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Derivatives of Sine, Cosine and Tangent Functions and their proofs
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Theorems
Theorem: Derivative of Sine Function: D x ( sinx )=cos x
Proof:
Let f be the sine function so that f(x) = sinx
From the definition of derivative,
f’(x) = lim△ x→0
f ( x+△ x )−f (x )
△ x
= lim△ x→0
sin ( x+△ x )−sinx
△ x
f’(x) = lim△ x→0
sinxcos (△ x )+cosxsinx (△ x )−sinx
△ x
= lim△ x→0
sinx [cos (△ x )−1 ]△ x
+lim△ x→0
cosxsin (△ x )
△ x
= − lim
△ x→01−cosx (△ x )
△ x ( lim△ x→0sinx )+( lim△ x→0
cosx )lim△ x→0
sin (△ x )
△ x
From the theorems: lim△ x→0
1−cos (△ x)
△ x = 0
lim△ x→0
sin (△ x)
△ x=1
Substituting from these equations:
f’(x) = −0 · sinx+cosx ·1
f’(x) = cosx
Theorem: Derivative of Cosine Function: D x (cosx )=−sin x
Proof:
If g is the cosine function, then
g(x) = cosx
g’(x) = lim△ x→0
g (x+△ x )−g(x)
△ x
= lim△ x→0
cos ( x+△ x )−cosx
△ x
= lim△ x→0
cos x cos (△ x )−sin x sin (△ x )−cos x
△ x
= lim△ x→0
cos x [cos (△ x )−1]
△ x - lim△ x→ 0
sin x sin (△ x )
△ x
= − lim
△ x→01−cos (△ x )
△ x( lim△ x→o
cos x ) ― ( lim△ x→osin x )
lim△ x→o
sin (△ x)
△ x
g’(x) = -0 · cosx – sinx · 1
g’(x) = - sin x
Theorem: Derivative of Tangent Function:D x (tanx )=sec2 x
Proof:
D x( tanx))= D x( sinxcosx )
= cosx ·D x ( sinx )−sinx · D x (cosx )
cos2 x
= (cosx ) (cosx )− (sinx ) (−sinx )
cos2 x
= cos2 x+sin2 xcos2 x
= 1
cos2 x
D x( tanx) = sec2 x
EXAMPLES:
1. f(x) = sin x
1−2cos x
f’(x) = ¿¿
= ¿¿
= cos x−2(cos2¿x+sin2 x )¿¿¿ ¿
f’(x) = cos x−2¿¿¿