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A general approach to rates of change Using a similar approach to that in the previous slide show it is possible to find the gradient at any point (x,

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A general approach to rates of change

Using a similar approach to that in the previous slide show it is possible to find the gradient at any point (x, y) on the curve y = f(x).

At this point it is useful to introduce some “new” notation due to Leibniz.

The Greek letter ∆(delta) is used as an abbreviation for “the increase in”.

Thus the “increase in x” is written as ∆x, and the “increase in y” is written as ∆y.

P (x1, y1)

Q (x2, y2)

x

y

O

12 yy

12 xx

So when considering the gradient of a straight line, ∆x is the same as x2 – x1 and ∆y is the same as y2 – y1.

∆x

∆y

Gottfried Leibniz1646 - 1716

gradient

Note∆x is the same as h used on the previous slide show.

Gradient of the curve y = x2 at the point P(x, y)Suppose that the point Q(x + ∆x, y + ∆y) is very close to the point P on the curve.

The small change from P in the value of x is ∆x and the corresponding small change in the value of y is ∆y.

It is important to understand that ∆x is read as “delta x” and is a single symbol.

The gradient of the chord PQ is:

xO

y

P(x, y)

Q(x + ∆x, y + ∆y)

y = x2

x

y y∆x

∆y

The coordinates of P can also be written as (x, x2) and the coordinates of Q as [(x + ∆x), (x + ∆x)2].

So the gradient of the chord PQ can be written as:

= 2x + ∆x

So = 2x + ∆x

As ∆x gets smaller approaches a limit and we start to refer to it in theoretical terms.

This limit is the gradient of the tangent at P which is the gradient of the curve at P.

It is called the rate of change of y with respect to x at the point P.

x

yxy

x δ

δdd

0δlim

For the curve y = x2,

xxxy

xδ2

dd

0δlim

= 2x

This is the result we obtained previously.

This is denoted by or .xy

dd

Gradient of the curve y = f(x) at the point P(x, y)

xO

y

P(x, y)

Q(x + δx, y + δy)

y = f(x)

x

y yδx

δy

For any function y = f(x) the gradient of the chord PQ is:

xy

xxxyyy

δδ

)δ()δ(

The coordinates of P can also be written as (x, f(x)) and the coordinates of Q as [(x + δx), f(x + δx)].

So the gradient of the chord PQ can be written as:

xxxxxx

)δ(

)(f)δ(f

x

yxy

x δ

δdd

0δlim

xxx

xxx

x )δ(

)(f)δ(f

0lim

x

xxx

x δ

)(f)δ(f

0lim

It is defined by

In words we say:

The symbol is called the derivative or the differential coefficient of y with respect to x.xy

dd

x

xxxxy

x δ

)(f)δ(fdd

0δlim

“dee y by dee x is the limit of as δx tends to zero”xy

δδ

“tends to” is another way of saying “approaches”

DEFINITION OF THE DERIVATIVE OF A FUNCTIONDEFINITION OF THE DERIVATIVE OF A FUNCTION

Sometimes we write h instead of ∆x and so the derivative of f(x) can be written as

h

xhxxy

h

)(f)(fdd

0lim

DEFINITION OF THE DERIVATIVE OF A FUNCTIONDEFINITION OF THE DERIVATIVE OF A FUNCTION

If y = f(x) we can also use the notation:

xy

dd = f’ (x)

In this case f’ is often called the derived function of f. This is also called f-prime.

The procedure used to find from y is called differentiating y with respect to x.xy

dd

Find for the function y = x3.

Example (1)

In this case, f(x) = x3.

xy

dd

h

xhxxy

h

)(f)(fdd

0lim

h

xhx

h

33

0

)(lim

h

xhxhhxx

h

33223

0

33lim

h

hxhhx

h

322

0

33lim

22

033lim hxhx

h

= 3x2

f(x) f ‘ (x)

x2 2x

x3 3x2

Results so far

−4 −3 −2 −1 1 2 3 4

5

10

15

x

yy = x3

−4 −3 −2 −1 1 2 3 4

5

10

15

x

yy = x3

Gradient at (2, 8) = 12

Find for the function y = x4.

Example (2)

In this case, f(x) = x4.

xy

dd

h

xhxxy

h

)(f)(fdd

0lim

h

xhx

h

44

0

)(lim

h

xhxhhxhxx

h

4432234

0

464lim

3223

0464lim hxhhxx

h

= 4x3

Results so far

h

hxhhxhx

h

43223

0

464lim

f(x) f ‘(x)

x2 2x

x3 3x2

x4 4x3

Find for the function y = .

Example (3)

xy

dd

x1

In this case, f(x) = .x1

h

xhxxy

h

)(f)(fdd

0lim

h

xhxh

11

0lim

h

hxxhxx

h

)()(

0lim

h

hxxh

h

)(

0lim

)(0lim

hxxh

h

h

)(

1

0lim

hxxh

21x

So we now have the following results:

We also know that if y = x = x1 then )1or ( 1dd 0x

xy

and if y = 1 = x0 then )0or ( 0dd 1 x

xy

These results suggest that if y = xn then 1dd nnx

xy

It can be proven that this statement is true for all values of n.

n xn

–1

2 x2 2x

3 x3 3x2

4 x4 4x3

xy

dd

)or ( 1 1xx)or ( 1 2

2 x

x