A02-Demo

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12B30 / 12C30 / CET - B02 Slide # 1

STEEL CUTTING CHARGES

• Block charges

• Special charges

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12B30 / 12C30 / CET - B02 Slide # 2

BLOCK CHARGES

• P = 3 / 8 A

• Hasty Calculation

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12B30 / 12C30 / CET - B02 Slide # 3

FORMULA for MILD or STRUCTURAL STEEL

P = 3 / 8 A

P = Pounds of TNT

3/8 = Constant (.375)

A = Area of cross sectionin square inches

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12B30 / 12C30 / CET - B02 Slide # 4

Flange

Flange

Web

CROSS SECTIONAL AREA

OF TARGET = "A"

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12B30 / 12C30 / CET - B02 Slide # 5

CROSS SECTIONAL AREA

OF TARGET = "A"

Flange

Flange

Web

1"

1"14"

8"

12"

= 8"x1"

= 8"x1"

= 12"x1"

=8 sq in

=8 sq in

=12 sq in

A = 28 sq in

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12B30 / 12C30 / CET - B02 Slide # 6

CACULATE for TNT

P = (3/8)A or P= (.375)A

P = Pounds of TNT

3/8 (.375) = Constant

A = Cross sectional area in

square inches

P = .375 x 28 = 10.5 lbs TNT

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12B30 / 12C30 / CET - B02 Slide # 7

12"

15"

1"

1"

PROBLEM

Use C-4 (M112)

Total of 4 Beams

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12B30 / 12C30 / CET - B02 Slide # 8

SOLUTION

Step 1. 15" x 1" = 15 sq in12" x 1" = 12 sq in

15" x 1" = 15 sq in

A = 42 sq in

Step 2. P=3/8AP=.375 x 42 = 15.75 lbs TNT

Step 3. 15.75 = 11.75 lbs C-4

1.34

Step 4. 11.75 = 9.4 10 pkgs C-41.25

Step 5. 4beams = 4charges

Step 6. 10 x 4 = 40 pkgs C-4

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12B30 / 12C30 / CET - B02 Slide # 9

3/4

3/4

9.5” 1"

9"

PROBLEM

Use: M112

12 Beams

P=3/8A

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12B30 / 12C30 / CET - B02 Slide # 10

SOLUTION

Step 2. P=3/8AP=.375 x 23 = 8.62 lbs TNT

Step 3. 8.62 = 6.43 lbs C-4

1.34

Step 4. 6.43 =5.14 6 pkgs C-4

1.25


Step 6. 6 x 12 = 72 pkgs C-4

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12B30 / 12C30 / CET - B02 Slide # 11

HASTY CALCULATION

TNT Needed To Cut Steel Sections Average

thickness

of

section in

inches

Pounds of explosive* for rectangular steel sections of given dimensions

Height of section in inches

2 3 4 5 6 7 8 9 10 11 12 14 16 18 20 22 24

0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2 1.3 1.5 1.7 1.9 2.1 2.3

0.3 0.5 0.6 0.7 0.9 1.1 1.2 1.3 1.4 1.6 1.7 2.0 2.3 2.6 2.8 3.1 3.4

0.4 0.6 0.8 1.0 1.2 1.4 1.5 1.7 1.9 2.1 2.3 2.7 3.0 3.4 3.8 4.2 4.5

0.5 0.7 1.0 1.2 1.4 1.7 1.9 2.2 2.4 2.7 2.9 3.3 3.8 4.3 4.7 5.2 5.7

0.6 0.9 1.2 1.4 1.7 2.0 2.3 2.6 2.8 3.1 3.4 4.0 4.5 5.1 5.7 6.3 6.8

0.7 1.0 1.4 1.7 2.0 2.4 2.7 3.0 3.3 3.7 4.0 4.6 5.3 6.0 6.6 7.3 7.9

0.8 1.2 1.5 1.9 2.3 2.7 3.0 3.4 3.8 4.2 4.5 5.3 6.0 6.8 7.5 8.3 9.0

1/4

3/8

1/2

5/8

3/4

7/8

1

* TNTTo Use: 1. Measure rectangular sections of members separately.

2. Using table, find charge for each section.

3. Add charges for sections to find total charge.

4. If dimensions of sections do not appear on table, use next larger dimension.

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12B30 / 12C30 / CET - B02 Slide # 12

Section

Thickness

(inches)

Weight of Composition C4 Required for Rectangular Steel Sections

(Height or Width, In Inches)

2 3 4 5 6 8 10 12 14 16 18 20 22 24

1/4

3/81/2

5/8

3/4

7/8

1

0.2 0.3 0.3 0.4 0.5 0.6 0.8 0.9 1.0 1.2 1.3 1.5 1.6 1.8

0.3 0.4 0.5 0.6 0.7 0.9 1.1 1.3 1.5 1.8 2.0 2.1 2.4 2.60.3 0.5 0.6 0.8 0.9 1.2 1.5 1.8 2.1 2.3 2.6 2.9 3.2 3.4

0.4 0.6 0.8 0.9 1.1 1.5 1.8 2.2 2.5 2.9 3.2 3.5 3.9 4.3

0.5 0.7 0.9 1.1 1.3 1.8 2.1 2.6 3.0 3.4 3.8 4.3 4.7 5.1

0.6 0.8 1.1 1.3 1.5 2.1 2.5 3.0 3.5 4 4.5 5.0 5.5 5.9

0.6 0.9 1.2 1.5 1.8 2.3 2.9 3.4 4.0 4.5 5.1 5.6 6.2 6.8

NOTE: Round UP to the nearest 1/10 pound when calculating charge size.

