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11.4 Hardy-Wineberg Equilibrium

11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

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Page 1: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

11.4 Hardy-Wineberg Equilibrium

Page 2: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Equation - used to predict genotype frequencies in a population

• Predicted genotype frequencies are compared with Actual frequencies– used for traits in simple dominant-recessive systems

"The Hardy-Weinberg equation is based on Mendelian genetics. It is derived from a simple Punnett square in which p is the frequency of the dominant allele and q is the frequency of the recessive allele."

p2 + 2pq + q2 = 1

11.4 Hardy-Weinberg Equilibrium

Page 3: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

• q2 = # homozygous recessive/entire population

• p2 = # homozygous dominant/entire population

• Take the square roots to find p & q• If the predicted genotypes match the actual

genotype frequencies than population is in equilibrium

• If it is not in equilibrium– it is changing - evolving

11.4 Hardy-Weinberg Equilibrium

Page 4: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Chi-Square Test

• Determines whether the experimental data fits the results expected

• For example– 290 purple flowers – 110 white flowers – Close to a 3 : 1 ratio– How do you know for sure?

Page 5: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Goodness of Fit

• The chi-square test is a “goodness of fit” test– Answers the question of how well do

experimental data fit expectations• Ex: self-pollination of a heterozygote

– The null hypothesis is that the offspring will appear in a ratio of 3 dominant to 1 recessive.

Page 6: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Formula

• First determine the number of each phenotype that have been observed and how many would be expected

• “Χ” - Greek letter chi• “∑” - sigma

– Sum the following terms for all phenotypes• “obs” is the number of individuals of the given

phenotype observed• “exp” is the number of that phenotype expected from

the null hypothesis• Must use the number of individuals and NOT

proportions, ratios, or frequencies

exp

exp)( 22 obs

Page 7: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Example• F2 offspring

– 290 purple and 110 white flowers– Total of 400 offspring

• We expect a 3 : 1 ratio.• To calculate the expected numbers

– Multiply the total offspring by the expected proportions – Expected Purple = 400 * 3/4 = 300 purple– Expected White = 400 * 1/4 = 100 white

Page 8: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

• Purple obs = 290 and exp = 300• White obs = 110 and exp = 100• Plug into the formula: 2 = (290 - 300)2 / 300 + (110 - 100)2 / 100 = (-10)2 / 300 + (10)2 / 100 = 100 / 300 + 100 / 100 = 0.333 + 1.000 = 1.333 • = chi-square value

Page 9: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Reasonable• What is a “reasonable” result is subjective and

arbitrary• For most work a result is said to not differ

significantly from expectations if it could happen at least 1 time in 20

• That is, if the difference between the observed results and the expected results is small enough that it would be seen at least 1 time in 20 over thousands of experiments

• “1 time in 20” can be written as a probability value p = 1/20 = 0.05

Page 10: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Degrees of Freedom

• The number of independent random variables involved

• Simply the number of classes of offspring minus 1

• Example: – 2 classes of offspring: purple and white– Degrees of freedom (d.f.) = 2 -1 = 1.

Page 11: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Critical Chi-Square

• Critical values for chi-square are found on tables, sorted by degrees of freedom and probability levels

• If your calculated chi-square value is greater than the critical value from the table, you “reject the null hypothesis”

• If your chi-square value is less than the critical value, you “fail to reject” the null hypothesis – Accept that your genetic theory about the expected ratio is

correct

Page 12: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Chi-Square Table

Page 13: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Using the Table

• Example of 290 purple to 110 white• Chi-square value of 1.333, with 1 degree of freedom• 1 d.f. is the first row, and p = 0.05 is the sixth column• Critical chi-square value = 3.841• Calculated chi-square = 1.333

– less than the critical value, 3.841– “fail to reject” the null hypothesis– An observed ratio of 290 purple to 110 white is a good fit

to a 3 to 1 ratio

Page 14: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Another Example: from Mendelphenotype observed expected

proportionexpected number

round yellow

315 9/16 312.75

round green

101 3/16 104.25

wrinkled yellow

108 3/16 104.25

wrinkled green

32 1/16 34.75

total 556 1 556

Page 15: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Finding the Expected Numbers

• Add up the observed offspring to get the total number of offspring

• Example: 315 + 101 + 108 + 32 = 556• Multiply total offspring by the expected

proportion --expected round yellow = 9/16 * 556 = 312.75 --expected round green = 3/16 * 556 = 104.25 --expected wrinkled yellow = 3/16 * 556 = 104.25 --expected wrinkled green = 1/16 * 556 = 34.75

Page 16: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Calculating the Chi-Square Value

X2 = (315 - 312.75)2 / 312.75 + (101 - 104.25)2 / 104.25 + (108 - 104.25)2 / 104.25 + (32 - 34.75)2 / 34.75 = 0.016 + 0.101 + 0.135 + 0.218 = 0.470.

exp

exp)( 22 obs

Page 17: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

D.F. and Critical Value• Degrees of freedom • 4 - 1 = 3 d.f.• 3 d.f. and p = 0.05

– critical chi-square value = 7.815• Observed chi-square (0.470) is less than

the critical value– Fail to reject the null hypothesis– Accept Mendel’s conclusion that the

observed results for a 9/16 : 3/16 : 3/16 : 1/16 ratio

Page 18: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Chi-Square Table

Page 19: 11.4 Hardy-Wineberg Equilibrium. Equation - used to predict genotype frequencies in a population Predicted genotype frequencies are compared with Actual

Mendel’s Yellow vs. Green Results