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8/10/2019 03.2 Chapter3_SensitivityAnalysis.pdf
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Chapter 3
Sensitivity AnalysisCompanion slides of
Applied Mathematical Programming
by Bradley, Hax, and Magnanti(Addison-Wesley, 1977)
prepared by
Jos Fernando Oliveira
Maria Antnia Carravilla
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The custom-molder problem
Suppose that a custom molder has one injection-moldingmachine and three different dies to fit the machine.
Due to differences in number of cavities and cycle times,with the first die he can produce 100 cases of six-ounce
juice glasses in six hours, while with the second die he canproduce 100 cases of ten-ounce fancy cocktail glasses infive hours and with the third die he can produce 100 casesof champagne glasses in eight hours. He prefers to operateonly on a schedule of 60 hours of production per week.
He stores the weeks production in his own stockroomwhere he has an effective capacity of 15,000 cubic feet. Acase of six-ounce juice glasses requires 10 cubic feet ofstorage space, while a case of ten-ounce cocktail glassesrequires 20 cubic feet due to special packaging and a caseof champagne glasses requires 10 cubic feet.
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The custom-molder problem
The contribution of the six-ounce juice glasses is$5.00 per case; however, the only customeravailable will not accept more than 800 cases perweek. The contribution of the ten-ounce cocktail
glasses is $4.50 per case and there is no limit onthe amount that can be sold, which is also truefor the champagne glasses, that have acontribution of $6.00 per case.
How many cases of each type of glass should beproduced each week in order to maximize thetotal contribution?
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The custom-molder model
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The initial simplex tableau
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And the final (optimal) simplex tableau
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Aims
We wish to analyze the effect on the optimal solutionof changing various elements of the problem datawithout re-solving the linear program or having toremember any of the intermediate tableaus generated
in solving the problem by the simplex method. The type of results that can be derived in this way are
conservative, in the sense that they provide sensitivityanalysis for changes in the problem data small enough
so that the same decision variables remain basic, butnot for larger changes in the data.
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SHADOW PRICES, REDUCED COSTSAND NEW ACTIVITIES
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Shadow prices
Definition. The shadow price associated with
a particular constraint is the change in the
optimal value of the objective function per
unit increase in the righthand-side value forthat constraint, all other problem data
remaining unchanged.
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Suppose that the production capacity in the
first constraint of our model is
increased from 60 to 61 hours:
Solving a new problem with 1 unit more on
the right-hand side is algebraically equivalent
to allow the slack variablex4to take on the
negative value of -1 in the original problem.
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How does the objective function changes
whenx4is replaced byx4 1 (i.e., from its
optimal valuex4= 0 tox4= 1)?
In the optimal solutionx3= x
4= x
5= 0 because
they are nonbasic variables.
If nowx4= 1, the profit increases by 11/14
hundred dollarsthe shadow price
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The shadow price for a particular constraint is merelythe negative of the coefficient of the appropriateslack (or artificial) variable in the objective function ofthe final tableau.
Shadow prices are associated with the constraints ofthe problem and not the variables.
For our example, the shadow prices are 11/14 hundreddollars per hour of production capacity, 1/35 hundreddollars per hundred cubic feet of storage capacity, andzero for the limit on six-ounce juice-glass demand.
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Reduced costs
Definition. The reduced cost associated with
the nonnegativity constraint for each variable
is the shadow price of that constraint (i.e., the
corresponding change in the objectivefunction per unit increase in the lower bound
of the variable).
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The reduced costs can also be obtained directlyfrom the objective equation in the final tableau:
Increasing the righthand side ofx3 0 by oneunit tox3 1 forces champagne glasses to beused in the final solution. Therefore, the optimalprofit decreases by 4/7.
Increasing the righthand sides ofx1 0 andx2 0by a small amount does not affect the optimalsolution, so their reduced costs are zero.
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In every case, the shadow price for the
nonnegativity constraint on a variable
(reduced cost of the variable) is the objective
coefficient for this variable in the finalcanonical form. For basic variables, these
reduced costs are zero.
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Pricing out an activity
The operation of determining the reduced
cost of an activity from the shadow price and
the objective function is generally referred to
aspricing out an activity.
