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RATE OF RETURN ANALYSIS
1
INTERNAL RATE OF RETURN (IRR)The Internal Rate of Return (IRR) method solves for the interest rate that
equates the equivalent worth of a project's cash outflows (expenditures)to the equivalent worth of cash inflows (receipts or savings).
2
INTERNAL RATE OF RETURN (IRR)By definition:
Given a cash flow stream, IRR is the interest rate i at which thebenefits are equivalent to the costs or the NPW=0
The Internal Rate of Return is the rate of return that yields a Net PresentValue of zero.
NPW=0
PW of benefits - PW of costs =0
PW of benefits = PW of costs
PW of benefits / PW of costs=1
EUAB-EUAC=0
3
INTERNAL RATE OF RETURN (IRR)
In other words, the IRR is the interest rate that makes the PW, AW, and FWof a project's estimated cash flows equal to zero. That is, PW(i') of cashinflow = PW(i') of cash outflow.
We commonly denote the IRR by i'.
PW(i' %) = 0
AW(i' %) = 0
FW(i' %) = 0
4
Internal Rate of Return
-$1,000
$350
years1 2 3 4
$350$350 $350
15.00000,1
1
350
1
350
1
350
1
350432
IRRIRRIRRIRRIRR
$350
years1 2 3 4
$350$350 $350
$1,063
$1,00015%
12%
Internal Rate of Return
• Example: A company invests $10,000 in a computer and resultsin equivalent annual labor savings of $4,021 over 3 years. Thecompany is said to earn a return of 10% on its investment of$10,000.
PROJECT BALANCE CALCULATION:
0 1 2 3
Beginningproject balance
Return oninvested capital
Paymentreceived
Ending projectbalance
-$10,000 -$6,979 3,656
-$1,000 -$697 -$365
-$10,000 +$4,021 +$4,021 +$4,021
-$10,000 -$6,979 -$3,656 0
The firm earns a 10% rate of return on funds that remain internallyinvested in the project. Since the return is internal to the project, we callit internal rate of return.
INTERNAL RATE OF RETURN (IRR)
8
700 = 100/(1+i) + 175/(1+i)2 + 250/(1+i)3 + 325/(1+i)4.
It turns out that i = 6.09 %.
Suppose you have the following cash flow stream. Youinvest $700, and then receive $100, $175, $250, and $325at the end of years 1, 2, 3 and 4 respectively. What is the IRRfor your investment?
0 1
$700
$100
time2 3 4
$175$250
$325
How to calculate IRR?
COMPUTATION OF IRR
Direct Solution
Trial and Error Solution
Computer Solution
9
Internal Rate of Return MethodInternal Rate of Return MethodInternal Rate of Return Method
Management is evaluating a proposal toacquire equipment costing $97,360. The
equipment is expected to provide annual netcash flows of $20,000 per year for seven
years.
Management is evaluating a proposal toacquire equipment costing $97,360. The
equipment is expected to provide annual netcash flows of $20,000 per year for seven
years.
$97,360
$20,000= 4.868
Determine the table valueusing the present value foran annuity of $1 table.
Internal Rate of Return MethodInternal Rate of Return MethodInternal Rate of Return Method
Amount to be invested
Equal annual cash flow
Present Value of an Annuity of $1Present Value of an Annuity of $1Present Value of an Annuity of $1
1 0.943 0.909 0.893 0.870
2 1.833 1.736 1.690 1.626
3 2.673 2.487 2.402 2.283
4 3.465 3.170 3.037 2.855
5 4.212 3.791 3.605 3.353
6 4.917 4.355 4.111 3.785
7 5.582 4.868 4.564 4.160
Year 6% 10% 12% 15%
Internal Rate of Return MethodInternal Rate of Return MethodInternal Rate of Return Method
Find the seven year line on thetable. Then, go across theseven-year line until the closestamount to 4.868 is located.
