TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 1 GIO DC HNG PHC S : 01 H v tn hc sinh:.................................................................... S bo danh................................................................................. THI TH I HC 2012 Mn: VT L; KHI A Thi gian lm bi: 90 pht, khng k thi gian pht Cho bit: hng s Plng h = 6,625.10-34 J.s; ln in tch nguyn t e = 1,6.10-19 C; tc nh sng trong chn khng c = 3.108 m/s; 1u = 931,5 MeV/c2. Cu 1: Khi t mt in p xoay chiu vo hai u mch gm in tr thun R mc ni tip vi mt t in C th biu thc dng in c dng: 1 0i I cos( t ) (A)6t= e+ . Mc ni tip thm vo mch in cun dy thun cm L ri mc vo in p xoay chiu ni trn th biu thc dng in c dng: 2 0i I cos( t ) (A)3t= e . Biu thc in p hai u mch c dng: A: 0u U cos( t ) (V).12t= e+ B: 0u U cos( t ) (V).4t= e+C: 0u U cos( t ) (V).12t= e D: 0u U cos( t ) (V).4t= eCu 2: Mt vt dao ng iu ha vi phng trnh x = 5 cos( 6tt +t3 ) cm. Hy xc nh vn tc trung bnh ca vt trong mt chu k dao ng? A:60 cm/sB: 20 cm/sC: 5 cm/sD: 0 cm/s Cu 3: To ra sng dng trn mt si dy c u B c nh, ngun sng c phng trnh x = 2cos( et + ) cm. Bc sng trn si dy l 30 cm. Gi M l mt im trnsi dy dao ng vi bin A = 2 cm. Hy xc nh khong cch BM nh nht? A: 3,75 cmB: 15 cmC: 2,5 cmD: 12,5 cm Cu 4: Mt my bin p; cun s cp c N 1vng; cun th cp N 2vng. c mc vo mng in 100V. Nu gim s vng dy ca cun s cp i 100 vng th hiu in th cun th cp l 400V. Nu tng s vng dy cun s cp thm 200 vng th hiu in th cun th cp 100V. Hy xc nh hiu in th cun th cp lc u? A: 100VB: 200 VC: 300VD: 400VCu 5: Mt khe F hp pht nh sng trng chiu sng hai khe F1, F2 song song vi F v cch nhau 1,2mm. Mn quan st M song song vi mt phng cha F1, F2 v cch n 2m. Cho bit bc sng nh sng nhn thy c gii hn t 380nm n 760nm. Ti im A trn mn M cch vn trng trung tm 4mm c my vn sng? Ca nhng bc x no? A:C 3 vn sng ca 1 = 380nm, 2 = 570nm v 3 = 760nm. B:C 2 vn sng ca 1 = 600nm v 2 = 480nm. C:C 3 vn sng ca 1 = 600nm, 2 = 480nm v 3 = 400nm. D:C 3 vn sng ca 1 = 380nm, 2 = 600nm v 3 = 760nm. Cu 6: Cho phn ng ht nhn: 73p Li 2 17, 3MeV + o + . Cho NA = 6,023.1023 mol-1. Tnh nng lng ta ra khi to c 1g Hli ? A: 26,04.1023MeV.B: 8,68.1023MeV.C: 34,72.1023MeV.D: 13,02.1023MeV. Cu 7: Cho A,M,B l 3 im lin tip trn mt on mch xoay chiu khng phn nhnh, bit biu thc hiu in th trn cc on AM, MB ln lt l: uAM=40cos(t+/6) (V); uBM=50cos(t - /2) (V). Xc nh hiu in th cc i gia hai im A,B? A: 60,23 (V).B: 90 (V).C: 78,1 (V).D: 45,83 (V). Cu 8: on mch RLC mc ni tip, in tr c th thay i c. Cho Zc = 144 , khi R1 = 121 v khi R2 = 36 th lch pha ca hiu in th trong mch so vi cng dng in trong hai trng hp l 1, 2 ta c : 1 + 2 = - 900 . Tnh ZL A: ZL =210 B: ZL = 150 C: p n khcD: ZL = 78 Cu 9: Trong bi kho st on mch in xoay chiu c R, L, C mc ni tip (hnh v) bng phng n dng ng h hin s a nng o in p xoay chiu, v dng phng php gin Fre-nen xc nh L, r, C v cos ca on mch. Ngi ta dng thc v compa dng c gin vct nh sau: Trong MN = 4 cm; NH = 3 cm. Qua gin trn ta xc nh c gi tr r ca cun l: A: 1,33R.B: 0,5R.C: R.D: 0,75R. Cu 10:Mt vt dao ng iu ha vi phng trnh x = A.cos( et + ) cm. Hy xc nh v tr gia tc t cc i? A: x = 0 cmB: x = - A cmC: x = A cmD: Khng phi cc p n trn Cu 11:Hai ngun sng S 1; S 2dao ng cung pha v cch nhau 8 cm. V mt pha ca S 1S 2ly thm hai im S 3S 4sao cho S 3 S 4= 4 cm v hp thnh hnh thang cn S 1S 2S 3S 4. Bit bc sng ca sng trn mt nc l = 2cm. Hi ng cao ca hnh thang ln nht lbao nhiu trn on S 3S 4c 5 im dao ng cc i. A: 62cmB: 32cmC: 22cmD: 4 cm f = 50Hz U MRNL,r PC Q P MNH TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 2 Cu 12:Chiu nh sng trng i qua lngknh c gc chit quang 30o th thy nh sng tm c gc lch cc tiu. Hy tm gc lch ca tia bit n d = 1,54; n t = 1,58. A: 16o 50B: 16,5o C: 15o 6 D: 15,6o Cu 13:Mt nh my pht in gm n t my c cng cng sut P hot ng ng thi. in sn xut ra c a ln ng dyv truyn n ni tiu th vi hiu sut truyn ti l H. Hi khi ch cnmt t my hot ng bnh thng th hiu sut truyn ti H lbao nhiu? Coi in p truyn ti, h s cng sut truyn ti v in tr ng dy khng i. A: HH'n= B: H = HC: n H 1H'n+ = D: H = n.H Cu 14:Cng thc gn ng cho bn knh ht nhn l R=R0A1/3 vi R0=1,2fecmi A l s khi. Khi lng ring ca htnhn l: A:0,26.1018kg/m3.B: 0,35.1018kg/m3.C: 0,23.1018kg/m3.D: 0,25.1018kg/m3. Cu 15:Cho on mch in xoay chiu RLCmc ni tip trong tin c in dung thay i c bit in p hai u on mch lu = 200 2 cos100t(V) khi C = C1 = 2,5.10-5 F v C = C2 = 5.10-5 F th mch in c cng cng sut P=200W. Cm khng v in tr thun ca on mch l A: ZL=300 ;R=200B: ZL=200 ;R=200C: ZL=300 ;R=100D: ZL=100 ;R=100 Cu 16: Dung dch Fluorxin hp th nh sng c bc sng 0,49m v pht ra nh sng c bc sng 0,52m. ngi ta gi hiu sut ca s pht quang l t s gia nng lng nh sng pht quang v nng lng nh sng hp th. Bit hiu sut ca s pht quang ca dung dch Fluorxin l 75%. S phn trm ca phtn b hp th dn n s pht quang ca dung dch l A: 82,7%B: 79,6%C: 75,0% D: 66,8% Cu 17:on mch ni tip gm 3 phn t: in tr thun R, cun cm thun L v t in C mc vo mng in xoay chiu c tn s f1th cm khng l 36 O v dung khng l 144 O. Nu mng in c tn s f2 = 120 Hz th cng dng in cng pha vi in p hai u on mch. Gi tr f1 l A: 240 Hz.B: 60 Hz.C: 30 Hz.D: 480 Hz. Cu 18:Mt toa xe trt khng ma st trn mt ng dc xung di, gc nghing ca dc so vi mt phng nm ngang l = 300. Treo ln trn toa xe mt con lc n gm dy treo chiu di = 1 m ni vi mt qu cu nh. Trong thi gian xe trt xung, kch thch cho con lc dao ng iu ho vi bin gc nh. B qua ma st, ly g = 10 m/s2. Chu k dao ng ca con lc l A: 2,135 s.B: 1,849 s.C: 2,294 s.D: 1,721 s. Cu 19:Mc on mchgmcun dy thuncm ni tip vimt in tr thunvo ngun inxoay chiu th h s cng sutca mch bng 0,5. Nu ch gim t cm ca cun dy i 3 ln th khi h s cng sut ca mch s bng A: 32.B: 1.C: 12.D: 35. Cu 20:Mt vt dao ng iu ha vi phng trnh x = Acos( et ). Hy xc nh t s gia tc trung bnh v vn tc trung bnhkhi vt i c 3T4 u tin? A: 1B: 3C:2D: v cng ln Cu 21:Ngi ta a mt con lc n t mt t ln mt ni c cao 5 km. Hi di ca n phi thay i nh th no chu k dao ng khng thay i( R = 6400Km) A: l= 0,997lB: l= 0,998lC: l= 0,996lD: l= 0,995l Cu 22:Chiu chm sng gm 3 nh sng n sc vng, lam, chm vo lng knh c gc chit quang 45o theo phng vung gc vi mt bn AB. Bit chit sut ca tia vng vi cht lm lng knh l2 . Xc nh s bc x n sc c th l ra khi mt bn kia ca lng knh. A: 0B: 1C: 2D: 3 Cu 23:Mt qu cu c lm bng kim loi c gii hn quang in 0,5 m, bn kinh 10cm c chiu sng bng nh sng t ngoi cbc sng 0,3 m. ( Th nghim c thc hin trong khng kh) Cho k = 9,109 Nm2 C2 . Hy xc nh in tch cc i m qu cu c th tch c? A: 18,4pCB: 1,84pCC: 184pCD: Thiu d kin tnh Cu 24:Ht nhnPo21084 phng xov bin i thnh ht nhn ch bn. Ban u trong mu Po cha mt lng om (g). B qua nng lng ca photon gama. Khi lng ht nhn con to thnh tnh theo omsau bn chu k bn r l ? A: om 92 , 0 B: om 06 , 0 C: om 98 , 0 D: om 12 , 0Cu 25:Lc t = 0 u O ca dy cao su cng thng nm ngang bt u dao dng i ln vi bin 1,5 cm, chu k T= 2s. Hai im gn nhau nht trn dy dao ng cng pha l 6cm. Tnh thi im u tin im M cch O 6 cm ln n im cao nht. Coi bin khng i A: t = 2,5sB: t = 1sC: t = 2sC: t = 0,75s Cu 26:Dng in trong mch LC l tng c dng i = 0,02cos(2000tt) (A). Thi gian ngn nht k t lc ban u, dng in c ln bng dng in hiu dng l A: 4108sB: 3104sC: 3108sD: 2108s Cu 27:Trong cc pht biu sau v th gii v m, pht biu no cha ng? A: Sao Dim Vng c t chc thin vn th gii loi khi danh sch cc hnh tinh trong h mt tri nm 2006. B: Thin h cha h mt tri c tn l sng Ngn TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 3 C: Kh quyn ca mt trng ch yu cha cc loi kh khng ph hp cho s sng v vy n nay ngi ta vn cha pht hin c s sng trn mt trng D: Ch Sun trong t Sunday ( ch nht) c ly ra t The Sunv c ngha l ngy mt tri. Cu 28:Chomch in RLCmc nitip, c rL= 0,R lbin tr. tvo hai uonmchinpxoaychiu cbiu thcu= 120 2 cos120 t t(V). Bit rng ng vi hai gi tr ca bin tr R=R1 = 18Ov R = R2 = 32 Oth cng sut tiu th P trn on mch nh nhau. Cng sut P ca on mchnhn gi tr no sau y? A: 576WB: 282WC: 288WD: 144W Cu 29:Mt vt c khi lng ngh m o. khi chuyn ng vi vn tc v = 0,8c th khi lng ca n l bao nhiu? A: khng i B: 1,25m o C: 1,66m o D: 0,6m o

Cu 30:Nu quan nim nh sng ch c tnh cht sng th khng th gii thch c hin tng no di y? A: Khc x nh sng.B: Giao thoa nh sng.C: Quang in.D: Phn x nh sng. Cu 31:Trong th nghim Ing v giao thoa nh sng, khong cch gia hai khe l a=1,5mm, khong cch t hai khe n mn l D=1,5m v ngun sng pht hai bc x c bc sng 1=480nm v 2=640nm. Kch thc vng giao thoa trn mn l p=2cm (chnh gia vng giao thoa l vn sng trung tm) S vn sng quan st c trn mn lA: 54. B: 72.C: 61. D: 51.Cu 32:Mch in gm ba phn t1 1 1R , L , Cc tn s cng hng 1ev mch in gm ba phn t 2 2 2R , L , Cc tn s cng hng 2e(1 2e= e ). Mc ni tip hai mch vi nhau th tn s cng hng ca mch s lA: 1 22 . e = e e B: 2 21 1 2 21 2L L.L Le+ ee =+C: 1 2. e= e e D: 2 21 1 2 21 2L L.C Ce+ ee =+ Cu 33:Mtmch dao nggm mt t in c in dung 1000pF v mt cuncm c tcm 10F, v mt in tr 1 . Phi cung cp mt cng sut bng bao nhiu duy tr dao ng ca n, khi hiu in th cc i hai u t in l U 0 =2(V)? Hy chn kt qu ng trong cc kt qu sau: A: P = 0,001WB: P = 0,01WC: P = 0,0001WD: P = 0,00001W Cu 34:Mt con lc l xo dao ngtt dn trn mt phng nm ngang vi cc thng s nh sau:m = 0,1kg, V max = 1m/s, = 0,05. Tnh ln vn tc ca vtkhi vt i c 10cm. A. 0,95cm/sB: 0,3cm/sC: 0,95m/sD: 0,3m/s Cu 35:Mt vt thc hin ng thi hai dao ng iu ha: x 1= A 1.cos( et) cm; x 2= 2,53 cos( et + 2 ) v ngi ta thu c bin ca dao ngtng hp l 2,5 cm. Bit A 1t gi tr cc i, hy xc nh 2? A: Khng xc nh cB:t6 radC:2t3 radD:5t6 rad Cu 36:Thc hin giao thoa sng c trn mt nc vi hai ngun cng pha s 1; s 2 cch nhau 12 cm. Bit bc sngca sng trn mt ncl = 3cm. Trn ng trung trc ca hai ngun c mt im M, M cch trung im I ca hai ngun 8cm. Hi trn on MI c bao nhiu im dao ng cng pha vi hai ngun? A: 4 imB: 2 im C: 6 imD: 3 im Cu 37:Cho hvt nh hnh v: M = 2kg; m= 0,5 kg; K = 100 N/m; g = 10m/s2 ; h s mast ngh gia vt M v m l 0,5. Nng lng cc i ca h trn vt m khng b vng ra ngoi? K M m A: 0,55425JB. 0,78125JC: 0,12455 JD: 0,345J. Cu 38:C 3 ngun m c tn s 20Hz, 40Hz v 60Hz khi tng hp chng li thnh mt ngun m th tn s l: A: 60Hz.B: 120Hz.C: 40Hz.D: 20Hz. Cu 39:Chn cu ng. Chiu di ng so cng ln th m pht raA: Cng caoB: Cng trm C: Cng toD: Cng nh Cu 40:dao ng c L = 10 mH, c C = 10 pF ang dao ng. Lc t = 0 cng tc thi ca mch c gi tr cc i v bng 31,6 mA. Biu thc cng dng in trong mch l: A:q = 10-9 cos(10 6 tt) (C)B: 10-6 cos(10 6 t t +t2 ) (C) C: q = 10-8 cos (10 6 tt - t2 ) (C)D:10-6 cos (10 6 tt - t2 ) (C)Cu 41:Pht biu no sau y l sai khi ni v in t trng? A:in trng v t trng l hai mt th hin khc nhau ca mt loi trng duy nht gi l in t t trng B:Nam chm vnh cu l mt trng hp ngoi l ch c t trng C:in trng bin thin no cng sinh ra t trng bin thin v ngc li D:Khng th c in trng v t trng tn ti c lp Cu 42:Ti im M trn mn c vn sng bc 10. Dch mn i so vi v tr c 10 cm th cng ti M c vn ti th 10 k t vn sng trung tm. Khong cch t mt phng cha hai khe n mn trc khi dch chuyn l? A: D = 1,2mB: D = 1,9mC: D = 1,5mD: D = 1m Cu 43:Mt ngun sng n sc = 0,6m chiu vo mt mt phng cha hai khe h S1, S2, hp, song song, cch nhau 1mm v cch u ngun sng. t mt mn nh song song v cch mt phng cha hai khe 1m. Nu khng t bn thu tinh m y vo khong gia khe v mn mt cht lng c chit sut n', ngi ta thy khong cch gia hai vn sng lin tip bng 0,45mm. Tnh chit sut n' ca cht lng ? A:1,5 B: 1,33C: 1,4 D: 1,6TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 4 Cu 44:Catt ca t bo quang in chn khng l mt tm kim loi phng c gii hn quang in l o = 0,6 m . Chiu vo catt nh sng c bc sng = 0,5m. Ant cng l tm lim loi phng cch catt 1cm. Gia chng c mt hiu inth 10V. Tm bn knh ln nht trn b mt ant c quang electron p ti. A: R = 4,06 mmB: R = 4,06 cmC: R = 8,1 mm D: R = 6,2 cmCu 45:Trong quangph hidro, khi e chuyn t qu o L v K s pht ra photon c bc sng o.Gi B l bc sng ca tia lam trong dy Banme. Hy xc nh B? A. 5,4 o B: 4 o C: 4,5 o D: 6 o

