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8/11/2019 13 May M1 International Model Red
1/8
Ht
MftY
2ot3
rNEeNfrrtoNr\L
1.
Two
particles
I and
B,
of
mass 2 kg and 3 kg respectively, are moving towards each other
in
opposite directions along
the same straight line
on
a smooth horizontal surface. The
parlicles
collide
directly.
Immediately before the
collision
the speed ofl is 5 m s
I
and
the
speedofB
is 6 m
s-r.
The magnitude
of the impulse
exertedonBbyl
is
14Ns.
Find
(a)
the
speed of ,4 immediately
after the
collision,
(3)
(b)
the
speed
of
B immediately after the collision.
(3)
ft-s
a
Vp
lYlorn
A
blare-'
to
e
lmou[se-
--
r+
ln.^$
ger
-
Lxln
ci-Il
SxL+
Ln-6
=
Lr-Z+
3V6
-bB
-
o_
Vc
2Vn
=
-tf
vft.4
-
=>
-8 =-9+3Vg
=)
3Vs=
-*
...
Vg't
8/11/2019 13 May M1 International Model Red
2/8
2-
Figure
I
A
particle
of
weight 8
N is attached
at C to
the
ends
of
two light
inextensible strings
lC
and.BC.
The other
ends,
I
and
-8,
are attached
to a fixed
horizontal ceiling.
The
particle
hangs
at rest in equilibrium,
with
the strings
in
a vertical
plane.
The string
lC
is
inclined
at
35'
to the
horizontal and
the string
BC is
inclined
at25"
to
the
horizontal, as shown
in
Figure 1. Find
(i)
the tension
in
the
string
lC,
(ii)
the tension
in
the string
BC.
(8)
(oStn'LS
Ts
(os2S
=)
TB= TA-C"sS
Cos2,S
*8
fr+4--O
8/11/2019 13 May M1 International Model Red
3/8
3.
6
-{
t^"
5rP-'$3.148196
'>
{nnar
=7r,tNA
- 11'6
k
+"
.$:"*
ag
Figure
2
A fixed rough
plane
is
inclined
at 30o to the
horizontal. A
small
smooth
pulley
P
is
fixed
at the top of
the
p1ane.
Two
parlicles
A
and
B,
of mass
2 kg and 4 kg respectively, are
attached
to the ends of a
light
inextensible string
which
passes
over the
pulley
P.
The
part
of
the string
from I to P is
parallel to a line of
greatest
slope of
the
plane
and
B hangs
freely below P, as shown
in Figure 2.
The coefficient of
friction between
I and the
plane
i,
*.
tritiutty
z is held
at rest on the
plane.
The
parlicles
are
released
from
rest with
3
the string taut and
I
moves up
the
plane.
Find the tension
in
the
string
immediately after the
particles
are
released.
(e)
\,Ld4_
s.Xstcx-
frh:
t'6^
=)
{"{o-{
Sre
}ur^-.{Lo-
pL"r-
=
30.
45-T
--
k".
o
+g-r-
f3
T=
*aru
r
-b):
=
-:
^,
*b
8/11/2019 13 May M1 International Model Red
4/8
4. At time r
:
0,
two
balls
I
and
B are
projected vertically upwards. The ball
I
is
projected
vertically upwards
with speed
2 m s
1
from
a
point
50
m above
the
horizontal
ground.
The ball
-B
is
projected
vertically
upwards
from
the
ground
with speed
20 m s
1.
At time
l: 7 seconds,
the
two
balls
are
at the same
vertical height, h metres, above
the
ground.
The
balls
are modelled
as
particles
moving freely
under
gravity.
Find
(a)
the
value
of
7,
(s)
(b)
the
value
of
ft.
(2)
S
.
-
(so-h)
Lt,
-
2^
V
(
=
-1.8
L,
r
---q.8
:{
s
t{
V
A
t
.I
,20
g
=
6t+ atl -4
h-
50
=
LT
-
*-\ro
h
--
eor-
+'1T"
=)
/.
SO
=x
+/-rcf
:)
-SO=
-lgr
o
@
*.1T1,
."
T=7
b)
h=
2o(?)-
q,r(?)'
,
Eb
8/11/2019 13 May M1 International Model Red
5/8
5.
Figure
3
A
particle P of
mass 0.6 kg slides
with
constant
acceleration
down a line
of
greatest
slope
of
a
rough
plane, which
is
inclined at 25"
to the
horizontal.
The
particle passes through
two
points
A
and
B, where
AB: 10
m,
as shown in Figure 3.
The
speed
of
P at A is
2 m
sr.
The
particle
P takes
3.5
s
to
move
from
I
to
B.
Find
(a)
the
speed
of
p
at
B, (3)
(b)
the acceleration
of P,
e)
(c)
the coefficient
of friction
between P
and
the
plane.
