FORMULASFORMULASC= d A=LWC= d A=LW
D=2rD=2r
QUOTE OF THE DAYQUOTE OF THE DAY““The greater the obstacle, the The greater the obstacle, the
more glory in overcoming it.”more glory in overcoming it.”
MoliereMoliere
? Of the Day? Of the Day
Why didn’t and Why didn’t and
like talking to ?like talking to ?
????PLEXER????????PLEXER????
SIGHT SIGHTSIGHT SIGHT
JOURNAL TOPICJOURNAL TOPIC Some parents give their child Some parents give their child
an unusual name, such as an unusual name, such as Rainbow or Tree. What would Rainbow or Tree. What would be some possible effects of be some possible effects of this on the child’s life?this on the child’s life?
[email protected]@sanjuan.edu
? ?
WEBSITEWEBSITE www.allmath.comwww.allmath.com
GEOGRAPHYGEOGRAPHY Massachusetts Massachusetts Capital: BostonCapital: Boston
FAMOUS PEOPLE FROM FAMOUS PEOPLE FROM MASSACHUSETTSMASSACHUSETTS
John & John Quincy AdamsJohn & John Quincy Adams John F. KennedyJohn F. Kennedy George BushGeorge Bush Paul ReverePaul Revere
SpellingSpelling perimeterperimeter• circumferencecircumference diameterdiameter radiusradius widthwidth
SpellingSpelling heightheight volumevolume rectangularrectangular areaarea pipi
PERIMETER OF A PERIMETER OF A SQUARESQUARE
P = 4S (side)P = 4S (side)
If S = 2”, then 4 x 2” = 8”If S = 2”, then 4 x 2” = 8”
Word ProblemsWord Problems The Adams familyThe Adams family
are remodeling theirare remodeling their
bathroom. They wantbathroom. They want
to put decorative tile around the top ofto put decorative tile around the top of
the walls. The room is 8’ x 8’. Howthe walls. The room is 8’ x 8’. How
many feet will they need? P= 4S =4 x 8=many feet will they need? P= 4S =4 x 8=
32 feet of tile.32 feet of tile.
Perimeter of a Perimeter of a RectangleRectangle
P = 2L + 2W (length and width)P = 2L + 2W (length and width)
If L = 4” and W = 2”, thenIf L = 4” and W = 2”, then
2 x 4 = 8 and 2 x 2 = 4.2 x 4 = 8 and 2 x 2 = 4.
8” + 4” = 12”.8” + 4” = 12”.
Word ProblemsWord Problems The Bells want to put aThe Bells want to put a
railing around their new patiorailing around their new patio
which is 20’ by 10’. How manywhich is 20’ by 10’. How many
feet of railing will they need?feet of railing will they need?
P= 2L + 2W (2 x 20 + 2 x 10)]P= 2L + 2W (2 x 20 + 2 x 10)]
P = 40 + 20 = 60’ of railing.P = 40 + 20 = 60’ of railing.
Perimeter of a TrianglePerimeter of a Triangle P = S + S + SP = S + S + S
If S one is 2”, S two is 3”, and If S one is 2”, S two is 3”, and S three is 4”, then P = 9”S three is 4”, then P = 9”
Word ProblemWord Problem The Bells have a smallThe Bells have a small
triangular garden area triangular garden area
which is 7’ x 6’ x 5’.which is 7’ x 6’ x 5’.
They wish to put a smallThey wish to put a small
fence around the garden.fence around the garden.
How much fencing will they need?How much fencing will they need?
P = 7+6+5 = 18’ of fencing.P = 7+6+5 = 18’ of fencing.
Circumference of a Circumference of a CircleCircle
C= d (diameter) (3.14C= d (diameter) (3.14))
If d= 4”, then 3.14If d= 4”, then 3.14 x 4”x 4” 12.56” 12.56”
Word ProblemWord Problem The Bells new spa is 14’The Bells new spa is 14’ in diameter. They wishin diameter. They wish to put decorative tilesto put decorative tiles around the edge. Howaround the edge. How many feet of tile will they need?many feet of tile will they need? C= d (use pi = 22/7). They will C= d (use pi = 22/7). They will
needneed 44’ of tiles. (22 x 14 44’ of tiles. (22 x 14 2 2 ) = 44’) = 44’ 7 7 11
JOKEJOKE
THE ROUNDEST KNIGHT AT King THE ROUNDEST KNIGHT AT King Arthur’s round table was Sir Arthur’s round table was Sir Cumference. He acquired his size Cumference. He acquired his size from too much pi.from too much pi.
Area of a SquareArea of a Square
A= SA= S
IfIf S = 2”, A = 4 square S = 2”, A = 4 square inchesinches
If S = 3”, A = 9 square” If S = 3”, A = 9 square”
(3 x 3)(3 x 3)
Word ProblemsWord Problems If the Adams’ new bathroomIf the Adams’ new bathroom
is 8’ by 8’, how many 12”is 8’ by 8’, how many 12”
tiles will they need to tile thetiles will they need to tile the
bathroom?bathroom?