Cu 46: Khi chiu ln lt hai bc x in t c bc sng 1 v 2 vi 2 = 2 1 vo mt tm kim loi th t s ng nng ban u cc i ca quang electron bt ra khi kim loi l 9. Gii hn quang in ca kim loi l o.Mi quan h gia bc sng 1 v gii hn quang in o l? A: 1 = 35 0 B: 1 = 57 o C: = 516 o D: 716 o

Cu 47:Nguyn t 3613S. Tm khi lng nguyn t ca lu hunh theo n v u? Bit m p = 1,00728u; m n = 1,00866u; m e = 5,486.10-4 u. A: 36 uB: 36,29382uC: 36,3009518uD: p n khc Cu 48:Ti thi im t ot s gia lng cht cn li v lng cht phng x l 17 . Bit chu k bn r ca cht trn l 12 nm. Hi sau bao nhiu nm th t s trn l 131 . A:20 nmB: 27,3 nmC: 36,8 nmD: 24 nm Cu 49:Mt mi nhn S chm vo mt nc dao ng iu ho vi tn s f = 40Hz. Ngi ta thy rng hai im A v B trn mt nc cng nm trn phng truynsng cchnhau mt khong a = 20cm lun dao ng ngc pha nhau. Bit tc truyn sng nm trong khong t 3m/s n 5m/s. Tc l: A: 3,5m/sB: 4,2m/sC: 5m/sD: 3,2m/s Cu 50:Trong cc ht sau ht no khng phi l ht quc A: Ht duyn dngB: Ht yC: Ht xungD: Ht mi GIO DC HNG PHC S : 02 H v tn hc sinh:.................................................................... S bo danh................................................................................. THI TH I HC 2012 Mn: VT L; KHI A Thi gian lm bi: 90 pht, khng k thi gian pht Cho bit: hng s Plng h = 6,625.10-34 J.s; ln in tch nguyn t e = 1,6.10-19 C; tc nh sng trong chn khng c = 3.108 m/s; 1u = 931,5 MeV/c2. Cu 1: Mt vt dao ng iu ho, khong thi gian gia hai ln lin tip vt qua v tr cn bng l 0,5s; qung ng vt i c trong 2s l 32cm. Ti thi im t=1,5s vt qua li x 2 3cm =theo chiu dng. Phng trnh dao ng ca vt l: A:x 8cos( t )cm3t= t B: 5x 4cos(2 t )cm6t= t+ C:x 8cos( t )cm6t= t+ D:x 4cos(2 t )cm6t= tCu 2: Vt dao ng iu ha, bit thi gian ngn nht vt i t v tr cn bng n v tr c ng nng bng 3 ln th nng l 0,1s. Tc trung bnh ca vt trong na chu k l:A: 2,5A3.B: 5A3.C: 10A3.D: 20A3. Cu 3: Cho hai dao ng iu ha cng phng cng tn s : x1=acos(100t+) (cm;s); x2=6sin(100t+3t) (cm;s). Dao ng tng hp x = x1 + x2 = 63cos(100t) (cm;s). Gi tr ca a v l : A: 6cm ; -/3 radB: 6cm ; /6 radC: 6cm; /3 radD: 6 3 cm ; 2/3 rad Cu 4: Trong mt khong thi giant A , mt con lc l xo thc hin c 10 dao ng ton phn. Gim bt khi lng m ca vt cn mt na v tng cng ca l xo ln gp i th trong khong thi giant Acon lc l xo mi thc hin c bao nhiu dao ng ton phn? A: 15 dao ng.B: 5 dao ng. C: 20 dao ng.D: Mt s dao ng khc. Cu 5: Mt con lc n c dy treo dil = 0,4m v khi lng vt nng l m = 200g. Ly g =10m/s2; b qua ma st. Ko con lc dy treo lch gco0 = 600 so vi phng thng ng ri bung nh. Lc lccng ca dy treo bng 4N th vn tc cu vt l: A: v =2 m/s.B: v = 2 2 m/s.C: v = 5m/s.D: v = 2m/s . Cu 6: iu no sau y l ng khi ni v c nng ca mt vt dao ng iu ha A.Bin thin tun hon theo thi gian vi chu k bng mt na chu k dao ng ca vt: B. Tng gp i khi bin dao ng ca vt tng gp i. C.Bng ng nng ca vt khi vt ti v tr cn bng.D.Bin thin tun hon theo thi gian vi vchu k bng chu k dao ng ca vt. TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 5 Cu 7: th no sau y th hin ng s thay i ca gia tc a theo li x ca mt vt dao ng iu ho vi bin A? Cu 8: Hai dao ng iu ho cng phng, cng tn s1 1x A cos( .t )6t= e cm v 2 2x A cos( .t ) = et cm c phng trnh dao ng tng hp l x = 9cos(et+) cm. bin A2 c gi tr cc i th A1 c gi tr A: 18 3 cm.B: 7cmC: 15 3 cmD: 9 3 cm Cu 9: Mt vt c khi lng m dao ng iu ha vi phng trnhx Acos t6t | |= e+ |\ .. ng nng ca vt bin thin theo thi gian c biu thc l A: 2 2d1W m A 1 sin 2 t4 3 t ( | |= e + e+ |(\ . B: 2 2 2d1W m A cos t2 6t | |= e e+ |\ . C: 2 2 2d1W m A sin 2 t2 3t | |= e e+ |\ .D: 2 2d1W m A 1 cos 2 t4 3 t ( | |= e e+ |(\ . Cu 10:Khi ni v mt vt dao ng iu ha c bin A v chu k T, vi mc thi gian (t = 0) l lc vt v tr ng nng bng th nng vi tc ang tng, pht biu no sau y l sai? A: Sau thi gian l T8, vt i c qung ng bngA 22.B: Sau thi gian l T4, vt i c qung ng bng A. C: Sau thi gian l T, vt i c qung ng bng 4A.D: Sau thi gian l T2, vt i c qung ng bng 2A. Cu 11:iu no sau y ng khi ni v sng m? A:Tp m l m c tn s khng xc nh B:Nhng vt liu nh bng, nhung, xp truyn m tt C:Vn tc truyn m tng theo th t mi trng: rn, lng, kh D:Nhc m l m do cc nhc c pht ra Cu 12:Tc truyn sng c hc ph thuc vo yu t no ? A: Tn s sng.B: Bn cht ca mi trng truyn sng. C: Bin ca sng.D: Bc sng. Cu 13:Trong th nghim giao thoa sng trn mt nc hai ngun kt hp A, B dao ng cng pha vi tn s 10Hz. Tc truyn sng trn mt nc l 20cm/s. Hai im M, N trn mt nc c MA=15cm, MB=20cm, NA=32cm, NB=24,5cm. S ng dao ng cc i gia M v N l: A: 4 ng.B: 7 ng.C: 5 ngD: 6 ng Cu 14:Cng sut m thanh cc i ca mt my nghe nhc gia nh l 10W. Cho rng c truyn trn khong cch 1m, nng lng m b gim 5 % so vi ln u do s hp th ca mi trng truyn m.Bit I0 = 10-12 W/m2, Nu m to ht c th mc cng m khong cch 6 m l A: 102 dBB: 107 dBC: 98 dB D: 89 dB Cu 15:Mt ngun m ng hng pht ra t O. Gi A v B l hai im nm trn cng mt phng truyn v cng mt pha so vi O. Mc cng m ti A l 50dB, ti B l 30dB. Tnh mc cng m ti trung im M ca AB. Coi mi trng khng hp th m. A: 34,6dB.B: 35,2dB.C: 37,2dB.D: 38,5dB. Cu 16:Mt sng ngang c m t bi phng trnh 0cos 2 ( )xy y ft t= trong x,y c o bng cm, v t o bng s. Vn tc dao ng cc i ca mi phn t mi trng gp 4 ln vn tc sng nu. A: 04y t = B: 02 y t = C: 0y t = D: 02y t =Cu 17:Biu thccain tch, trongmch dao ngLC l tng,l 7 42 10 cos(2 10 . q . . t)= (C) .Khi) C ( 10 q7 =th dng in trong mch l: A:). mA ( 3 . 3 B:). mA ( 3 C: 2(mA).D:). mA ( 3 . 2Cu 18:c im no trong s cc c im sau khng phi l c im chung ca sng c hc v sng in t: A. Mang nng lng. B. L sng ngang. C. B nhiu x khi gp vt cn. D. Truyn c trong chn khng. A B CD a -A 0 +A x a 0 x -A+A a -A0 +Ax a +A -A0x TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 6 Cu 19:Trong mt mch dao ng LC khng c in tr thun, c dao ng in t t do (dao ng ring). Hiu in th cc i gia hai bn t v cng dng in cc i qua mch ln lt l U0 v I0. Ti thi im cng dng in trong mch c gi tr 0I2 th ln hiu in th gia hai bn t in l A: 03U .4B: 03U .2C: 01U .2D: 03U .4 Cu 20:Mt mch dao ng gm t in c in dung C = 40 nF v cun cm c t cm L = 2 H, in tr thun r = 0,01 O. Np cho t in mt in tch ban u Q0 = 2 C. duy tr dao ng ca mch th phi cung cp cho mch mt cng sut l A: 0,25 WB: 0,5 WC: 1 WD: 2 W Cu 21:Mt n ng c mc vo mng in xoay chiu tn s f = 50(Hz), U = 220(V). Bit rng n ch sng khi hiu in th gia hai cc ca n t gi tr u > 155(V). Trong mt chu k thi gian n sng l: A: 1100(s)B: 2100(s)C: 4300(s)D: 5100(s) Cu 22:Mt mch in xoay chiu gm cc linh kin l tng R, L, C mc ni tip. Tn s gc ring ca mch l e0, in tr R c th thay i. Hi cn phi t vo mch mt in p xoay chiu c gi tr hiu dng khng i, c tn s gc e bng bao nhiu in p hiu dng URL khng ph thuc vo R? A: e = 02eB: e = e0.C: e = e0 2D: e = 2e0 Cu 23:Dng in xoay chiu c cng i 2cos(100 t)(A) = tchy qua mt on mch in. S ln dng in c ln 1(A) trong 1(s) l A: 200 lnB: 400 lnC: 100 lnD: 50 ln Cu 24:Mt on mch in gm mt it l tng mc ni tip vi mt in trR 50 = O. t vo hai u mch in p xoay chiu u 200 2cos(100 t)(V) = t . Nhit lng ta ra trn on mch trong thi gian 30 pht l A: 720(kJ)B: 360(kJ)C: 1440(kJ)D: 480(kJ) Cu 25:Mt on mch in xoay chiu mc theo th t gm: on AM l cun cm thun, on MN l in tr, on NB l t in. t vo hai u AB mt in p xoay chiu th o c ANU 200(V) = , MBU 150(V) = ng thi uAN lch pha /2 so vi uMB. Dng in chy qua mch li 2cos(100 t)(A) = t . Cng sut tiu th ca on mch l A: 100(W)B: 120(W)C: 120 2(W) D: 240(W) Cu 26:Mt my bin p c t s vng dy s cp v th cp bng 10. My c mc vo in p xoay chiu c gi tr hiu dng 220V, tn s 50Hz. Hai u cun th cp c ni vi ti l mt in tr R, khi dng in chy qua cun th cp c cng 5(A). Coi h s cng sut mch th cp v s cp ca my u bng 1, my c hiu sut 95% th cng dng in chy qua cun s cp xp x bng A: 0,53(A)B: 0,35(A)C: 0,95(A)D: 0,50(A) Cu 27: Cng sut ca dng in xoay chiu trn on mch RLC ni tip khng ph thuc vo A: t s gia in tr thun v tng tr ca mch. B: lch pha gia dng in v hiu in th gia hai bn t. C: cng hiu dng ca dng in qua mch. D: hiu in th hiu dng gia hai u on mch. Cu 28:Ngi ta truyn ti in nng t A n B. A dng mt my tng th v B dng mt my h th, dy dn t A n B c in tr 40O. Cng dng in trn dy l 50A. Cng sut hao ph trn dy bng 5% cng sut tiu th B v hiu in th hai u cun th cp ca my h th l 200V. Bit dng in v hiu in th lun cng pha v b qua hao ph trn cc my bin th. T s bin i ca my h th l: A : 0,005.B: 0,05.C: 0,01.D: 0,004. Cu 29:Mch in xoay chiu RLC mc ni tip, vi R = 10O, cm khng ZL = 10O, dung khng ZC = 5O ng vi tn s f. Khi f thay i n f th trong mch c hin tng cng hng in. Hi t l no sau y l ng? A:2 f= fB: f = 0,5fC: f= 4fD: f=2 f Cu 30:Dng in xoay chiu chy qua mt on mch c biu thc c biu thc cng l ( )0i = I cos t -/2 , vi I0 > 0. Tnh t lc t = 0(s), in lng chuyn qua tit din thng ca dy dn ca on mch trong thi gian bng na chu k ca dng in l:A: 0.I 2.B: 0.C: 0.I 2. D: 02I . Cu 31:Chiu mt chm tia sng trng hp ti mt bn ca lng knh c gc chit quang A = 60. Bit chit sut ca lng knh i vi nh sng tm l 1,54. Gc lch cc tiu ca tia mu tm bng : A: 51,3. B: 40,71.C: 30,43. D: 49,46.Cu 32:Tia hng ngoi l mt bc x c bn cht l sng in t c kh nng A: m xuyn mnhB: Ion ha khng kh mnh C: Kch thch mt s cht pht quangD: Giao thoa v nhiu x Cu 33:Trong th nghim I - ng v giao thoa nh sng, hai khe S1, S2 cch nhau 1mm, khong cch t mt phng cha hai khe ti mn quan st bng 2m. Chiu sng hai khe S1, S2 bng hai bc x n sc c bc sng 1= 0,72m v 2 , th thy vn sng bc 3 ca bc x 2trng vi vn sng bc 2 ca bc x 1 . Khong vn i2 ng vi bc x 2c gi tr TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 7 A: 1,54mm.B: 1,44mm.C: 0,288mm.D: 0,96mm. Cu 34:Chia tia sng n sc mu lc vo lng knh c gc chit quang5o th thy tia l ra c gc lch cc tiu. Xc nh gc ti ca tia lc l bao nhiu. Bitn l = 1,55. A: 3o B: 4o 15C: 3o 52D: 3,45 rad Cu 35:Thc hin th nghim giao thoa bng khe Y-ng, khong cch hai khe bng 1,2mm khong cch t hai khe n mn bng 1,8m, ngunsngcbcsng0,75 m tcchmn2,8m.DchchuynngunsngStheophngsongsongvihaikhemtony =1,5mm. Hai im M,N c ta ln lt l 4mmv 8,8mmv nm cng mt pha vn trung tm v ngun S di chuyn v pha ngc hng vi MN. S vn sng v s vn ti trong on MN sau khi dch chuyn ngun l A: 4 vn ti, 5 vn sng.B: 4 vn sng, 4 vn tiC: 5 vn sng, 5 vn tiD: 4 vn sng, 5 vn ti Cu 36: Trong th nghim Y- ng v giao thoa nh sng. Ngun S c chiu ng thi bi 3 bc x c bc sng ln lt 1 = 0,48m ; 2 = 0,54m ; 3 = 0,72m. Ba bc x trn cho vn trng gn vn trung tm nht ti vn sng bc my ca bc x 2 ? A: 27B: 12C: 8D: 18 Cu 37:Chn pht biu ng v mu nguyn t Bo: A: Trng thi dng l trng thi m nng lng ca nguyn t khng thay i c B: Nng lng ng vi cc qu o dng t l thun vi bnh phng cc s nguyn lin tip. C: Vch c bc sng di nht trong dy Banme c th nm trong vng hng ngoi. D: Qu o dng c bn knh t l thun vi bnh phng cc s nguyn lin tip. Cu 38:T bo quang in c hai cc phng cch nhau d = 1cm, gii hn quang in l 0 cho UAK = 4,55V. Chiu vo tm cattmttiasngnscc 02 = ccquanglctronrivoanttrnmtmttrnbnknhR=1cm.Bcsng0 nhn gi tr: A: 1,092mB: 2,345mC: 3,022mD: 3,05m Cu 39:Bit cng thot electron ca litium l 2,39eV. Bc x in t no c thnh phn in trng bin thin theo qui lut di y s gy ra c hin tng quang in i vi litium? A: E = E0.cos(2.1015 t) ( t tnh bng giy).B: E = E0.cos(9.1014t) ( t tnh bng giy). C: E = E0.cos(5.1014t) ( t tnh bng giy).D: E = E0.cos(10.1014t) ( t tnh bng giy). Cu 40:Laze l my khuych i nh sng da trn hin tngA: Quang pht quangB: Quang dnC: Quang in ngoiD: Pht x cm ng Cu 41:Pht biu no sau y l khng ng? A: Dy Banme nm trong vng t ngoi. B: Dy Banme nm trong vng nh sng nhn thy. C: Dy Banme nm trong vng hng ngoi. D: Dy Banme nm mt phn trong vng nh sng nhn thy v mt phn trong vng t ngoi. Cu 42:S pht sng ca ngun sng no di y l s pht quang? A: Bng n xe my. B: Hn than hng.C: n LEDD: Ngi sao bng. Cu 43:U23892 sau nhiu ln phng x o v |- bin thnhPb20682. Cho bit chu k bn r ca qu trnh bin i ny l T. Gi s ban u c mt mu urani khng c ch. thi im hin ti, c 10 nguyn t urani trong mu c 5 nguyn t ch. Tui ca mu cht urani l A: 0,514TB: 0,585T C: 1,58TD: 0,482TCu 44:Chn cu ng. A: Ht nhn cng bn khi ht khi cng ln. B: Trong ht nhn s proton lun lun bng s ntron. C: Khi lng ca proton nh hn khi lng ca ntron.D: Khi lng ca ht nhn bng tng khi lng ca cc nuclon.Cu 45:Nguyn t 3613S. Tm khi lng ht nhn ca lu hunh theo n v u? Bit m p = 1,00728u; m n = 1,00866u; m e = 5,486.10-4 u. A: 36 uB: 36,29382uC: 36,3009518uD: p n khcCu 46:Xesi Cs13455 l cht phng x |-, c chu k bn r T = 2 nm. Thi gian 99% lng cht phng x b bin mt l A: 5,3 nmB: 11,92 nmC: 13,29 nmD: 15,2 nm Cu 47:Chn cu tr li ng. Cho phn ng ht nhn sau: 2 2 3 11 1 2 03, 25 D D He n MeV + + + Bit ht khi ca 21H l 0, 0024Dm u A = v 21 931 / u MeV c = . Nng lng lin ca ht nhn 32He l: A: 77,188MeV.B: 7,7188eV.C: 771,88MeV.D: 7,7188MeV Cu 48:i lng no sau y khng phi l c trng ca ht s cp? A: Nng lng nghB: Kch thcC: S lng t SpinD: Thi gian sng trung bnh Cu 49:Trong h mt tri hnh tinh no c qu o chuyn ng gn Tri t nht? A: Kim TinhB: Mc TinhC: Thy TinhD: Ha Tinh Cu 50:Khi ni v photon, pht biu no sau y l sai A:Photon lun chuyn ng vi tc rt ln trong khng kh B:ng lng ca photon lun bng khng C:Mi photon c mt nng lng xc nhD:Tc ca cc photon trong chn khng l khng i TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 8 GIO DC HNG PHC S : 03 H v tn hc sinh:.................................................................... S bo danh................................................................................. THI TH I HC 2012 Mn: VT L; KHI A Thi gian lm bi: 90 pht, khng k thi gian pht Cho bit: hng s Plng h = 6,625.10-34 J.s; ln in tch nguyn t e = 1,6.10-19 C; tc nh sng trong chn khng c = 3.108 m/s; 1u = 931,5 MeV/c2. Cu 1: Vo cng mt thi im no hai dng in xoay chiu) cos(1 0 1 e+ = t I iv) cos( 22 0 2 e+ = t I i c cng gi tr tc thi 20I nhng mt dng in ang tng v mt dng in ang gim. Hai dng in lch pha nhau A: 6tB: 4tC: 127tD: 2t Cu 2: Mt sng dng hnh thnh trn si dy n hi c biu thccm t x u )210 cos( )4sin( 4ttt =trong xtnh bng m, thi gian t tnh bng giy. Vn tc truyn sng trn dy l: A: 40cm/sB: 20cm/sC: 40m/sD: 20m/s Cu 3:Mt ngi chi n ghita khi bm trn dy dy c chiu di 0,24 m v 0,2 m s pht ra m c bn c tn s tng ng bng vi tn s ca ha m bc n v n + 1 pht ra khi khng bm trn dy. Chiu di ca dy n khi khng bm l A: 0,8 m.B: 1,6 m.C: 1,2 m.D: 1 m. Cu 4:TrnmtchtlngtihaiimAvBcchnhau8,5cmchaingundaongtheophngthngngvicc phng trnh: uA = 3cos(8t) (cm) ; uB = 2 cos(8t + ) (cm). Tc truyn sng trn mt cht lng v = 6 cm/s. S im dao ng vi bin 5 cm trn on AB l A: 13.B: 10.C: 11.D: 12. Cu 5:t in p xoay chiu vo hai u on mch gm in tr thun R, in dung C v cun cm thun c t cm L thay i c. iu chnh t cm L in p hiu dng hai u cun cm t cc i. Khi A: 2 2 2 2C R LU U U U = + + . B: 2 2 2 2C R LU U U U = + + .C: 2 2 2 2L R CU U U U = + + . D: 2 2 2 2R C LU U U U = + + . Cu 6:m do cc nhc c pht ra ng vi A: mt ph tn s xc nh gm m c bn f0 v cc ho m 2f0; 3f0 B: mt di tn s bin thin lin tc. C: mt ph tn s xc nh gm m c bn f0 v cc ho m.... f ; f3020 D: mt tn s xc nh. Cu 7:MtmchdaongLCltnggmcundythuncmctcmkhngthayivmttinchaibn phng t song song cch nhaumt khong c nh. pht ra sng in t c tn s dao ng ring tng 2 ln th din tch i din ca bn t phi A: tng 4 ln.B: gim2ln.C: gim 4 ln.D: tng 2 ln Cu 8:Hai ngun sng kt hp S1 v S2 cng pha, cch nhau 3 m, pht ra hai sng c bc sng 1 m. Mt im A nm trn ng thngvunggc vi S1S2, i qua S1vcch S1 mt on . Gi tr ln nht ca phn t vt cht ti A dao ng vi bin cc i l A: 1,5 m.B: 1 m.C: 2 m.D: 4 m. Cu 9: Trong mch dao ng LC l tng c dao ng in t ring vi tn s gc 104 rad/s. in tch cc i trn t in l 10-9 C. Khi cng dng in trong mch bng 5.10-6 A th in tch trn t l A: 8,7.10-9 C.B: 104.10 C.C: 102.10 C.D: 105 3.10 C. Cu 10:Cho mt h l xo nh hnh v 1, m = 100g, k1 = 100N/m,k2= 150N/m. Khi vt v tr cn bng tng dn cahai l xo l 5cm. Ko vt ti v tr l xo 1 c chiu di t nhin, sau th vt dao ng iu ho. Bin v tn s gc ca dao ng l (b qua mi ma st). A: 25cm;50 Rad/s.B: 3cm; 30Rad/s.C: 3cm;50 Rad/s.D: 5cm;30Rad/s. Cu 11:t con lc vo trong in trngE hng theo phng ngang v c ln E = 104V/m. Bit khi lng ca qu cu l 20g, qu cu c tch in q = -2 3. 10-5, chiu di dy treo con lc l 1m, ly g = 10m/s2 v 210 t ~ . Chu k dao ng biu kin ca con lc: TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 9 A: 10 stB: 10 stC: 5 stD: 20 st Cu 12:Mt nh sng n sc c bc sng 0,6m trong chn khng v 0,4m trong mt cht lng trong sut. Chit sut ca cht lng i vi nh sng l A: 1,2.B:3 C: 1,5.D:2Cu 13:Trong th nghim giao thoa Ing thc hin ng thi hai bc x n sc c bc sng vi khong vn trn mn nh thu c ln lt l i1 = 0,48 mm v i2 = 0,64 mm. Xt ti hai im A, B trn mn cng pha vn trung tm cch nhau mt khong 6,72mm. Ti A c hai h vn u cho vn sng, cn ti B h i1 cho vn sng h i2 cho vn ti. S vch sng trn on AB l A: 22B: 26C: 20D: 24 Cu 14:Sng truyn vi tc 5m/s gia hai im O v M nm trn cng mt phng truyn sng. Bit phng trnh sng ti O l uO = acos(5tt - t/6) (cm) v ti M l: uM = acos(5tt + t/3) (cm). Xc nh chiu truyn sng v khong cch OM? A: t O n M, OM = 0,25m.B: t O n M, OM = 0,5m.C. t M n O, OM = 0,5m.D: t M n O, OM = 0,25m. Cu 15:Trong mch dao ng LC l tng, nu in tch cc i trn t in l Q0 v cng dng in cc i trong mch l I0 th chu k dao ng in t trong mch l A: T = 2tLC. B: 002QTI .C: 002ITQ .D: T = 2tQ0I0. Cu 16:t in p xoay chiu u = 120 2 cos100t (V) vo hai u mt on mch RLC khng phn nhnh. Bit on mch c in tr R = 60 O, cun cm thun c t cm L =Ht 54. Khi cho in dung ca t in tng dn t 0 th in p hiu dng hai u t in s c mt gi tr cc i bng A: 240V.B: 200V.C: 420V.D: 200 2 V. Cu 17:Cho mch RLC mc ni tip, c in dung C bin i. t vo hai u on mch hiu in th xoay chiu n nh. iu chnh C UCmax. Tm UCmax? A: UCmax = RR Z U2 2L +.B: UCmax = RR Z U2 2L .C: UCmax = RR Z U2 2C +.D: UCmax = L2 2LZR Z U +. Cu 18:Trong mt mch dao ng LC khng c in tr thun, c dao ng in t t do (dao ng ring). Hiu in th cc i gia hai bn t v cng dng in cc i qua mch ln lt l U0 v I0. Ti thi im cng dng in trong mch c gi tr 0I2 th ln hiu in th gia hai bn t in l A: 03U .4B: 03U .2C: 01U .2D: 03U .4 Cu 19:Tm nhn xt sai v sng c A: Qu trnh truyn sng l qu trnh lan truyn trng thi dao ng. B: Sng m truyn c trong mi trng cht lng, cht kh v cht rn. C: Trn mt phng truyn sng khong cch ga hai im dao ng vung pha bng s nguyn ln mt phn t bc sng. D: Khong cch gia hai im dao ng cng pha trn cng phng truyn sng bng s nguyn ln bc sng. Cu 20:Chn p n khng chnh xc khi ni v my pht in xoay chiu ba pha c roto l phn cm. A: Phn cm l phn to ra t trngB: Phn ng l phn to ra sut in ng C: Khi roto quay s to ra t trng quayD: Phi dng ti b gp a in ra ngoi Cu 21:Chn pht biu ng khi ni v cc loi quang ph A: Quang ph lin tc ph thuc vo bn cht ca vt B: Quang ph vch pht x ph thuc vo nhit C: Quang ph hp th thu c l di mu lin tc t n tm. D: Quang ph vch pht x ca cc nguyn t khc nhau th khc nhau. Cu 22:Mt ng h qu lc t trn mt thang my th chy chm. Hi thang my phi chuyn ng nh th no? Chn p n ng.A: Chuyn ng thng u B: Nhanh dn u ln trn C: Nhanh dn u xung di D: Chm dn u xung di Cu 23:Trong th nghim I.ng v giao thoa nh sng, bit ngun im S pht ra ng thi 3 bc x: Mu tm c bc sng 1, mu c bc sng 2, mu lc c bc sng 3, khong vn tng ng cho ba mu trn l i1, i2, i3 ta c A. i2 > i3 > i1B: i1> i3 > i2C: i2 > i1 > i3D: i3 > i1 > i2 Cu 24:Cho mt con lc n dao ng trong mi trng khng kh. Ko con lc lch khi phng thng ng mt gc 0,1 rad ri th nh. Bit lc cn ca khng kh tc dng ln con lc l khng i v bng 0,001 ln trng lng ca vt. Coi bin gim u trong tng chu k. S ln con lc con lc i qua v tr cn bng t lc bt u dao ng n lc dng li l A: 25B: 50C: 100D: 200TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 10 Cu 25:Cho mt vt dao ng iu ho vi bin A = 10 cm, tn s f = 2Hz. Tc trung bnh nh nht m vt t c trong thi gian 1/6 s lA: 30 cm/sB: 30 3cm/sC: 60 3cm/sD: 60 cm/s Cu 26:on mch xoay chiu RLC ni tip. Cc gi tr R, L, C khng i v mch ang c tnh cm khng, nu tng tn s ca dng in th A: ban u cng sut ca mch tng, sau gim.B: cng sut tiu th ca mch tng. C: c th xy ra hin tng cng hng.D: cng sut tiu th ca mch gim. Cu 27:t in p xoay chiu c tr hiu dng U = 150 V vo hai u on mch R, L, C ni tip c L thay i. iu chnh L ULmax, khi UC = 200 V. Gi tr ULmax l A: 370,3 V.B: 170,5 V.C: 280,3 V.D: 296,1 V. Cu 28:Cho mch chn sng cng hng gm cun cm v mt t xoay. Khi in dung ca t l C1 th mch thu c sng c bc sng 1= 10 m, khi t c in dung C2 th mch thu c sng c bc sng 2 =20 m. Khi t in c in dung C3= C1 + 2C2 th mch thu uc sng c bc sng 3bng A: 15 m.B: 14,1 m.C: 30 m.D: 22,2 m. Cu 29:Hai mi nhn S1. S2 cch nhau 9 cm, gn u mt cu rung c tn s f = 100Hz c t cho chm nh vo mt mt cht lng. Vn tc truyn sng trn mt cht lng l v = 0,8 m/s. G nh cho cn rung th 2 im S1, S2 dao ng theo phng thng ng vi phng trnh dng: u= acos2t ft. im M trn mt cht lng cch u v dao ng cng pha S1 , S2gn S1 , S2 nht c phng trnh dao ng. A: uM = acos( 200t t + 20t ).B: uM = 2acos( 200t t - 12t ). C: uM = 2acos( 200t t - 10t ).D: uM = acos( 200t t). Cu 30:Mt sng m truyn t khng kh vo nc th A: Tn s v bc sng u thay i.B: Tn s khng thay i, cn bc sng thay i. C: Tn s v bc sng u khng thay i.D: Tn s thay i, cn bc sng khng thay i. Cu 31:Trong mt khong thi giant A , mt con lc l xo thc hin c 10 dao ng ton phn. Gim bt khi lng m ca vt cn mt na v tng cng ca l xo ln gp i th trong khong thi giant Acon lc l xo mi thc hin c bao nhiu dao ng ton phn? A: 15 dao ng.B: 5 dao ng. C: 20 dao ng.D: Mt s dao ng khc. Cu 32:Khi mc dng c P vo in p xoay chiu c gi tr hiu dng bng 220 V th cng dng in c gi tr hiu dng bng 5,5 A v tr pha6 so vi in p gia hai u on mch. Khi mc dng c Q vo in p xoay chiu trn th cng dng in trong mch cng c gi tr hiu dng bng 5,5 A nhng sm pha 2 so vi in p. Khi t in p trn vo hai u on mch cha P v Q mc ni tip th cng dng in c gi tr hiu dng l A: 11 2 A v tr pha 3 so vi in p.B: 5,5 A v sm pha 6 so vi in p. C: 11 2 A v sm pha 6 so vi in p.D: 5,5 A v cng pha so vi in p. Cu 33:Mch chn sng ca my thu v tuyn gm mt cun dy thun cm c t cm L = 21081tmH v mt t xoay. T xoay bin thin theo gc xoay C =30 + o (pF). thu c sng in t c bc sng 15m th gc xoay ca t phi l: A: 36,50.B: 38,50.C: 35,50.D: 37,50. Cu 34:tvo hai u on mch R, L, C c C thay iv cun dythuncm cmt inp) V ( t 100 cos . 