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An introduction to scalars in mechanics: energy, power & efficiency
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Scalars in mechanics
Photo: Flickr
Quantities
Scalars in mechanics 2
Scalar quantities Vector quantities
mass m (kg)
energy E (J)
power P (W)
displacement ๐ (๐)
velocity ๐ฃ (๐๐ โ1)
acceleration ๐ (๐๐ โ2)
force ๐น (๐)
momentum ๐ (๐๐๐๐ โ1) torque ๐ (๐๐)
โข Magnitude โข Magnitudeโข Directionโข Point of application
History
Scalars in mechanics 3
17th centuryVector mechanics
GallileiHuygensNewtonLeibniz 19th century
Scalar mechanics
DavyRitter
OerstedFaradayKelvin
It was observed that โnatural forcesโ could transform.19th century natural philosophers (later physicists)Searched for a conserved โnatural forceโ.
This resulted in the new concept โENERGYโ
Concept of energy
Scalars in mechanics 4
IT
โข Is transformed in all physical changes
โข Is required to make anything happen
โข Is puts limits to any process or activity
โข Is the most fundamental concept in modern science
pixabay
Concept of work
Scalars in mechanics 5
StudentHotel
HollandISC
you (today)
๐ = 4.3๐๐ ๐น๐๐๐๐ค๐๐๐
Assume constant ๐ฃ๐๐๐๐ = 3 ๐๐ โ1 so ฮฃ ๐น = 0 โ
๐น๐๐๐๐ค๐๐๐ = โ ๐น๐๐๐๐ + ๐น๐๐๐ = 12๐๐ด๐ถ๐ท ๐ฃ๐๐๐๐+๐ฃ๐ค๐๐๐
2 + ๐ถ๐๐๐๐ โ ๐น๐ =
๐น๐๐๐๐
๐น๐๐๐+
1
2โ 1.29 โ 0.4 โ 1 โ 3 + 5 2 + 0.02 โ 70 โ 9.81 = 16.5 + 13.7 = 30๐
Work done = ๐ = ๐น โ ๐ = 30 โ 4.3 โ 103 = 1.3 โ 105๐ฝ๐๐ข๐๐
Work vs. Impulse
Scalars in mechanics 6
Why not use FORCE TIME as a measure of work?
๐น๐๐๐๐ค๐๐๐
๐น๐๐๐๐ค๐๐๐
start
same force, same time,โฆsame work?
Impulse is a vector: ๐น โ ๐ก = ๐ผ
Vector Scalar = Vector
Work is a scalar: ๐น โ ๐ = ๐
Vector Vector= Scalar
Vector โdotโ product
Force & displacement at an angle
Scalars in mechanics 7
๐น
๐
๐
๐นโโ๐
๐นโฅ๐
๐
90ยฐ
๐นโโ๐ = 0
๐นโฅ๐ = ๐น ๐น
๐
๐
๐นโโ๐
๐นโฅ๐
๐ = ๐นโโ๐ โ ๐ = ๐น โ ๐ถ๐๐ ๐ โ ๐ = ๐น โ ๐ โ ๐ถ๐๐ ๐
Nett driving forceProvides energy
W > 0
Nett inhibiting forceWithdraws energy
W < 0
No driving forceNo energy transferred
W = 0
Non-constant forces
Scalars in mechanics 8
๐น pulling force
๐ ๐
๐น
๐ ๐๐๐ฅ
๐น๐๐๐ฅ
๐น๐๐ฃ๐
๐ = ๐น๐๐ฃ๐ โ ๐
๐ = 0
๐
๐น โ ๐๐
๐ = 0
๐
๐น โ ๐ถ๐๐ ๐ โ ๐๐
๐ = 0
๐
๐น โ ๐ ๐
more general
more generalwith angle
complete formas vector dot product
W=Area
Work transforms energy
Scalars in mechanics 9
wikimedia
Work transforms energy
Scalars in mechanics 10
wikimedia
Work by the resistant force of the target transforms kinetic energy of the arrow to heat in the target.