In this view, the shadow prices are thought of
as the opportunity costs associated with
diverting resources away from the optimalproduction mix.
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Example with variablex3
Since the new activity of producing champagne glassesrequires 8 hours of production capacity per hundredcases, whose opportunity cost is 11/14 hundred dollarsper hour, and 10 hundred cubic feet of storage capacity
per hundred cases, whose opportunity cost is 1/35hundred dollars per hundred cubic feet, the resultingtotal opportunity cost of producing one hundred casesof champagne glasses is:
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Now the contribution per hundred cases is only 6hundred dollars so that producing any champagneglasses is not as attractive as producing the currentlevels of six-ounce juice glasses and ten-ounce cocktail
glasses. Therefore, if resources were diverted from the current
optimal production mix to produce champagne glasses,the optimal value of the objective function would be
reduced by 4/7 hundred dollars per hundred cases ofchampagne glasses produced. This is exactly thereduced cost associated with variablex3.
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Generalization
Objective function in the optimal solution
Shadow prices
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Relationship between shadow prices,
reduced costs and the problem data
Recall that, at each iteration of the simplex
method, the objective function is transformed
by subtracting from it a multiple of the row in
which the pivot was performed.
Consequently, the final form of the objective
function could be obtained by subtracting
multiples of the original constraints from theoriginal objective function.
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Relationship between shadow prices,
reduced costs and the problem data
Consider first the final objective coefficientsassociated with the original basic variablesxn+1,
xn+2, . . . ,xn+mand let1, 2, . . . , nbe themultiples of each row that are subtracted from
the original objective function to obtain its finaloptimal form.
Sincexn+iappears only in the ith constraint andhasa+1 coefficient, we should have:
which, combined with means that
The shadow prices yi
are the multiples
i
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The multiples can be used to obtain every objectivecoefficient in the final form.
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Since
for the m basic variables of the optimal solution, we
have:
This is a system of m equations in m unknowns that
uniquely determines the values of the shadow pricesyi.
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VARIATIONS IN THE OBJECTIVECOEFFICIENTS
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Variations in the objective coefficients
How much the objective-function coefficients
can vary without changing the values of the
decision variables in the optimal solution?
We will make the changes one at a time,
holding all other coefficients and righthand-
side values constant.
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Variation of objective coefficient ofx3,
a nonbasic variable in our example
Suppose that we increase the objective function
coefficient ofx3in the original problem formulation
by c3:
In applying the simplex method, multiples of the
rows were subtracted from the objective function to
yield the final system of equations.
Therefore, the objective function in the final tableau
will remain unchanged except for the addition
of c3x3.
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x3 will become a candidate to enter the optimal solution at apositive level, i.e., to enter the basis, only when its objective-
function coefficient is positive. The optimal solution remains
unchanged so long as:
Equivalently, we know that the range on the original objective-
function coefficient ofx3, say c3new, must satisfy
< c3new
6 4/7 if the optimal solution is to remain unchanged.
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Variation of objective coefficient ofx1,
a basic variable in our example
Suppose now that we increase the objective function
coefficient ofx1in the original problem formulation
by c1:
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Asx1is basic, this tableau is not canonical and
therefore a pivot operation has to be made.
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In order to have the current solution remainunchanged:
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Taking the most limiting inequalities, the
bounds on c1are:
If we let c1new= c1+ c1be the objective-
function coefficient ofx1
in the initial tableau,
then:
Which variables will enter and leave the basis
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Which variables will enter and leave the basis
when the new cost coefficient reaches either
of the extreme values of the range?
When c1new= 5 2/5:
the objective coefficient ofx5in the final tableau
becomes 0; thusx5enters the basis for any furtherincrease ofc1
new
by the usual ratio test of the simplex method
variablex6leaves the basis:
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When c1new= 4 7/11:
the objective coefficient ofx3in the final tableau
becomes 0; thusx3enters the basis for any further
decrease ofc1new by the usual ratio test of the simplex method
variablex1leaves the basis.
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VARIATIONS IN THE RIGHTHAND-SIDE VALUES
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Overview
When changing a righthand-side, the values ofthe decision variables are clearly modified!