To use this table:

1. Measure each rectangular section of the total member separately.

2. Find the appropriate charge size for the rectangular section from the table. If

the section dimension is not listed in the table, use the next larger dimension.

3. Add the individual charges for each section to obtain the total charge weight.

Hasty Steel-Cutting Chart for C4

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12B30 / 12C30 / CET - B02 Slide # 13

10"

1"

3/8"

5"

PROBLEM: USE HASTY CALCULATION

Use: TNT

6 Beams

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12B30 / 12C30 / CET - B02 Slide # 14

SOLUTIONStep 1. 5" x 1" flange Hasty TNT

10" x 3/8" web 6 Beams5" x 1" flange

5" x 1"

10" x 3/8"5" x 1"

Step 2. 1.9 lbs

1.4 lbs1.9 lbs

Total = 5.2 lbs TNT

Step 3. N/A

Step 4. 5.2 6 pkgs TNT


Step 6. 6 x 6 = 36 pkgs TNT

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12B30 / 12C30 / CET - B02 Slide # 15

PROBLEM

HASTY CALCULATION

• How many packages of C-4, (M112)

are required to cut 5, I-beamswith dimensions of 8" x 1/2"for the flanges, and 10" x 1"for the web?

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12B30 / 12C30 / CET - B02 Slide # 16

SOLUTIONStep 1. 8" x 1/2" flange

10" x 1" web

8" x 1/2" flange

10" x 1"

8" x 1/2"

Step 2. 8" x 1/2" 1.2 lbs

1.2 lbs

2.9 lbs

Total = 5.3 lbs C-4

Step 3. N/A

Step 4. 5.3=4.24 5 pkgs C-41.25Step 5. 5beams = 5charges

Step 6. 5 x 5 = 25 pkgs C-4

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12B30 / 12C30 / CET - B02 Slide # 17

CABLES-CHAINS-RODS-BARS

"Rule of Thumb"

FORMULA: High Carbon Alloy Steel

* P = D

RULE OF THE THUMB: Structural Steel

* Up to 1" diam.- use 1 pound* Over 1" to 2" dia. - use 2 pounds* Over 2" - use P=3/8A

2

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12B30 / 12C30 / CET - B02 Slide # 18

RAILROAD DESTRUCTION"Rule of Thumb"

• Rails * Less than 5"Use: 1/2 pound C-4 or TNT

• Rails * 5" or moreUse: 1 pound C-4 or TNT

NOTE: Place charges at alternate rail

splices for a distance of 500 feet.

Charges

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12B30 / 12C30 / CET - B02 Slide # 19

RAILWAY DESTRUCTION"Rule of Thumb" FROGS CROSSOVERS SWITCHES

* figure 3-10 page 3-15

* FROGS - 2LBS

* CROSSOVERS - 1LB

* SWITCHES - 1LB

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12B30 / 12C30 / CET - B02 Slide # 20

SPECIAL CHARGES

• Ribbon

• Saddle

• Diamond

• NOTE: Use C-4 (M112)

or Sheet explosive (M118)

ONLY

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12B30 / 12C30 / CET - B02 Slide # 21

RIBBON CHARGE

• Charge thickness = 1/2 TGTbut never less than 1/2 inch

• Charge width = 3 times the

charge thickness• Charge length = length of

TGT to be cut

• T x W x L = volume cubicinches needed

• Maximum target thickness =3 inches

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12B30 / 12C30 / CET - B02 Slide # 22

Top Flange (TF)

Bottom Flange (BF)

Web (W)

1"

1"14" 11"

10"

1/2

Tx Wx L =

TF .5 1.5 9 6.75

W

BF

.5 1.5 11 8.25

.5 1.5 9 6.75

Total cu. in. = 21.75

+

+

Tx Wx L =

1 3 20 60 cu. in.2"

20"

DIMENSION CALCULATING(Ribbon Charge)

I-Beam

Plate

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12B30 / 12C30 / CET - B02 Slide # 23

24"2"

PROBLEM

How much C-4 (M112) is required to cutthis one plate using the MINIMUM amountof explosive?

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12B30 / 12C30 / CET - B02 Slide # 24

SOLUTION

Tx Wx L =

1 3 24 72 cu. in.Step 2.

