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96 ANSWERS TO EXERCISES
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CHAPTER 8 • CHAPTER CHAPTER 8 • CHAPTER
LESSON 8.1
1. 228 m2
2. 41.85 cm2
3. 8 yd
4. 21 cm
5. 91 ft2
6. 182 m2
7. 96 in2
8. 210 cm
9. A � 42 ft2
10. sample answer:
11. 3 square units
12. 10 square units
13. 7�12
� square units
14. sample answers:
15. possible answer:
16. 23.1 m2
17. 2(4)(3) � 2(5.5)(3) � 57 m2
18. For a constant perimeter, area is maximized by
a square. 100 m � 4 � 25 m per side; A � 625 m2.
19. �5
130�
20. 112
21. 96 square units
22. 32 square units
4 cm
16 cm16 cm
16 cm16 cm
64 cm2
8 cm
4 cm
16 cm
64 cm2
8 cm
4 cm
12 cm
8 cm
6 cm
48 cm2
48 cm2
Answers to Exercises23. 500 cm2
24a. smallest: 191.88 cm2; largest: 194.68 cm2
24b. Answers will vary. Sample answer: about
193 cm2.
24c. Answers will vary. The smallest and largest
area values differ at the ones place, so the digits
after the decimal point are insignificant compared
to the effect of the limit of precision in the
measurements.
25a. In one Ohio Star block, the sum of the red
patches is 36 in2, the sum of the blue patches is
72 in2, and the yellow patch is 36 in2.
25b. 42
25c. About 1814 in2 of red fabric, about 3629 in2
of blue fabric, and about 1814 in2 of yellow
fabric. The border requires 5580 in2 (if it does
not need the extra 20%).
26. 100; 36 � 64. The area of the square on the
longer side is the same as the sum of the areas on
the other two legs.
27. a � 76°,b � 52°,c � 104°,d � 52°,e � 76°,
f � 47°, g � 90°, h � 43°, k � 104°, m � 86°.
Explanations will vary.
28. sample construction:
29a. 29b.
29c.
30°
30°A M
8
ANSWERS TO EXERCISES 97
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LESSON 8.2
1. 20 cm2
2. 49.5 m2
3. 300 square units
4. 60 cm2
5. 6 cm
6. 9 ft
7. 30 ft
8. 5 cm
9. 16 m
10. 168 cm
11. 12 cm
12. 3.6 ft; 10.8 ft
13. sample answer:
14. sample answer:
15. sample answer:
16. The length of the base of the triangle equals
the sum of the lengths of both bases of the
trapezoid.
2 cm
3 cm 3 cm
7 cm 9 cm
12 cm
46 cm 35 cm
45 cm 56 cm
12 cm
4 cm
8 cm
10 cm 9 cm
7 cm
7 cm
12 cm
9 cm 12 cm
9 cm
17. �12
�(To see why, draw altitude PQ�.)
18. more than half, because the top card
completely covers one corner of the bottom card
19a. 86 in. of balsa wood and 960 in2 of Mylar
19b. 56 in. (or less, if he tilts the kite)
20. 3600 shingles (to cover an area of 900 ft2)
21. The isosceles triangle is a right triangle
because the angles on either side of the right
angle are complementary. If you use the trapezoid
area formula, the area of the trapezoid is �12
�(a � b)(a � b). If you add the areas of the
three triangles, the area of the trapezoid is�12
�c2 � ab.
22.
Given: trapezoid ABCD with height h. area
of �ABD � �12
� hb1; area of �BCD � �12
�hb2; area
of trapezoid � sum of areas of two triangles
� �12
�h�b1 � b2�23. 11�
14
� square units
24. 7 square units
25. 70 m
26. 144 cm2
27. 828 ft2; 144 ft
28. 1440 cm2; 220 cm
29a. incenter
29b. orthocenter
29c. centroid
30. a � 34°, b � 68°, c � 68°, d � 56°, e � 56°,
f � 90°, g � 34°, h � 56°, m � 56°, n � 90°,
p � 34°. Possible explanation: Let O be the center
of the circle. mBC� � 112° by the Inscribed Angle
Conjecture, and d � e � mBC� by the Central
Angle Conjecture. �OBA is congruent to �OCA
by SSS, so d � e � 56°. DEC� is a semicircle, so
mDE� � 68°. By the Inscribed Angle Conjecture,
p � 34°. Using �OEC and the Triangle Sum
Conjecture, n � 90°.
31. 32.62�3.6.3.6
D
A b1
b2
h
B
C
LESSON 8.3
1a. 121,952 ft2
1b. 244 gal of base paint and 488 gal of finishing
paint
2. He should buy at least four rolls of wallpaper.
(The area of each roll is 125 ft2. The total surface
area to be papered is 480 ft2.) If paper cut off at the
corners is wasted, he’ll need 5 rolls.