(5)
{r***__ltNr
NK--
s.3z1o6qtr'
ts\
^
f
"o'b59a2s
-'
{L^r
=
s'j21oE981^
0.53tosZs
.f\
=r,rc.
z)
L'+8+715
-S'3210818110
S
--
lO
S=tr"t
+ aL'--)
tO
'++fo.(s.s)'
(r
2-
v
b)
..-^,y
avt
t
=3.S
a)
V
=tr.+at
V=2-+(H,X|)
.
+
c)
a.+8tr11s
-
o
6(T)=
s'321o81trl,r
.'-
),\--
O.+l
(zsp)
blanl
c\.
8/11/2019 13 May M1 International Model Red
6/8
6,
lln
this
question
i
and
j
are horizontal
unit
vectors due east and
due north
respectively.
Position
vectors ore
given with
respect
to a
fixed
origin O.)
A ship 5
is moving
with constant
velocity
(3i
+
3j)
km h
r.
At time t: 0,
the
position
vector
of
S is
(-4i
+
2j) km.
(a)
Find the
position
vector
of
S
at time
I hours.
(2)
A ship 7
is
moving
with
constant
velocity
()i
+
ni)
km h
r.
At
time
I
:
0, the
position
vector of
7 is
(6i
+
j)
km. The two
ships
meet
at the
point
P.
(b)
Find the
value
ofr.
(s)
(c)
Find
the
distance
OP.
(4)
67
=64"
")
v
'
(e)
s=
(-I).
b)
r=(t)--(l)
fi
2+3t
ol+tn
-)
2-+L=
c)
P"
(-;)-
(t
)
=
(;
)
.
(i)
2b
=
-S+3t"
=
5b
t'L
-,
+2n
i
2a:
$ =)fPlS
=
8.2Sha,.
(3sg)
----
8/11/2019 13 May M1 International Model Red
7/8
1
Figure
4
A
truck of
mass 1750
kg
is
towing
a
car
of
mass
750
kg
along
a
straight
horizontal
road.
The
two
vehicles
are
joined
by
a light towbar
which is inclined
at
an angle d to the
road,
as shown in
Figure 4.
The vehicles
are
travelling at 20
m
s
I
as they
enter a
zone where
the speed
limit
is
14 m s
1.
The
truck's
brakes
are applied to
give a constant braking
force
on the
truck.
The distance travelled
between
the instant when
the brakes are
applied and
the instant when
the
speed
ofeach
vehicle
is
14
m s
I
is 100
m.
(a)
Find the
deceleration
of the truck
and
the car.
(3)
I
u
v
a\
t
+)
A.
-l'OL
?''-
Note
-
6lls*
bre
tL'ng
tprr,rtorr-
rs'TH(I)ST
r-oz
4-
r. oL
()
urt\dLz-s")s+e$r
R+
S@
+360
+o.qT
-O-tr
.2S00y1.02
=1
(tt6O
2
2SSo
:.
[2,
i45ON
.-...._-.....-
=)
T-hcust.
5l+.,
(ssp)
- -.--.-.-.
1
16()
V
2
,
(,tZ+,l*a.S
t1[
-
*OD+ZOOa
=)
?-@a= -2OY
The
constant
braking
force on
the truck
car also
experience
constant
resistances
Given
that cos d
:
0.9,
find
(b)
the
lorce
in
the towbar,
(c)
the value
ofR.
=20
=
tg
has magnitude
R newtons.
The
truck
and the
to motion of 500
N and
300
N respectively.
(4)
(4)
b)
Car
3oO
+
o.1T
=?E>Q-oz)
8/11/2019 13 May M1 International Model Red
8/8
R
tr
D
.
t'
C
A
0.2m
2m
Figure
5
A uniform rod
lB
has length 2 m and mass
50 kg. The rod is in equilibrium
in
a
horizontal
position,
resting
on two smooth supports
at C
and D,
where AC
:
O.2
metres
and
DB: x
metres,
as
shown
in Figure 5. Given
that
the
magnitude
of the
reaction on
the
rod
at D
is
twice
the magnitude
of the reaction
on the rod at C,
(a)
find
the
value
ofx.
(6)
The
support
at
D is
now moved
to
the
point
E on the
rod,
where
EB
:
0.4
metres. A
particle
of
mass
m
kg is
placed
on the
rod at B, and
the
rod
remains
in equilibrium
in a
horizontal
position.
Given
that
the
magnitude
of the reaction on the
rod at E
is
four
times
the magnitude
ofthe reaction on
the
rod
at
C,
(b)
find
the value
of m.
A
,
so3
.xm
a)
t=
il.
,1,
+
3r= sga
L.
9q
3u
-) *{*
=
Lo4
so9
Bt
4r(yp.k+(x1.8
"
SOSxl
C*z
a
$5x
I's
=
5o3r
t
r.)
t2SO.
ol=
32OJ
+
r.^{
\aul1p,
b)
.'.
k--
Ea
l+J
z(=
rya.
2q
s
Q.6
f"\
16)
'-)
3'$e--
SoS
t.-V
-)
$r(
=
SO5'i
n^5