1 2 3
๐ธ๐โ ๐ธ๐ ๐ธ๐ ๐
3
Work by the elastic force transforms elastic potential energy in the bow to kinetic energy of the arrow.
2
Work by the pulling force transforms chemical potential energy in master Kimโs arm to elastic potential energy in the string.
1
Gravitational (potential) energy
Scalars in mechanics 11
+โ1
โ2
๐ โ ๐
๐น
๐ = ๐น โ ๐ = ๐ โ ๐ โ โ2 โ โ1 = โ๐ธ๐
To lift the object, the average lifting force needs to equal ๐ โ ๐The lifting force performs positive workGravitational potential energy is built up
Strictly ๐ธ๐ = 0 at the Earthโs centre.
Since this is not practical, we set ๐ธ๐ = 0 and โ = 0
at the lowest point in your context.
Gravitational (potential) energy
Scalars in mechanics 12
โ1
โ2
๐ โ ๐
๐น
๐ = 10๐๐๐ = 9.81๐๐ โ2
โ1 = 5.0๐โ2 = 7.0๐
To lift the object from the floor to โ1, the lifting force performs work:๐ = ๐ โ ๐ โ โ1 = 10 โ 9.81 โ 5.0 = 4.9 โ 10
2๐ฝ
Arrived at โ1the object has a potential energy ๐ธ๐ = 4.9 โ 102๐ฝ
To lift the object from โ1 to โ2, the lifting force performs work:๐ = ๐ โ ๐ โ โ2 โ โ1 = 10 โ 9.81 โ 2.0 = 2.0 โ 102๐ฝ
Arrived at โ2the object has a new potential energy: ๐ธ๐ = 4.9 โ 10
2๐ฝ + 2.0 โ 102๐ฝ = 6.9 โ 102๐ฝ
Example
๐ธ๐ = 4.9 โ 102๐ฝ
๐ธ๐ = 6.9 โ 102๐ฝ
๐ธ๐ = 0
4.9 โ 102๐ฝWork done
2.0 โ 102๐ฝWork done
Elastic (potential) energy
Scalars in mechanics 13
๐
๐น
๐น๐๐๐ฅ
๐น = ๐ถ โ ๐
๐
๐น๐๐๐ฅ2
๐ = ๐น๐๐ฃ๐ โ ๐ =1
2๐ถ โ ๐ โ ๐ =
1
2๐ถ๐ 2 = โ๐ธ๐
To pull the object, the average pulling force equals 1
2๐ถ โ ๐
The pulling force performs positive workElastic potential energy is built up
๐
Elastic (potential) energy
Scalars in mechanics 14
๐น = ๐ถ โ ๐
0
0.2
0.4
0.6
0.8
1
1.2
1.4
1.6
1.8
2
0 1 2 3 4 5 6 7 8 9 10
F (N
)
s (cm)
Example with spring ๐ถ = 0.20๐/๐๐
The spring starts without potential energy: ๐ธ๐ = 0
To extend the spring 4.0 ๐๐, the pulling force does work:
๐ = ๐น๐๐ฃ๐ โ ๐ =0 + 0.8
2โ 0.040 = 0.016๐ฝ
The spring then has a potential energy: ๐ธ๐ = 0.016๐ฝ
To extend the spring 3.0 ๐๐ more, the pulling force does work:
๐ = ๐น๐๐ฃ๐ โ ๐ =0.8 + 1.4
2โ 0.030 = 0.033๐ฝ
The spring then has a new potential energy: ๐ธ๐ = 0.016 + 0.033 = 0.049๐ฝ
Area =1st W
Area =2nd W
Kinetic energy
Scalars in mechanics 15
๐ก
๐ฃ1
๐ก1 ๐ก2
๐ฃ2
โ๐ฃ
โ๐ก
Total work done on an object โกWork done by the overall force !
