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Chapter # 5 : Sequential Circuit

Sequential

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Page 1: Sequential

Chapter # 5 :Sequential Circuit

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Combinational Circuit

• So far we’ve just worked with combinational circuits, where applying the same inputs always produces the same outputs.

• This corresponds to a mathematical function, where every input has a single, unique output.

• No way of remembering or storing information after inputs have been removed.

CombinationalcircuitInputs Outputs

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Sequential Circuit

• The outputs of a sequential circuit depend on not only the inputs, but also the state, or the current contents of some memory.

• This makes things more difficult to understand, since the same inputs can yield different outputs, depending on what’s stored in memory.

• The memory contents can also change as the circuit runs. Combinational

circuitInputs

Memory

Outputs

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Sequential Circuit

• Many real-life devices are sequential in nature:– Combination locks open if you enter numbers in

the right order.– Elevators move up or down and open or close

depending on the buttons that are pressed on different floors and in the elevator itself.

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Types of Sequential Circuits

• Synchronous

– State changes synchronized by one or more clocks

• Asynchronous

– Timing of changes are independent of any clocks

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Synchronous Sequential Circuits

• Changes enabled by clock

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Storage Elements

• Latch

• Flip-Flop – a latch that transitions on a clock

• Registers

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Memory• A memory should have at least three properties.

1. It should be able to hold a value.2. You should be able to read the value that was saved.3. You should be able to change the value that’s saved.

• We’ll start with the simplest case, a one-bit memory.

1. It should be able to hold a single bit, 0 or 1.2. You should be able to read the bit that was saved.3. You should be able to change the value. Since there’s only a single bit, there

are only two choices:– Set the bit to 1– Reset, or clear, the bit to 0.

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Basic Idea of Storage

• How can a circuit “remember” anything, when it’s just a bunch of gates that produce outputs according to the inputs?

• The basic idea is to make a loop, so the circuit outputs are also inputs.

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SR (set-reset) Latches

S

Q

Q’

R

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SR (set-reset) Latches

• Here Q and Q’ feed back into the circuit. They’re not only outputs, they’re also inputs!

• To figure out how Q and Q’ change, we have to look at not only the inputs S and R, but also the current values of Q and Q’: Qnext = (R + Q’current)’

Q’next = (S + Qcurrent)’

Qnext = (R + Q’current)’Q’next = (S + Qcurrent)’

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SR (set-reset) Latches

• What if S = 0 and R = 0?• The equations reduce to:

Qnext = (0 + Q’current)’ = Qcurrent

Q’next = (0 + Qcurrent)’ = Q’current

• So when SR = 00, then Qnext = Qcurrent. Whatever value Q has, it keeps.

• This is exactly what we need to store values in the latch.

SR = 00

Qnext = (R + Q’current)’Q’next = (S + Qcurrent)’

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SR (set-reset) Latches

• What if S = 1 and R = 0?• Since S = 1, Q’next is 0, regardless of Qcurrent:

Q’next = (1 + Qcurrent)’ = 0

• Then, this new value of Q’ goes into the top NOR gate, along with R = 0.

Qnext = (0 + 0)’ = 1

• So when SR = 10, then Q’next = 0 and Qnext = 1.• This is how you set the latch to 1. The S input stands

for “set.”

SR = 10

Qnext = (R + Q’current)’Q’next = (S + Qcurrent)’

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SR (set-reset) Latches

• Notice that it can take up to two steps (two gate delays) from the time S becomes 1 to the time Qnext becomes 1.

• But once Qnext becomes 1, the outputs will stop changing. This is a stable state.

SR = 10

Qnext = (R + Q’current)’Q’next = (S + Qcurrent)’

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SR (set-reset) Latches

0. Suppose that initially, Q = 0 and Q’ = 1.

1. Since S=1, Q’ will change from 1 to 0after one NOR-gate delay (marked byvertical lines in the diagram for

clarity).

2. This change in Q’, along with R=0, causes Q to become 1 after another gate delay.

3. The latch then stabilizes until S or Rchange again.

SR = 10

Qnext = (R + Q’current)’Q’next = (S + Qcurrent)’

S

R

Q

Q’

0 1 2 3 4

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SR (set-reset) Latches

• What if S = 0 and R = 1? • Since R = 1, Qnext is 0, regardless of Qcurrent:

Qnext = (1 + Q’current)’ = 0

• Then, this new value of Q goes into the bottom NOR gate, where S = 0.

