JEE (Main)

Mathematics

फि�जि�क्सच्या syllabus चे� दो�न स�क्शन्स के� ले� आहे�त.

Section – A मध्या� एके� ण २० या�फिनट् स अस�न त्याले ८०% वे�ट्��

आहे�.

Section – B मध्या� प्रॅ&क्टिक्ट्केले के(म्पो�नन्ट् (experimental skills)

फिवेचेरात घे�तले� �त,ले. याले २०% वे�ट्�� आहे�. यातले� बरा�चेस�

experiments त�म्हे, अकेरावे,त के� ले�ले� आहे�त.

Maths आणिण Physics चे अभ्यासक्रम केम, वे आट्�क्यात

या�ण्यासराखा आहे�. Chemistry चे syllabus मत्र त्या मनन� बराचे

�स्त आहे�. अर्था7त यातले� बरा�चेस� या�फिनट् स त�म्हे, अकेरावे,त के� ले�ले� आहे�त.

JEE (Main)

Chemistry त एके� ण त,न स�क्शन्स आहे�त. Section – A हे

Physical Chemistry चे अस�न त्यात दोहे या�फिनट् स आहे�त.

Section – B हे Inorganic Chemistry चे अस�न यात ८

या�फिनट् स आहे�त. Section – C हे organic Chemistry चे

अस�न

यात १० या�फिनट् स आहे�त. शे�वेट्च्या या�फिनट् मध्या� experimental

skills वे Activities दिदोले�ल्या आहे�त.

JEE (Main)

JEE (Main)

SYLLABUS

UNIT 1 : SETS, RELATIONS AND FUNCTIONS

UNIT 2 : COMPLEX NUMBERS AND QUADRATIC EQUATIONS

UNIT 3 : MATRICES AND DETERMINANTS

UNIT 4 : PERMUTATION AND COMBINATION

JEE (Main)

UNIT 5 : MATHEMATICAL INDUCTION

UNIT 6 : BINOMIAL THEOREM AND ITS SIMPLE APPLICATIONS

UNIT 7 : SEQUENCES AND SERIES

UNIT 8 : LIMIT, CONTINUITY AND DIFFERNTIABILITY

SYLLABUS

JEE (Main)

UNIT 9 : INTEGRAL CALCULUS

UNIT 10 : DIFFERENTIAL EQUATIONS

UNIT 11 : CO – ORDINATE GEOMETRY

UNIT 12 : THREE DIMENSIONAL GEOMETRY

SYLLABUS

JEE (Main)

UNIT 13 : VECTOR ALGEBRA

UNIT 14 : STATISTICS AND PROBABILITY

UNIT 15 : TRIGONOMETRY

UNIT 16 : MATHEMATICAL REASONING

SYLLABUS

JEE (Main) 2013 Results

In Pune 24,000 students

appeared for this exam and

only 2% i.e. 480 were

eligible for advanced.

(For which criterion was

around 31% i.e. 98%

students could not get even

31%.)

In Mumbai 44,000 students

appeared for this exam and

only 4.5% i.e. 2000 were

eligible for advanced.

(For which criterion was

around 31% i.e. 95.5%

students could not get even

31%.)

JEE (Main) 2013 Results

Multiple Choice Questions

-9

2. Distance between the pair of lines

represented by the equation

x2 – 6xy +9y2 +3x – 9y – 4 = 0

)(2

2

baaacg

23

,4,9,1 gcba

25

10425

2)91(1

)4(49

2

Sol :

The distance between the pair of straight lines given

by

ax2 + 2hxy + by2 + 2gx + 2fy + c = 0 is

Here

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