2 160 u t = . iu chnh C UCmax = 200V th URL bng: A: 102VB: 100VC: 120VD: 160V Cu 35:Mt vt dao ng iu ha vi bin 6cm. Qung ng nh nht m vt i c trong mt giy l 18cm. Thi im kt thc qung ng th vt c li A: 2 cm.B: 3 cm hoc -3 cm.C: 6 cm hoc -6 cm.D: bng 0. Cu 36:Mt sng c truyn trn trc Ox vi ngun sng l O theo phng trnh2 os( )6 12 4u c t xt t t= +cm, trong x tnh bng mt (m), t tnh bng giy (s). Sng truyn theo A: Chiu dng trc Ox vi tc 2 cm/sB: Chiu dng trc Ox vi tc 2 m/s C: Chiu m trc Ox vi tc 2 m/sD: Chiu m trc Ox vi tc 2 cm/s Cu 37: Khi ni v dao ng cng bc pht biu no di y l ng. A: Dao ng cng bc c bin khng i v tn s bng tn s ca ngoi lc cng bc. B: Dao ng ca con lc ng h l dao ng cng bc. C: Bin dao ng cng bc ch ph thuc bin ngoi lc cng bc. D: Dao ng cng bc c tn s nh hn tn s ngoi lc cng bc. TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 11 Cu 38: Mtvt dao ng iu havi tn s 1 Hz, bin 10 cm. Tc trung bnh ln nht m vt dao ng c c khi i ht on ng 30 cm l A: 40 cm/s.B: 80 cm/s.C: 45 cm/s.D: 22,5 cm/s. Cu 39: t in p xoay chiu c in p hiu dng U khng i vo hai u on mch RLC khng phn nhnh. iu chnh in dung ca t in in p hiu dng hai u t in t cc ivc gi tr bng 2U. in p hiu dng hai u on mch RL l A: CU21.B: CU23.C: C3U .D: CU43. Cu 40:Khung dao ng vi t in C v cun dy c t cm L ang dao ng t do. Ngi ta o c in tch cc i trn mt bn t l Q0 = 106(J) v dng in cc i trong khung I0 = 10(A). Bc sng in t cng hng vi khung c gi tr: A: 18(m)B: 188,5(m)C: 188(m)D: 160(m) Cu 41:Trong th nghim giao thoa ca Ing, khong cch hai khe S1, S2: a = 2mm, khong cch t hai khe ti mn D = 2m. Ngun sng dng trong th nghim gm hai bc x 1 = 0,4m v 2 = 0,5m. Vi b rng ca trng giao thoa L = 13mm, ngi ta quan st thy s vn sng c bc sng 1 v 2 trng nhau l: A: 9 vn.B: 3 vn.C: 7 vn.D: 5 vn. Cu 42: o chu k ca cht phng x, ngi ta dng mt my m xung. trong t1 gi u tin my m c n1 xung; trong t2 = 2t1 gi tip theo my m c 2 1964n n =xung. Chu k bn r T c g tr l : A: 13tT = B: 12tT = C: 14tT = D: 16tT =Cu 43:Htoc ng nng3, 51 K MeVo=bay n p vo ht nhn nhm ng yn gy raphn ngX P Al + +30152713o . Gi s hai ht sinh ra c cng ng nng. Tm vn tc ca ht nhn photpho v ht nhn X. Bit rng phn ng thu vo nng lng 4,176.10-13J. C th ly gn ng khi lng ca cc ht sinh ra theo s khi mp = 30u v mX = 1u. A: Vp = 7,1.105m/s; VX = 3,9.105m/s.B: Vp = 7,1.106m/s; VX = 3,9.106m/s. C: Vp = 1,7.106m/s; VX = 9,3.106m/s.D: Vp = 1,7.105m/s; VX = 9,3.105m/s. Cu 44:Mt mu cht phng x, sau thi gian t1 cn 20% ht nhn cha b phn r. n thi im t2 = t1+100 (s)s ht nhncha b phn r ch cn 5%. Chu k bn r ca ng v phng x l: A: 400(s)B: 50(s)C: 300(s)D: 25(s) Cu 45:Bn mt ht proton vo ht nhtLi73ang ng yn. Phn ng to ra 2 ht ging nhau c cng tc v hp vi phng chuyn ng ca proton gc 600. Ly khi lng cc ht nhn theo n v u bng s khi. T s vn tc ca ht Proton v ht X l : A: 2B: 4C: 0,25D: 0,5 Cu 46:Cht phng x Rai c chu k bn r l 1600 nm. Thi gian t s ht nhn ca Rai gim e ln c gi l tui sng trung bnh ca ht nhn Rai (e l c s t nhin). Tnh thi gian sng trung bnh ca ht nhn Rai? A: 1600 nm.B: 3200 nm.C: 2308 nm.D: 11600 nm Cu 47: Bn mt ht proton c khi lng mp vo ht nhn73Ling yn. Phn ng to ra hai ht nhn X ging ht nhau c khi lng mX bay ra c cng ln vn tc v cng hp vi phng ban u ca proton mt gc 450. T s ln vn tc ca ht X (v) v ht proton (v) l: A: pXmv '2v m= B: pXmv '2v m= C: pXmv'v m= D: pXmm 2v'v=Cu 48:Sao khng pht sng, cu to bi mt loi cht c khi lng ringcckln, htc phtn nhsng v khng cho thot ra ngoi, l mt A: thin h.B: quaza.C: l en.D: punxa. Cu 49:Sao no di y khng phi l hnh tinh ca h mt tri A: Sao ThyB: Tri tC: Sao bngD: Sao Ha Cu 50:Kt lun no sau y sai khi ni v l en? A:L en l mt thin th c pht hin nh nh quan st qua knh thin vn B:L en c trng hp dn rt ln C:Thin thc gi l l en khng pht x ra bt k mt loi sng in t no D:Ngi ta pht hin ra l en nh mt tia X pht ra khi l en ht mt thin th gn GIO DC HNG PHC S :04 H v tn hc sinh:.................................................................... S bo danh................................................................................. THI TH I HC 2012 Mn: VT L; KHI A Thi gian lm bi: 90 pht, khng k thi gian pht TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 12 Cho bit: hng s Plng h = 6,625.10-34 J.s; ln in tch nguyn t e = 1,6.10-19 C; tc nh sng trong chn khng c = 3.108 m/s; 1u = 931,5 MeV/c2. Cu 1: Con lc n dao ng iu ho vi bin gc 0010 o < . Tc ln nht ca qu nng trong qutrnh dao ng l: A: 02gl o B:02 gl o C: 0gl o D: 03gl oCu 2: Cho mt vt dao ng iu ho vi phng trnh: x = 2cos(20tt + t/2) cm. Thi im u tin m vt c gia tc bng 4t2 m/s2 v ang chuyn ng li gn v tr cn bng lA: 1/120 sB: 5/120 sC: 7/120 sD: 11/120 s Cu 3: Mt con lc l xo gm vt m treo vo l xo th ti v tr cn bng l xo dn mt on 4cm. Chiu di qu o ca vt trong qu trnh dao ng l 16 cm. Chn mc thi gian ti v tr vt c ng nng bng th nngv khi vt ang i v pha v tr cn bng theo chiu dng ca trc ta . Biu thc dao ng ca con lc l? A:x 16cos(5 t )cm4t= tB:x 8cos(5 t )cm4t= t C: 3x 16cos(5 t )cm4t= t D: 3x 8cos(5 t )cm4t= tCu 4: Mt vt dao ng iu ha vi chu k T = 2 2ts. Ti v tr c li x =3 cm vt c vn tc v = 4 2 cm. Tnh bin dao ng ca vt ? A:3 cmB: 2 cmC: 1 cm.D: 4 cm. Cu 5: Mt con lc l xo treo thng ng, u di gn vt khi lng 0,5 kg. Phng trnh dao ng ca vt l:x 10cos t = t cm. Ly g = 10 m/s2. Lc tc dng vo im treo l xo ti thi im 1t s3= l: A: 0,25 NB: 5,25 NC: 1,5 ND: 0 Cu 6: Mt con lc n treo hn bi nh bng kim loi khi lng m = 0,01kg mang in tch q = 2.10-7 C. Khi cha c in trng con lc dao ng b vi chu k T = 2 s. a con lc vo trong in trng uE c phng thng ng hng xung di, E = 104 V/m. Ly g = 10 m/s2. Chu k dao ng mi ca con lc l A: 2,02 s.B: 1,01 s.C: 1,98 s.D: 0,99 s. Cu 7: Con lc l xo (m1 ; k) c tn s 1f ; con lc (m2 ; k) c tn s 2f . Con lc| |1 2( ); m m k +c tn sftnh bi biu thc no ? A: 1 21 2..f ff f +B: Mt biu thc khcC: 1 22 21 2..f ff f +D: 2 21 2. f f +Cu 8: Trong qu trnh dao ng iu ha ca con lc n. Nhn nh no sau y l sai? A: Khi qu nng im gii hn, lc cng dy treo c c ln ca nh hn trng lng ca vt B: ln ca lc cng dy treo con lc lun ln hn trng lng vt. C: Chu k dao ng ca con lc khng ph thuc vo bin dao ng ca n. D: Khi khi gc hp bi phng dy treo con lc v phng thng ng gim, tc ca qu nng s tng. Cu 9: Mtvtdaong iuho,khivtc li x1=4cm thvn tc 1v 40 3 cm/ s = t ;khivtcli 2x 4 2cm =th vn tc 2v 40 2 cm/ s = t . ng nng v th nng bin thin vi chu k A: 0,1 sB: 0,8 sC: 0,2 sD: 0,4 s Cu 10:Trn mt nc c 2 ngun sng ging ht nhau A v B cch nhau mt khong AB = 24cm. Cc sng c cng bc sng = 2,5cm. Hai im M v N trn mt nc cng cch u trung im ca on AB mt on 16 cm v cng cch u 2 ngun sng v A v B. S im trn on MN dao ng cng pha vi 2 ngun l: A: 7B: 8C: 9.D: 6 Cu 11:C 3 ngun m c tn s 20Hz, 40Hz v 60Hz khi tng hp chng li thnh mt ngun m th tn s l: A: 60Hz.B: 120Hz.C: 40Hz.D: 20Hz. Cu 12:Hai ngun sng c AB cch nhau dao ng chm nh trn mt cht lng, cng tn s 100Hz, cng pha theo phng vung gc vi mt cht lng. Vn tc truyn sng 20m/s.S im khng dao ng trn on AB =1m lA: 10 im B: 20 imC: 5 imD: 11 im Cu 13:Sng dc ( sng c ) truyn c trong cc mi trng no? A: Ch trong cht rn v trn b mt cht lng. B: Truyn c trong cht rn v cht lng v cht kh. C: Truyn c trong cht rn, cht lng, cht kh v c chn khng.D: Khng truyn c trong cht rn. Cu 14:Ct khng kh trong ng thy tinh c cao l c th thay i c nh iu khin mc nc trong ng. t mt m thoa k trn ming ng thy tinh. Khi m thoa dao ng, n pht ra mt m c bn, ta thy trong ct khng kh c mt sng dng n nh. Khi cao thch hp ca ct khng kh c tr s nh nht l o = 13cm, ngi ta nghe thy m to nht, bit rng u A h ca ct khng kh l mt bng sng, cn u B kn l mt nt sng, vn tc truyn m l 340m/s. Tn s ca m do m thoa pht ra c th nhn gi tr trong cc gi tr sau? A: f = 563,8HzB: f = 658HzC: f = 653,8HzD: f = 365,8Hz TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 13 Cu 15:Mt sngc hcc truyn theo phng Ox vi vn tc v=20 cm/s. Gi s khi sng truyn i bin khng thay i. Ti ngunO dao ng c phng trnh: uo=2cos4tt (mm; s). Trong t o bng giy. Ti thi im t1 li ti im O l u= 3 mm v ang gim. Lc im M cch O mt on d=40 cm thi im ( t1+0,25) ss c li l : A: - 3 mm.B: 1 mm.C:3 mm.D: -1 mm. Cu 16:Mt mch dao ng gm cun dy thun cm L v t in C: Nu gi I0 l dng in cc i trong mch th h thc lin h gia in tch cc i trn bn t in Q0 v I0 l A:Q0 =CLtI0 .B: Q0 =LCI0C: Q0 =CL tI0 D: Q0 = 1LCI0 . Cu 17:Trong mch dao ng in t l tng c dao ng in t iu ho vi tn s gce = 5.106 rad/s. Khi in tch tc thi ca t in l 8q 3.10=th dng in tc thi trong mch i = 0,05A: in tch ln nht ca t in c gi tr A: 3,2.10-8 CB: 3,0.10-8 CC: 2,0.10-8 CD: 1,8.10-8 C Cu 18:Mch dao ng gm cun dy thun cm c h s t cm L = 5 mH v t in c in dung C = 12,5 F. T in c tch in n hiu in n in tch 0,6.10-4 C, sau cho t in phng trong mch.Chn gc thi gian l lc t in bt u phng in. Phng trnh hiu in th gia bn t in l: A: u C =4,8cos( 4000t + t/2) VB: u C =4,8cos( 4000t ) V C: u C =0,6.10-4 cos( 4000t ) VD: u C =0,6.10-4 cos( 400t + t/2) V Cu 19:Trong cc thit b in t no sau y trng hp no c c my pht v my thu v tuyn: A: My vi tnh. B: in thoi bn hu tuyn. C: in thoi di ng. D: Dng cu iu khin tivi t xa. Cu 20:Mt mch dao ng LC l tng gm cun dy thun cm c t cm khng thay i v mt t in c hai bn phng t song song cch nhau mt khong c nh. pht ra sng in t c tn s dao ng ring tng 2 ln th din tch i din ca bn t phi A: tng 4 ln.B: gim2ln.C: gim 4 ln.D: tng 2 ln. Cu 21:Mt ng ti in ba pha c 4 dy a, b, c, d. Mt bng n khi mc vo gia hai dy a v b hoc gia hai dy b v c hoc gia hai dy b v d th sng bnh thng. Nu dng bng n mc vo gia hai dy a v c th A:n sng bnh thng B: n sng yu hn bnh thng C: Bng n sng qu mc bnh thng (c th b chy) D: n khng sng. Cu 22:on mch gm cun dy c li st v mt bng n c in tr thun R mc ni tip vo mt in p xoay chiu. n ang sng bnh thng, nu rt dn li st ra khi ng dy th sng ca n: A: Tng ln.C: Gim i. B: C th tng hoc gim ty theo in tr n.D: Khng i. Cu 23:Mtngckhngngbbaphaccccundyphncmu hnh saovo inxoaychiubaphacinp dy l 380(V). ng c c cng sut c l 1,5(kW) v hiu sut l 75%, h s cng sut ca ng c l 0,85 th cng dng in chy qua ng c xp x A: 12,7 (A)B: 3,57 (A)C: 6,2 (A)D: 10,7 (A) Cu 24:Mt on mch gm cun dy c in tr thun r=10Ov t cm L=(110t)H mc ni tip vi in tr thun R=20Ov t in C=3104tF. t vo hai u on mch mt hiu in th u=180 2 cos(100 t t) (V). lch pha ca hiu in th gia haiu cun dy v hai u t in l A: -4tB: 34t C: 34t D: 4t Cu 25:Mt bng n ng c mc vo mng in xoay chiu tn s f = 50 Hz. Bit rng n ch sng khi in p gia hai cc ca n t gi tru>110 2 V. Trong 2 s thi gian n sng l 4/3s. Xc nh in p hiu dng hai u bng n l A:220VB: 220 3 A C: 220 2 AD: 200 A Cu 26:MchinxoaychiuRLCcRthayicmcvohiuinthxoaychiu200cos100 u tV t = .Bitkhi 50 R = O v200 R = O th