Training New Employees

TRAINING NEW EMPLOYEES

Presenter NamePresentation Date

Questions 8 & 10

Answers Included!

Mitchell P2 8-5Modelling WithCombined Functions

Relax! We already

did all the work for you.

1st and only edition

Question 8

.

Analyzing the Question

.

Take away irrelevant/unimportant information

Preparing to Graph- Separate each part of skier’s run into

separate instances- Graph each one individually before

combining them all- Make height of hill 60m, as it is the

easiest number to work with

The Graph:

Meaning of the Graph:

Skier is going downhill

Skier riding up chairlift

Skier waiting for chairlift

Algebraic Expressions

- Unfortunately, we don’t know any algebraic expressions that result in such a graph

- Instead, make 3 different equations for each interval!

Algebraic Expressions:

h (𝑡 )=−𝑡+60

h (𝑡 )=.5 𝑥−60.

h (𝑡 )=0

Negative Slope of 1m/s

Hill height is 60m

Constant height of 0

Positive Slope of .5m/s

Crosses t – intercept at 120

Question 10

Analyzing the Question

Requires - Scatter Plot - Graphing

Calculator - Thinking Cap

Scatter Plot- Nothing really to it, just plot the

points on a graph with a reasonable scale and axis titles

Regression

- As you can see, the imaginary curve of best fit does not resemble cubic or linear regressions

- Therefore, comparing logarithmic and quadratic regression would be the best approach here

The Result

Outlier in 1966

N(t) with outlier

N(t) without outlier

- As you can tell from the data, in 1966 there were only 6 hockey teams

- This information functions as an outlier negatively affects the curve of best fit

- Removing the outlier from your data can make a very noticeable impact on regression

Outlier in 1966 Cont’d

N(t) with outlier

N(t) without outlier

NOW, ON TO HOMEWORK!

FT. SAMI