I Want tobeThe Teacher of Chemistry

1By : Ika Septiana_ReSaint

2

ASAM BASAPeta konsep

ASAM BASAPENGERT

IAN

ARRENIUS

BROWNSTED LOWRYLEWIS

ASAM

ASAM KUAT

ASAM LEMAH

BASA

BASA KUAT

BASA LEMAH

MANFAAT

By : Ika Septiana_ReSaint

3

ARrHENIUSASAM : Menghasilkan H+ atau (H3O+)Exp : HCl(aq) → H+

(aq) + Cl-(aq)

BASA : Menghasilkan OH-

Exp : NaOH(aq) → Na+(aq)

+ OH-(aq)

Menghasilkan H+

Menghasilkan OH-

By : Ika Septiana_ReSaint

By : Ika Septiana_ReSaint 4

BROWNSTED LOWRY

ASAM : donor H+ atau protonExp : HCl(aq) + H2O(aq) → Cl-(aq) + H3O+

(aq)

BASA : aseptor H+ atau protonExp : NH3(aq) + H2O(aq) → NH4

+(aq)

+ OH-

(aq)

Asam Basa Konjugasi

Basa Asam Konjugasi

By : Ika Septiana_ReSaint 5

LEWISASAM : aseptor e-

BASA : donor e-

Exp : H F H- -H + F-B-F → H-N : B-F N̈ H F H F

Memiliki PEB untuk donor

Tidak Memiliki PEB,maka Aseptor

6By : Ika Septiana_ReSaint

Larutan Elektrolit pH < 7 rasanya asam ABIMA (Asam Biru Merah)

Asam Kuat → ἁ = 1 Asam Lemah → ἁ < 1

ASAM

By : Ika Septiana_ReSaint 7

ASAM KUATExp : HCl, HBr, H2SO4, HNO3, Dll.Hitung pH

Contoh : Berapa pH larutan HCl 0.01 M ?Jawab : HCl(aq) → H+

(aq) + Cl-(aq)

0.01 M 0.01 MMaka [H+]=0.01 M → pH= -Log[H+]

= - log 10-2

= 2

pH= -Log [H+]

By : Ika Septiana_ReSaint 8

ASAM LEMAHExp : HF, H2SO3, H3PO4, HNO2, CH3COOH,HCOOH,

H2CO2 Dll.Hitung pH: [H+]=

Contoh:Berapa pH larutan HF 0.01 M dg Ka=10-4 ?Jawab : [H+]= = = 10-3

Maka [H+]= 10-3 M → pH= -Log[H+] = - log 10-3

= 3

pH= -Log [H+]

By : Ika Septiana_ReSaint 9

BASA Larutan Elektrolit pH > 7 rasanya pahit BAMBU (Basa

Merah Biru) Basa Kuat → ἁ = 1 Basa Lemah → ἁ

< 1

By : Ika Septiana_ReSaint 10

BASA KUATExp : NaOH, Ca(OH)2,KOH, Ba(OH)2, Dll.Hitung pH:

Contoh : Berapa pH larutan Ca(OH)2 0.005 M ?Jawab : Ca(OH)2(aq) → Ca+2

(aq) + 2OH-

(aq) 0.005 M 0.01 M

Maka [OH-]=0.01 M → pOH= -Log[OH-] = - log 10-2

pH=14-pH = 2pH= 14-2 =12

pOH= -Log [OH-]pH=14 - pOH

By : Ika Septiana_ReSaint 11

BASA LEMAHExp : NH3, Al(OH)3,Fe(OH)3 Dll.Hitung pH: [OH-]=

Contoh : Berapa pH larutan NH3 0.01 M dg Kb=10-4 ?Jawab : [NH3]=10-2

[0H-] = = = 10-3

Maka [H+]= 10-3 M → pOH = -Log[0H-] = - log 10-3

pH=14-pH = 3pH= 14-3 =11

pOH= -Log [OH-]

pH=14 - pOH

By : Ika Septiana_ReSaint 12

Manfaat Asam askorbat: Vit. C dan asam sitrat HCl : getah lambung CH3COOH : Cuka H2CO3 : rasa segar pada minuman H2SO4 : accu NH3 : pelarut desinfektan yang berbau

kuat NaOH : Soda apiAl(OH)3 & Mg(OH)2 : obat maag

13

Terima Kasih Atas Perhatiannya Wassalamu’alaikum

warahmatullahi Wabarakatuh..

By : Ika Septiana_ReSaint