , y we get

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    0

    ( )( 1) p nnn

    p n p n a x

    0

    ( ) p nnn

    p n a x

    2 2

    0

    ( ) 0p n

    n

    n

    x p a x

    Divide throughout byxp, we get

    2

    0

    ( )( 1) ( ) nnn

    p n p n p n p a x

    2

    0

    0nnn

    a x

    In the second , replace n byn-2. We then get

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    2 2

    0

    ( ) nnn

    p n p a x

    22

    0nnn

    a x

    Note that the constant term is absent. Thus

    the above equation becomes

    1 22

    (2 1) (2 ) 0nn nn

    p a x n p n a a x

    Thus 1(2 1) 0p a

    2(2 ) 0, 2n nn p n a a n

    1 0a

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    2

    1, 2

    (2 )n na a n

    n p n or

    Recurrence relation forans

    n=3 gives 3 11

    03(2 3)a ap

    Putting n = 5, 7, we get

    0 for all oddna n

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    n = 2 gives2 0 02

    1 1

    2(2 2) 2 ( 1)a a a

    p p

    n = 4 gives4 2 22

    1 1

    4(2 4) 2 2( 2)a a a

    p p

    2

    04

    1( 1)

    2 1 2 ( 1)( 2)a

    p p

    2

    04

    1( 1)

    2 2! ( 1)( 2)a

    p p

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    Proceeding like this we get

    2 02

    1( 1)2 ! ( 1)( 2)...( )

    n

    n na a

    n p p p n

    n = 1, 2,

    Hence the solution corresponding to the

    exponent m =p is

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    2

    0 20

    1( 1)

    2 ! ( 1)( 2)...( )

    p n n

    nn

    y a x xn p p p n

    Now choosing 01

    2 !pa

    p we get the solution

    2

    0

    1( 1)

    ! ( )! 2

    n p

    n

    n

    xy

    n p n

    This solution is denoted by ( )pJ x and is

    referred to as Bessels function of the first kind.

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    Thus2

    0

    1( ) ( 1)

    !( )! 2

    n p

    np

    n

    xJ x

    n n p

    Ifp is a positive integer or zero, we see that

    Jp(x) is a power series

    Ifp is odd,Jp(x) contains only odd powersofx

    Ifp is even,Jp

    (x) contains only even powers

    ofx

    Jp(x) converges absolutely for allx > 0.

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    Ifp is NOT an integer or zero, we easily

    show that a second LI solution is2

    0

    1( ) ( 1)

    !( )! 2

    n p

    n

    pn

    xJ x

    n n p

    Hence whenp is NOT an integer or zero,

    the general solution of Bessels equation is

    1 2( ) ( ),p py c J x c J x

    c1, c2 arbitrary constants

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    Ifp is a positive integerm, we formally define

    2

    0

    1( ) ( 1)!( )! 2

    n m

    nm

    n

    xJ xn n m

    Noting that1 1

    0 for 0 ,( )! n mn m

    we get2

    1

    ( ) ( 1) !( )! 2

    n m

    n

    mn m

    x

    J x n n m

    Changing n to n+m, we get

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    2

    0

    1( ) ( 1)

    !( )! 2

    n m

    n mm

    n

    xJ x

    n n m

    2

    0

    1( 1) ( 1)

    !( )! 2

    n m

    m n

    n

    x

    n n m

    ( 1) ( )m

    mJ x

    HenceJm(x) andJ-m(x) are not LI.( m, a positive integer)

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    Bessels Function of the second kind

    We define the standard Bessel function

    of the second kind by

    ( ) cos ( )( )

    sin

    p p

    p

    J x p J xY x

    p

    p not an integer.It is obvious that we can write the general

    solution of Bessels equation of orderp also as

    1 2( ) ( )p py c J x c Y x (c1, c2 arbitrary constants)

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    It has been shown that ( ) lim ( )m pp m

    Y x Y x

    exists, is a solution of Bessels equation of

    orderm and thatJm(x) and Ym(x) are LI.

    Hence for allp (integer or not), the generalsolution of Bessels equation of orderp is

    1 2( ) ( )p py c J x c Y x (c1, c2 arbitrary constants)

    The following slides shows the graphs of

    J0(x) ,J1(x), .. and Y0(x), Y1(x),

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