cng sut mch in u bng nhau v bng P. Gi tr ca P l: A: 80WB: 400WC: 160WD: 100W Cu 27:Khi mc dng c P vo in p xoay chiu c gi tr hiu dng bng 220 V th cng dng in c gi tr hiu dng bng 5,5 A v tr pha6 so vi in p gia hai u on mch. Khi mc dng c Q vo in p xoay chiu trn th cng dng in trong mch cng c gi tr hiu dng bng 5,5 A nhng sm pha 2 so vi in p. Khi t in p trn vo hai u on mch cha P v Q mc ni tip th cng dng in c gi tr hiu dng l A: 11 2 Av tr pha 3 so vi in p.B: 5,5 A v sm pha 6 so vi in p. C: 11 2 A v sm pha 6 so vi in p.D: 5,5 A v cng pha so vi in p. TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 14 Cu 28:Chn cu sai. A: My pht in c cng sut ln th rto l cc nam chm in B: MP m rto l phn cm th khng cn c b gp.C: Trong MP, cc cun dy ca phn cm v phn ng u c qun trn li thp D: Vi my pht in xoay chiu mt pha th nam chm phi l nam chm in Cu 29:Mt cun dy c in tr thunO = 3 100 Rv t cm L = 3/H mc ni tip vi mt on mch X c tng tr ZX ri mc vo in p c xoay chiu c gi tr hiu dng 120V, tn s 50Hz th thy dng in qua mch in c cng hiu dng bng 0,3A v chm pha 300 so vi in p gia hai u mch. Cng sut tiu th trn on mch X bng: A:0W 4 B:W 3 9 C:W 3 18 D:W 30Cu 30:Mt my pht in xoay chiu c 8 cp cc, phn ng gm 22 cun dy mc ni tip. T thng cc i do phn cm sinh ra i qua mi cun dy c gi tr cc i 110tWb. Rto quay vi vn tc 375 vng/pht. Sut in ng cc i do my c th pht ra l: A: 220 VB: 220 2VC: 110 2 VD: 110 V Cu 31:Mt b nc su 1,2m. Mt chm nh sng mt tri chiu vo mt nc di gc ti i sao cho sini = 0,8. Chit sut ca nc i vi nh sng l 1,331 v i vi nh sng tm l 1,343. B rng ca di quang ph di y b l :A: 2,5cm.B: 1,25cm. C: 2cm.D: 1,5cm. Cu 32:Chn cusai. S phn tch chm nh sng trng i qua lng knh thnh cc tia sng mu l do A: Vn tc ca cc tia mu trong lng knh khc nhauB: Nng lng ca cc tia mu khc nhau C: Tn s sng ca cc tia mu khc nhauD: Bc sng ca cc tia mu khc nhau Cu 33:nh sng n sc c tn s 5.1014 Hz truyn trong chn khng vi bc sng 600 nm. Chit sut tuyt i ca mt mi trng trong sut ng vi nh sng ny l 1,52. Tn s ca nh sng trn khi truyn trong mi trng trong sut nyA: nh hn 5.1014 Hz cn bc sng bng 600 nm. B: ln hn 5.1014 Hz cn bc sng nh hn 600 nm.C: vn bng 5.1014 Hz cn bc sng nh hn 600 nm. D: vn bng 5.1014 Hz cn bc sng ln hn 600 nm.Cu 34:Hai khe Y- ng cch nhau a = 1mm, khong cch gia hai khe n mn l D = 3m. . t bn mng c b dy e =0,5mm, chit sut n =1,5 sau khe S1 th h thng giao thoa trn mn thay i th no ? A:H thng dch chuyn ln pha S1 mt on 75mm.B: H thng dch chuyn xung pha S1 mt on 750mm. C: H thng khng thay i.D: H thng dch chuyn ln pha S1 mt on 750mm. Cu 35:Trong th nghim Ing, hai khe c chiu bng nh sng trng c bc sng 0,4m 0,75m. Khong cch gia hai khe l 0,3mm, khong cch t hai khe n mn l 2m. Tnh khong cch gia vn sng bc 3 mu v vn sng bc 3 mu tm cng mt bn so vi vn trung tm. A: x = 7mm.B: x = 9mm.C: x = 11mm. D: x = 13mm.Cu 36:Chiu ng thi ba bc x n sc c bc sng 0,4m; 0,48m v 0,6m vo hai khe ca th nghim Ing. Bit khong cch gia hai khe l 1,2mm, khong cch t hai khe ti mn l 3m. Khong cch ngn nht gia hai v tr c mu cng mu vi vn sng trung tm l: A: 12mmB: 8mmC: 24mmD: 6mm Cu 37:Trong quang ph vch ca hir (quang ph ca hir), bc sngca vch th nht trong dy Laiman ng vi s chuyn ca lectrn (lectron) t qu o Lv qu o K l0,1217 m , vch th nht ca dy Banme ngvischuyn M v L l 0, 6563 m . Bc sng ca vch quang ph th hai trong dy Laiman ng vi s chuyn M v K bng A:0, 7780 m B:0,1027 m C:0, 3890 m D: 123nm Cu 38:Tnh cht no sau y khng phi ca Tia Laze? A: B nc v thy tinh hp th mnhB: Mang nng lng ln C: nh hng caoD: C tnh n sc Cu 39:Theo thuyt lng t nh sng, pht biu no di y l sai? A: Phn t, nguyn t pht x hay hp th nh sng, cng c ngha l chng pht x hay hp th phtn. B: nh sng c to thnh bi cc ht gi l phtn. C: Nng lng ca cc phtn nh sng l nh nhau, khng ph thuc tn s ca nh sng. D: Trong chn khng, cc phtn bay dc theo tia sng vi tc c = 3.108 m/s. Cu 40:Chiu ln lt bc x n sc c bc sng vo hai tm kim loi c gii hn quang in ln lt l 0 v 20 . Cc electron bt ra vi vn tc ban u cc i ln lt l v1 v v2 vi v2= 2v1 . T s bc sng/0:A: 5/6 B: 6/7 C: 1/2 D: 8/9 Cu 41: Dung dch Fluorxin hp th nh sng c bc sng 0,49m v pht ra nh sng c bc sng 0,52m. ngi ta gi hiu sut ca s pht quang l t s gia nng lng nh sng pht quang v nng lng nh sng hp th. Bit hiu sut ca s pht quang ca dung dch Fluorxin l 75%. S phn trm ca phtn b hp th dn n s pht quang ca dung dch l Cu 42: Nng lng cc trng thi dng ca nguyn t hidro cho bi E n =-13,6n2 eV. Vi n= 1,2,3ng vi cc qu o K,L,M Bit h = 6,625.10-34 Js; c = 3.108 m/s. Nguyn t hidro ang thi c bn th nhnc mt photon c tn s f = 3,08.1015 Hz, electron s chuyn ng ra qu o dng . A: LB: MC: ND: Cu 43:Mt vt c khi lng ngh m o. khi chuyn ng vi vn tc v = 0,8c th khi lng ca n l bao nhiu? A: khng i B: 1,25m o C: 1,66m o D: 0,6m o

TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 15 Cu 44:Trong phn ng ht nhn : H21+ H31 He42 +n, nu nng lng lin kt ring ca cc ht nhnH21,H31 v He42 ln lt l a, b v c (tnh theo n v MeV) th nng lng c gii phng trong phn ng (tnh theo n v MeV) lA: a + b - cB: c - a bC: 2a+3b-4cD: 4c-2a-3b Cu 45:B sung vo phn thiu ca cu sau : Mt phn ng ht nhn ta nng lngth khi lng ca cc ht nhn trc phn ng . khi lng ca cc ht nhn sinh ra sau phn ng A: nh hn B: bng vi ( bo ton nng lng)C: ln hn D: c th nh hoc ln hn Cu 46:HtTriti(T)vDteri(D)thamgiaphnngnhithchtothnhhto vntrn.Chobithtkhicacc ht 0, 0087Tm u A = ; 0, 0024Dm u A =; 0, 0305 m uoA = ,21 931MeVuc= .Nng lng ta ra t mt phn ng l: A: 18,0614 JB:38,7296 MeVC:38,7296 JD:18,0614 MeV Cu 47:U 238 v U 235 l cht phng x c chu k bn r ln lt l T 1 = 4,5.109 nm v T 2 = 7,13.108 nm. Hin nay trong qung urani thin nhin c ln U 238v U 235 theo t l s nguyn t l 140: 1. Gi thit thi im hnh thnh tri t t l ny l 1:1. Tui tri t l: A: X = 8.109 nmB: X = 9.108 nmC: X = 6.109 nmD: X = 2.108 nm Cu 48:Chn cu ngA:Hu ht ht s cp u l cc ht bn B:Tt c mi ht s cp u khng bn C:Nhng ht s cp khng bn c thi gian sng trung bnh khong hng nm D:Nhng ht s cp khng bn(tr notron) c thi gian sng trung bnh rt ngn(mt phn ca giy) Cu 49:kt lun no sau y ng khi ni v ht v ht v phn ht trong qu trnh tng tc ca cc ht s cp, c th xy ra cc hin tngA: hy mt cp ht + phn ht c khi lng ngh khc 0 thnh cc photon hoc cng lc sinh ra cp ht + phn ht t nhng photon. B: Hy ht v sinh ra phn ht C: Hy phn ht v sinh ht D: Ch sinh phn ht Cu 50:Mt tri c khi lng khong 2.1030 kg v cng sut bc x l 3,9.1026 W. Ly c = 3.108 m/s. Sau mt t nm na so vi khi lng hin nay, khi lng Mt tri gim i A: 1,5%B: 4 %C: 0,2%D: 0,0068% GIO DC HNG PHC S : 05 H v tn hc sinh:.................................................................... S bo danh................................................................................. THI TH I HC 2012 Mn: VT L; KHI A Thi gian lm bi: 90 pht, khng k thi gian pht Cho bit: hng s Plng h = 6,625.10-34 J.s; ln in tch nguyn t e = 1,6.10-19 C; tc nh sng trong chn khng c = 3.108 m/s; 1u = 931,5 MeV/c2. Cu 1: Ti mt im O trn mt nc yn lng ngi ta gy ra mt dao ng iu ha theo phng thng ng vi bin a, tc truyn sng trnmt nc l 2(m/s). Hai im M, N trn mt ncnm trncng mt phng truyn sng cch O ln lt 80(cm) v 82(cm). Phng trnh dao ng ti N l N Nu a cos(100 t )(cm)6t= t th phng trnh dao ng A: ti M l M M7u a cos(100 t )(cm)6t= t B: ti M l M M7u a cos(100 t )(cm)6t= t+C: ti O l O247u acos(100 t )(cm)6t= t D: ti O l O245u acos(100 t )(cm)6t= t+Cu 2: Ti im O trn mt cht lng ngi ta gy ra dao ng vi phng trnh) )( 4 cos( 2 cm t u t = , tc truyn sng trn mt cht lng l 60cm/s. Gi s ti nhng im cch O mt on x th bin gim 2,5 xln. Dao ng ti M cch O mt on 25cm c biu thc l A: 5u 2.cos(4 t )cm3t= t .B: 5u 0,16.cos(4 t )cm3t= t . C: 5u 0,16.cos(4 t )cm6t= t D: 5u 2.cos(4 t )cm6t= tCu 3: Mt con lc l xogm vt m = 0,4kg v mt l xo c cng k = 40N/m.Vt ang v tr cn bng, ngi ta truyn cho n vn tc ban u 20cm/s theo chiu dng.Phng trnh dao ng ca vt nng l A: x = 2cos(10t + 2t)cm.B: x = 2sin(10t+6t) cm.C: x=2cos(10t -2t) cm .D: x = 2cos(10t) cm. TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 16 Cu 4: Hai l xo c cng l k1, k2 v mt vt nng m = 1kg. Khi mc hai l xo song song th to ra mt con lc dao ng iu ho vi 1= 10 5 rad/s, khi mc ni tip hai l xo th con lc dao ng vi2 = 2 30 rad/s. Gi tr ca k1, k2 l A: 100N/m, 200N/mB: 200N/m, 300N/mC: 100N/m, 400N/mD:200N/m,400N/m Cu 5: Mt con lc n c chiu di l = 0,249 m, qu cu nh c khi lng m = 100 g. Cho n dao ng ti ni c gia tc trng trng g = 9,8 m/s2 vi bin gc 0 = 0,07 rad trong mi trng di tc dng ca lc cn (c ln khng i) th n s dao ng tt dn c cng chu k nh khi khng c lc cn. Ly1416 , 3 = t . Bit con lc n ch dao ng cs 100 = tth ngng hn. Xc nh ln ca lc cn. A: 1,5.10-2 NB: 1,57.10-3 NC: 2.10-4 ND: 1,7.10-4 NCu 6: Pht biu no sau y l sai v s tng t gia dao ng c hc ca con lc n dao ng vi li gc nh vi dao ng in t trong mch LC? A:Lc cnmi trng ( hay ma st) lm tt dn dao ng con lc n tng t nh in tr thun lm tt dn dao ng in t trong mch ng. B: C nng con lc tng t nh nng lng in t trong mch dao ng. C: Ko con lc n ra khi cn bng ri th nh tng t nh ban u np in cho t in. D: Con lc n c th nng ln nht khi qu nng bintng t nh nng lng t trng cc i khi dng in trong mch cc i. Cu 7: Dao ng iu ha x = 4sin(2tt +t3 ) (cm). Thi gian ngn nht vt i t x = 2cm n v tr c gia tc a = -802cm/s2 l: A:524 s. B:t2,4 s.C: 2.4t s.D: 24t s. Cu 8: Mt cht im dao ng iu ha trn trc 0x xung quanh gc 0 vi bin 6(cm) v chu k 2(s). Mc tnh thi gian c chn l thi im cht im i qua li x = 3(cm) theochiu dng th khong thi gian cht im i c qung ng 249(cm) kt thi im ban u l A: 127(s)6B: 125(s)6C: 62(s)3D: 61(s)3 Cu 9: Hai dao ng iu ha (1) v (2) cng phng, cng tn s v cng bin A = 4cm. Ti mt thi im no , dao ng (1) c li x = 23cm, ang chuyn ng ngc chiu dng, cn dao ng (2) i quav tr cn bng theo chiu dng. Lc , dao ng tng hp ca hai dao ng trn c li bao nhiu v ang chuyn ng theo hng no? A: x = 8cm v chuyn ng ngc chiu dng.B: x = 0 v chuyn ng ngc chiu dng. C: x = 4 3cm v chuyn ng theo chiu dng.D: x = 2 3cm v chuyn ng theo chiu dng. Cu 10:Hai ngun kt hp cng pha trn mt nc cch nhau 38cm. Trn ng ni hai ngun, ngi ta quan st c 7 im dao ng vi bin cc i (khng k 2 ngun). Bit vn tc truyn sng trn mt nc l 60cm/s. Tn s dao ng ca ngun c th l A: 9 HzB: 7 HzC: 4 HzD: 6 Hz Cu 11:Mt si dy n hi cng ngang, ang c sng dng n nh. Trn dy, A l mt im nt, B l mt im bng gn A nht, C l trung im ca AB, vi AB = 10 cm. Bit khong thi gian ngn nht gia hai ln m li dao ng ca phn t ti B bng bin dao ng ca phn t ti C l 0,2 s. Tc truyn sng trn dy lA: 0,25 m/s. B: 0,5 m/s. C: 2 m/s. D: 1 m/s. Cu 12:Kt lun no sau y l khng ng? A: Nhc m l nhng m c tn s xc nh. Tp m l nhng m khng c tn s xc nh. B: m sc l mt c tnh sinh l ca m ph thuc vo cc c tnh vt l l tn s v bin . C: to ca m l c tnh sinh l ca m ph thuc vo mc cng v tn s m. D: cao l c tnh sinh l ca m ph thuc vo c tnh vt l tn s v nng lng m. Cu 13:Cho hai ngun sng m kt hp A, B t cch nhau 2 m dao ng cng pha nhau. Di chuyn trn on AB, ngi ta thy c 5 v tr m c to cc i. Cho bit tc truyn m trong khng kh l 350 m/s. Tn s f ca ngun m c gi tr tho mn A: 350 Hz s f T2, W1 > W2, v1 > v2D: T1 < T2, W1 < W2, v1 < v2 Cu 6: Hai vt A v B cng bt u dao ng iu ha, chu k dao ng