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Mrs. Meeks
hypotenuse
leg
leg
x6 in
8 in
a² + b² = c²
x6 in
8 in
a² + b² = c²6² + 8² = c²
x6 in
8 in
a² + b² = c²6² + 8² = c²36 + 64 = c²
x6 in
8 in
a² + b² = c²6² + 8² = c²36 + 64 = c² 100 = c²
x6 in
8 in
a² + b² = c²6² + 8² = c²36 + 64 = c² √100 = √c²
x6 in
8 in
a² + b² = c² 6² + 8² = c² 36 + 64 = c² √100 = √c² 10 = cThe hypotenuse is 10 in.
5 ina
4 in
a² + b² = c²a² + 4² = 5²
5 ina
4 in
a² + b² = c²a² + 4² = 5²a² + 16 = 25
5 ina
4 in
a² + b² = c²6² + 8² = c²a² + 16 = 25 -16 -16 a² = 9
5 ina
4 in
a² + b² = c²6² + 8² = c²a² + 16 = 25 -16 -16 √a² = √9
5 ina
4 in
a² + b² = c²6² + 8² = c²a² + 16 = 25 -16 -16 √a² = √9 a = 3
The missing leg is 3in.
Now we will watch this video demonstrating the Pythagorean Spiral project. You will have 3 days to complete the project. Make sure you read the directions and rubric carefully!
Click image to go to video
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