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    IS 456:2000

    BEAM DESIGN

    PROBLEM 1

    Singly fixed beam

    L =5m B=300mm D=600mm M20 Fe415 Cl.cover =25mm

    W=150 kN/m

    DIAMETER OF

    BAR

    16 dia 25 dia 32 dia

    MANUAL Ast 1868 mm2 1891

    mm2

    1910

    mm2

    dt 33 37.5 41

    STAAD PRO V8I

    Ast1940.5 mm

    2 1894.4 mm

    2 1913.50

    mm2

    Use dt to match the

    results with STAAD

    46 38 42

    -In staad, Ast decreases as diameter of bar increases.

    -Encounters a problem in using dt.

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    PROBLEM 2

    Doubly fixed beam.

    L =5m B=300mm D=600mm M20 Fe415 cover =25mm

    W=180 kN/m

    DIAMETER OFBAR 16 dia 20 dia 32 dia

    Manual Ast 2251 mm2 2257mm

    2 2279mm

    2

    Manual Asc 219 mm 234mm 278 mm

    dt 33 35 41

    STAAD PRO V8I

    Ast2297.86 mm

    2 2286.54 mm

    2 2277.3mm

    2

    Asc 328.78 mm2 302.9 mm

    2 279.5 mm

    2

    Use dt to match theresults with STAAD 46 44 41

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    PROBLEM 3

    Simply supported doubly beam section

    diameter 16 mm 20 mm 32 mm

    staad Ast 2381.40 mm2 2346.20 mm

    2 2360.89

    mm2

    staad Asc 413.63 mm2 337.47 mm

    2 364.59 mm

    2

    use dt for

    matchindg result

    46 47 41

    manual Ast 2332 mm 2339 mm 2362 mm

    manual Asc 302 mm 317 mm 363 mm

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    PROBLEM 4

    4.1

    Tv >TC

    Sv ,By design worksheet

    distance 0 mm 1250 mm 2500 mm

    shear design Tv >TC Tv >TC Tv

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    4.2

    This type of problem occurred in simply supported beam.

    By Design worksheet :

    MANUAL SV

    0mm 250mm 500mm 750mm 1000 mm

    Tv >TC Tv >TC Tv >TC Tv >TC Tv

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    PROBLEM 5 (Torsion design)

    5.1

    -20 mm diameter are provided in staad pro.

    Eff. Cover = 25 + 10 = 35 mm

    Results from manual calculations are not matched with staad pro result.

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    5.2

    AT SUPPORT : 0 m

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    If we consider the effective cover as 42 mm then the answers are nearer

    to the results of staad pro.

    AT 1.250m

    If we consider the effective cover as 52 mm then the answers are nearer

    to the results of staad pro.

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    5.3

    Torsion design + Shear design

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    At support

    At 1.25 m

    At 2.5 m

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    5.4

    Torsion in simply supported beam

    At 2.5 m

    Actually Asc does not require in design but somehow staad provides.

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    At 3.75 m

    Actually Asc does not require in design but somehow staad provides.

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    5.5

    Torsion in simply supported beam (doubly beam section)

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    At 2.5 m

    Required Asc = 95 mm^2 ( Manually )

    Required Asc = 350.24 mm^2 ( Staad result )

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    Problem 5.6

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    At support : 0 m TV < TC

    Shear design is verified ( matched ) with design worksheet.

    AT 1.25m TV < TC

    Required Sv = 300 mm ( Manually )

    Provided Sv = 190 mm ( Staad result )

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    At end : 5 m

    Required Sv = 300 mm ( Manually )

    Provided Sv = 190 mm ( Staad result )

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    Problem 6 Tee beam (fixed beam)

    6.1

    l=5m M20 Fe415

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    -This doesnt require Asc but staad provides 306 mm^2 at 0 m.

    -Shear design problems are same as a beam design.

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    6.2

    Cantilever tee beam design

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    Ast and Asc are not matched with staad pro v8i.