Present Value of an Annuity of $1Present Value of an Annuity of $1Present Value of an Annuity of $1
1 0.943 0.909 0.893 0.870
2 1.833 1.736 1.690 1.626
3 2.673 2.487 2.402 2.283
4 3.465 3.170 3.037 2.855
5 4.212 3.791 3.605 3.353
6 4.917 4.355 4.111 3.785
7 5.582 4.868 4.564 4.160
Year 6% 10% 12% 15%
4.8684.868
Internal Rate of Return MethodInternal Rate of Return MethodInternal Rate of Return Method
Internal Rate of Return MethodInternal Rate of Return MethodInternal Rate of Return Method
Move vertically to the top of thetable to determine the interestrate.
Present Value of an Annuity of $1Present Value of an Annuity of $1Present Value of an Annuity of $1
1 0.943 0.909 0.893 0.870
2 1.833 1.736 1.690 1.626
3 2.673 2.487 2.402 2.283
4 3.465 3.170 3.037 2.855
5 4.212 3.791 3.605 3.353
6 4.917 4.355 4.111 3.785
7 5.582 4.868 4.564 4.160
Year 6% 10% 12% 15%
4.8684.868
10%10%
10%
DIRECT SOLUTION
Example
15
n Cash Flow
1 -$2,000
2 1300
3 1500
0)1(
1500$
)1(
1300$000,2$)(
2
iiiPW
)1(
1
ixAssume
01500$1300$2000$)( 2 xxiPW
)(%160667.1
%25%258.0
667.18.0*
cesignificaneconomicnoix
iix
orxSolving
TRIAL AND ERROR METHOD
Aiming for i that makes PW(i)=0
Guess a value of i*
Compute the PW of net cash flows
Observe if PW is +, -, or zero
PW(i) is negative, lower the interestrate
PW(i) is positive, raise the interest rate
Continue until PW(i) is approximatelyzero
16
4 Example Continued – IRR method
Find i'% such that the PW(i'%) = 0.
0 = -$50,000 + $17,500(P|A, i'%,5) + $10,000(P|F, i'%,5)
PW (20%) = 6354.50 tells us that i' > 20%
PW (25%) = 339.75 > 0, tells us that i'% > 25%
17
PW (30%) = -4,684.24 < 0, tells us that i'% < 30%
25% < i' < 30%
Use linear interpolation to estimate i'%.
18
19
20
Example
0
1 2 3 4 5 6 7 8
Years
(Units in millions)
$10
$1.8 1.8 1.8 1.8 1.8 1.8 1.8
$2.8
After tax net cash flows
Guess i=8%
PW(8%) = -$10+$1.8(P/A, 8%, 8)+$1(P/F, 8%, 8) = $0.88
Sale value = $1
Since PW is positive, raise the interest rate
Assume i=12%
PW(12%) = -$10+$1.8(P/A, 12%, 8) + $1(P/F, 12%, 8) = -$0.65
Use interpolation
%3.10)65.0(88.0
088.0%)8%12(%8*
i
Check PW(i) with this i*, iterate if necessary. Computer value = 10.18%
Trial
interest
rates
NPW
0 $50.00
5 $26.46
10 $9.24
15 ($3.49)
20 ($12.97)
25 ($20.06)
30 ($25.37)
35 ($29.36)
40 ($32.34)
45 ($34.54)
50 ($36.16)($50.00)
($40.00)
($30.00)
($20.00)
($10.00)
$0.00
$10.00
$20.00
$30.00
$40.00
$50.00
$60.00
0 5 10 15 20 25 30 35 40 45 50
Ne
tP
res
en
tV
alu
e
Year Cash flow
0 ($100.00)
1 $20.00
2 $30.00
3 $20.00
4 $40.00
5 $40.00
21
EXAMPLE2 :GRAPHIC SOLUTION
PW of costs = PW of benefits
100=20/(1+i)+30/(1+i)2+20/(1+i)3+40/(1+i)4+40/(1+i)5
i=13.5%
NPW=-100+20/(1+i)+30/(1+i)2+20/(1+i)3+40/(1+i)4+40/(1+i)5
Internal Rate of Return versus NPVExample:
-$10,000
$20,000Project A
-$20,000
$35,000Project B
000,101
000,20
rrNPVA
year1 year1
000,201
000,35
rrNPVB
NPV(A) and NPV(B) as function of the discount rate
Example:
ProjectCash flows ($)
IRRNPV at
10%t=0 t=1
A -10,000 +20,000 100 +8,182
B -20,000 +35,000 75 +11,818
Internal Rate of Return versus NPV
