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Unified Field Explained 9
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¡ All physical constants are RATIOS
¡ Every RATIO is a RATIO between two charges
¡ These two charges move following the law of Sin and Cosine
¡ The sum of both functions represent the total field.
LEFT RIGHT
LET US BEGIN TAKING A SNAP SHOT AT A WAVE MOVING AHEAD:
WE HAVE FOUND THE TWO OPPOSED FORCES AT REST
ONE TO THE LEFT : THE COSINE “Y “ at 180° = -‐1 ONE TO THE RIGHT: THE SIN “ Y” at 0° = 0
Sin Y= 0 Cos Y=-‐1
Sin Y= 0 H +
Cos Y=-‐1 O -‐
In Order to make it less abstract we put two opposite forces: Oxygen to the left and Hydrogen to the right
Then let´s observe them move 45°
Magnetism: Sin Y = + 0.70711 Cos Y = + 0.70711
H-‐OH
Electricity Sin Y = + 0.70711 Cos Y= -‐ 0.7011
OH-‐H
Sin Y= 0 H+
Cos Y=-‐1 O-‐
Magnetism: Sin Y = + 0.70711 Cos Y = + 0.70711
H-‐OH
Electricity Sin Y = + 0.70711 Cos Y= -‐ 0.7011
OH-‐H
Now we have: ELECTRICITY and MAGNETISM at an angle of 90° between them.
And ionized Water as Hydrogen Hydroxide
Sin Y= 0 H+
Cos Y=-‐1 O-‐
Magnetism: Sin Y = + 0.70711 Cos Y = + 0.70711
H-‐OH
Electricity Sin Y = + 0.70711 Cos Y= -‐ 0.7011
OH-‐H
GRAVITY: Sin 90°= 1 Cos 90°= 0
G= Sin Y + Cos Y = 1 + 0 = 1 And H2O WATER! (MATTER)
G
• When the two polar forces oppose, at sin 0°=0, and Cos 180°= -1 ,
the resultant field is 100% an EMISSION FIELD.
• When the two polar forces oppose at an angle of 90°, the resultant field is a MAGNETIC FIELD/ ELECTRICAL
FIELD
• When the two polar forces approach Sin 90°=1 and Cos 90°=0 both vectors add, changing direction 180°, thus the resultant force will oppose the emission field
and it is called Gravity
So Gravity is the sum: G = sin y + cos y
G = 1 + 0 Which means that the resultant force will be
equal to 1, or almost one, as 0.981 . Now, G, the constant, the gravitational constant, in Newton
´s equation: F=G (M1M2)/r2
Actually represents the sine added to the cosine of the angle equal to 90°
G = Sin y + Cos y = 1 – 0 = 1 Note: We have divided G/10=0.981
So the Max Planck´s equation: E= hν
h = Sin y + Cos y
ν=C/λ
Becomes the equation of the Unified Field:
E= (Sin y + Cos y)x ν or
E= (Sin y + Cos y)(C/λ)
79° Gravity
Elec
tricity
Magnetism
Earth Gravity= 9.81 Nm 10 – 9,81 = 0.19 Sin 0.19 = 78.5°
78.5°
Gravity at the northen hemisphere
78.5°
Gravity at the southern hemisphere
11.5°
Ecliptic
Sin 23°=0.391
The two vectors of Gravity add, Giving as the result the inclination of axis of the Earth on Ecliptic
23°
The Pythagorean Monochord
1
1
2 =1.414….. +
Electricity Sin Y = + 0.70711 Cos Y= -‐ 0.7011
Magnetism: Sin Y = + 0.70711 Cos Y = + 0.70711
Pythagoras Monochord
Terra: Earth, Solid
Aqua: Water, Liquid
Ignis :Fire, Plasma
Aer : Air, Gas
The eccentricity of planets´orbits it is
related to the intensity of the emission field =
Cos y
Mercury eccentricity= 0.21AC Phase angle Deg.: 22.33 Cos y (grades) Cos y
78.14 168.14 -‐0.978636Gravity (sin y) Field (-‐cos y) EM field
