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CONFIDENTIAL
3472/1
3472/1 NO. KAD PENGENALAN
Matematik
Tambahan
ANGKA GILIANPa!e" 1
#e!tembe"
2$$4 %A&ATAN PENDIDIKAN #A&A'
2 (am
)%IAN #ETAA #EPTEM&E 2$$4
ADDITIONAL MATHEMATICS
PAPER 1 Dua jam
%ANGAN &)KA KETA# #OALAN INI
#E'INGGA GI*EN T'ATTA')
1. Tuliskan angka giliran and nombor kad !ng!nalan anda ada ruang "ang
dis!diakan.
#. Calon dik!$!ndaki m!mba%a ara$an di
$alaman # .
&. '!r(as soalan ini $!ndakla$ dis!ra$kan di
ak$ir !!riksaan.
'!r(as soalan ini m!ngandungi 1) $alaman b!r%!(ak.
3472/1 +Lihat #ebe,ah
Kod Pemeriksa
Soalan
Marks
P!nu$
Marks
Di!rol!$1 #
# *
& *
* &
+ *
) &
, &
- *
&
1/ &
11 &1# &
1& &
1* *
1+ &
1) &
1, &
1- #
1 &
#/ &
#1 *
## *
#& &
#* &
#+ &
%-m,ah
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3472/1
Rumus0rumus b!riku( bola$ m!mban(u anda m!njaab soalan. Simbol0simbol "ang gi2!n ($a( is
"ang biasa digunakan.
ALGE&A
1a
a)bb /
#
*# −±−= -
a
bb
)
)
alog
loglog =
# nmnmaaa
+=× d na! n 314 −+=
& nmnmaaa
−=÷ 1/ 5314#6#
d nan
% n −+=
* mnnm
aa =34 11 1−= n
n ar !
+ nmmn aaa logloglog += 1# 17
1
314
1
314≠
−
−=
−
−= r
r
r a
r
r a%
nn
n
) nmn
maaa logloglog −= 1& 7
1 r
a%
−=∞ 1<r
, mnm a
n
a loglog =
KALK)L)#
1d/
du0
d/
d0u
d/
dyu0 y +== 7 * Luas di baa$ l!ngkung
8 ∫ b
a
y d/ a(au
##
70
d/
d0u
d/
du0
d/
dy
0
u y
−== 8 ∫
b
a
/ dy
+ Isiadu janaan
&d/
du
du
dy
d/
dy×= 8 ∫
b
a
y#
π d/ a(au
8 ∫ b
a
/#
π dy
3472/1
CONFIDENTIAL
CONFIDENTIAL
3472/1
&
7/23/2019 MAT TAMB K1 SEP
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#TATI#TIK
1 1
/ / ∑= , ∑
∑=i
ii
2
# 2 #
# ∑∑= .
/. / - 394
9
r n
n P r n
−=
& #
##34 /
1
/
1
/ /−=
−= ∑∑
σ 9394
9
r r n
n3 r
n
−=
* #
##34
/ .
./
.
/ / . −=
−=
∑∑
∑∑
σ 1/ 34343434 B A P B P A P B A P ∩−+=∪
+ 3 .
4 1
5mm
3#
1
4
−+= 11 1734 =+== −
6 p6 p3 r 7 P r nr
r
n
) 1//1
×=o8
8 # 1# Min 8 np
1& np6=σ
1*σ
µ −= /
9
GEOMETI
1 :arak 8 #
#1
#
#1 3434 y y / / −+−
# Ti(ik (!nga$ 4; 7 " 3 8
++#7#
#1#1 y y / /
& Ti(ik "ang m!mba$agi sua(u (!mb!r!ng garis
++
++
=nm
myny
nm
m/n/ y / #1#1 7374
* Luas s!gi(iga 8 3434#
1&1#&1#1&&##1 y / y / y / y / y / y / ++−++
+ ## y /r +=
) ##<
y /
j yi /r
+
+=
3472/1
CONFIDENTIAL
CONFIDENTIAL
3472/1
TIGONOMETI
*
7/23/2019 MAT TAMB K1 SEP
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1 Panjang l!ngkok 7 θ j s =
# Luas s!k(or 7 θ #
#
1 j 5 =
& 1sin ##
=+ Akos A
* A A sek ## (an1+=
+ Akot Akosek ## 1+=
) A A sin##sin = kos A
, A Akos Akos ##
sin# −= 8 1# # −kos
8 1 = # sin A#
- BkosA AkosB B A sinsin3sin4 ±=±
B AkosAkosB B Akos sinsin34 =±
1/ B A
B A B A
(an(an1
(an(an3(an4
±=±
11 A
A A
#(an1
(an##(an
−=
1#3
)
B
b
A
a
sinsinsin==
1& b))ba #### −+= kos A
1* Luas s!gi(iga 8 ab#
1 sin C
3472/1CONFIDENTIAL
+
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CONFIDENTIAL
Answer all 6uestions
1. >i2!n ($a( &7&
#? ≠
−→ /
/ / . and &#? +→ / / g . @ind 34 / .g in ($!