IRR
NPV at 10%
Internal Rate of Return versus NPVAnother example:
-$9,000
$3,500
Project C
$6,000
Project D
000,91
000,4
1
000,5
1
000,632
rrrrNPVD
year1
000,91
500,35
1
n
nCr
rNPV
$3,500 $3,500 $3,500 $3,500
2 3 4 5
$5,000 $4,000
-$9,000
-4000
-2000
0
2000
4000
6000
8000
10000
0 10 20 30 40 50
Project C
Project D
Another example:
ProjectCash flows ($)
IRRNPV at
10%t=0 t=1 t=2 t=3 t=4 t=5
C -9,000 +6,000 +5,000 +4,000 0 0 33 +3,592
D -9,000 +3,500 +3,500 +3,500 +3,500 +3,500 27 +4,268
NPV(C) and NPV(D) as function of the discount rate
IRRNPV at 10%
26
Rate of Return AnalysisExample statements about a project:1. The net present worth of the project is $32,000.2. The equivalent uniform annual benefit is $2,800.3. The project will produce a 23% rate of return
The third statement is perhaps most widely understood.
Rate of return analysis is probably the most frequently used analysistechnique in industry.Its major advantage is that it provides a figure of merit that is readilyunderstood.
27
Motivating Example.
Banks 1 and 2 offer you the following Deals 1 and 2 respectively:
Deal 1.Invest $2,000 today. At the end of years 1, 2, and 3 get $100,$100, and $500 in interest; at the end of year 4, get $2,200in principal and interest.
Deal 2:Invest $2,000 today. At the end of years 1, 2, and 3 get $100,$100, and $100 in interest; at the end of year 4, get $2,000 inprincipal only.
Question. Which deal is the best?
Rate of Return Analysis
28
Deal 1:Find out the implicit interest rate you would be receiving;that is, solve for
2000 = 100/(1+i)1 + 100/(1+i)2 + 500/(1+i)3 + 2200/(1+i)4
IRR: i = 10.7844 %.
This is the interest rate for the PV of your payments to be $2,000.
Deal 2:We find i for which
2000 = 100/(1+i)1 + 100/(1+i)2 + 100/(1+i)3 + 2000/(1+i)4
IRR: i = 3.8194%.
Which deal would you prefer?
Rate of Return Analysis
29
Judging proposed investments
• IRR gets more complicated whencomparing multiple alternatives
– (Rather than evaluating a single project)
• Why?
– Desirability depends on both
• IRR
and
• size of initial investment
30
Example
• Consider two alternatives:
– Invest $1 at an IRR of 100%
– Invest $1,000,000 at an IRR of 20%
• Which investment would you prefer?
31
Example
• Consider two alternatives:
– Invest $1 at an IRR of 100%
– Invest $1,000,000 at an IRR of 20%
• The more expensive project has:
– Smaller IRR
but
– Larger present worth!
32
Judging proposed investments
• If you are going to pick only one alternativefrom several,
– Need to compare them against each other!
• (based on differences in cost)
– not only against the base rate of return i*
• Need to evaluate each incrementalinvestment to see if it is worthwhile
33
CFS AnalysisWe have two CFS’s.
1. Number them CFS1 and CFS2, with CFS1 having the largest year 0cost (in absolute value).
2. Compute CFS = CFS1 – CFS2. (It’s year 0 entry must be negative.)3. Find the IRR for CFS, say IRR .4. If IRR MARR, choose CFS1. If not, choose CFS2.
Example: there are two cash flows: (-20,28) and (-10,15). MARR = 6%.