But any change in the righthand-side values that
keep the current basis, and therefore thecanonical form, unchanged has no effect uponthe objective-function coefficients.
Consequently, the righthand-side ranges are such
that the shadow prices and the reduced costsremain unchanged for variations of a single valuewithin the stated range.
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Varying the righthand-side value for the
demand limit on six-ounce juice glasses
If we add an amount b3to the righthand side
of this constraint, the constraint changes to:
x1is nonbasic (equal to zero) andx6was basic
in the initial tableau and is basic in the optimal
tableau, thereforex6is merely increased or
decreased by b3. In order to keep thesolution feasible:
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This implies that:
or, equivalently, that:
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Varying the righthand-side value for the
storage-capacity constraint
If we add an amount b2to the righthand side
of this constraint, the constraint changes to:
This is equivalent to decreasing the value of
the slack variablex5of the corresponding
constraint byb2; that is, substitutingx5 b2
forx5in the original problem formulation.
In this case,x5, which is zero in the final
solution, is changed tox5= b2.
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Making these substitutions in the final tableau
provides the following relationships:
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In order for the current basis to remain optimal, it
need only remain feasible, since the reduced costs
will be unchanged by any such variation in the
righthand-side value:
which implies:
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All these computations can be carried out
directly in terms of the final tableau
When changing the ithrighthand-side by bi , we
simply substitute bifor the slack variable in the
corresponding constraint and update the current
values of the basic variables accordingly:Example for b2
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Variable transitions
When changing demand on six-ounce juiceglasses, we found that the basis remains optimalif b3
new6 3/7 and that for b3new< 6 3/7 , the
basic variablex6
becomes negative.
In the later casex6has to leave the basis, sinceotherwise it would become negative.
What variable would then enter the basis to take
its place? In order to have the new basis be anoptimal solution, the entering variable must bechosen so that the reduced costs are not allowedto become positive.
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Regardless of which variable enters the basis,
the entering variable will be isolated in row 2
of the final tableau to replacex6, which leaves
the basis.
To isolate the entering variable, we must
perform a pivot operation, and a multiple, say
t, of row 2 in the final tableau will besubtracted from the objective-function row.
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Assuming that b3newwere set equal to 6 3/7 in
the initial tableau the final tableau would be:
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In order that the new solution be an optimalsolution, the coefficients of the variables in the
objective function of the final tableau must benonpositive:
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Since the coefficient ofx3is most constrainingon t, x3will enter the basis. Note that therange on the righthandside value and the
variable transitions that would occur if thatrange were exceeded by a small amount areeasily computed.
However, the pivot operation actually
introducingx3into the basis and eliminatingx6need not be performed.
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ALTERNATIVE OPTIMAL SOLUTIONSAND SHADOW PRICES
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Alternative optimal solutions
As in the case of the objective function and
righthand-side ranges, the final tableau of the
linear program tells us something conservative
about the possibility of alternative optimalsolutions
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If all reduced costs of the nonbasic variablesare strictly negative (positive) in amaximization (minimization) problem, then
there is no alternative optimal solution,because introducing any variable into thebasis at a positive level would reduce(increase) the value of the objective function.
If one or more of the reduced costs are zero,there may exist alternative optimal solutions.
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Example
x3could be introduced into the basis without changing
the value of the objective function. By the minimum ratiox1leaves the basis.
The alternative optimal solution is then found bycompleting the pivot that introducesx3and eliminatesx1.
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Alternative shadow prices
Independent of the question of whether or
not alternative optimal solutions exist in the
sense that different values of the decision
variables yield the same optimal value of theobjective function, there may exist alternative
optimal shadow prices.
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If all righthand-side values in the final tableau
are positive, then there do not exist
alternative optimal shadow prices.
If one or more of these values are zero, thenthere mayexist alternative optimal shadow
prices.
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Example
Since the righthand-side value in row 2 is zero, it is possibleto dropx6(basic variable in row 2) from the basis as long as
there is a variable to introduce into the basis. The variable to be introduced into the basis can be
determined from the entering variable condition: