Click here to load reader
Upload
lawrence-de-vera
View
236
Download
0
Embed Size (px)
Citation preview
TOPIC
LENGTH OF AN ARCand
AREA OF SURFACE OF REVOLUTION
LENGTHS OF CURVES
To find the length of the arc of the curve y = f (x) between x = a and x = b let ds be the length of a small element of arc so that:
2
222 1 thus
dx
dy
dx
dsdydxds
LENGTHS OF CURVES
In the limit as the arc length ds approaches zero:
and so: 2
1ds dy
dx dx
2
1
b
x a
b
x a
dss dx
dx
dydx
dx
LENGTHS OF CURVES – PARAMETRIC EQUATIONS
Instead of changing the variable of the integral as before when the curve is defined in terms of parametric equations, a special form of the result can be established which saves a deal of working when it is used. Let:
dt dtdy
dtdx
s and dtdy
dtdx
dtds
0dt as so dtdy
dtdx
dtds
so
dydxds before As .tFx and tfy
t
tt 1
2 2222
222
222
LENGTH OF AN ARC
A. Rectangular Coordinates
f(x)y , 12
dxdx
dyds g(y) x, dy
dy
dx1ds
2
B. Parametric Form
dtdt
dy
dt
dxds
22
when x=x(t), y=y(t); where t is a parameter
1. 2.
C. Polar Coordinates
f(r) , drdr
dr1ds
22
)g(r , dd
drrds
22
2.1.
EXAMPLE
Find the length of the arc of each of the following:
2
3
3
3
ty
ttx
1.
from t=o to t=1
2.
tsiney
tcosext
t
from t=o to t=4
5. Length of the arc of the semicircle222 ayx
2x to 1x fromee
lny x
x
1
13.
4.),(to),(from
xy2100
8 23
AREA OF SURFACE OF REVOLUTION
• DEFINITION:Let y = f(x) have a continuous derivative on the interval [a, b]. The area S of the surface of revolution formed by revolving the graph of f about a horizontal or vertical axis iswhere r(x) is the distance between the graph of f and the axis of revolution.
xof function a is y dx)x('f)x(rSb
a 212
If x = g(y) on the interval [c, d], then the surface area is
where r(y) is the distance between the graph of g and the axis of revolution.
yof function a is x dy)y('g)y(rSd
c 212
EXAMPLE
1. Find the area formed by revolving the graph of f(x) = x3 on the interval [0,1] about the x-axis.
2. Find the area formed by revolving the graph of f(x) = x2 on the interval [0, ] about the y – axis.
3. Find the area of the surface generated by revolving the curve
, 1 ≤ x ≤ 2 about the x – axis.4. The line segment x = 1 – y, 0 ≤ y ≤ 1, is revolved about the y
– axis to generate the cone. Find its lateral surface area.
2
xy 2