A = S squared, A = 8 squared,A = S squared, A = 8 squared,
A = 64 square feet or 64 tiles.A = 64 square feet or 64 tiles.
Area of a RectangleArea of a Rectangle
A = LW (length times A = LW (length times width)width)
If L = 4 and W = 2, then If L = 4 and W = 2, then A = 8 squareA = 8 square If L = 3If L = 3”” and W = 1 and W = 1””,,Then A = 3 square inches Then A = 3 square inches
Word ProblemsWord Problems If the Bells new patio is 20’If the Bells new patio is 20’
by 10’, how many 12” tiles by 10’, how many 12” tiles
will they need to cover thewill they need to cover the
patio? A = LW (20 x 10 = 200)patio? A = LW (20 x 10 = 200)
They will need 200 square feet orThey will need 200 square feet or
200 tiles.200 tiles.
Area of a TriangleArea of a Triangle
A = 1/2BH (base x height)A = 1/2BH (base x height) If B = 8If B = 8”” and H = 4 and H = 4””,,
then A = ½ of 32then A = ½ of 32A = 16 square inchesA = 16 square inches
Word ProblemsWord Problems If the Bells decide to If the Bells decide to
paint half of the tilespaint half of the tiles
a contrasting color, howa contrasting color, how
many tiles will they paint?many tiles will they paint?
A = ½ BH. B 20’ x H 10’ = 200’,A = ½ BH. B 20’ x H 10’ = 200’,
A = 100 square feet or 100 tiles.A = 100 square feet or 100 tiles.
Area of a CircleArea of a CircleA = r pi = 3.14A = r pi = 3.14 r= radiusr= radius If r = 3If r = 3”,”, then 3 squared is 9 then 3 squared is 9 3.143.14 x 9x 9 28.26 square inches28.26 square inches
Word ProblemsWord Problems The Bells want to make a coverThe Bells want to make a cover for their new spa. How muchfor their new spa. How much material will they need?material will they need? A= r . If the spa isA= r . If the spa is
14’ across, the radius is 7’, squared is 49’14’ across, the radius is 7’, squared is 49’ Use 22/7 for pi. Then 22 x 7 = 154 squareUse 22/7 for pi. Then 22 x 7 = 154 square feet. ( feet. ( 22 x 49 22 x 49 77 = = 22 x 7 = 154 )22 x 7 = 154 )
77 11
Volume of a CubeVolume of a Cube
V= SV= S If S = 3If S = 3”,”, then then
V = 3 x 3 x 3 = 27 cubic V = 3 x 3 x 3 = 27 cubic inchesinches
Volume of a RectangleVolume of a Rectangle
V = LWH (length xV = LWH (length x
width x heightwidth x height
If L = 3’, W = 2’ andIf L = 3’, W = 2’ and
H = 2’, then V = 12 cubic H = 2’, then V = 12 cubic feet.feet.
Volume of a CylinderVolume of a Cylinder V = r h V = r h If r = 4”, then 4 squaredIf r = 4”, then 4 squared = 16. If h= 2”, then= 16. If h= 2”, then V = 3.14 (pi)V = 3.14 (pi) x 32x 32 628628 942942 10,048 cubic inches10,048 cubic inches
Word ProblemWord Problem The Garden-Gro Shop has several The Garden-Gro Shop has several
different sizes of planter “boxes”.different sizes of planter “boxes”. Some are square, some rectangular, Some are square, some rectangular,
and some are round. We need to and some are round. We need to find the amount of potting soil we will find the amount of potting soil we will need for each kind and size need for each kind and size purchased.purchased.
Planters (cont.)Planters (cont.)
V=S If the sides ofV=S If the sides of
this cube-shaped planter box arethis cube-shaped planter box are
2’, then V=2 x 2 x 2 = 8 cubic feet.2’, then V=2 x 2 x 2 = 8 cubic feet.
Planters (cont.)Planters (cont.) If this rectangular flower boxIf this rectangular flower box
is 3’ x 2’ x 2’, then V=LWH oris 3’ x 2’ x 2’, then V=LWH or
3 x 2 x 2= 12 cubic feet.3 x 2 x 2= 12 cubic feet.
Planters (cont.)Planters (cont.) If this circular flower pot has aIf this circular flower pot has a radius of 7” and is 10” high, thenradius of 7” and is 10” high, then V= r h.V= r h.
V= 22/7 x 7 x 10V= 22/7 x 7 x 10V= 22/7 x 49 x 10 (V= 22/7 x 49 x 10 (22/7 x 49 722/7 x 49 7))V = 22 x 7 x 10 = 154 x 10 = 1,540 V = 22 x 7 x 10 = 154 x 10 = 1,540
cubic “ of potting soil needed. cubic “ of potting soil needed.
Answer to ? Of the DayAnswer to ? Of the Day and didn’t like talkingand didn’t like talking
to because he went on to because he went on forever!forever!
Pi = 3.1428571,etc! Pi = 3.1428571,etc!
ANSWER TO PLEXERANSWER TO PLEXER
LOVE AT FIRST SIGHT!!LOVE AT FIRST SIGHT!!
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ALGEBRA ANDALGEBRA AND