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Distribution Law Mathematics

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Page 1: Distribution Law Mathematics
Page 2: Distribution Law Mathematics

Muhaimina Sa ’adah Helvy Ef fendi

1640604055Pendidikan Matematika Local A1 2016

Page 3: Distribution Law Mathematics

DISTRIBUTIVE LAWS

3. The distributive law can also be extended to division as long as there aren’t any denominators that end up being equal to zero. For all real numbers a, b, and c, where a ≠0 the following equations are valid:

a(b + c)= ab + ac

1. For all real numbers a, b, and c, the following equation holds. The operation of multiplication is distributive with respect to addition:

2. The above statement logically implies that multiplication is distributive with respect to subtraction, as well:

a(b – c)= ab-ac

(ab-ac)/a = ab/a - ac/a = b- c

(ab+ac)/a = ab/a + ac/a = b+ c

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example:

a = 5, b = 2, and c = 3

1.Step workmanship:

Way 2: a (b + c) = ab + ac = ...1. Multiply by b (ab = 10)2. Multiply by c (ac = 15)3. Add multiplication result ab = 10 and ac = 15 and produce 25.

1. Add first in brackets. A + b = 2 + 3 = 52. Multiply the number of results a + b = 5 with a=5 and the result 25

Way 1: a (b + c) = ...

Way 2: a (b-c) = ab-ac = ...1. Multiply by b (ab = 10)2. Multiply by c (ac = 15)3. Subtract product ab = 10 with bc = 15 yield -5.

2. Step workmanship Way 1: a (b-c) = ...1.First reduce the brackets, b-c = 2-3 = -12.Multiply the result of deductions by 5 and yield -5.

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B. (ab-ac) / a = ab / a - ac / a = b- c1. Subtract the first from inside brackets. Ab-ac = -52. Divide the deduction with a. -5 / a = -5 / 5 = -1

3. Steps of workmanship:

example:

a = 5, b = 2, and c = 3

A. (ab + ac) / a = ab / a + ac / a = b + c

1. Count first in brackets. Ab + ac = 252. Divide the number by a. 25 / a = 25/5 = 5

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