Step 1. one plate, 2"x24", ribbon, C-4(M112)

Step 3. N/A

Step 4. 72 = 3.6 4 pkgs C-4(M112)20

Step 5. 1plate = 1charge

Step 6. 4 x 1 = 4 pkgs C-4(M112)

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12B30 / 12C30 / CET - B02 Slide # 25

1"

1"15"

10"

Tx Wx L =

TF .5 1.5 9 6.75

W

BF

.5 1.5 14 10.5

.5 1.5 9 6.75

Total cu. in. = 24

+

+

TF BF& = 9" (10" - 1" web)

W = 14 (15” - 1” for charge thickness)

CHARGES LENGTHS

PROBLEMCalculate for volume/cubic inches

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12B30 / 12C30 / CET - B02 Slide # 26

2"

2"

19.5"

14"

PROBLEM

Use: C-4(M112)15 Beams

Ribbon Charge

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12B30 / 12C30 / CET - B02 Slide # 27

SOLUTIONStep 1. 15 beams, C4(M112), ribbon

Top Flange (TF)

Bottom Flange (BF)

Web (W)

2"

2"14" 12"

19.5

1"

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12B30 / 12C30 / CET - B02 Slide # 28

SOLUTION(cont.)

Step 2.Tx Wx L =

TF 1

1

1

3

3

3

17.5

12

17.5

52.5

52.5

W

BF

36

Total cu. in. = 141

+

+

Step 3. N/A

Step 4. 141 = 7.05 8 pkgs C-4(M112)20Step 5. 15beams = 15charges

Step 6. 8 x 15 = 120 pkgs C-4

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12B30 / 12C30 / CET - B02 Slide # 29

SADDLE CHARGE

• Round or rectangular steel up to 8" in diameter

• Long Axis = distance around target in inches

• Base = 1/2 distance around target in inches

• Volume needed = Long axis X base X 1/2 = vol. cu. in.LA x B x 1/2 = vol. cu. in.

• Explosive = 1" thick

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12B30 / 12C30 / CET - B02 Slide # 30

C = 16"

PROBLEM

How much C-4 (M112) is required to cutone mild steel bar using a saddlecharge?

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12B30 / 12C30 / CET - B02 Slide # 31

SOLUTION

Step 1. one bar, C=16, C-4, saddle

Step 2. P=LA x B x .5P=16 x 8 x .5 = 64 cu. in.

Step 3. N/A

Step 4. 64 = 3.2 4 pkgs C-4

20

Step 5. 1bar = 1charge

Step 6. 1 x 4 = 4 pkgs C-4

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12B30 / 12C30 / CET - B02 Slide # 32

PROBLEM

How much C-4 (M112) is required

to cut a steel bar 8 timesusing the saddle charge?

* C = 15"

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12B30 / 12C30 / CET - B02 Slide # 33

SOLUTION

Step 1. 8 cuts, C=15, C-4, saddle

Step 2. P=LA x B x .5P=15 x 7.5 x .5 = 56.25cu. in.

Step 3. N/A

Step 4. 56.25 = 2.81 3 pkgs C-420

Step 5. 8cuts = 8charges

Step 6. 8 x 3 = 24 pkgs C-4

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12B30 / 12C30 / CET - B02 Slide # 34

DIAMOND CHARGE

• Used on any steel round or rectangular up to 8"in diameter (not pipe)

• Long Axis = distance around target• Short Axis = 1/2 distance around target

• Volume needed = Long Axis X Short Axis x .5

LA x SA x .5 = vol. cu. in.• Explosive = 1" thick

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12B30 / 12C30 / CET - B02 Slide # 35

4"

8"

Distance around target = 8" + 4" x 2 = 24"

PROBLEM

How much C-4 (M112) is required to cutone steel plate using the diamondcharge?

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12B30 / 12C30 / CET - B02 Slide # 36

SOLUTION

Step 1. one bar, LA=24", C-4, diamond

Step 2. P=LA x SA x .5P=24 x 12 x .5 = 144 cu. in.

Step 3. N/A

Step 4. 144 = 7.2 8 pkgs C-4

20

Step 5. 1plate = 1charge

Step 6. 1 x 8 = 8 pkgs C-4

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12B30 / 12C30 / CET - B02 Slide # 37

PROBLEM

• How many packages of sheet explosive (M118)

is required to cut 6 bars using thediamond charge?

• C = 14"

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12B30 / 12C30 / CET - B02 Slide # 38

SOLUTION

Step 1. 6 bars, C=14, pkgs of M118, diamond

Step 2. P=LA x SA x .5P=14 x 7 x .5 = 49 cu. in.

Step 3. N/A

Step 4. 49 = 5.44 6 sheets M118

9

Step 5. 6bars = 6charges

Step 6. 6 x 6 = 36 sheets M118

36 sheets 4 sheets per pkg = 9 pkgs M118..

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A02-Demo