ca vt A l TA, chu k dao ng ca vt B l TB. Bit TA = 0,125TB. Hi khi vt A thc hin c 16 dao ng th vt B thc hin c bao nhiu dao ng? A : 2B: 4 C: 128 D: 8 Cu 7: Mt con lc n c treo vo trn ca mt thang my chuyn ng thng ng ln - xung, khi thang my c gia tc khng i a th chu k ca con lc tng 20 0/0 so vi chu k dao ng ca n khi thang my ng yn, cho g = 10m/s2. Chiu v ln ca gia tc a ca thang my l A: gia tc hng xung, a = 2(m/s2).B: gia tc hng ln, a = 2(m/s2). C: gia tc hng ln, a = 3(m/s2).D: gia tc hng xung, a = 3(m/s2). Cu 8: Mt cht im c khi lng m = 50g dao ng iu ho trn on thng MN di 8cm vi tn s f = 5Hz. thi im t = 0 cht im i qua v tr cn bng theo chiu dng. Ly t2 = 10. Lc gy ra dao ng ca cht im thi im 1t = s12 c ln l A: 10 N.B: 100 N.C: 1 N.D: 0,1 N. Cu 9: Mt l xo c khi lng khng ng k c cng k = 100N/m. Mt u treo vo mt im c nh, u cn li treo mt vt nng khi lng 500g. T v tr cn bng ko vt xung di theo phng thng ng mt on 10cm ri bung cho vt dao ng iu ha Ly g = 10m/s2, khong thi gian m l xo b nn mt chu k lA:3 2ts.B: 5 2ts.C: 15 2ts.D:6 2ts. Cu 10:Con lc n gm si dy nh khng gin, mt u c nh , mt u gn vi hn bi khi lng m. Ko vt ra khi VTCB sao cho si dy hp vi phng thng ng gc 0,1 rad/ ri th nh. Trong qu trnh dao ng con lc lun chu tc dng ca lc cn c ln TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 34 bng 1/500 trng lc tc dng ln vt. Coi chu k dao ng l khng i trong qu trnh dao ng v bin dao ng gim u trong tng na chu k. S ln vt i qua VTCB k t lc th vt cho n khi vt dng hn lA: 25 B: 50C: 75D: 100 Cu 11:Mt con lc l xo thng ng dao ng iu ho vi bin 10cm. Trong qu trnh dao ng t s lc n hi cc i v cc tiu ca l xo l 133, ly g=t2m/s. Chu k dao ng ca vt l A: 1 sB: 0,8 sC: 0,5 sD: p n khc.Cu 12:iu no sau y l khng ng khi ni v s truyn ca sng c hc? A: Tn s dao ng ca sng ti mt im lun bng tn s dao ng ca ngun sng. B: Khi truyn trong mt mi trng nu tn s dao ng ca sng cng ln th tc truyn sng cng ln. C: Khi truyn trong mt mi trng th bc sng t l nghch vi tn s dao ng ca sng. D: Tn s dao ng ca mt sng khng thay i khi truyn i trong cc mi trng khc nhau. Cu 13:Ti hai im A v B trn mt cht lng c hai ngun pht sng: uA = 4.coset (cm) v uA = 2.cos(et + t/3) (cm), coi bin sng khng i khi truyn i. Tnh bin sng tng hp ti trung im ca on AB A: 6 cmB: 5,3 cmC: 0D: 4,6 cm Cu 14:Mt sng c hc lan truyn trn mt phng truyn sng. Phng trnh sng ca mt im M trn phng truyn sng l: uM = 3cost t (cm). Phng trnh sng ca mt im N trn phng truyn sng ( MN = 25 cm)l: uN = 3 cos (t t +t /4) (cm). Ta c A Sng truyn t M n N vi vn tc 2m/s. B: Sng truyn t N n M vi vn tc 2m/s. C: Sng tuyn t N n M vi vn tc 1m/s.D: Sng tuyn t M n N vi vn tc 1m/s. Cu 15:Biu thcca sng ti mt im c ta x nm trn phng truyn sng cho bi: u = 2cos( tt/5 - 2tx) (cm) trong t tnh bng s. Vo lc no li ca sng ti mt im P l 1cm th sau lc 5s li ca sng cng ti im P l; A: - 1cmB: + 1 cmC: - 2vmD: + 2cm Cu 16:Mt si dy thp AB di 41cm treo l lng u A c nh, u B t do. Kch thch dao ng cho dy nh mt nam chm in vi tn s dng in 20Hz, tc truyn sng trn dy 160cm/s. Khi xy ra hin tng sng dng trn dy xut hin s nt sng v bng sng l: A:21 nt, 21 bng.B:21 nt, 20 bng.C:11 nt, 11 bng.D:11 nt, 10 bng. Cu 17:Trn mt thong ca cht lng c hai ngun kt hp A v B cch nhau 20cm vi phng trnh dao ng: u 1 = u 2 = cos et cm. Bc sng = 8cm. Bin sng khng i. Gi I l mt im trn ng trung trc ca AB dao ng cng pha vi cc ngun A,Bv gn trung im O ca AB nht. khong cch OI o c l: A: 0B:156 cmC:125 D: 15cm Cu 18:Mch chn sng ca mt my thu v tuyn in gm mt t in c in dung 0,9nF v cun cm c t cm 30H. Mch dao ng trn c th bt c sng v tuyn thuc di A: Sng cc ngnB: Sng diC: Sng ngnD: Sng trung Cu 19:Pht biu no sau y v sng in t l khng ng? A:Tn s ca 1 sng in t l ln nht khi truyn trong chn khng. B:Sng in t c th truyn qua nhiu loi vt liu. C:Sng in t c th b phn x khi gp cc b mt.D:Tc truyn sng in t trong cc mi trng khc nhau th khc nhau. Cu 20:Chn pht biu ng khi so snh dao ng ca con lc l xo v dao ng in t trong mch LC: A: Khi lng m ca vt nng tng ng vi h s t cm L ca cun dy. B: cng k ca l xo tng ng vi in dung C ca t in. C: Gia tc a tng ng vi cng dng in i. D: Vn tc v tng ng vi in tch q. Cu 21:Trong mch dao ng LC l tng c dao ng in t ring vi tn s gc 104 rad/s. in tch cc i trn t in l 10-9 C. Khi cng dng in trong mch bng 5.10-6 A th in tch trn t l A: 8,7.10-9 C.B: 104.10 C.C: 102.10 C.D: 105 3.10 C. Cu 22:Mch dao ng ca my thu sng v tuyn in c t in vi in dung C v cun cm c t cm L, thu c sng in t c bc sng 100 m. thu c sng in t c bc sng 25 m th ngi ta phi mc ni tip vi t in ca mch dao ng trn mt t in c in dung C' bng A: 15 CB: C/15C: 16CD: C/16 Cu 23:Cho on mch xoay chiu gm bin tr R, cun dy khng thun cm c in tr r, t in C. iu chnh R cng sut trn R cln nht. Khi in p gia hai u on mch ln gp 1,5 ln in p gia hai u in tr. H s cng sut ca mch khi l: A: 0,67B: 0,75C: 0,5D: 0,71 Cu 24:t in p xoay chiu c gi tr hiu dng khng i, tn s 50Hz vo hai u on mch mc ni tip gm in tr thun R, cun cm thun c t cm L =3H.t v t in xoay (dng t phng hnh bn nguyt, in dung ca t t l thun vi gc xoay). iu chnh gc xoay n gi tr 300 v 600 th cng sut tiu th trn on mch u c gi tr bng nhau. Gi tr in dung ca tbng A: 410F8t hoc410F4t.B: 410F4t hoc 410F2t TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 35 C: 410F2t hoc410Ft.D: 410F6t hoc410F3t. Cu 25:Mch in gm ba phn t1 1 1R , L , Cc tn s cng hng 1ev mch in gm ba phn t 2 2 2R , L , Cc tn s cng hng 2e(1 2e= e ). Mc ni tip hai mch vi nhau th tn s cng hng ca mch s lA: 1 22 . e= e e B: 2 21 1 2 21 2L L.L Le+ ee=+C: 1 2. e= e e D: 2 21 1 2 21 2L L.C Ce+ ee=+ Cu 26:Mt con lc l xo c vt nng v l xo c cng k = 50 N/m dao ng theo phng thng ng vi bin 2 cm, tn s gc 10 5rad / s e= . Cho g =10m/s2. Trong mi chu k dao ng, thi gian lc n hi ca l xo c ln khng vt qu 1,5N l: A: 60 5t (s);B: 215 5t (s);C: 15 5t(s);D: 30 5t(s); Cu 27:on mch in gm in tr thun R= 50O mc ni tip vi hp X. t vo hai u on mch mt in p c dng u = U0 cos( 100t t + ) (V;s) th cng dng in trong mch sm phat /3 so vi in p. Bit hp X ch c cha mt trong cc phn t: in tr thun r, t in C, cun dy L. Phn t trong hp X l A: cun dy thun cm c 32L Ht= B: t in c 42.103.C Ft=C: in tr thun r = 50 3 D: cun dy c r = 50 3 v 32L Ht=Cu 28:Cho on mch in xoay chiu RLCmc ni tip trong tin c in dung thay i c bit in p hai u on mch lu = 200 2 cos100t(V) khi C = C1 = 2,5.10-5 F v C = C2 = 5.10-5 F th mch in c cng cng sut P=200W. Cm khng v in tr thun ca on mch l A: ZL=300 ;R=200B: ZL=200 ;R=200C: ZL=300 ;R=100D: ZL=100 ;R=100 Cu 29:Cho mch khng phn nhnh R L C. t vo hai u on mch mt hiu in th xoay chiu c tn s50Hz thu lch pha 450 so vi i. Bit C = (1/4t ).10-4F , L = 2/t H. in tr thun ca mch l: A: 200 2 OB: 200 3 OC: 160OD: 200O Cu 30:Cho mch in khng phn nhnh R L - C mc ni tip, cun dy thun cm, R = 100O, L = 1/ t H, C = 10-4/ t F. t vo hai u mch mt in p xoay chiu u = 200cos(100t t)V. Ti thi im cng sut ca mch l100W th cng sut tc thi trn cun dy v t in khi l A: 0W, 0WB: 100 3 W, 100 3 WC: 100W, 100WD: 100 3 W, -100 3 W Cu 31:Cho mch in xoay chiu RLC ni tip (cun dy thun cm), in tr thun R thay i c. in p hai umch c gi tr khng i. Khi R=R1 th , UR= U3 , UL=U, Uc=2U. Khi R=R2 th UR=U2 , in p hiu dng hai u t C lc ny bng A: U7 B: U3 C: U2 D: 2U2Cu 32:Mt khung dy quay u trong t trngB vung gc vi trc quay ca khung vi tc n = 1800 vng/ pht. Ti thi im t = 0, vct php tuynn ca mt phng khung dy hp viB mt gc 300. T thng cc i gi qua khung dy l 0,01WB Biu thc ca sut in ng cm ng xut hin trong khung l : A:e 0, 6 cos(30 t )Wb6t= t t .B: e = 0,6 cos( 60t - 3 ) WB C:e 0, 6 cos(60 t )Wb6t= t t+ .D:e 60cos(30t )Wb3t= + . Cu 33:Chiu mt chm tia sng trng song song , hp vo mt bn ca mt lng knh c gc chit quangA=50 theo phng vung gc vi mt phn gic ca gc chit quang . Chit sut ca lng knh i vi tia l nd=1,5, i vi tia tm l nt=1,54. Trn mn M t song song v cch mt phn gic trn mt on 1,5m, ta thu c di mu c b rng A: 4mm.B: 5,236mm.C: 4,236mm.D: 3mm. Cu 34:Trong th ngim Y-ng v giao thoa vi ngun nh sng n sc, h vn trn mn c khong vn i. Nu khong cch gia 2 khe cn mt na v khong cch t 2 khe n mn gp i so vi ban u th khong vn giao thoa trn mn A: khng i.B: tng ln hai ln.C: tng ln bn ln.D: gim i bn ln. Cu 35:Trong th nghim ca Y-ng v giao thoa nh sng vi ngun nh sng trng, hai khe hp cch nhau 0,5mm. Khong cch gia vn sng bc mt ca nh sng mu c bc sng di nht ( = 0,75m) v vn sng bc mt ca nh sng mu tm c bc sng ngn nht(t = 0,40m) trn mn (gi l b rng ca quang ph bc mt) lc u o c 0,55mm. Khi dch mn ra xa hai khe thm 40cm th b rng ca quang ph bc mt bng A: 0,83mm.B: 0,86mm.C: 0,87mm.D: 0,89mm. Cu 36:Khi chiu nh sng n sc t mi trng trong sut ny sang mi trng trong sut khC: Cc i lng no sau y l khng i? A: Tn s, bc sng, mu scB: Tn s, mu sc, vn tc C: Tn s, mu sc, nng lng ca phtn.D: Bc sng, vn tc, Nng lng ca phtn Cu 37: Ngun sng no sau y khi phn tch khng cho quang ph vch pht x? TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 36 A: n hi hyr.B: n hi thy ngn.C: n hi natri.D: n dy tc Cu 38:Trong th nghim giao thoa nh sng bng khe Iang. khong cch gia 2 khe kt hp l a = 1 mm, khong cch t hai khe n mn l D = 50cm. nh sng s dng gm 4 bc x c bc sng : 1 = 0,64m , 2 = 0,6m ,3 = 0,48m . Trong khong gia hai vn trng mu vi vn trung tm lin tip c bao nhiu vch sng n sc?A: 41 B: 48 C:34D: 51 Cu 39: Nng lng cc trng thi dng ca nguyn t hidro cho bi E n =-13,6n2 eV. Vi n= 1,2,3ng vi cc qu o K,L,M Bit h = 6,625.10-34 Js; c = 3.108 m/s. Nguyn t hidro ang thi c bn th nhnc mt photon c tn s f = 3,08.1015 Hz, electron s chuyn ng ra qu o dng . A: LB: MC: ND: Cu 40:Trong quang phca nguyn t hiro, ba vch u tin trong dy Lai man c bc sng1 = 121,6 nm;2 = 102,6 nm;3 = 97,3 nm. Bc sng ca hai vch u tin trong dy Ban me lA: 686,6 nm v 447,4 nm.B: 660,3 nm v 440,2 nm. C: 624,6nm v 422,5 nm.D: 656,6 nm v 486,9 nm. Cu 41:S pht x cm ng l g? A. l s pht ra phtn bi mt nguyn t. B. l s pht x ca mt nguyn t trng thi kch thch di tc dng ca mt in t trng c cng tn s. C. l s pht x ng thi ca hai nguyn t c tng tc ln nhau. D. l s pht x ca mt nguyn t trng thi kch thch, nu hp th thm mt phtn c cng tn s Cu 42:Mt nh sng pht quang c tn s 6.1014 Hz. Hi bc x c tn s no s khng gy ra c hin tng pht quang? A: 5.1014 HzB:6.1014 HzC: 6,5.1014 HzD: 6,4.1014 Hz Cu 43:Chiu vo catot ca mt t bo quang in mt bc x bc sng vi cng sut P, ta thy cng dng quang in bo ho c gi tr I. Nu tng cng sut bc x ny ln 20% th thy cng dng quang in bo ha tng 10%. Hiu sut lng t s: A: Tng 8,3%B: Gim 8,3%C: Tng 15%D: Gim 15% Cu 44:Chiu bc x c bc sng = 0,546m ln mt tm kim loi c gii hn quang in o. Dng mn chn tch ra mt chm hp cc electron quang in v cho chng bay vo t trng u theo hng vung gcvi cc ng cm ng t c B = 10-4 T. Bit bn knh cc i ca qu o cc electron l R = 23,32mm. Gii hn quang in l: A: 0,38mB: 0,52mC: 0,69mD: 0,85mCu 45:Tnh s lng phn t trong mt gam kh O2 bit nguyn t lng O l 15,99 A:188.1019B:188.1020 C: 18,8.1018 D: 188.10 24 Cu 46:Bit s Avgar l 6,02.1023/mol, khi lngmol ca uraniU92238 l 238 g/mol. S ntrn (ntron) trong 119 gam uraniU 238 lA: 8,8.1025.B: 1,2.1025.C: 4,4.1025.D: 2,2.1025.Cu 47:Cho: mC = 12,00000 u; mp = 1,00728 u; mn = 1,00867 u; 1u = 1,66058.10-27 