siml!s( orm. 6# marks5
Answer :
;;;;;;;;;
#. Diagram 1 s$os ($! maing o un%(ion 1− . and g . >i2!n ($a(
un%(ion ba/ / . +→? and un%(ion 7? /a
b / g → %al%ula(! ($! 2alu!s o
a and b .
6* marks5
Answer : a 8 BBBBBB..
b 8 BBBBBB..
3472/1 +Lihat ebe,ah
CON
FIDENTIAL
3472/1 or
e/amineruse
1
#
#
*
#
&
*
g 1− .
Diagram 1
)
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CONFIDENTIAL
3472/1
or </aminer
use
&
*
*
&
&. On! o ($! roo(s o ($! !ua(ion 1#)# # −=+ p / / is (i%! o ($! o($!r
roo( i($ p is %ons(an(. @ind ($! roo(s and ($! 2alu! o p. 6* marks5
Answer :root:;;;;;;;; p=;;;;;;;;;..
*. @ind ($! rang! o i /1314 ## =−++− p / p / do!s no( $a2! ($! r!al roo(s
6& marks5
Answer:;;;;;;;;;;.
3472/1
CONFIDENTIAL
,
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CONFIDENTIAL
+. I y / 1/1/ log#log& =− 7 s(a(! / in (!rms o y . 6* marks5
Answer:
;;;;;;;;;;.
). Sol2! ($! !ua(ion##11
1)*# +−−
=⋅ / / /
. 6& marks5
Answer:;;;;;;;;;;.
,. M is a oin( on ($! lin! $i%$ joining ($! oin( 4& 7 )3 and
411 7 #3 su%$ ($a( M 8 &M. @ind ($! %oordina(! o oin( M .
6& marks5
Answer:
;;;;;;;;;;.
3472/1 +Lihat #ebe,ah
CONFIDENTIAL
3472/1
or
e/aminer
use
+
*
)
&
,
&
-
7/23/2019 MAT TAMB K1 SEP
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CONFIDENT
IAL
ore/aminer
use
-
*
&
3472/1
-. @ind ($! !ua(ion o ($! !r!ndi%ular bis!%(or (o ($! lin! joining i($ ($! oin(s A4* 7# 3 and F40# 7 )3 . 6 * marks5
Answer:
;;;;;;;;;;.
. >i2!n ($a(+434 += / / . . @ind ($! 2alu! o 314G − . .
6& marks5
Answer:;;;;;;;;;;
3472/1
CONFIDENTIAL
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CONFIDENTIAL
1/. @ind ($! s(andard d!2ia(ion or ($! s!( o ($! numb!rs +7 )7 )7 *7 ,.
6& marks5
Answer:;;;;;;;;;;.
11. P!rim!(!r o a s!%(or is &/ %m. @ind ($! ar!a o ($! s!%(or i ($! radius is- %m . 6& marks5
Answer:
;;;;;;;;;;.
1#. >i2!n ($a( ($! irs( ($r!! (!rms or an ari($m!(i% rogr!ssion ar! )7 #;17 +;.
@ind ($! %ommon di!r!n%! o ($! ari($m!(i% rogr!ssion. 6& marks5
Answer:;;;;;;;;;;.
3472/1 +Lihat ebe,ah
CONFIDENTIAL
3472/1
or
e/aminer use
1/
&
11
&
1#
&
1/
7/23/2019 MAT TAMB K1 SEP
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CONFIDENTIAL
or
e/aminer use
1&
&
1*
*
3472/1
1&. In a g!om!(ri% rogr!ssion7 !a%$ o ($! (!rms is osi(i2!. I s!%ond
(!rm is ) and ($! or($ (!rm is 7&
#*# ind ($! 2alu! o ($! irs(
(!rm. 6& marks5
Answer ?
BBBBBBBB.