1. CFS1= (-20,28), CFS2= (-10,15)
2. CFS = CFS1-CFS2 =(-10,13)
3. IRR = 30%.
4. IRR > MARR => we choose CFS1 = (-20,28).
34
Why we use ΔIRR in IRR analysis
Years01
A-1015
B-2028
B-A-1013
ΔIRRB-A 30% MARR < ΔIRRB-A Select B
MARR=6%
IRR 50% 40%
NPV 3.92 6.05 Select B
Select A
Although the rate of return of A is higher than B, B got $8 return fromthe $20 investment and A only got $5 return from $10 investment.
Project B: you put $20 in project B to get a return $8.Project A: you put $10 in project A (and $10 in your pocket) to get a
return $5.
35
Example:
n B1 B2 B2-B10 -$3,000 -$12,000 -$9,000
1 1,350 4,200 2,850
2 1,800 6,225 4,425
3 1,500 6,330 4,830
IRR 25% 17.43%
MARR=10%
0i,3),$4,830(P/F
i,2),$4,425(P/Fi,1),$2,850(P/F$9,000
Solve and obtain i*B2-B1= 15% (simple investment)
Since IRRB2-B1 > MARR, we select B2
Alternatively could have measured for B1 and B2 the NPW at MARR and accepted thelargest NPW in excess of zero.
36
NPW
Interest Rate,%
0
i*B2-
B1=15%
Select B2
Select B1
PW(i)B2 > PW(i)B1
B2
B1
NPW Profiles
37
Example
• Compare options A and B:
A: First cost = $1420
– Annual benefit = $256/year for 40 years
– Rate of return = 18%
B: First cost = $1684
– Annual benefit = $300/year for 40 years
– Rate of return = 17.8%
• You can only do one of these!
38
Example
• Option B has:
– Slightly lower rate of return,
• but
– Higher initial investment
• Present worth of benefit may be greaterthan option A!
39
Example
• Need to evaluate the incremental investmentto see if it is worthwhile:
– Delta first cost = $1684 - 1420 = $264
– Delta annual benefit = $300 - 256 = $44
(for 40 years)
– Rate of return = 16.6%
• Is option B worthwhile?
– (Depends on i*)
40
Example
• Option A has IRR 18%, first cost $1420
– (B - A) has IRR 16.6%, first cost $264
• If i* = 15%, then:
– Option A is worthwhile
– The delta for option B is also worthwhile
• If i* = 17%, then:
– Option A is worthwhile, but not B
41
Example
• Option A has IRR 18%
– (B - A) has IRR 16.6%
• If i* = 20%, then:
– Neither option A nor option B is good
42
Example
• Option A has IRR 18%
– (B - A) has IRR 16.6%
• If i* = 20%, then:
– Neither option A nor option B is good
Investment Classification
Simple Investment
• Def: Initial cash flowsare negative, and onlyone sign change occursin the net cash flowsseries.
• Example: -$100, $250,$300 (-, +, +)
• ROR: A unique ROR
Nonsimple Investment
• Def: Initial cash flowsare negative, but morethan one sign changes inthe remaining cash flowseries.
• Example: -$100, $300, -$120 (-, +, -)
• ROR: A possibility ofmultiple RORs
Period (N)
Project A Project B ProjectC
0 -$1,000 -$1,000 +$1,000
1 -500 3,900 -450
2 800 -5,030 -450
3 1,500 2,145 -450
4 2,000
Project A is a simple investment.Project B is a nonsimple investment.Project C is a simple borrowing.
Example 7.6 Multiple Rates of Return Problem
• Find the rate(s) of return:
2
$2,300 $1,320( ) $1,000
1 (1 )
0
PW ii i
$1,000
$2,300
$1,320
L et T h en ,
S o lv in g fo r yie ld s ,
o r
S o lv in g fo r yie ld s
o r 2 0 %
xi
P W ii i
x x
x
x x
i
i
1
1
0 0 03 0 0
1
3 2 0
1
0 0 0 3 0 0 3 2 0
0
1 0 1 1 1 0 1 2
1 0 %
2
2
.
( ) $ 1,$ 2 ,
( )
$ 1,
( )
$ 1, $ 2 , $ 1,
/ /
PW Plot for a Nonsimple Investment with MultipleRates of Return