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Vedic Maths
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How to findSquares of Numbers ending in 5
in less than 3 seconds?
352 452 852 etc.
Lets take for example
35
35x
Here we see that
35
35x
That the Units place adds upto 5+5 = 10 and that the Ten’s place is same.
When this is true what we do is
35
35x
Apply the Word Formulae ‘ By one more than the One before” to the ten’s place.
So Whats 1 more than 3?. It is 4. So we multiply 3 with 4 to get 12. That’s the first part
of our answer.
12
To get the second part of our answer
35
35x
We multiply 5 with 5 to get 25. That’s the second part of our answer.
So our answer becomes 1225.
1225
Now try
85
85x
Solution
85
85x
7225 We multiply 5 with 5 to get 25. And multiply 8
with the next number 9 to get 72. So our answer becomes 7225. Simple.
Now try 452 552 652 952 1052 1252 etc.
in the same way.
Now what do we do for these sums?
26
24x
48
42x
67
63x
Now what do we do for these sums?
26
24x
48
42x
67
63x
Note that the units add upto 10 and the tens place is same.
So we can apply the same rule “ By one more than
the One before” . Lets see what we get.
26
24x
48
42x
67
63x
26
24x
48
42x
67
63x
6|24 20|16 42|21In 48 x 42 we have 4 multiplied with the next number 5 which gives us 20 and 8 x2 which
gives us 16. Therefore our answer 2016. Similarly try the other sums.