Mrs. Meeks

hypotenuse

leg

leg

x6 in

8 in

a² + b² = c²

x6 in

8 in

a² + b² = c²6² + 8² = c²

x6 in

8 in

a² + b² = c²6² + 8² = c²36 + 64 = c²

x6 in

8 in

a² + b² = c²6² + 8² = c²36 + 64 = c² 100 = c²

x6 in

8 in

a² + b² = c²6² + 8² = c²36 + 64 = c² √100 = √c²

x6 in

8 in

a² + b² = c² 6² + 8² = c² 36 + 64 = c² √100 = √c² 10 = cThe hypotenuse is 10 in.

5 ina

4 in

a² + b² = c²a² + 4² = 5²

5 ina

4 in

a² + b² = c²a² + 4² = 5²a² + 16 = 25

5 ina

4 in

a² + b² = c²6² + 8² = c²a² + 16 = 25 -16 -16 a² = 9

5 ina

4 in

a² + b² = c²6² + 8² = c²a² + 16 = 25 -16 -16 √a² = √9

5 ina

4 in

a² + b² = c²6² + 8² = c²a² + 16 = 25 -16 -16 √a² = √9 a = 3

The missing leg is 3in.

Now we will watch this video demonstrating the Pythagorean Spiral project. You will have 3 days to complete the project. Make sure you read the directions and rubric carefully!

Click image to go to video