ฮฃ๐ = ฮฃ๐น โ ๐ = ๐ โ ๐ โ ๐
= ๐ โ๐ฃ2 โ ๐ฃ1โ๐ก
โ๐ฃ2 + ๐ฃ12
โ โ๐ก
= ๐ โโ๐ฃ
โ๐กโ ๐ฃ๐๐ฃ๐ โ โ๐ก
=๐
2โ ๐ฃ2 โ ๐ฃ1 โ ๐ฃ2 + ๐ฃ1
=1
2๐๐ฃ2
2 โ1
2๐๐ฃ1
2 = โ๐ธ๐ฮฃ๐ = ฮ๐ธ๐
2nd law of Newton (rephrased)
Scalars in mechanics 16
Vector mechanics: the acceleration of an object equals the overall force divided by its mass
Scalar mechanics: the increase of objectโs kinetic energy equals the overall work done on the object
ฮฃ๐ = ฮ๐ธ๐
ฮฃ ๐น = ๐ ๐
Energy transfer & efficiency
Scalars in mechanics 17
Photo: wikimedia
Aggregate
GeneratorEfficiency ๐2
๐ธ๐โ
๐
๐1
๐ธ๐
๐2
Chemical 100J Work 30J
Heat 70J
Heat 8J
Electric 22J
Flows out of the system
The engine converts chemical energy to work with an efficiency
๐1 =๐
๐ธ๐โ=30
100= 0.30 (30%)
The generator converts work to electrical energy with an efficiency
๐2 =๐ธ๐๐=22
30= 0.73 (73%)
Overall efficiency =๐ = ๐1 โ ๐2 =
0.30 โ 0.73 = 0.22 (22%)
EngineEfficiency ๐1
Energy conservation
Scalars in mechanics 18
EngineEfficiency ๐1
GeneratorEfficiency ๐2
๐ธ๐โ
๐
๐1
๐ธ๐
๐2
Chemical 100J Work 30J
Heat 70J
Heat 8J
Electric 22J
Surrounding air
Aggregate
Closed system
Loss for the aggregate
First law of thermodynamics (energy conservation law): In a closed system the total energy is conserved
Conservation of energy โ Example I
Scalars in mechanics 19
A ball is thrown vertically upwards with a velocity of 8.0 m/s. Which height will the ball reach (above the point of release)?
๐ธ๐ด = ๐ธ๐ต๐ธ๐๐ด + ๐ธ๐๐ด = ๐ธ๐๐ต + ๐ธ๐๐ต
0 +1
2๐๐ฃ๐ด
2 = ๐๐โ๐ต + 0
1
2๐ฃ๐ด2 = ๐โ๐ต
1
2โ 8.02 = 9.81 โ โ๐ต
โ๐ต = 3.3๐
Strategy:
Indicate 2 points:A = point of releaseB = highest point
Set โ = 0 in A (lowest point)So, in A there is NO potential energy
In B there is no kinetic energy
Solve the energy conservation law
B
A
๐ฃ๐ด
โ๐ด = 0
๐ฃ๐ต = 0
Solution:
Conservation of energy โ Example II
Scalars in mechanics 20
๐ธ๐ด = ๐ธ๐ต
๐ธ๐๐ด + ๐ธ๐๐ด = ๐ธ๐๐ต + ๐ธ๐๐ต
0 +1
2๐๐ฃ๐ด
2 = ๐๐โ๐ต +1
2๐๐ฃ๐ต
2
1
2๐ฃ๐ด2 = ๐โ๐ต +
1
2๐ฃ๐ต2
1
2โ 8.02 = 9.81 โ 2.0 +
1
2โ ๐ฃ๐ต2
๐ฃ๐ต = 5.0๐๐ โ1
Strategy:
Indicate again 2 points:A = point of releaseB = highest point
Set โ = 0 in A (lowest point)So, in A there is NO potential energy
In B there is both potential and kinetic energy
Solve the energy conservation law
B
A
๐ฃ๐ด
โ๐ด = 0
Solution:
A ball is thrown upwards with a velocity of 8.0 m/s at a certain angle.The ball climbs 2.0 m. Calculate the magnitude of the velocity at the highest point
๐ฃ๐ต
โ๐ต
Making work easier (but not less) - I
Scalars in mechanics 21
โ1
โ2
100๐๐ โ 9.81๐๐ โ2
๐น1
โโ = 2.0๐๐น2 ๐
There is NO other force than weight.Only the vertical displacement requires work.
