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· PDF fileSet P Q correctly shaded, award K1 K1 K2 P 3 Q R P Q R P Q R SULIT

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  • SULIT 1449/2(PP)

    [Lihat sebelah 1449/2(PP) SULIT

    1449/2 (PP) Matematik Kertas 2 Peraturan Pemarkahan 17 Sept 2008

    PERSIDANGAN KEBANGSAAN PENGETUA-PENGETUA

    SEKOLAH MENENGAH NEGERI KEDAH DARUL AMAN.

    PEPERIKSAAN PERCUBAAN SPM 2008

    UNTUK KEGUNAAN PEMERIKSA SAHAJA

    Peraturan pemarkahan ini mengandungi 17 halaman bercetak

    MATHEMATICS

    Kertas 2

    PERATURAN PEMARKAHAN

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  • SULIT 1449/2(PP)

    1449/2(PP) SULIT

    2

    Section A [ 52 marks]

    Question Solution and Mark Scheme Marks

    1(a)

    (b)

    Note: Set P Q correctly shaded, award K1

    K1

    K2

    3

    P Q R

    P Q R

    P Q R

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  • SULIT 1449/2(PP)

    [Lihat sebelah 1449/2(PP) SULIT

    3 Question Solution and Mark Scheme Marks

    2

    3 21p q or 22 143

    p q or equivalent

    5 25p or 5 103

    q or equivalent

    OR

    42

    qp or 4 2q p or equivalent (K1)

    5 25p or 5 103

    q or equivalent (K1)

    OR

    1 71131 41 1 2 2 1

    3

    pq

    or equivalent (K2)

    5p

    6q Note : Accept

    1. 56

    pq

    as final answer, award N1

    2.

    111311 1 2 2 1

    3

    or equivalent seen, award (K1)

    K1

    K1

    N1

    N1

    4

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  • SULIT 1449/2(PP)

    1449/2(PP) SULIT

    4

    Question Solution and Mark Scheme Marks 3

    23 10 0x x

    3 5 2 0x x or equivalent

    2x

    53

    x or 1 67

    Note : 1. Accept without = 0

    2. Accept three terms on the same side, in any order.

    3. Do not accept solutions solved not using factorisation.

    4. Accept 5 52 0, with , 23 3

    x x x

    for KK2

    K1

    K1

    N1

    N1

    4

    4

    Identify UPT or TPU

    tan 2 2

    75 4

    UPT

    or equivalent

    66 8 or 66 48 '

    P1

    K1

    N1

    3

    5(a)

    (b)

    32

    y

    Gradient SR = 4

    *6 41

    yx

    or *6 4 1 c or equivalent

    4 10y x or equivalent 10

    N1

    P1

    K1

    N1

    N1

    5

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  • SULIT 1449/2(PP)

    [Lihat sebelah 1449/2(PP) SULIT

    5

    Question Solution and Mark Scheme Marks

    Non-statement P1

    Implication 1 : If x p > y p , then x > y K1

    Implication 2 : If x > y, then x p > y p K1

    6(a)

    (b)

    (c) If k is a multiple of 9, then it is multiple of 3 P1

    True dep P1

    (d) Premise 2 : 384 is divisible by 12

    or

    384 boleh dibahagi tepat dengan 12 K1 4

    7(a)

    (b)

    90 222 14360 7

    or 60 222 7360 7

    14 + 90 222 14360 7

    + 60 222 7360 7

    + 7 + 7

    172

    3 or 157

    3 or 57 33

    290 22 14360 7

    or 2180 22 7360 7

    or 260 22 7360 7

    290 22 14

    360 7 2180 22 7

    360 7 + 260 22 7

    360 7

    3083

    or 21023

    or 102 67

    Note :

    1. Accept for K mark. 2. Correct answer from incomplete working, award KK2.

    K1

    K1

    N1

    K1

    K1

    N1

    6

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  • SULIT 1449/2(PP)

    1449/2(PP) SULIT

    6

    Question Solution and Mark Scheme Marks

    8(a)

    (b)

    1 23 5

    215

    85

    31

    52

    31

    52

    31

    Note : 1 23 5 or 1 3

    3 5 or

    85

    31 , award K1

    (with condition of not more than 3 pairs)

    360195 or

    12065 or

    2413 or 0.5417

    K1

    N1

    K2

    N1

    5

    9(a)

    (b)

    10k

    3p

    4 2 413 1 24 1 2 3

    xy

    2x

    1y Note :

    1. * inverse 4

    matrix 2xy

    or

    4 213 14 1 2 3

    seen,

    award K1

    2. Do not accept * inverse 1 2

    matrix 3 4

    or * inverse 1 0

    matrix 0 1

    .

    3. 21

    xy

    as final answer, award N1.

    4. Do not accept any solution solved not using matrices.

    P1

    P1

    K2

    N1

    N1

    6

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  • SULIT 1449/2(PP)

    [Lihat sebelah 1449/2(PP) SULIT

    7

    Question Solution and Mark Scheme Marks

    10(a) 9

    P1

    (b) 9 3 3 95 0 0 5

    or

    K1

    6 11 1 25 5

    or or

    N1

    Note: Without working, award K1N1

    (c) 1 13 9 5 5 9 9 21 16 1532 2

    t t or equivalent K2

    12 N1 6

    Note : Allow one mistake in distance expression for any two or

    one correct areas for K1.

    11

    40 7

    1 22 3 3 53 7

    40 7 1 22 3 3 53 7

    232 8 232 9

    Note: 1. Accept for K mark 2. Correct answer from incomplete working, award KK2

    K1

    K1

    K1

    N1

    4

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  • SULIT 1449/2(PP)

    1449/2(PP) SULIT

    8

    Question Solution and Mark Scheme Marks

    12(a)

    (b)

    (c)(i)

    (ii)

    (d)

    10

    5

    Note : K only meant for table value Graph Axes drawn in correct direction, uniform scales in 3 5 x 4 and 34 y 11 7 points and *2 points correctly plotted or curve passes through these points for 3 5 x 4