kg; 1eV = 1,6.10-19 J ; c = 3.108 m/s. Nng lng ti thiu tch ht nhnC 126thnh cc nucln ring bit bngA: 72,7 MeV.B: 89,1 MeV.C: 44,7 MeV.D: 8,94 MeV. Cu 48:ng v 21084 Po phng x o. Chu k bn r ca Po l 138 ngy. Lc u c 1mg Po th sau 414 ngu th tch khi heli thu c iu kin chun l? A: V = 4,5.10-3 lB: V = 5,6.10-4 lC: V = 9,3.10-5 lD: 1,8.10-6 l Cu 49:Cht phng x S1 c chu k bn r T1, cht phng x S2 c c ch k bn r T2. Bit T2 =2 T1. Sau khong thi gian t = T2 th: A:Cht S1 cn li 14, cht S2 cn li 1.2B: Cht S1 cn li 12, cht S2 cn li 1.2 C:Cht S1 cn li 14, cht S2 cn li 1.4D: Cht S1 cn li 12, cht S2 cn li 1.4 Cu 50: Sp xp theo th t tng dn v bn vng ca cc ht nhn sau :5626 F ;147 N ;23892 U.Cho bit : mF = 55,927u ; mN = 13,9992u ; mU = 238,0002u ; mn = 1,0087u ; mp = 1,0073u. A:147N ;23892U ;5626F.B:5626F; 23892U; 147N C: 5626F; 147N; 23892UD: 147N ;5626F ; 23892U GIO DC HNG PHC S : 11 H v tn hc sinh:.................................................................... S bo danh................................................................................. THI TH I HC 2012 Mn: VT L; KHI A Thi gian lm bi: 90 pht, khng k thi gian pht Cho bit: hng s Plng h = 6,625.10-34 J.s; ln in tch nguyn t e = 1,6.10-19 C; tc nh sng trong chn khng c = 3.108 m/s; 1u = 931,5 MeV/c2. Cu 1: Chn pht biu sai: A: Hai dao ng iu ho cng tn s,ngc pha th li ca chng lun lun i nhau. B: Khi vt nng ca con lc l xo i t v tr bin n v tr cn bng th vect vn tc v vect gia tc lun lun cng chiu. C: Trong dao ng iu ho,khi ln ca gia tc tng th ln ca vn tc gim.D: Dao ng t do l dao ng c tn s ch ph thuc c tnh ca h,khng ph thuc cc yu t bn ngoi. Cu 2: Mt cht im ang dao ng vi phng trnh:6 os10 ( ) x c t cm t = . Tnh tc trung bnh ca cht im sau 1/4 chu k tnh t khi bt u dao ng v tc trung bnh sau nhiu chu k dao ng TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 37 A: 1,2m/s v 0B: 2m/s v 1,2m/sC: 1,2m/s v 1,2m/sD: 2m/s v0 Cu 3: Mt con lc l xo phng thng ng dao ng iu ho theo phng trnh x = 6cos(et - 2t/3) ( cm). Gc to l v tr cn bng ca vt, trong qu trnh dao ng t s gia gi tr cc i v cc tiu ca lc n hi xut hin l xo l 5/2. Ly g = t2 = 10 m/s2. Bit khi lng ca vt nng l m = 280 g. ti thi im t = 0, lc n hi ca l xo c gi tr no sau y. A: 1,2 N B: 2,2 NC: 3,2 ND: 1,6 N Cu 4: Mt con lc l xo thng ng c cng k =100N/m vvt c khi lng m = 500g. Ban u ko vt ra khi v tr cn bng mt on l 10cm ri th nh cho n dao ng. Trong qu trnh dao ng vt lun chu tc dng ca lc cn bng 0,005 ln trng lng ca n. Coi bin ca vt gim u trong tng chu k, ly g = 10m/s2. S ln vt i qua v tr cn bng l: A: 150 lnB: 50 lnC: 100 lnD: 200 ln Cu 5: Mt vt dao ng vi chu k T, bin A. tnh vn tc trung bnh trong mt chu k: A: 2 v max /tB: Ae/t C:A e/2t D: Ae/2Cu 6: Ti cng mt ni c gia tc trng trng g, hai con lc n c chiu di ln lt l l1 v l2 c chu k ln lt T1 v T2. Tnh chu k dao ng ca con lc n th 3 c chiu di bng tch ch s chiu di ca hai con lc ni trn l: A: 1 22TT gT2=tB: 12TTT= C: 1 2T T.T = D: 12T gT2 T=t Cu 7: Vn tc trong dao ng iu haA:Lun lun khng iC: t gi tr cc i khi i qua v tr cn bng B:Lun lun hng v v tr cn bng v t l vi li D: Bin i theo hm cosin theo thi gian vi chu k T2

Cu 8: Pht biu no sau y l sai khini v dao ng iu ha ca mt cht im: A:Li dao ng bin thin theo qui lut dng sin hoc cos theo thi gian. B:Khi i t v tr cn bng n v tr bin, vt chuyn ng chm dn u. C:ng nng v th nng c s chuyn ha ln nhau, nhng c nng c bo ton. D:Khi i qua v tr cn bng, cht im c vn tc cc i v gia tc cc tiu. Cu 10:Khng nh no sau y ng? A: Sng m lun l sng dc. B: Sng m lan truyn c trong c 3 mi trng rn, lng, kh. C: Sng m truyn trong khng kh l sng dc, trong cht rn l sng ngang. D: Sng m ch c tn s t 16Hz n 20KHz. Cu 11:Trn mt nc phng lng c hai ngun im dao ng S 1, S 2l f = 120Hz. Khi trn mt nc, ti vng giao S 1, S 2 ngi ta qua st thy 5 gn li v nhng gn ny chia on S 1S 2 thnh 6 on m hai on hai u ch di bng mt na cc on cn li. cho S 1 S 2 = 5 cm. Bc sng l: A: = 4cmB: = 8cmC: = 2 cmD: Kt qu khc. Cu 12:Hai gun pht sng im M, N cch nhau 10 cm dao ng ngc pha nhau, cng tn s l 20Hz cng bin l 5mm v to ra mt h vn giao thoa trn mt nc. Tc truyn sng l 0,4m/s. S cc im c bin 5mm trn ng ni hai ngun l: A: 10B: 21C: 20D: 11 Cu 13:Hai ngun kt hp S 1, S 2 cch nhau 50mm trn mt thong thy ngn dao ng ging nhau x = acos 60tt mm. Xt v mt pha ng trung trc ca S 1, S 2 thy vn bc k i qua im M c M S 1 - M S 2 = 12mm. v vn bc ( k + 3) i qua im M c M S 1 - M S 2 = 36 mm. Tm Bc sng, vn bc k l cc i hay cc tiu? A:8mm, cc tiuB: 8mm, cc iC: 24mm, cc tiuD: 24mm, cc i Cu 14:A v B l hai im nm trn cng mt phng truyn sng. Sng truyn t B n A vi tc 8m/s. Phng trnh dao ng ca A v B ln lt l6cos(20 3 / 2)Au t cm t t = v6cos(20 / 2)Bu t cm t t = . Khong cch gn nht gia A v B l A: 20cmB: 80cmC: 40cmD: 10cm Cu 15:Thc hin giao thoa sng vi hai ngun cngpha S 1S 2cch nhau 20cm . Bit vn tc truyn sng trn b mt cht lng l 40 cm/s, tn s ca ngun l f = 8Hz. Hitrn on S 1S 2 c bao nhiu im dao ng vi bin cc i nhng ngc pha vi hai ngun A: 3B:5C: 4D: 9 Cu 16:Mt mch dao ng LC gm t in c in dung C = 400pF v mt cun cm c L = 10H, r = 0,02O. Bit in p cc i trn t in bng 20V. duy tr dao ng ca mch th nng lng cn phi cung cp cho mch trong mt chu k bng:A: 16.10-5 J. B: 64pJ. C: 16mJ. D: 64mJ.Cu 17:Mch chn sng ca my thu v tuyn gm mt cun dy thun cm c t cm L = 21108tmH v mt t xoay. T xoay bin thin theo gc xoay C =30 o+ (pF). thu c sng in t c bc sng 15m th gc xoay ca t phi l: A: 36,50.B: 38,50.C: 35,50.D: 37,50. Cu 18:Trong mch dao ng in t l tng c dao ng in t iu ha vi tn s gc 65.10 e = Rad/s. Ti mt thi im, khi in tch ca t l 8q 3.10= C th dng in trong mch li 0, 05A = . in tch ln nht ca t c gi tr bng: A: 2.10-8CB: 3,2.10-8CC: 1,8.10-8CD: 3.10-8C Cu 19:Mch dao ng c L = 0,5 H, cng tc thi trong mch l i = 8cos2000t (mA). Biu thc hiu in th gia hai bn cc ca t in l: A: u = 8cos(2000t -t2 )(V)B: u = 8000cos(200t)(V) TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 38 C: u = 8000cos(2000t -t2 )(V)D: u = 20cos(2000t +t2 )(V) Cu 20:Mch dao ng gm t c in dung C = 30 F, cun dy c t cm L =0,5 H v in tr thun r = 1 . duy tr dao ng in t trong mch vi hiu in th cc i gia hai bn t l U 0 = 5 V th ta phi cung cp cho mch mt cng sut l: A: 3,5.10-3 WB: 15,0.10-4 WC: 7,5.10-4 W D: 7,0.10-3 W Cu 21:Cho mch in xoay chiu nh hnh v. it l tng, in tr ampe k khng ng k. Khi K ng ampe k ch 2A, khi K ngt ampe k ch bao nhiu? A R K A: 1AB: 2AC: 1,5AD:2 A Cu 22:Cho mch in xoay chiu RLC c cun thun cm L c th thay i gi tr c. Dng ba vn k xoay chiu c in tr rt ln o in p hiu dng trn mi phn t. iu chnh gi tr ca L th nhn thy in p hiu dng cc i trn cun cm ln gp 2 ln in p hiu dng cc i trn in tr. Hi in p hiu dng cc i trn cun cm gp bao nhiu ln in p hiu dng cc i trn t?A: 3 lnB: 4 lnC:3 lnD: 23ln. Cu 23:Ni hai cc ca mt my pht in xoay chiu mt pha vo hai u on mch AB gm in tr thun R mc ni tip vi cun cm thun. B qua in tr cc cun dy ca my pht. Khi rto ca my quay u vi tc n vng/pht th cng dng in hiu dng trongonmchl1A.Khirtocamyquayuvitc3nvng/phtthcngdnginhiudngtrongonmchl 3 A.Nu rto ca my quay u vi tc 2n vng/pht th cm khng ca on mch AB l A:2R 3 .B: 2R3.C:R 3 .D: R3. Cu 24:Mt on mch RLC khng phn nhnh gm in tr thun 100 , cun dy thun cm c h s t cm L=1/(10) v t in c in dung C thay i c t vo hai u on mch in hiu in th u = 200 2sin100 t (V). Thay i in dung C ca t in cho n khi hiu in th gia hai u cun dy t gi tr cc i. Gi tr cc i bng A: 200 V.B: 1002V.C: 502V.D: 50 V Cu 25:Mt khung dy dn phng, quay u vi tc gc equanh mt trc c nh trong mt t trng u, c vc t cm ng t vung gc vi trc quay ca khung, sut in ng cm ng trong khung c biu thc) V ( )2t cos( E e0t+ e = . Vo thi im t = 0, vc t php tuyn ca mt phng khung dy hp vi vct cm ng t mt gc bng A: 1800.B: 1500.C: 450.D: 900. Cu 26:Cho on mch in xoay chiu gm cun dy c in tr thun R, mc ni tip vi t in. Bit hiu in th gia hai u cun dy lch pha 2t so vi hiu in th gia hai u on mch. Mi lin h gia in tr thun R vi cm khng ZL ca cun dy v dung khng ZC ca t in l A: R2 = ZC(ZL - ZC)B: R2 = ZL(ZL - ZC)C: R2 = ZL(ZC - ZL)D: R2 = ZC(ZC - ZL) Cu 27:MchR1 , L1, C1 c tn s cng hng f1. Mch in R2 , L2 , C2 c tn s cng hng f2. Bit f2 = f1. Mc ni tip hai mch vi nhau th tn s cng hngl fA: f = 3f1.B: f = 2f1. C: f = 1,5 f1.D: f = f1. Cu 28:Mt my pht in xoay chiu 1 pha c in tr trong khng ng k . Ni 2 cc my pht vi 1 cun dy thun cm . Khi rto ca my quay vi vn tc gc n vng / s th cng dng in i qua cun dy c cng hiu dng I . Nu rto quay vi vn tc gc 2n vng / s th cng hiu dng ca dng in trong mch l A: I B: 2I C: 3I D: I 3Cu 29:Mch xoay chiu RLC1 mc ni tip. Bit tn s dng in l 50 Hz, R = 40 ( O ), L = 1(H)5t, C1 = 310(F)5t. Mun dng in trong mch cc i th phi ghp thm vi t in C1 mt t in c in dung C2 tho mn A: Ghp song song v C2 = 43.10 (F)tB: Ghp ni tip v C2 = 45.10 (F)t C: Ghp song song v C2 = 45.10 (F)tD: Ghp ni tip vC2 = 43.10 (F)t Cu 30:Trong cc n v sau y, n v no l n v ca cng dng in A:.Wb.s O .radB: .sWbO.radC: .WbsO.radD: Wb.s O.rad Cu 31:Trong th nghim giao thoa nh sng vi khe Young, khong cch gia hai khe S1S2 l 1mm, khong cch t hai khe n mn quan st l D = 2m . Chiu vo hai khe S1,S2ng thi hai bc x c bc sng 1 0, 6 m = v bc sng 2cha bit. Trong khong rng L = 2,4cm trn mn quan st c 33 vch sng, trong c 5 vch l kt qu trng nhau ca hai h vn. Tnh 2bit 2 trong 5 vch trng nhau nm ngoi cng ca trng giao thoa A: 2 = 0,45 m B: 2 = 0,55 m C: 2 = 0,75 m D: 2 = 0,65 m Cu 32:Chiu mt tia sng trng vo mt lng knh c gc chit quang A=40 di gc ti hp. Bit chit sut ca lng knh i vi nh sng v tm ln lt l 1,62 v 1,68. rng gc quang ph ca tia sng sau khi l khi lng knh l: A: 0,015 radB: 0,0150.C: 0,24 radD: 0,240.TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 39 Cu 33:Khi tng dn nhit ca khi hir th cc vch trong quang ph ca hir s A: Xut hin theo th t , lam, chm, tmB: Xut hin ng thi mt lc C: Xut hin theo th t , chm, lam, tmD: Xut hin theo th t tm, chm, lam, Cu 34: Ngun sng trong th nghim giao thoa nh sng cng lc ba bc x n sc c bc sng 1 = 0,64m; 2 = 0,54m v 3 = 0,48 m. V tr trn mn ti ba vn sng trng nhau u tin k t vn sng trung tm l vn sng bc bao nhiu ca vn sng mu ? A: 27B: 15C: 36D: 9 Cu 35:Trong th nghim giao thoa nh sng bng khe Young, dng nh sng n sc c bc sng = 0,5m. Khong cch gia hai khe a = 2mm. Thay bi ' = 0,6m v gi nguyn khong cch t hai khe n mn. khong vn khng i th khong cch gia hai khe lc ny l :A: a' = 1,5mm. B: a' = 1,8mm. C: a' = 2,2mm. D: a' = 2,4mm.Cu 36:Chiu ng thi ba bc x n sc 1=0,4m; 2=0,52mv 3=0,6m vo hai khe ca th nghim Ing. Bit khongcch gia hai khe l 1mm, khong cch t hai khe ti mn l 2m. Khong cch gn nht gia hai v tr c mu cng mu vi vn sng trung tm l A: 31,2mm.B: 15,6mm.C: 7,8mmD: p n khc.Cu 37:Trong cc ng dng sau, laze khng c dng lm g? A: Thng tin lin lcB: S dng trong y t C: ng dng trong cng nghipD: Si m cho cy trngCu 38: Dung dch Fluorxin hp th nh sng c bc sng 0,49m v pht ra nh sng c bc sng 0,52m. ngi ta gi hiu sut ca s pht quang l t s gia nng lng nh sng pht quang v nng lng nh sng hp th. Bit hiu sut ca s pht quang ca dung dch Fluorxin l 75%. S phn trm ca phtn b hp th dn n s pht quang ca dung dch l A: 82,7%B: 79,6%C: 75,0% D: 66,8% Cu 