Φ= 0.38 -‐0.98 -‐0.5987 -‐5.99 NmVenus eccentricity= 0.01
AC Phase angle Deg.: 64.16 Cos y (grades) Cos y89.61 179.61 -‐0.999977
Gravity (sin y) Field (-‐cos y) EM fieldΦ= 0.90 -‐1.00 -‐0.1000 -‐1.00 Nm
Earth eccentricity= 0.02AC Phase angle Deg.: 78.81 Cos y (grades) Cos y
1.38 89.04 179.04 -‐0.999861Gravity (sin y) Field (-‐cos y) EM field
Φ= 0.98 -‐1.00 -‐0.0189 -‐0.19 NmMoon (a) eccentricity= 0.03
AC Phase angle Deg.: 38.46 Cos y (grades) Cos y88.51 178.51 -‐0.999662
Gravity (sin y) Field (-‐cos y) EM fieldΦ= 0.62 -‐1.00 -‐0.3777 -‐3.78 Nm
Moon (b) eccentricity= 0.08AC Phase angle Deg.: 22.33 Cos y (grades) Cos y
85.58 175.58 -‐0.997031Gravity (sin y) Field (-‐cos y) EM field
Φ= 0.38 -‐1.00 -‐0.6170 -‐6.17 NmMars eccentricity= 0.09
AC Phase angle Deg.: 22.33 Cos y (grades) Cos y84.64 174.64 -‐0.995629
Gravity (sin y) Field (-‐cos y) EM fieldΦ= 0.38 -‐1.00 -‐0.6156 -‐6.16 Nm
Jupiter eccentricity= 0.05AC Phase angle Deg.: -‐39.79 Cos y (grades) Cos y
87.23 177.23 -‐0.998833Gravity (sin y) Field (-‐cos y) EM field
Φ= 2.64 -‐1.00 1.6412 16.41 NmSaturn eccentricity= 0.06
AC Phase angle Deg.: 68.43 Cos y (grades) Cos y86.79 176.79 -‐0.998431
Gravity (sin y) Field (-‐cos y) EM fieldΦ= 0.93 -‐1.00 -‐0.0684 -‐0.68 Nm
Uranus eccentricity= 0.05AC Phase angle Deg.: 62.87 Cos y (grades) Cos y
87.36 177.36 -‐0.998937Gravity (sin y) Field (-‐cos y) EM field
Φ= 0.89 -‐1.00 -‐0.1089 -‐1.09 NmNeptune eccentricity= 0.01
AC Phase angle Deg.: -‐6.89 Cos y (grades) Cos y89.44 179.44 -‐0.999953
Gravity (sin y) Field (-‐cos y) EM fieldΦ= 1.12 -‐1.00 0.1200 1.20 Nm
A proof of Mercury´s emission field
It is obvious that at Sin y= 90°the Emission Field is at its Maximum and the Gravity Field, being equal to
Cos y=0 is at its Minimum, so the Emission Field is at its Minimum at
Sin y=270°=-1and the Gravity Field is at its Maximum at Cos y=270°=0
Thus: • The lesser the emission field the greater the
gravity (mass) field:
• E = (Sin y + Cos y)(C/λ)
We have adopted the notation Where the Maximum EM Field “Repulsion” be expressed as
A NEGATIVE VALUE/CHARGE
Sin y + Cos Y إإمماامم إإمماامم √2
1 1
The Unified field
A wave……..
EVERYTHING IS ELECTRIC AND EVERY PHENOMENON IN NATURE IS AN ALTERNATE CURRENT”…..AT DIFFERENT
PHASE ANGLES BETWEEN THE TWO OPPOSITE FORCES
In order to know how Energy develops following The Unified Field Law, let us do: E = ( S i n y + C o s y ) x ν E= (Sin y * ν ) + (Cos y * ν ) T h u s , l e t u s t a k e s o m e k n o w n f r e q u e n c i e s ; S o u n d f r e q u e n c i e s a n d p l o t t h e m :
WE GET A LOGARITHM SPIRAL The perfect expression of Power from a Birkeland Current, or an Alternate Current or……
Andromeda galaxy, under IR light,
where all the Suns look connected
SPIRAL APPEARED IN NORWAY DEC.9TH. 2009
The FIBONACCI series The Way of Nature The Way of The Unifed Field!
Sin Y= 0 Cos Y=-‐1
EMISSION FIELD
GRAVITY FIELD
45 ° 45 °
Sin Y + Cos Y
180°
Adolfo Rios Pita Giurfa
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