1*. T$! 2ariabl!s / and y ar! r!la(!d b" an !ua(ion #& b/a/ y += su%$
($a( a and b ar! %ons(an( . A s(raig$( lin! gra$ is ob(ain!d b"
lo((ing # /
y agains( / as s$on in Diagram # . Cal%ula(! ($! 2alu!
o a and b . 6* marks5
# /
y 417)3
4 & 7* 3
/
Diagram #
Answer ? a 8 BBBBBB b 8 BBBBBB
3472/1
CONFIDENTIAL
CONFIDENTIAL 3472/1
11
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1+. E2alua(! d/ /
/ /∫
+−#
1
#
3&34&46&
marks5
Answer ?
BBBBBBBB.
1) >i2!n ($a( ∫ =&
1
1/34 d/ / g 7 ind ($! 2alu! o k in !ua(ion
∫ =−&
1
1#534#6 d/k/ / g 6& marks5
Answer ? k 8 BBBBBBB..BB
6Lihat ebe,ah
3472/1
CONFIDENTIAL
or
e/aminer
use
1+
&
1)
&
1#
7/23/2019 MAT TAMB K1 SEP
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CONFIDENTIAL
3472/1 or
e/aminer
use
1,
&
1-
#
1,. >i2!n ($a( ji p )# −= and jik 6 .−= . I p is arall!l i($ 6 7ind ($! 2alu! o k . 6 & marks5
Answer ?k8BBBBBB
1-. >i2!n ($a( />P = and y>? = . OR is arall!l i($ S and >% = 2%P .
@ind P8 in (!rms o / and y . 6 # marks5
R
O S P
Answer ?BBBBBBBBB.
3472/1
CONFIDENTIAL
1&
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CONFIDENTIAL
1. I1&
+sin = A and oo
1-// ≤≤θ 7 ind ($! 2alu! o A#sin . 6& marks5
Answer : ;;;;;;;;;;.
#/. Sol2! ($! !ua(ion o)/sin#kos −=θ or oo#,/1-/ <<θ .
6& marks5
Answer :
;;;;;;;;;;.
#1. Ho man" numb!rs o *0digi( !2!n numb!r gr!a(!r ($an )/// %an b!
orm!d rom ($! digi(s #7 +7 )7 , and i($ou( r!!(i(ionJ6* marks5
Answer : ;;;;;;;;;;.
+Lihat ebe,ah
3472/1 or
e/aminer
use
1
&
#/
&
#1
*
3472/1 CONFIDENTIAL
1*
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CONFIDENTIAL
3472/1 or
e/amine
r use
##
*
#&
&
##. T$! robabili(" ($a( a durian in a bo; is ro((!n is+
1. I & durian ar!
randoml"
%$os!n rom ($! bo;. @ind ($! robabili(" ($a(4a3 all ($r!! durian ar! ro((!n.4b3 onl" on! durian is ro((!n. 6* marks5
Answer :@a
;;;;;;;;.. @b
;;;;;;;;..
#&. A %ommi((!! ($a( %onsis(s o m!mb!rs ar! orm!d (o sol2! ($! Malaria dis!as!
robl!m. T$a( %ommi((!! ar! s!l!%(!d rom ) ro!ssional7 + nurs!s7 and & so%ial ork!rs. Cal%ula(! ($! numb!r o a"s ($a( %ommi((!! %an b! orm!d su%$ ($a(
i( %onsis(s o & ro!ssional and a( l!as( on! so%ial ork!r. 6& marks5
Answer : ;;;;;;;;;;.
3472/1
1+
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CONFIDENTIAL
CONFIDENTIAL
3472/1
#*. >i2!n ($a( ($! robabili(" o a bo" gi2ing bir($ in a amil" is
+
&. I ($a(
amil" $as + %$ildr!n7 ind ($! robabili(" ($!r! is !;a%(l" & bo"s.6& marks5
Answer :
;;;;;;;;;;.
#+. T$! $!ig$( o a grou o bo"s ar! normall" dis(ribu(!d i($ a m!an o1+/.& )m and s(andard d!2ia(ion + )m . Cal%ula(! ($! robabili(" ($a( a bo" is
%$os!n and $is $!ig$( is l!ss ($an 1+& )m. 6& marks5
Answer :
;;;;;;;;;;.