3. 1552 ft2; 776 ft2 more surface area
4. 21
5. 336 ft2; $1780
6. $760
7. 220 terra cotta tiles, 1107 blue tiles; $1598.15
8. 72 cm2
9. AB � 16.5 cm, BD � 15.3 cm
10. 60 cm2 by either method
11. Because �AOB is isosceles, m�A � 20° and
m�AOB � 140°. mAAAB� � 140° and mCD� � 82°.
mAC�� mBD� because parallel lines intercept
congruent arcs on a circle.�360°�1240°� 82°�� 69°.
12. E
98 ANSWERS TO EXERCISES
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ANSWERS TO EXERCISES 99
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USING YOUR ALGEBRA SKILLS 8
1. x2 � 6x � 5 2. 2x2 � 7x
3. 6x2 � 19x � 10
4. (3)(2x � 1) 5. (x � 5)(x � 3)
6. (2x � 3)(x � 4)
7. x2 � 26x � 165 8. 12x2 � 13x � 35
9. x2 � 8x � 16 10. 4x2 � 25
2x
�5
52x
4x 2 10x
�10x �25
x
4
4x
x 2 4x
4x 16
4x
5
�73x
12x 2 �28x
15x �35
x
�11
�15x
x 2 �15x
�11x 165
x � 4x
4
x2x � 3
x 3
x � 3x
3
5x
x � 5
x 2
2x � 1
x
x
3
1
2x � 5
x
x
5
x3x � 2x x 2
2x � 7
x
x
7
x
x � 1 x
1
5xx � 5
x 2
11. a2 � 2ab � b2 12. a2 � b2
13. (x � 15)(x � 4) 14. (x � 12)(x � 2)
15. (x � 5)(x � 4)
16. (x � 3)2 � (x � 3)(x � 3)
17. (x � 6)(x � 6)
18. (2x � 7)(2x � 7)
19. x � �4 or x � �1
20. x � �10 or x � 3
21. x � 3 or x � 8
22. x � ��12� or x � �4
23a and b.
23c. �12
�[h � (h � 4)]h � 48
23d. h � �8 or h � 6. The height cannot be
negative, so the only valid solution is h � 6.
The height is 6 feet, one base is 6 feet, and the
other base is 10 feet.
h � 4
h
h
2x
�7
72x
4x 2 14x
�14x �49
x
�6
6x
x 2 6x
�6x �36
x
�3
�3x
x 2 �3x
�3x 9
x
�4
5x
x 2 5x
�4x �20
x
2
�12x
x 2 �12x
2x �24
x
4
15x
x 2 15x
4x 60
a
�b
ba
a 2 ab
�ab �b 2
a
b
ba
a 2 ab
ab b 2
LESSON 8.4
1. 2092 cm2 2. 74 cm
3. 256 cm 4. 33 cm2
5. 63 cm 6. 490 cm2
7. � 57.6 m 8. � 25 ft
9. � 42 cm2 10. � 58 cm2
11. a � �12
�s; A � �12
�asn � �12
� � �12
�s � s � 4 � s2
12. It is impossible to increase its area, because a
regular pentagon maximizes the area. Any
dragging of the vertices decreases the area.
(Subsequent dragging to space them out more
evenly can increase the area again, but never
beyond that of the regular pentagon.)
13. � 996 cm2
14. � 497 cm2
15. total surface area � 13,680 in2 � 95 ft2;
cost � $8075
16. Area is 20 square units.
x
y
y � x � 5 1_2
y � �2x � 10
(2, 6)
17. Area is 36 square units.
18. Conjecture: The three medians of a triangle
divide the triangle into six triangles of equal area.
Argument: Triangles 1 and 2 have equal area
because they have equal bases and the same
height. Because the centroid divides each median
into thirds, you can show that the height of
triangles 1 and 2 is �13
� the height of the whole
triangle. Each has an area �16
� the area of the whole
triangle. By the same argument, the other small
triangles also have areas �16
� the area of the whole
triangle.
19. nw � ny � 2x
20. 504 cm2
21. 840 cm2
h12
x
y
y � – x � 12 4_3
y � – x � 6 1_3(6, 4)
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ANSWERS TO EXERCISES 101
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LESSON 8.5
1. 9� in2
2. 49� cm2
3. 0.8 m2
4. 3 cm
5. �3� in.
6. 0.5 m
7. 36� in2
8. 7846 m2
9. 25� � 48, or about 30.5 square units
10. 100� � 128, or about 186 square units
11.
12. 804 m2
13. 11,310 km2
14. 154 m2
15. 4 times
r � 18 cm
16. A � �r 2 because the 100-gon almost
completely fills the circle.
17. 456 cm2
18. 36 ft2
19. The triangles have equal area when the point
is at the intersection of the two diagonals. There is
no other location at which all four triangles have
equal area.
20. x � mDE� � 2 � 24° � 48°
21. 90° � 38° � 28° � 28° � 180°
22.
18 cm6 cm
12 cm
24 cm
LESSON 8.6
1. 6� cm2
2. �64
3�� cm2
3. 192� cm2
4. (� � 2) cm2
5. (48� � 32) cm2
6. 33� cm2
7. 21� cm2
8. �10
25�� cm2
9. 6 cm
10. 7 cm
11. 75
12. 100
13. 42
14. $448
15a.
15b.
15c.
15d.
16. sample answer:
17a. (144 � 36�) cm2; 78.54%
17b. (144 � 36�) cm2; 78.54%
17c. (144 � 36�) cm2; 78.54%
17d. (144 � 36�) cm2; 78.54%
18. 480 m2
19. AB � 17.0 cm, AG � 6.6 cm
20. True. If 24� � �39600
� � 2�r, then r � 48 cm.
21. True. If �3
n60� � 24, then n � 15.
22. False. It could be a rhombus.
23. true; Triangle Inequality Conjecture
102 ANSWERS TO EXERCISES
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ANSWERS TO EXERCISES 103
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LESSON 8.7
1. 150 cm2 2. 4070 cm2
3. 216 cm2 4. 340 cm2
5. � 103.7 cm2 6. � 1187.5 cm2
7. � 1604.4 cm2 8. � 1040 cm2
9. � 414.7 cm2 10. � 329.1 cm2
11. area of square � 4 � area of trapezoid � 4 �area of triangle
12. $1570
13. sample answer:
14. sample tiling
33.42/32.4.3.4/44
15. a � 75°, b � 75°, c � 30°, d � 60°,
e � 150°, f � 30°
16. About 23 days. Each sector is about 1.767 km2.
17. a � 50°, b � 50°, c � 80°, d � 100°, e � 80°,
f � 100°, g � 80°, h � 80°, k � 80°, m � 20°,
n � 80°. Explanations will vary. Sample
explanation: The angle with measure d corresponds
to the angle forming a linear pair with g. Because
d � 100°, by the Parallel Lines Conjecture, the
angle adjacent to g measures 100°, and by the
Linear Pair Conjecture, g � 80°. The angle with
measure f corresponds to the angle measuring
100°, so f � 100°. The angles measuring g and k
are the base angles of an isosceles triangle, so by
the Isosceles Triangle Conjecture, k � 80°.
18. 398 square units
CHAPTER 8 REVIEW
1. B (parallelogram) 2. A (triangle)
3. C (trapezoid) 4. E (kite)
5. F (regular polygon) 6. D (circle)
7. J (sector) 8. I (annulus)
9. G (cylinder) 10. H (cone)
11. 12.
13.
14. Sample answer: Construct an altitude from
the vertex of an obtuse angle to the base. Cut off
the right triangle and move it to the opposite side,
forming a rectangle. Because the parallelogram’s
area hasn’t changed, its area equals the area of the
rectangle. Because the area of the rectangle is
given by the formula A � bh, the area of the
parallelogram is also given by A � bh.
15. Sample answer: Make a copy of the trapezoid
and put the two copies together to form a
parallelogram with base �b1 � b2� and height h.
Thus the area of one trapezoid is given by the
formula A � �12
� �b1 � b2�h.
16. Sample answer:Cut a circular region into a large
number of wedges and arrange them into a shape
that resembles a rectangle.The base length of this
“rectangle”is�r and the height is r, so its area is�r2.
ThustheareaofacircleisgivenbytheformulaA��r2.
17. 800 cm2 18. 5990.4 cm2
19. 60� cm2 or about 188.5 cm2
�r
r
b1
b2
b2
b1
h h
bh
bh
Apothem
20. 32 cm 21. 32 cm 22. 15 cm
23. 81� cm2 24. 48� cm 25. 40°
26. 153.9 cm2 27. 72 cm2 28. 30.9 cm2
29. 300 cm2 30. 940 cm2 31. 1356 cm2
32. Area is 112 square units.
33. Area is 81 square units.
34. 6 cm 35. 172.5 cm2
36. sample answers:
37. 1250 m2
38. Circle. For the square, 100 � 4s, s � 25,
A � 252 � 625 ft2. For the circle, 100 � 2�r,
r � 15.9, A � �(15.9)2 � 794 ft2.
39. A round peg in a square hole is a better fit.
The round peg fills about 78.5% of area of the
square hole, whereas the square peg fills only about
63.7% of the area of the round hole.
40. giant 41. about 14 oz
42. One-eighth of a 12-inch diameter pie;
one-fourth of a 6-inch pie and one-eighth of a
12-inch pie both have the same length of crust,
which is longer than one-sixth of an 8-inch pie.
43a. 96 ft; 40 ft 43b. 3290 ft2
44. $3000 45. $4160
46. It’s a bad deal.2�r1 � 44 cm.2�r2 � 22 cm,
which implies 4�r2 � 44 cm. Therefore r1 � 2r2.
The area of the large bundle is 4��r2�2 cm2. The
combined area of two small bundles is 2��r2�2 cm2.
Thus he is getting half as much for the same price.
47. $2002 48. $384 (16 gal)
x
y
R (4, 15)
U (9, 5)
O (4, –3)
F (0, 0)
xA (0, 0)
D (6, 8) C (20, 8)
y
B (14, 0)
104 ANSWERS TO EXERCISES
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