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Powerpoint on Arcs and Chords of Circles
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AB CD&
Since AB and CD are equal and the only two unknown arcs, let both arcs be X.
Solve for x and you are done!!!
Add 50 + 20 to get the degree of the arc corresponding with chord PS.
•Since Arc PS = Arc QR•Chords PS and QR are equal.
PS = 12 so QR = 12
•Add the degrees you have so far, then subtract from 360•Compare degrees to the other arc degrees•Your answer will be the length with the same arc degree.
Cross at 90°
12
13
Radius AD=13, AE= 12 so 13-12 = 1
AC = radius
AB = radius
132 - 122
Radius = perpendicular bisector
Add 5 + 5
220°
360 – 220 = 140
Central angle of arc CB
½ angle CAB
½ arc CB
Whole chord = 12, each half = 6
10068 22
30 – 60 – 90 trianglesx 2x3x2x =
6 x = 3
33
22 35Press for each
step of example 9