KETA# #OALAN TAMAT
3472/1
or
e/aminer use
#*
&
#+
&
1)
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CONFIDENTIAL
1,
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CONFIDENTIAL
Jawab semua soalan
1. >i2!n ($a( &7&
#? ≠
−→ /
/ / . and &#? +→ / / g . @ind 34 / .g in
b!n(uk (!rmuda$. 6#
marks5
&3
#
−+ / + P1
/
1 + P2
Answer : /
1 + P2
#. Diagram 1 s$os !m!(aan bagi un%(ion 1− . and g . >i2!n ($a(
un%(ion ba/ / . +→? and un%(ion 7? /a
b / g → $i(ungkan ($! 2alu! o
a and b . 6* marks5
*
diagram 1
&1− . g #
*3&41 =− . a(au 4*3 8 & a(au #3*4 = g + P1
a4*3 b 8 & a(au #3*4 =a
b a(au 4b = 2a
%uba m!n"!l!saikan # !ua(ion +P3
&
1
=b and &
#
=a + P4 Answer :;;;;;;;;;
3472/1 +Lihat ebe,ah
CON
FIDENTIAL
3472/1ntuk
Kegunaan Pemeriks
a
1
#
#
*
1-
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CONFIDENTIAL
3472/1
ntuk Kegunaan
Pemeriksa
&
*
*
&
&. Sa(u dariada un%a !ua(ion 1#)# # −=+ p / / is dua kali un%a "ang
sa(u lagi7 d!ngan k!adaan p is %ons(an( . @ind un%a0un%a (!rs!bu(
and ($! 2alu! o p . 6* marks5
HTPP ? &#
)# −=
−=+ α α + P1
1−=α and #314# −=− + P2
HDPP ?#
1#3#4
+−=
pα α +P1
#
1#314# # +−
=− p
+P3
#
&−= p +P2
Answer : pun)a: "1 and "2 +P2
p=#
&−
+P2
*. @ind rang! ($! 2alu! o i /1314 ## =−++− p / p / (idak m!mun"ai
un%a n"a(a . 6& marks5
313414*35146 ## p p −−+− 0 $ +P1
/&#+ # <−+ p p a(au @p C 3@PD1 E - + P2
+
&1 <<− p + P3
Answer:+
&1 <<− p . + P3
3472/1
CONFIDENTIAL
1
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CONFIDENTIAL
+. I y / 1/1/ log#log& =− 7 n"a(akan / in s!bu(an y . 6* marks5
&
1/ 1/log + P1
/
1///log1/ + P2
#1///
y /
= + P3
#
1///
y / = + P4
Answer: #
1///
y / = + P 4
). S!l!saikan !ua(ion ##111)*# +−− =⋅ / / / . 6& marks5
3#14## /− a(au 3#4*# + / / / *#1# −+− a(au /&1# − + P1
-*&1 +=− / / + P2
1−= / + P3
Answer: 1−= / + P3
,. M is sa(u (i(ik ada garis "ang m!n"ambungkan (i(ik 4& 7 )3 and
411 7 #3 sua"a M 8 &M. @ind koordina( (i(ik M . 6& marks5
Tunjukkan gambadiagram (i(ik 7 M 7 d!ngan nisba$ "ang b!(ul
1 M & +P1
*
11+ a(au
*
1-# + + P2
3
*
#/7
*
#/4 a(au 4 + 7 + 3 + P3
Answer: @ & +P3
3472/1 +Lihat #ebe,ah
CONFID
ENTIAL
3472/1
ntuk
kegunaan
pemeriksa
+
*
)
&
,
&
#/
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CONFIDENTIAL
untuk
kegunaan pemeriksa
-
*
&
3472/1
-. @ind !ua(ion garis !mba$agi dua sama s!r!njang k!ada garis lurus
"ang m!n"ambungkan (i(ik A4* 7# 3 and F )37#4− . 6*
marks5
(i(ik (!nga$ AF 8 4 1 7 * 3 + P1
mAF &
#
)
*
#*
)#−=−=
+−
+ P2
mA& #
& + P3
+&# += / y ata-#
+
#
&+= / y ata- /+&# =−− / y + P4
Answer: +&# += / y ata-#
+
#
&+= / y ata- /+&# =−− / y + P4
. >i2!n ($a(+434 += / / . . @ind ($! 2alu! o bagi 314G − . .