39:Trong nguyn t hir, bn knh Bo l r0 = 5,3.10-11 m. mt trng thi kch thch ca nguyn t hir, lectron chuyn ng trn qu o dng c bn knh l r = 2,12.10-10 m. Qu o c tn gi l qu o dng A: N. B: M. C: O. D: L. Cu 40:Trong nguyn t hir , bn knh Bo l r0 = 5,3.10-11m. Sau khi nguyn t hir bc x ra phtn ng vi vch (vch Ho) th bn knh qu o chuyn ng ca lctrn trong nguyn t gim A: 13,6nm.B: 0,47nm.C: 0,265nm.D: 0,75nm. Cu 41:Mt qu cu bng kim loi c gii hn quang in l 0,277m c t c lp vi cc vt khc . Chiu vo qu cu nh sng n sc c Em) th nguyn t pht ra 1 phtn c nng lng nh hn hoc bng En Em.TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 43 Cu 40:Ln lt chiu 2 nh sng c bc sng 1 = 0,54 m v 2 = 0,35m vo mt tm kim loi lm catot ca mt t bo quang in ngi ta thy vn tc ban u cc i ca cc quang electron thot ra t catot trng hp dng bc x ny gp i bc x kia. Cng thot electron ca kim loi l? A: 1,05eVB: 1,88eVC: 2,43eVC: 3,965eV Cu 41:Chiu nh sng c bc sng = 0,4m vo catot ca mt t bo quang in lm bng kim loi c cngthot A = 2,48eV. Nu hiu in th gia anot v catot l U AK = 4V th ng nng ln nht ca quang electron khi p vo anot l: A: 52,12.10-19 JB: 7,4.10-19 JC: 64.10-19 JD: 45,72.10-19 J Cu 42:Chiu ln lt hai bc x n sc c bc sng 1v 2 vo catot ca TBQ. Cc electron bt ra vi vn tc ban u cc i ln lt l v1 v v2 vi v1= 2v2 . T s cc hiu in th hm Uh1/Uh2 cc dng quang in trit tiu l:A: 4 B: 3 C: 2 D: 5 Cu 43:Phn ng sau y khng phi l phn ng ht nhn nhn to A: 238 4 23492 2 90U He Th + B: 27 30 113 15 0Al P n +o + C: 4 14 17 12 7 8 1He N O H + + D: 238 1 23992 0 92U n U + Cu 44:Cu no sau y l sai khi ni v s phng x. A: Tng khi lng ca ht nhn to thnh c khi lng ln hn khi lng ht nhn m. B: khng ph thuc vo cc tc ng bn ngoi.C: ht nhn con bn hn ht nhn m. D: L phn ng ht nhn t xy ra. Cu 45:Mt nh my in nguyn t dng U235 phn hch ta ra 200MeV. Hiu sut ca nh my l 30%. Nu cng sut ca nh my l 1920MW th khi lng U235 cn dng trong mt ngy : A: 0,6744kg.B: 1,0502kg. C: 2,5964kg.D: 6,7455kg Cu 46:Ngi ta dng prton bn ph ht nhn Bri ng yn. Hai ht sinh ra l Hli v X. Bit prton c ng nng K= 5,45MeV, Ht Hli c vn tc vung gc vi vn tc ca ht prton v c ng nng KHe = 4MeV. Cho rng ln ca khi lng ca mt ht nhn (o bng n v u) xp x bng s khi A ca n. ng nng ca ht X bngA:6,225MeV .B:1,225MeV .C: 4,125MeV.D: 3,575MeV . Cu 47:Trong s phn hch ca ht nhn 23592U , gi k l h s nhn ntron. Pht biu no sau y l ng? A: Nu k < 1 th phn ng phn hch dy chuyn xy ra v nng lng ta ra tng nhanh. B: Nu k > 1 th phn ng phn hch dy chuyn t duy tr v c th gy nn bng n. C: Nu k > 1 th phn ng phn hch dy chuyn khng xy ra. D: Nu k = 1 th phn ng phn hch dy chuyn khng xy ra. Cu 48: phn loi ht s cp ngi ta cn c vo: A: ln ca in tch cc ht s cpB: Khi lng ngh ca cc ht s cp C: Momen ng lng ring ca cc ht s cpD: Thi gian sng trung bnh ca cc ht s cp Cu 49:Ht nhn nguyn t no cho sau y l cc ht s cp. A: Ht nhn heli`B: Ht nhn cacbonC: Ht nhn hidroD: Ht nhn oxi Cu 50:c trng no sau y l ca tri t l sai? A:Bn knh khong 6400 km B:Chu k quay quanh trc khong 24h C:Chu k chuyn ng quanh mt tri khong 365 ngy D:Khong cch t Tri t n Mt tri l 1,5 n v thin vn GIO DC HNG PHC S : 13 H v tn hc sinh:.................................................................... S bo danh................................................................................. THI TH I HC 2012 Mn: VT L; KHI A Thi gian lm bi: 90 pht, khng k thi gian pht Cho bit: hng s Plng h = 6,625.10-34 J.s; ln in tch nguyn t e = 1,6.10-19 C; tc nh sng trong chn khng c = 3.108 m/s; 1u = 931,5 MeV/c2. Cu 1: Mt tm vn bc qua mt con mng c tn s dao ng ring l 0,5Hz. Mt ngi i qua tm vn vi bao nhiu bc trong 12 giy th tm vn b rung ln mnh nht? A: .8 bc.B: 4 bc.C: 6 bc.D: 2 bc. Cu 2: Mt vt dao ng iu ho vi chu k T =2s, ly 210 t ~ . Ti thi imban u t = 0 vt c gia tc a = -0,1 m/s2, vn tc v = -3 t cm/s. Phng trnh dao ng ca vt l: A: x = 2cos t cm3t | |t+ |\ .B: x = 2cos2t cm3t | |t |\ .C: x = 2cos t cm6t | |t+ |\ .D: x = 2cos5t cm6t | |t |\ . Cu 3: Mt con lc n gm mt dy kim loi nh c u trn c nh, u di c treo qu cu nh bng kim loi. Chiu di ca dy treo l l = 1 m. Ly g = 9,8 m/s2.Ko vt nng ra khi v tr cn bng mt gc 0,1 rad ri th nh vt dao ng iu ho. Con lc dao ng trong t trng u c vect B vung gc vi mt phng dao ng ca con lc. Cho B = 0,5 T. Sut in ng cc i xut hin gia hai u dy kim loi l A: 0,3915 V B: 0,1566 VC: 0,0783 V D: 2,349 V TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 44 Cu 4: Trong dao ng iu ha ca con lc l xo i lng no sau y ph thuc vo khi lng ca vt? A: C nng B: Lc phc hi cc iC: Gia tc cc i D: Bin dao ng Cu 5:Mt con lc n c gn vo trn mt thang my. Chu k dao ng nh ca con lc n khi thang my ng yn l T, khi thang my ri t do th chu k dao ng nh ca con lc n l A: 2T.B: 0.C: T.D: v cng ln. Cu 6: Mt vt dao ng iu ha, khi vt i t v tr cn bng ra im gii hn th A: Chuyn ng ca vt l chm dn u.B:th nng ca vt gim dn. C: Tc ca vt gim dn.D:lc tc dng ln vt c ln tng dn.Cu 7: Mt con lc n gmmt qu cu nh bng kim loickhi lng 10g, in tch q = 2.10-7C treovosi dy mnh cch in khng dn c khi lng khng ng k (Gia tc trng trng g = 10m/s2). Khi khng c in trng chu k dao ng nh ca con lc l 2s. t con lc vo trong in trng u E = 104V/m c phng thng ng hng xung. Chu k dao ng nh ca con lc trong in trng l A: 0,99sB: 1,01sC: 1.25s D: 1,98s Cu 8: Vt dao ng iu ha dc theo trc Ox, quanh VTCB O vi bin A v chu k T. Trong khong thi gian T/3, qung ng nh nht m vt c th i c l A: ( 3- 1)A;B: 1A; C: A 3 , D: A:(2 -2 ) Cu 9: Mt ng h m giy s dng con lc n chy ng cao 200m, nhit 240C. Bit thanh con lc c h s n di 2.10-5K-1, bn knh Tri t 6400km. Khi a ng h ln cao 1km, nhit l 200C th mi ngy m n chy A: chm 14,256 s.B: chm 7,344 s.C: nhanh 14,256 s.D: nhanh 7,344 s. Cu 10:Tm nhn xt sai v sng c A: Qu trnh truyn sng l qu trnh lan truyn trng thi dao ng. B: Sng m truyn c trong mi trng cht lng, cht kh v cht rn. C: Trn mt phng truyn sng khong cch ga hai im dao ng vung pha bng s nguyn ln mt phn t bc sng. D: Khong cch gia hai im dao ng cng pha trn cng phng truyn sng bng s nguyn ln bc sng. Cu 11:Lc t = 0 u O ca dy cao su cng thng nm ngangbt u dao ng i ln bin a, chu k T = 1s. Hai im gn nhau nht trn dy dao ng cng pha cch nhau 6cm. Tnh thi im u tin M cch O 12cm dao ng cng trng thi ban u vi O. Coi bin khng i. A: t =0,5sB: t = 1sC: 2sD: 0,75s Cu 12:Mt mch dao ng in t l tng ang c dao ng in t t do. Ti thi im t = 0, in tch trn mt bn t in cc i. Sau khong thi gian ngn nht t th in tch trn bn t ny bng mt na gi tr cc i. Chu k dao ng ring ca mch dao ng ny l A: 4t.B: 6t.C: 3t.D: 12t. Cu 13:Tin thnh th nghim giao thoa sng trn mt thong ca mt cht lng nh hai ngun kt hp cng pha S 1, S 2. Tn s dao ng ca mi ngun l f = 30Hz. Cho bit S 1S 2 = 10cm. Mt im M nm trn mt thong cch S 2 mt on 8cm. v cch S 1 mt on 4cm. Gia M v ng trung trc S 1S 2 c mt gn li dng hypepol. Bin dao ng ca M l cc i. S im dao ng cc tiu trn S 1S 2 l: A: 12B: 11C: 10D: 9 Cu 14:Hai ngun sng kt hp ging ht nhau c t cch nhau mt khong cch x trn ng knh ca mt vng trn bn knh R ( x v hpkn X cha hai trong 3 phn t Rx, Cx, Lx mc ni tip. Cng dng in i v hiu in th u hai u on mch cng pha vi nhau th trong hp kn X phi c A: RX v LX B: RX v CX

C: Khng tn ti phn t tha mn D: LX v CX Cu 29:Mt my bin p h th gm cc cun dy 100 vng v 500 vng. B qua mi hao ph ca my bin p. Khi ni hai u cun s cp vi in p u = 100 2 cos100tt (V) th in p hiu dng hai u cun th cp h l: A: 50 V.B: 500 V.C: 10 V.D: 20 V. Cu 30:Mch xoay chiu gm bin tr R, cun dy c in tr r = 30O, t cm L =Ht6 , 0, t in c in dungmF Ct 21=mc ni tip. t vo 2 u on mch mt in p xoay chiu 100V 50 Hz. cng sut tiu th trn bin tr t cc i th gi tr ca n phi bng? A: 40OB: 50OC: 0D: 10O Cu 31:Chiuchm sng gm 5 nh sng n sc khc nhau l ; cam;vng; lc, v tm i t nc ra khng kh, thy nh sng mu vng l ra ngoi song song vi mtnc Xc nh s bc x m ta c th quan st c pha trn mt nc A: Ngoi vng ra cn c cam v B: tt c u trn mt nc C: Ch c l ra pha trn mt ncD: Ch c lc v tm l ra khi mt nc Cu 32: Chiu nh sng trng i qua lngknh c gc chit quang 30o th thy nh sng tm c gc lch cc tiu. Hy tm gc lch ca tia bit n d = 1,54; nt = 1,58. A: 16o 50B: 16,5o C: 15o 6 D: 15,6o Cu 33:Chn cu sai khi ni v tnh cht v ng dng ca cc loi quang ph A: Da vo quang ph vch hp th v vch pht x ta bit c thnh phn cu to ngun sng. B:Mi nguyn t ho hc c c trng bi mt quang ph vch pht x v mt quang ph vch hp th. C: Da vo quang ph lin tc ta bit c nhit ngun sng. D: Da vo quang ph lin tc ta bit c thnh phn cu to ngun sng. TUYN TP 60 THI TH I HC 2012Ex: Nguyn Hng Khnh _ HKP TP 2: 30 HAY V KHMobile: 09166.01248 Email: Khanhcaphe@gmail.com Gio Dc Hng Phc - Ni Khi u c M! Trang 46 Cu 34:Mt ngun sng n sc = 0,6m chiu vo mt mt phng cha hai khe h S1, S2, hp, song song, cch nhau 1mm v cch u ngun sng. t mt mn nh song song v cch mt phng cha hai khe 1m. Nu khng t bn thu tinh m y vo khong gia khe v mn mt cht lng c chit sut n', ngi ta thy khong cch gia hai vn sng lin tip bng 0,45mm. Tnh chit sut n' ca cht lng ? A:1,5 B: 1,33C: 1,4 D: 1,6Cu 35:Trong th nghim ca Young, khong cch gia hai khe S1S2 n mn l 2m. Ngun S pht ra nh sng n sc t cch u hai khe mt khong 0,5m. Nu di S theo phng song song vi S1S2 mt on 1mm th vn sng trung tm s dch chuyn mt on l bao nhiu trn mn ?A: 3mm.B: 5mm.C: 4mm. D: 2mm.Cu 36:Trong th nghim Ing, ngi ta dng nh sng n sc c bc sng = 0,6m. Khong cch gia hai khe sng l 1,5mm, khong cch gia hai khe n mn hng vn l 3m. Khong cch gia vn sng vi vn ti lin tip nhau l : A: 1,2mm.B: 0,3mm. C: 0,6mm.D: 1,5mm.Cu 37:Hy chn cu ng.Hiu sut ca mt laze A: Nh hn 1.B: Bng 1.C: Ln hn 1.D: Rt ln so vi 1. Cu 38:Pht biu no sau y l sai khi ni v s pht quang? A: S hunh quang thng xy ra i vi cc cht lng v cht kh. B: S ln quang thng xy ra i vi cc cht rn. C: Bc sng ca nh sng pht quang bao gi cng ln hn bc sng ca nh sng kch thch. D: Bc sng ca nh sng pht quang bao gi cng nh hn bc sng ca nh sng kch thch. Cu 39:Nguyn t hir chuyn t trng thi dng c nng lng En = -1,5 eV sang trng thi dng c nng lng Em = -3,4 eV. Bc sng ca bc x m nguyn t hir pht ra xp x bng A: 0,654.10-7m.B: 0,654.10-6m.C: 0,654.10-5m.D: 0,654.10-4m. Cu 40:Cng thot camt kim loi dng lmcatt camt t bo quang in l A, gii hn quang in ca kim loi ny l 0. Nu chiu bc x n sc c bc sng = 0,60 vo catt ca t bo quang in trn th ng nng ban u cc i ca cc electron quang inlA: 0,66. AB: 5A/3C: 1,5A D:2A/3 Cu 41:ng nng ban u cc i ca cc electrn quang in khi bt ra khi catt ca mt t bo quang in l 2,065 eV. Bit vn tc cc i ca cc electrn quang in khi ti ant l 2,909.106m/s, khi lng electron 9,1.10-31 (kg), 1 eV = 1,6.10-19 J. Hiu in th gia ant (A) v catt (K) ca t bo quang in l A: UAK = - 24 VB: UAK = + 24 VC: UAK = - 22 VD:UAK = + 22 V Cu 42:Mt tm nhmc cng thot electron l 3,74eV. Khi chiu vo tm nhm bc x 0,085m ri hngcc quangelectron dc theo ng sc ca in trng c hng trng vi hng chuyn ng ca electron . Nu cng in trng c ln E =1500V/m th qung ng ti a electron i c l: A:7,25dm.B:0,725mm.C:7,25mm.D:72,5mm. Cu 43:Trong phn ng ht nhn ,protonA: c th bin thnh ntron v ngc li B:c th bin thnh nuclon v ngc liC:c bo ton D:A v C ngCu 44:Phn ng ht nhn l:A: S bin i ht nhn c km theo s ta nhit. B: S tng tc gia hai ht nhn dn n s bin