Q’next = (0 + 0)’ = 1

• So when SR = 01, then Qnext = 0 and Q’next = 1.• This is how you reset, or clear, the latch to 0. The R

input stands for “reset.”• Again, it can take two gate delays before a change in

R propagates to the output Q’next.

SR = 01

Qnext = (R + Q’current)’Q’next = (S + Qcurrent)’

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SR Latches are Memories

• This little table shows that our latch provides everything we need in a memory: we can set it, reset it, and remember the current value.

S R Q

0 0 No change0 1 0 (reset)1 0 1 (set)

The output Q represents the data stored in the latch. It is sometimes called the state of the latch.

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SR Latches are Memories• We can expand the table above into a state table, which

explicitly shows that the next values of Q and Q’ depend on their current values, as well as on the inputs S and R.

I nputs Current NextS R Q Q’ Q Q’

0 0 0 1 0 10 0 1 0 1 0

0 1 0 1 0 10 1 1 0 0 11 0 0 1 1 01 0 1 0 1 0

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SR Latches are Sequential

• Notice that for inputs SR = 00, the next value of Q could be either 0 or 1, depending on the current value of Q.

• So the same inputs can yield different outputs, depending on whether the latch was previously set or reset.

• This is very different from the combinational circuits that we’ve seen so far, where the same inputs always yield the same outputs.

I nputs Current NextS R Q Q’ Q Q’

0 0 0 1 0 10 0 1 0 1 0

0 1 0 1 0 10 1 1 0 0 11 0 0 1 1 01 0 1 0 1 0

S R Q

0 0 No change0 1 0 (reset)1 0 1 (set)

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What about SR = 11Qnext = (R + Q’current)’Q’next = (S + Qcurrent)’

0

0

0

0

0

0

1

1

Circuit ossiclates between 00 and 11 under the assumption that both NOR gates have exaclty the same delay.

Practically this would not be true so the state would be either 01 or 10.

Since we cannot predict it, so the latch is said to be in undefined state for input 11.

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SR Latches

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S’R’ Latch

• Similar – made from NANDs

R

Q

QN

S

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S’R’ Latch

• This is just like an SR latch, but with inverted inputs, as you can see from the table.• You can derive this table by writing equations for the outputs in terms of the

inputs and the current state, just as we did for the SR latch.

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SR Latch Summary• SR stands for Set/Reset Latch

– Stores one bit of state (Q)

• Control what value is being stored with S, R inputs– Set: Make the output 1 (S = 1, R = 0, Q = 1)– Reset: Make the output 0 (S = 0, R = 1, Q = 0)

• Behavior undefined/invalid when:– S = R = 1

S

R Q

Q

SR LatchSymbol

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SR Latch with Control Input

• Notice the hierarchical design!

– The dotted blue box is the S’R’ latch from the previous slide.

– The additional NAND gates are simply used to generate the correct inputs for

the S’R’ latch.

• The control input acts just like an enable.

C S R S’ R’ Q

0 x x 1 1 No change1 0 0 1 1 No change1 0 1 1 0 0 (reset)1 1 0 0 1 1 (set)1 1 1 0 0 Avoid!

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D Latch

• No illegal state

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D Latch

• A D latch is based on an S’R’ latch. The additional gates generate the S’ and R’ signals, based on inputs D (“data”) and C (“control”).– When C = 0, S’ and R’ are both 1, so the state Q does

not change.– When C = 1, the latch output Q will equal the input D.

• No more messing with one input for set and another input for reset!

C D Q

0 x No change1 0 01 1 1

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D Latch

• Symbol

D

C

Q

Q

C D Q Q

0 X NC NC

1 0 0 1

1 1 1 0

NC: No Change

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Summary

• A sequential circuit has memory. It may respond differently to the same

inputs, depending on its current state.

• Memories can be created by making circuits with feedback.

– Latches are the simplest memory units, storing individual bits.

– It’s difficult to control the timing of latches in a larger circuit.

• Next, we’ll improve upon latches with flip-flops, which change state only

at well-defined times. We will then use flip-flops to build all of our

sequential circuits.

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Standard Symbols - Latches

Circle at input indicates negation

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Latches vs Flip Flops

• Latch = level-sensitive device

– State changes with input when enabled (e.g. clock = 1)

– Holds last input value when disabled (when clock = 0)

• Flip-flop = edge-triggered device

– State of flip-flop can only change during clock transition

– Example: Flip-flops change on rising/falling edge of clock

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Level Sensitive vs Edge Triggered

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Flip Flops

• D Latch – Data is stored when the clock is high

How can we build a flip flop that stores on edge transitions?

