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軟軟軟軟 軟軟軟 軟軟軟 軟軟 rjwang 軟軟

軟體設計丙級

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軟體設計丙級. 林文恭 研究室 原著 rjwang 編修. 學科. 考題內容 採「考前公開」制 , 公告於勞委會網站 題庫內共 700 題單選題 範圍:計算機概論、程式設計 評分方法 考試時間 100 分鐘 答題數 80 題每題 1.25 分,答錯不倒扣 以 60 分為及格。. 術科. 考題內容 採「考前公開」制,公告於勞委會網站 分為 2 站共 8 個題目 : 第一站:基本指令應用 共 5 個題目 ×3 組迴圈指令,每人抽 3題 及 1組迴圈指令 作答。 第二站: 應用程式設計 共3個題目,每人抽 1題 作答。 軟體: - PowerPoint PPT Presentation

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  • rjwang

  • 700100801.2560

  • 2853Microsoft Visual Basic20052008()

  • (1)45940301.SM~940305.SM940301.T01~940305.T01SM T01~T03 ()

  • (2)940301~940305533Go To33

  • ()(windows,!)

    Vb2008c:\999901

    C:\999901

  • () c:\ title.exe C:\Title.exe c:\title.txt

  • 123C:\title.txt

  • [] [999901][01] [2010/11/11]

    ..

    ...

    PrintDocumenttitle.txt

  • 940301Input & Output940301.SM12321 is a palindrome.Palindrome

    =

    12321

    13~912321

  • 940301

    12345 / 10 = 12345123455 1234 / 10 = 1234123454 123 / 10 = 123123543 12 / 10 = 121254321 / 10 = 01 00154321

  • 940302Input & Output940302.SM 1121231234123451234561234567

    17

  • 940302

    ijj = 1 To im1 = m1 & jm111j = 1 To 1m1 = m1 & 11For i = 1 To 3 For j = 1 To i m1 = m1 & j Next jNext i212j = 1 To 2m1 = m1 & 1m1 = m1 & 2123123j = 1 To 3m1 = m1 & 1m1 = m1 & 2m1 = m1 & 3123

  • 940303Input & Output940303.SM12 is not a prime number.prime number

    n2n^0.5n,n()

    11

    112

  • 940303

    m1 = 7 , m1^0.5=2 ()im1 / i()27 / 231m2=0 For i = 2 To m1^0.5 if m1 mod i = 0 Then m2 = m2 + 1 Next I

    If m2 = 0 then txt_03.text=m1 & & m1 & is a prime number.Else txt_03.text=m1 & & m1 & is not a prime number.End If

  • 940304Input & Output940304.SMBMI=15

    12()176()45()165()50()170()55

  • 940304

    BMI = BMI(1)BMI(1) = 39BMI(2) = 29BMI(3) = 191BMI = 39392BMI = 39293BMI = 2919BMI = 19

  • 940305Input & Output940305.SM[6 8][10 12]

    12A(1,1)1A(1,2)2A(2,1)3A(2,2)4B(1,1)5B(1,2)6B(2,1)7B(2,2)8

  • 940305For i = 1 To 2 For j = 1 To 2 C( i , j ) = A( i , j ) + B( i , j ) Next jNext i

    IJA(I,J)B(I,J)C(I,J)11A(1,1) = 1B(1,1) = 5A(1,1) + B(1,1)1+5 = 62A(1,2) = 2B(1,2) = 6A(1,2) + B(1,2)2+6 = 821A(2,1) = 3B(2,1) = 7A(2,1) + B(2,1)3+7 = 102A(2,2) = 4B(2,2) = 8A(2,2) + B(2,2)4+8 = 12

  • 940306~940308194030X.SM 94030X.T01803

  • 1rdata2sp113sp224sp335wdata

  • Form_Loadrdatasp1sp2sp3sp4sp5btn_car_Clickbtn_week_Click

  • (swap)

  • m1/m2

    1rdata2sp13wdata

  • SMT013Alt + PrintScreen