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MERENCANAKAN BALOK KERAN (CRANEGIRDER) Data - Data Keran -Berdasarkan teori untuk Bentang = 32 Kapasitas takel = 5 Kapasitas keran = 20 Berat takle = 5 Jarak bersih dihitung dari atas rel = 1.5 Berat sendiri rel (ditaksir) = 25 Berat sendiri keran (ditaksir) = 18 Jarak roda-roda keran = 2.5 Jarak bersih dari permukaan kolom ke rel = 0.5 Jarak minimum lokasi takel terhadap rel = 1 0.5 m 1.5 m 29 m 1 m A B C D E 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37

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Page 1: baja 2 nando 3

MERENCANAKAN BALOK KERAN (CRANEGIRDER)

Data - Data Keran-Berdasarkan teori untuk

Bentang = 32Kapasitas takel = 5Kapasitas keran = 20Berat takle = 5Jarak bersih dihitung dari atas rel = 1.5Berat sendiri rel (ditaksir) = 25Berat sendiri keran (ditaksir) = 18Jarak roda-roda keran = 2.5Jarak bersih dari permukaan kolom ke rel = 0.5Jarak minimum lokasi takel terhadap rel = 1

0.5 m

1.5 m 29 m

1 m

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Page 2: baja 2 nando 3

MERENCANAKAN BALOK KERAN (CRANEGIRDER)

mtontontonmkg/mkg/mmmm

29 m

F G

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Page 3: baja 2 nando 3

P = 25 t

q = 18 t(ditaksir)

L = 31 m1 m

Ra = t Rb = 9.806 tRa = 29.539 t 1.6*Rb = 15.690 t

29.539 t

14.770 t 14.770 t

L = 2.5A B

m1 m

5.752.875 2.875

2.25 0.625 1.875 1

0.625 2.25

R1 = 11.559 t R2 = 17.980 t

Q1 = 11.559 jarak = 0 m Q1QA = 11.559 jarak = 2.25 m [Q]QB = -3.211 jarak = 4.75 m QbQ2 = -17.980 jarak = 5.75 m

2.25

Perhitungan Bidang MomenBgn (0<x<1.625)

Mx = R1*xx = 0 M1 = 0 tmx = 2.25 Ma = 26.007163 tm A

Bgn (1.625<x<4.125) [M] M1Mx = R1*x-Ra(x-1.625)

x = 2.25 Ma = 26.007163 tmx = 4.75 Mb = 17.980261 tm Ma

Bgn (4.125<x<4.5) 2.25Mx = R1*x-Ra(x-1.625)-Rb(x-4.125)

x = 4.75 Ma = 17.980261 tmx = 5.75 M2 = 0 tm

Mmaks = 26.007163 tmkoef kejut = 1.1529.9082375 tm29908.2375 kgm

Akibat Beban Mati- Berat Sendiri Rel = 25 kg/m- Berat Balok Kran = 562.5 kg/m

2913.632813 kgm

MLL =

MDL =1,2*(1/8*q*l2)

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Page 4: baja 2 nando 3

Mux

32821.87031 kgm328218703.1 Nmm

Sumbu y (Lemah)Momen Akibat Gaya Rem Melintang= 1/29 (Kapasitas Kran + Berat Takel) x 1/20.43103448 tm

Beban Roda = 14.77 tMmaks = 26.00716304 tm

Jadi akibat akibat gaya rem = 0.431034483 tm

momen =0.431034483

26.00716314.7695

0.758995502 tm= 75899.55022 Nmm

= MLL + MDL

Muy =

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Page 5: baja 2 nando 3

m

Qa

Q2

2.5 1

M2

Mb

2.5 1

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Page 6: baja 2 nando 3

J K L

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Page 7: baja 2 nando 3

Berat Sendiri Balok Kran = 562.5 =Menggunakan Baja Profil IWF

Profil = W16x89*d = in =bf = 10.365 in =tw = 0.525 in =tf = 0.875 in =hw = 13.625 in =Sx = 864 cm3 =Ix = 10800 cm4 =Zx = 937 cm3 =Sy = 292 cm3 =Iy = 3650 cm4 =r = 2.49 =A = 26.2 =G = 89 lbs/ft =x₁ = 3090 ksi =

= 1630 =Bj 37fy = 240 =fr = 70 =

Penyelesaian :* Periksa Kekompakang web dan Flens :- Flens λ = bf/(2tf) = 8.9285714286

Kompak

λp = = 10.9734528143λr = = 28.3777045874

- web λ = hw/tw = 21.1111111111λp = 1680/(fy^(1/2)) = 108.4435336938λr = 2550/(fy^(1/2)) = 164.6017922138

* Periksa Terhadap Tekuk Lateral :

Lb = 0.5L = 2.875 m =f = fy-fr = 170 MpaLp = 1.76ry(E/fy)^(1/2) = 3213.3284

Lr = = 50878.0755

* Kontrol :

Bentang PendekLb ≤ Lp True..!!!