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D Flip Flop

• The flip-flop inputs are C and D, and the outputs are Q and Q’.

• The D latch on the left is the master, while the SR latch on the right is called the slave.

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D Flip Flop

• The flip-flop input D is connected directly to the master latch.

• The master latch output goes to the slave.• The flip-flop outputs come directly from the slave latch.

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D flip-flops when C=0• The D flip-flop’s control input C enables either

the D latch or the SR latch, but not both.• When C = 0:

– The master latch is enabled, and it monitors the flip-flop input D. Whenever D changes, the master’s output changes too.

– The slave is disabled, so the D latch output has no effect on it. Thus, the slave just maintains the flip-flop’s current state.

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D flip-flops when C=1

• As soon as C becomes 1, (i.e. on the rising edge of the clock)– The master is disabled. Its output will be the last D input value seen just

before C became 1.– Any subsequent changes to the D input while C = 1 have no effect on the

master latch, which is now disabled.– The slave latch is enabled. Its state changes to reflect the master’s output,

which again is the D input value from right when C became 1.

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Positive Edge Triggering

• The D flip-flop’s behavior is similar to that of a D latch except for the positive edge-triggered nature, which is not explicit in this table.

C D Q

0 x No change1 0 0 (reset)1 1 1 (set)

This is called a positive edge-triggered flip-flop. The flip-flop output Q changes only after the positive edge of C. The change is based on the flip-flop input values that were present right at the

positive edge of the clock signal.

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D Flip Flop

• Is this +ve or –ve edge-triggered?

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Flip Flop Symbols

• Triangle indicates clock• Edge trigger:

– No bubble at clock: positive edge triggered– Bubble at clock: negative edge triggered

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Flip Flop Variations

• A JK flip-flop has inputs that act like S and R, but the inputs JK=11 are used to complement the flip-flop’s current state

C J K Qnext

0 x x No change1 0 0 No change1 0 1 0 (reset)1 1 0 1 (set)1 1 1 Q’current

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JK Flip FlopCreated from D flip flopD = JQ’+K’Q

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JK Flip FlopCreated from D flip flopD = JQ’+K’Q

J=1 & K=0

D = Q’+Q = 1Flip flop is SET

J=0 & K=1

D = 0+0 = 0Flip flop is RESET

J=1 & K=1

D = Q’+0 = Q’Output is Complemented

J=0 & K=0

D = Q+0 = QOutput unchanged

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T (Toggle) Flip Flop

• A T (toggle) flip-flop can only maintain or complement its current state.

C T Qnext

0 x No change1 0 No change1 1 Q’current

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T (Toggle) Flip FlopCreated from JK flip flop

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T (Toggle) Flip Flop

When T = 0, J=0 & K=0Output is unchanged

When T = 1, J=1 & K=1Output is complemented

Created from JK flip flop

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T (Toggle) Flip FlopCreated from D flip flopD = TQ’+T’Q

When T = 0, D=QOutput is unchanged

When T = 1, D=Q’Output is complemented

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Characteristic Tables

• The tables that we’ve made so far are called characteristic tables.– They show the next state Q(t+1) in terms of

the current state Q(t) and the inputs.

– For simplicity, the control input C is not usually listed.

– Again, these tables don’t indicate the positive edge-triggered behavior of the flip-flops that we’ll be using.

D Q(t+1) Operation

0 0 Reset1 1 Set

T Q(t+1) Operation

0 Q(t) No change1 Q’(t) Complement

J K Q(t+1) Operation

0 0 Q(t) No change0 1 0 Reset1 0 1 Set1 1 Q’(t) Complement

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Characteristic Equations• We can also write characteristic equations, where the next state Q(t+1) is defined in

terms of the current state Q(t) and inputs.

D Q(t+1) Operation

0 0 Reset1 1 Set

J K Q(t+1) Operation

0 0 Q(t) No change0 1 0 Reset1 0 1 Set1 1 Q’(t) Complement

Q(t+1) = D

Q(t+1)= K’Q(t) + JQ’(t)

Q(t+1)= T’Q(t) + TQ’(t)= T Q(t)

T Q(t+1) Operation

0 Q(t) No change1 Q’(t) Complement