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Slides from the Help Session going over the Study Guide for Unit 5.
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Mrs. Reynolds
About twenty percent of the National Football
League weighs more than 300 pounds. At this
weight, their Body Mass Index (BMI) places
them at Grade 2 obesity, which is one step
below morbid obesity. Determine the mass of a
300 pound (1330 N) football player.
About twenty percent of the National Football
League weighs more than 300 pounds. At this
weight, their Body Mass Index (BMI) places
them at Grade 2 obesity, which is one step
below morbid obesity. Determine the mass of a
300 pound (1330 N) football player.
Fg = 300 lb. = 1330 N Fg = mg
g = 9.8 m/s^2 m = Fg/g
m = ? m = 1330 N/9.8 m/s^2
m = 136 kg
According to the National Center for Health Statistics, the average mass of an adult American male is 86 kg. Determine the mass and the weight of an 86-kg man on the moon where the gravitational field is one-sixth that of the Earth. mearth = 86 kgGmoon = (1/6)g
= (1/6)*(9.8)mmoon = ?Fg moon = ?
According to the National Center for Health Statistics, the average mass of an adult American male is 86 kg. Determine the mass and the weight of an 86-kg man on the moon where the gravitational field is one-sixth that of the Earth. mearth = 86 kg mass doesn’t changeGmoon = (1/6)g so mmoon = 86 kg
= (1/6)*(9.8)mmoon = ?Fg moon = ?
According to the National Center for Health Statistics, the average mass of an adult American male is 86 kg. Determine the mass and the weight of an 86-kg man on the moon where the gravitational field is one-sixth that of the Earth. mearth = 86 kg Fg moon = mmoon Gmoon
Gmoon = (1/6)g Fg moon = (86)(9.8/6)= (1/6)*(9.8)Fg moon = 140 N
mmoon = ?Fg moon = ?
a. Determine the net force required to
accelerate a 540-kg ultralight car from 0 to
27 m/s (60 mph) in 10.0 seconds.
b. Determine the net force required to
accelerate a 2160-kg Ford Expedition from 0
to 27 m/s (60 mph) in 10.0 seconds.
a. Determine the net force required to
accelerate a 540-kg ultralight car from 0 to
27 m/s (60 mph) in 10.0 seconds.
m = 540 kg
vi = 0
vf = 27 m/s
t = 10.0 s
Fnet = ?
a. Determine the net force required to
accelerate a 540-kg ultralight car from 0 to 27
m/s (60 mph) in 10.0 seconds.
m = 540 kg To find Fnet we need
vi = 0 mass and accel. We
vf = 27 m/s have mass, but not accel.
t = 10.0 s So we need to find accel.
Fnet = ?
a. Determine the net force required to
accelerate a 540-kg ultralight car from 0 to 27
m/s (60 mph) in 10.0 seconds.
m = 540 kg Fnet = ma
vi = 0 Fnet = (540 kg)(2.7 m/s^2)
vf = 27 m/s Fnet = 1458 N
t = 10.0 s
a = 2.7 m/s^2
Fnet = ?
b. Determine the net force required to
accelerate a 2160-kg Ford Expedition from 0
to 27 m/s (60 mph) in 10.0 seconds.
m = 2160 kg
vi = 0
vf = 27 m/s
t = 10.0 s
Fnet = ?
b. Determine the net force required to
accelerate a 2160-kg Ford Expedition from 0 to
27 m/s (60 mph) in 10.0 seconds.
m = 2160 kg Fnet = ma
vi = 0 Fnet = (2160 kg)(2.7 m/s^2)
vf = 27 m/s Fnet = 5832 N
t = 10.0 s
a = 2.7 m/s^2
Fnet = ?
The Top Thrill Dragster stratacoaster at Cedar Point Amusement Park in Ohio uses a hydraulic launching system to accelerate riders from 0 to 54 m/s (120 mi/hr) in 3.8 seconds before climbing a completely vertical 420-foot hill . Determine the net force required to accelerate an 86-kg man. vi = 0 m/s Fnet = ?vf = 54 m/st = 3.8 s To find Fnet we need to findd = 420 ft acceleration.m = 86 kg
The Top Thrill Dragster stratacoaster at Cedar Point Amusement Park in Ohio uses a hydraulic launching system to accelerate riders from 0 to 54 m/s (120 mi/hr) in 3.8 seconds before climbing a completely vertical 420-foot hill . Determine the net force required to accelerate an 86-kg man. vi = 0 m/s Fnet = ?vf = 54 m/st = 3.8 sd = 420 ftm = 86 kga = 14.2 m/s^2
Blake is dragging a bag of grass from the
garage to the street on the evening before
garbage pick-up day with a force of 40.2 N.
The frictional force between the bag and
the ground is 5.7 N. What is the net force
acting on the bag?
Blake is dragging a bag of grass from the
garage to the street on the evening before
garbage pick-up day with a force of 40.2 N.
The frictional force between the bag and
the ground is 5.7 N. What is the net force
acting on the bag?
40.2
N
5.7 N
Silas and Ivey are members of the stage crew
for the Variety Show. Between acts, they must
quickly move a Baby Grand Piano onto stage.
After the curtain closes, they exert a sudden
forward force of 524 N to budge the piano from
rest and get it up to speed. The 158-kg piano
experiences 418 N of friction.a. What is the piano's acceleration during this phase of
its motion?
b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.a. What is the piano's acceleration during this phase of
its motion?
F1 = 524 N forward
F2 = 418 N backward
m = 158 kg
a = ?
524 N418 N
They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.a. What is the piano's acceleration during this phase of
its motion?
F1 = 524 N forward Fnet = 524 N – 418 N = 106 N
F2 = 418 N backward
m = 158 kg
a = ?
524 N418 N
They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.a. What is the piano's acceleration during this phase of
its motion?
F1 = 524 N forward Fnet = 524 N – 418 N = 106 N
F2 = 418 N backward Fnet = ma, so a = Fnet/m
m = 158 kg a = (106 N)/(158 kg)
a = ? a = 0.671 m/s^2
They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
a = 0.671 m/s^2
t = 1.44 s
They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
a = 0.671 m/s^2
t = 1.44 s
vi = 0 m/s
vf = ?
They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
a = 0.671 m/s^2
t = 1.44 s
vi = 0 m/s
vf = ?
They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
a = 0.671 m/s^2 vf = vi + at
t = 1.44 s
vi = 0 m/s
vf = ?
They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
a = 0.671 m/s^2 vf = vi + at
t = 1.44 s vf = 0 + (0.671 m/s^2)(1.44 s)
vi = 0 m/s vf = 0.966 m/s
vf = ?