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    6.3 cantilever

    STRESS DIAGRAM :

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    At support : 0 m

    Flexural steel matches with staad results.

    At 2.5 m

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    W = -75 kN

    When the applied point load is 60 kN downwards at mid span, the Ast is

    provided by Staad is at bottom and when the applied point load is 75 Kndownwards at mid span, the Ast is provided at top.

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    PROBLEM 7

    CONTROL OF DEFLECTION

    1.1 The vertical deflection limits may. Generally be assumed to besatisfied provided that the span to depth ratios are not greater than the

    values obtained as below:

    a) Basic values of span to effective depth ratios

    for spans up to 10m:

    a) cantilever-7

    simply supported-20

    continuous-26

    basic value of span to effective depth ratio for span up to 10 m.

    Allowable deflection as per IS 456

    =7*M.F

    By deflection chart M.F=0.82

    5.74

    Actual

    =8.33

    Actual

    < maximum

    8.33< 5.74 Not ok

    Staad pro v8i doesnt consider this criteria and provides a design

    without even any warning.

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    PROBLEM 8

    1.2 Slenderness Limit for Beams to Ensure Lateral Stability

    A simply supported or continuous beam shall be so proportioned that the clear

    distance between the lateral

    restraints does not exceed 60 b whichever is less,where d is the effective depth of the beam and b the breadth of the compression

    face midway between the lateral restraints. For a cantilever, the clear distance from

    the free end of the cantilever to the lateral restraint shall not exceed

    or 25 b

    or whichever is less.

    [not including this clause.]

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    Problem 9

    5.SIDE FACE REIINFORCEMENT

    Where the depth of the web in beam exceed 750 mm sidereinforcement shall be provide along the two faces. the reinforcement

    shall be not less than 0.1 % of the web area and shall be distributed

    equally distributed equally on two faces at a spacing not exceed 300

    mm or web thickness whichever is less.

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    Udl =6 kN/m

    Staad provides side face reinforcement, but it doesnt satisfy the

    spacing of bars which is limited to 300mm or width of web whichever is

    less.

    Calculation =

    Area of web=830*350=290500mm2

    0.1%web area=290 mm2

    Staad pro v8i provided=1-16i =402 mm2

    >290 mm2

    This criteria is provided in staad pro v8i.

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    Problem 10

    TORSION DESIGN

    In Torsion Design If Depth Increse more Then 450 Side Reinforcement Are

    Provided As Per Is 456.

    But staad pro does not provide a side face reinforcement.

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    Problem-11

    Deep beam

    a) A beam shall be deemed to be deep beam when the ratio of effective span to

    depth to overall depth l/d is less than :

    1) 2 for simply supported beam

    2) 2.5 for a continuous beam

    Deep beam is not designed assuming it to be a part of a continuous beam and

    away from the critical section for enhanced shear, ordinary shear check is

    performed.

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    Problem-12

    Fixed beam

    Ld =

    =

    = 483.5 (for tension)

    Ld =

    = 386.83

    -At end staad pro v8i provide a 0 development length.

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    Fixed beam 2

    Ld=

    =

    =483.5 (for tension)

    Ld=

    =386.83 (for compression)

    -at end staad pro v8i provide a 0 development length.

    -staad consider some time larger diameter and.sum time take a

    smaller diameter.

    -no meaning Ld provided at intermediate span.

    -in compression staad pro v8i not increase Tbd value 25%.

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    PROBLEM -13

    In Staad pro v8i 2legged stirrups are provided .and also inclined stirrups

    are not provided.

    PROBLEM -14

    Spacing Between Two Bar Are

    Spmain Criteria Are Provided In Staad Pro V8i.But Spacing BetweenTwo Bar Are Taken By Staad Pro Itself.

    SPMAIN design parameter are provided in staad pro v8i,still staad pro

    take spacing by itself.

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    At 1.5 m result are not matched.

    Example 2

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    Not mathched ast and asc.

    Example 3

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    Example 5

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