โ๐ธ๐ = ๐น1 โ โโ = ๐น2 โ ๐
981๐ โ 2.0๐ = ๐น2 โ 6.0๐
๐น2 = 3.3 โ 102๐
Feels like 33kg
Making work easier (but not less) - II
Scalars in mechanics 22
= 40๐ 120๐
The pulley block carries the weight on 3 ropes.The load must be lifted 10 m up.
The weight is split in 3. One only needs to pull with 40๐ !
But!!
โ๐ธ๐ = 120๐ โ 10๐ = 40๐ โ 30๐
You need to haul in 30 m of rope
Collisions
Scalars in mechanics 23
Elastic
Partlyinelastic
Before After ฮฃ ๐ ฮฃ๐ธ๐ฮฃ๐ธ
Conservation of
Totallyinelastic
+ heat
++ heat
Power
Scalars in mechanics 24
๐ =ฮ๐ธ
ฮ๐ก
Power is the rate of energy conversion
1๐๐๐ก๐ก = 1๐ฝ/๐
๐ =ฮ๐
ฮ๐ก=๐น โ โ๐
โ๐ก= ๐น โ
โ๐
โ๐ก= ๐น โ ๐ฃ
Power
Scalars in mechanics 25
๐น๐๐๐๐ค๐๐๐
๐น๐๐๐ ๐๐ ๐ก๐๐๐๐ ๐ฃ
A car travels at a constant velocity ๐ฃ. Newton: ๐น๐๐๐๐ค๐๐๐ = ๐น๐๐๐ ๐๐ ๐ก๐๐๐๐
The required power to keep the car driving at this velocity equals:
๐ =ฮ๐
ฮ๐ก=๐น๐๐๐๐ค๐๐๐ โ โ๐
โ๐ก= ๐น๐๐๐๐ค๐๐๐ โ
โ๐
โ๐ก= ๐น๐๐๐๐ค๐๐๐ โ ๐ฃ = ๐น๐๐๐ ๐๐ ๐ก๐๐๐๐ โ ๐ฃ
Power - Example
Scalars in mechanics 26
๐น๐๐๐๐ค๐๐๐
๐น๐๐๐ ๐๐ ๐ก๐๐๐๐ ๐ฃ
A BMW 7-series car has:Drag coefficient ๐ถ๐ท = 0.30Frontal area ๐ด = 2.2๐2
Calculate the mechanical power required to drive 160 km/h.
๐ฃ = 160๐๐โโ1 =160
3.6๐๐ โ1 = 44.4๐๐ โ1
Density of air = 1.29 ๐๐๐โ3
๐น๐๐๐ =1
2๐๐ด๐ถ๐ท๐ฃ
2 =1
2โ 1.29 โ 2.2 โ 0.30 โ 44.42
๐น๐๐๐ = 841๐
๐ฃ = ๐๐๐๐ ๐ก๐๐๐ก โ ๐น๐๐๐๐ค๐๐๐ = ๐น๐๐๐
๐ = ๐น๐๐๐ โ ๐ฃ = 841 โ 44.4 = 37 โ 103๐ = 37๐๐
Solution
Power & efficiency
Scalars in mechanics 27
๐ =๐ธ๐ข๐ ๐๐๐ข๐
๐ธ๐ก๐๐ก๐๐=
๐ธ๐ข๐ ๐๐๐ข๐ ๐ก
๐ธ๐ก๐๐ก๐๐ ๐ก=๐๐ข๐ ๐๐๐ข๐
๐๐ก๐๐ก๐๐
Efficiency can be related to a ratio of energies or a ratio of powers. Look at the context and choose!
END
Scalars in mechanics 28
DisclaimerThis document is meant to be apprehended through professional teacher mediation (โlive in classโ) together with a physics text book, preferably on IB level.