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A2 Biology
unit F215 – exam 1hour 45 mins50% of marks for A2
Population genetics
includes
Hardy Weinberg equations,
natural selection and artificial selection
Call for European Cystic Fibrosis healthcare gap to be closed
Press release 19 March 2010 by Bristol University• A healthcare gap amounting to a ‘death sentence’ for
Cystic Fibrosis (CF) children born in Eastern Europe must be closed say researchers from the EuroCareCF Coordination Action for Cystic Fibrosis.
• “We know that this disease occurs randomly in about 1 in 4,000 children born to healthy parents across the EU,” he said. “Despite this, the team encountered many fewer people with CF in poorer countries. CF patients there die far younger than in long standing EU countries.”
• Understanding the inheritance of characteristics and of population genetics can help governments to plan healthcare.
2 inherited characters in humans – both involve autosomal recessive alleles
Cystic fibrosis – excessive mucus in bronchioles reduces gas exchange + few digestive enzymes from pancreas reach gut
PKU = phenylketonuria – enzyme to convert phenylalanine into tyrosine not present; child has light skin and hair + brain damage (now blood test at birth + special diet)
Key definitions page 2
1) A population of a species is:-
a group of organisms which have similar characteristics e.g. anatomy, physiology, biochemistry and behaviour and which can interbreed to produce fertile offspring
2) The gene pool is:-
all the genes in the gametes of a population from which the genotypes or genomes of the next generation are formed
The Hardy Weinberg principle predicts that:-the frequency of an allele in the gene pool will not
change from one generation to the next (and so the frequency of genotypes / genomes also remains constant)
this is only true if
• the population is very large• there is no immigration or emigration from the
population • mating is random• all genotypes are equally fertile • there are no random mutations
Which could be met by a natural population?
Hardy Weinberg equations
• Allele frequency • frequency of dominant allele = p• frequency of recessive allele = q• total frequency of alleles for a character in the
population = 1
p + q = 1
So if r = 0.6 then frequency of R = 0.4
Hardy Weinberg equations
p2 = frequency of homozygous dominant genotype2pq = frequency of heterozygous genotypeq2 = frequency of homozygous recessive genotype
total frequency of all genotypes in population = 1
p2 + 2pq + q2 = 1
So if frequency rr is 0.39 and RR is 0.34 frequency of Rr = 0.27
Tables for Hardy-Weinberg calculations
decimal %
allele
p
allele
q
decimal%
genotype
p2
genotype
2pq
genotype
q2
Hardy Weinberg - answers
1) p = 0.3 and q = 0.7;
Genotype frequencies = 9% 49% 42%
2)a) q = 0.3 or 30% b) 0.49 or 49%
c) 0.42 or 42%
3) q = 0.008 or 0.8%
Hardy Weinberg - answers
4)a) q = 0.42 or 42% b) p = 0.58 or 58%
c) 33% and 49%
5)a) q = 0.07 so p = 0.93
b) 0.49% c) 0.13 or 13%
6)a) q = 0.01 b) 0.0198 or 1.98%
Hardy Weinberg - answers7) a) q = 0.4 homozygotes = 0.36 or 36%
heterozygotes = 0.48 or 48%
b) Allele for sickle cell anaemia gives resistance to malaria = an environmental selection pressure
People with allele for normal haemoglobin and for sickle cell haemoglobin have selective advantage where malaria is present so more likely to survive and pass on alleles to offspring
c) If malaria eradicated no advantage to have sickle cell allele
Also need large population, no immigration or emigration, random mating, equal fertility and no mutations
Hardy Weinberg - answers8)a) q = 0.6
Homozygotes = 0.16 or 16%
Heterozygotes = 0.48 or 48%
b) No selective advantage to be tongue roller – remains same if all the conditions of Hardy-Weinberg equation are fulfilled
9)a) no – until very recently people with cystic fibrosis have not reproduced
b) Termination of pregnancies may reduce allele frequencies – but gene may still mutate
Genetic drift and frog hoppers
1) St Agnes + St Mary’s – all striped;Other islands – striped and melanic but proportions vary;On all but one island more striped than melanic
2) Small population on island; may only have genes for striped = founder effect;Or chance means some genotypes reproduce more than
others – large effect on phenotypes as small number of individuals
3) Difficult!Allow small populations to breed for several generations in
lab and record resultsIn field could investigate environmental factors which might
affect breeding e.g. temperature, shelter, camouflage
Speciation – development of a new species
Needs reproductive isolation of a population so individuals cannot interbreed
Alleles do not pass from one gene pool to the other
Allopatric speciation = geographical isolation
Sympatric speciation = behavioural / seasonal isolation
Peppered moths – evolution in action http://www.biologycorner.com/worksheets/pepperedmoth.html
Which moths survive? Why are the moths
Why? different colours in different areas?
Definition of a species p11
Biological definition
Phylogenetic / evolutionary / cladistic definition
Why have 2 definitions?
Are they equally useful?
Artificial selection and natural selection Similarities and differences p13
Both select the organisms to reproduce
Humans choose the characteristics in artificial selection and it usually produces lower genetic diversity in the gene pool
Selection pressures in natural selection are less likely to reduce genetic diversity of the
species
Selective breeding = humans select the organisms that will reproduce
(this is not genetic engineering)
• Choose parents which show the desired characteristic (animals or plants)
• e.g. resistance to disease, speed of growth, height, milk yield
• Breed the parents • Select the offspring with the desired
characteristic• Use them for breeding• Continue for many generations
(detailed records needed)
• Result - desired features are more obvious but genetic diversity is decreased by the inbreeding
Producing bread wheat Triticum aestivum by artificial selection
1) Wild einkorn wheat 2N = 14 chromosomes = AA genome (haploid number = 7)
2) Einkorn wheat – artificial selection of desired characters by early farmers 2N = 14 chromosomes = AA genome
3) Crossed with wild grass 2N = 14 chromosomes = BB genome (happened by chance)Gametes fusing = A and B genomesProduced sterile hybrid 14 chromosomes = AB genome (no homologous pairs so meiosis cannot produce gametes)
Producing bread wheat Triticum aestivum by artificial selection
4) Random mutation chromosome number doubles tetraploid 4N = 28
Emmer wheat has genome AABB
5) Chance cross with goat grass 2N = 14 chromosomes = DD genome
Produced sterile hybrid – gametes fusing are AB and D – meiosis unsuccessful
6) Random mutation chromosome number doubles hexaploid 6N = 42
Modern bread wheat Triticum aestivum has genome AABBDD
Cloning animals – advantages or disadvantages?
• Many animals with desired characters produced
• Infertile animals can reproduce• Rare animals conserved
• Animals genetically identical• Very labour intensive and needs sterile
facilities and highly trained staff• Breeding can occur at any time of year
• Genetically modified animals can be used to produce pharmaceutical chemicals
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