6& marks5
/ / #3+4& ## + a(au ## 3+4) + / / + P1 >an(ikan 1−= / k! in / / #3+4& ## + a(au
## 3+4) + / / +P2
#1)− + P3
Answer: #1)− + P3
3472/1
CONFIDENTIAL
#1
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CONFIDENTIAL
1/. @ind sisi$an iaai bagi s!( nombor0nombor + 7) 7)7 * 7 , . 6& marks5
Min 8 3).+43+
#-43
+
,*))+4 atauatau
++++ + P1
A(au +
1)#+
*1)&)&)#+ atau++++ +P1
/*.1&).&1*.&# atau−=σ + P2
/1-.1=σ + P3
Answer:; /1-.1=σ + P3
11. P!rim!(!r bagi s!bua$ s!k(or bula(an is &/ %m . @ind luas s!k(or
bula(an i(u i j!jari bula(an is - %m . 6& marks5
*
,
-
1*1*- === θ θ atau + P1
L-a #3-34
*
,4
#
1 + P2
L-a +) %m# + P 3
Answer: L-a +) + P 3
.
1#. >i2!n ($a( (iga s!bu(an !r(ama bagi sua(u janjang ari(m!(ik is ) 7 #;1 7 +; .
@ind b!Ka s!un"a janjang ari(m!(ik i(u. 6& marks5
31#4+)1# +−=−+ / / / + P1
*−= / + P 2
1&−=d +P3
Answer: 1&−=d +P3
+Lihat ebe,ah
CONFIDENTIAL
3472/1
untuk
kegunaan pemeriks
a
1/
&
11
&
1#
&
##
7/23/2019 MAT TAMB K1 SEP
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CONFIDEN
TI
A
L
untuk
kegunaan pemeriksa
1&
&
1*
*
3472/1
1&. In sua(u janjang g!om!(ri7 s!(ia s!bu(an is osi(i . I s!bu(an
k!dua is ) and s!bu(an k!!ma( is 7&
#*# ind ($! 2alu! o s!bu(an
"ang !r(ama. 6& marks5
)=ar a(au&
#*#& =ar + P1
&
#=r + P2
1**=a + P3
Answer ?BB1** +P3
1*. P!mbol!$uba$ / and y di$ubungkan ol!$ !ua(ion #& b/a/ y += d!ngan
k!adaan a and b is %ons(an( . >ra garis lurus di!rol!$ d!ngan
m!mlo(# /
y m!laan / s!!r(i "ang di(unjukkan in Diagram # .
Hi(ungkan ($! 2alu! o a and ($! 2alu! o b .6* marks5
# /
y 41 7)3
Diagram #
4& 7* 3 /
1#
#
&1
*)−=−=
−−
=m +P1
Pada (i(ik 4& 7* 3
* 8 014&3 C
C 8 , +P2
,#
+−= / /
y +P3 antikan m an
#& , / / y +−=
a 8 1− b8 , +P4
Answer ? a 8 1− 7 b8 , +P4
CONFIDENTIAL 3472/1
#&
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1+. T$! 2alu! okan d/ /
/ /∫
+−#
1
#
3&34&46&
marks5
51
6
1#
−−
+− / / a(au 5
6
/ / + + P1
51
165
#
#6 +−+ +P2
+.&#
,−− atau +P3
Answer ? +.&#
,−− atau + P 3
1) >i2!n ($a( ∫ =&
1
1/34 d/ / g 7 ind ($! 2alu! o k in !ua(ion
∫ =−&
1
1#534#6 d/k/ / g 6& marks5
>an(ikan
∫ =
&
1
1/34 d/ / g iai(u #41/3 + P1
#
#k/ + P1
3#
1
#
&4
#
−k 8 - + P2
#=k + P3
Answer ? #=k + P3
6Lihat ebe,ah
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1+
&
1)
&
#*
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1,
&
1-
#
1,. >i2!n ($a( ji p )# −= and jik 6 .−= . I p s!lari d!ngan 6 7ind ($! 2alu! o k . 6 & marks5
k λ =# a(au 34) −=− λ
+ P1
&
#=λ + P2
&=k + P 3
Answer :? &=k + P 3
1-. >i2!n ($a( />P = and y>? = . OR s!lari d!ngan S and >% = 2%P .
@ind P8 in s!bu(an / and y . 6 # marks5
R
O S P
y / P? +−= + P1
34&
1 / y P8 −= + P2
Answer ? 34&
1 / y P8 −= + P2
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#+
7/23/2019 MAT TAMB K1 SEP
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1. I1&
+sin = A and oo
1-// ≤≤θ 7 ind ($! 2alu! o bagi A#sin . 6&
marks5
1&1#−=kosA + P 1
AkosA A sin##sin = ata- 31&
1#34
1&
+4# − + P 2
1)
1#/− + P3
Answer 51)
1#/− +P3
#/. S!l!saikan !ua(ion o)/sin#kos −=θ d!ngan k!adaan oo#,/1-/ <<θ .
