Justin Andrews

ACSG 520

Assignment #6

4. The pair of sockets used are 161, and 162.

5. Both sockets used in this case are 69.

6. a. 8 bytes.

b. 65,535 bytes.

c. The minimum size would be seen as 8 (header) + 20 (IP header’s length) = 28

d. The maximum size can be seen as 65,535 – 20 (IP header’s length) = 65,515

7. 16 + 8 (header) = 24. Ratio is 16/24 = 2/3

8. 24 + 20 (IP header) = 44. Ratio is 16/44 = 4/11

9. 16/44 = 4/11

10. a. 0045 = 69, the source port number.

b. DF00 = 57344 + 3840 = 61184, the destination port number.

c. 0058 = 88 bytes.

d. 88 – 8 = 80 bytes.

e. The packet is directed from server to client, in this case.

f. The client process is TFTP.