Bentang MenengahLp ≤ Lb ≤ Lr 0

Bentang PanjangLb ≥ Lr False..!!!

in³in²

x₂ *106 (ksi-1)²

170/(fy^(1/2))370/((fy-fr)^(1/2))

ry(X1/f)(1+(1+X2.f)^(1/2))^(1/2)

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Page 8: baja 2 nando 3

* Untuk Bentang Menengah :

Mn = fy.Zx = 224880000 Nmm

* Kontrol Terhadap Lentur 2 Arah :1. Kondisi BatasData-data :

= 328218703.125 Nmm= 75899.5502248876 Nmm

fu =+

= 380.14 MpaSx Sy

= 0.9fy = 216.00 Mpa

* Kontrol :

fun ≤ Tidak Ok

380.14 ≤ 216.00 Mpa

2. Kondisi Batas Tekuk Torsi LateralData-data :

= 0.9Mn = 202392000.0 Nmm

Mux = 328218703.1 Nmm

* Kontrol :

≥ Mux Tidak Ok

202392000.0 ≥ 328218703.1 Nmm

Mux

Muy

Mux Muy

øb.fy

øb.fy

øb.Mn

øb.Mn

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Page 9: baja 2 nando 3

377.9825235117 lbsMenggunakan Baja Profil IWF

250 mm250 mm

9 mm14 mm

190 mm864000.000 mm³108000000

937000 mm³292000 mm³

3650000063.246 mm

16903.192 mm²132.446599738 Kg/m

21305.55 Mpa

5.589E-02 Mpa

240 Mpa70 Mpa

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Page 11: baja 2 nando 3

MERENCANAKAN KONSOL

29.539 t0.5 m 0.2 m

29539 kg

0.5 m 0.2 mRa

29539 kg

M max = 14769.5 kgmM u = 1.6 x Mmax = 23631.2 kgm

= 236312000.0 Nmm

Dicoba Penampang :Profil = W10X60

d = 10.22 in =bf = 10.08 in =tw = 0.42 in =tf = 0.68 in =hw = 7.625 in =Sx = 66.7 in³ =Ix = 341 =Zx = 74.6 in³ =Sy = 23 in³ =Iy = 116 =ry = 2.57 in³ =A = 17.6 in² =G = 60 lbs/ft =x₁ = 3970 ksi =

= 525 =Bj 37fy = 240 =fr = 70 =

in4

in4

x *10₂ 6 (ksi-1)²

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Page 12: baja 2 nando 3

* Periksa Kekompakan Web dan Flens :- Flens λ = bf/(2tf) 7.4117647059

Kompak

λp = 170/(fy^(1/2)) 10.9734528143λr = 370/((fy-fr)^(1/2)) 28.3777045874

- web λ = hw/tw 18.1547619048λp = 1680/(fy^(1/2)) 108.4435336938λr = 2550/(fy^(1/2)) 164.6017922138

Mp = 293393993.856Mr = 185812918.696

Mn Berdasarkan Tekuk Lokal Web

Mn =λr - λ

Mp +λ - λp

Mrλr - λp λr - λp

= 315409892.102 Nmm

Mn Berdasarkan Tekuk Lokal Flens

Mn =λr - λ

Mp +λ - λp

Mrλr - λp λr - λp

= 466358102.785 Nmm

dipakai Mn terkecil Mn = 315409892.102 Nmm

Ø Mn = 283868902.892 Nmm

*Kontrol

Ø Mn > Mu Ok..!!283868902.891745 > 236312000

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Page 13: baja 2 nando 3

MERENCANAKAN KONSOL

260 mm256 mm

11 mm17 mm

194 mm1093017 mm³

1419349161222474.9744 mm³

376902.472 mm³48282845.3696

65.278 mm11354.816 mm²

89.28984252 Kg/m27373.15 Mpa

5.798E-03 Mpa

240 Mpa70 Mpa

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