6& marks5
-))./− + P1
o+1/# =θ +P2
o#++=θ + P3
Answer : o#++=θ + P3
#1. F!raaka$ bilangan nombor g!na * digi( "ang l!bi$ b!sar dariada
)///
"ang daa( dib!n(uk dariada digi( #7 +7 )7 , and (ana ulangan J 6* marks5
1-1#&& =××× +P1 1#1#&# =××× + P2
1- 1# (amba$kan # k!mungkinan dari P1 and P# + P3
&/ + P4
Answer : ;&/ + P4 ;;;.
+Lihat ebe,ah
CONFIDE
NTIALuntuk kegunaan
pemeriksa
1
&
#/
&
#1
*
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#)
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##
*
#&
&
##.+
1 dariada durian in s!bua$ ko(ak didaa(i rosak. I & biji durian
diili$ s!%ara raak dariada ko(ak (!rs!bu( . 'ira k!barangkalian ba$aa
4a3 s!mua k!(iga0(iga durian rosak.4b3 $an"a s!biji durian sa$aja rosak. 6* marks5
4a3&3
+
14
+
1
+
1
+
1atau×× + P1 4b3
+
1
+
*
+
*
+
*
+
1
+
*
+
*
+
*
+
1
1#+
1 + P2 ata- &
+
*
+
1 #
×
+P1
1#+
*- + P2
Answer @a1#+
1 + P2
4b31#+
*-
+ P2
#&. Sa(u jaa(ankuasa "ang (!rdiri dariada ) orang a$li !rlu dib!n(uk un(uk
m!nga(asi masala$ !n"aki( malaria . :aa(ankuasa i(u diili$ dariada ) orang
akar 7 + orang jururaa( and & orang a(!nand. Hi(ung bilangan %ara jaa(ankuasa i(u bol!$ dib!n(uk i jaa(ankuasa i(u m!s(i (!rdiri dariada &
orang akar and s!kurang0kurangn"a s!orang a(!nand . 6& marks5
1&
#+
&) 3 3 3 ⋅⋅ #
&1
+&
) 3 3 3 ⋅⋅ &&
/+
&) 3 3 3 ⋅⋅
8 11#/&+#/&1/#/ ××+××+×× +P1
8 )// &// #/ +P2
8 #/ +P3
Answer : #/ +P3
#,
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#*. >i2!n ($a( k!barangkalian bagi k!la$iran s!orang anak l!laki in s!bua$
k!luarga is+
&
. I k!luarga i(u m!mun"ai + orang anak 7 ind
k!barangkalian ba$aa (!rdaa( (!a( & orang anak l!laki .
6& marks5
P48&3 +P1
8#&
&+
&
#
+
&
3 +P2
8 &*+)./)#+
#1)atau +P3
Answer : &*+)./)#+
#1)atau +P3
#+. Tinggi s!kumulan l!laki m!ngiku( sa(u (aburan normal d!ngan min
1+/.& )m and sisi$an iaai + )m . @ind k!barangkalian s!orang l!laki "ang
diili$ s!%ara raak dariada kumulan i(u m!mun"ai (inggi kurang
dariada 1+& )m. 6& marks5
P4; 1+&3
8 P
−
<+
&.1+/1+& 9 a(au P ( )+*./< 9 +P1
3+*./4P1 >− 9 a(au 1 0 /.#*) +P2
8 /.,/+* +P3
Answer : -.'-4 +P3
untuk
kegunaan pemeriksa
#*
&
#+
&
#-
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:IAN SETARA
ADDITIONAL MATHEMATICS SPM
P!n"!laras? Pn. :ud" Lian !! Ling
4S!k(or P!ngurusan Akad!mik7
:aba(an P!ndidikan N!g!ri Saba$3
A$li Pan!l?
1. C$!ong N"uk Tai7 SM'4P3 Likas7 'o(a 'inabalu.#. C$ung Su 'iong7 SM:' Tiong Hua7 Sandakan.
&. P$oon C$i! @un7 SM' T!nom7 T!nom.
*. S$irn!" C$ua7 SM' Hol" Trini("7 Taau.
+. Suriani$ S!an7 SM' Tamaruli7 Tamaruli.). T$!r!sa L!! C$oon Moi7 SM' S(. Mi%$a!l P!namang7 P!namang.
,. Ting 'ai C$u7 Mak(ab Saba$7 'o(a kinabalu.-. !o$ S!k >o$7 SM' Agas!$7 La$ad Da(u.
#