Electrostatic Formula
Electric Force
F = 1 q1q2 = k q1q2
4 eo r2 r2
k = 9.0x10 9 N m2 = 1 = -------1------------
C2 4 eo 4 8.85x10-12 C2
N m2
Electric Force
F = 1 q1q2 = k q1q2
4 eo r2 r2
k = 9.0x10 9 N m2 = 1 = -------1------------
C2 4 eo 4 8.85x10-12 C2
N m2
Electric Force
F = 1 q1q2 = k q1q2
4 eo r2 r2
k = 9.0x10 9 N m2 = 1 = -------1------------
C2 4 eo 4 8.85x10-12 C2
N m2
Electric Force
F = 1 q1q2 = k q1q2
4 eo r2 r2
k = 9.0x10 9 N m2 = 1 = -------1------------
C2 4 eo 4 8.85x10-12 C2
N m2
Electric Force
F = 1 q1q2 = k q1q2
4 eo r2 r2
k = 9.0x10 9 N m2 = 1 = -------1------------
C2 4 eo 4 8.85x10-12 C2
N m2Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Force
F = 1 q1q2 = k q1q2
4 eo r2 r2
k = 9.0x10 9 N m2 = 1 = -------1------------
C2 4 eo 4 8.85x10-12 C2
N m2Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges
E = F q
F = kqq therefore E = Kqq therefore E =kq r2 r2q r2
Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges
E = F q
F = kqq therefore E = Kqq therefore E =kq r2 r2q r2
Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges
E = F q
F = kqq therefore E = Kqq therefore E =kq r2 r2q r2
Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges
E = F q
F = kqq therefore E = Kqq therefore E =kq r2 r2q r2
Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges
E = F q
F = kqq therefore E = Kqq therefore E =kq r2 r2q r2
Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field associated with point charges
E = F q
F = kqq therefore E = Kqq therefore E =kq r2 r2q r2
Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d
Electric Field Associated with Parallel Plates
The electric field is uniform between plates
Work is required to move +q from the – to +W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E = Volts q d meter
Capacitance
C = Q V
C = KAo
d K= dielectric constant A = area in m2
x10-12 C2
N m2
d = distance between plates in m
Capacitance
C = Q V
C = KAo
d K= dielectric constant A = area in m2
x10-12 C2
N m2
d = distance between plates in m
Capacitance
C = Q V
C = KAo
d K= dielectric constant A = area in m2
x10-12 C2
N m2
d = distance between plates in m
Capacitance
C = Q V
C = KAo
d K= dielectric constant A = area in m2
x10-12 C2
N m2
d = distance between plates in m
Capacitance
C = Q V
C = KAo
d K= dielectric constant A = area in m2
x10-12 C2
N m2
d = distance between plates in m
Capacitance
C = Q V
C = KAo
d K= dielectric constant A = area in m2
x10-12 C2
N m2
d = distance between plates in m
Capacitance
C = Q V
C = KAo
d K= dielectric constant A = area in m2
x10-12 C2
N m2
d = distance between plates in m
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and
progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2
V C = Q V = Q therefore U = ½ QV = ½ Q2
V C C
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
Cparallel = C1+C2+C3
2F
4F
6F
12F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 =U=1.08x10-4 J
What is the charged stored on each of the capacitors?CV=Q= 2x10-6F (3V) = 6x10-6C
CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q
CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q
Capacitance
1 = 1 + 1 + 1 Cseries C1 C2 C3
2F 4F 6F
1/C = 1/2F 1/4F + 1/6F
1/C = 11/12F = 12F/11=1.09 F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J
Capacitance
1 = 1 + 1 + 1 Cseries C1 C2 C3
2F 4F 6F
1/C = 1/2F 1/4F + 1/6F
1/C = 11/12F = 12F/11=1.09 F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J
Capacitance
1 = 1 + 1 + 1 Cseries C1 C2 C3
2F 4F 6F
1/C = 1/2F 1/4F + 1/6F
1/C = 11/12F = 12F/11=1.09 F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J
Capacitance
1 = 1 + 1 + 1 Cseries C1 C2 C3
2F 4F 6F
1/C = 1/2F 1/4F + 1/6F
1/C = 11/12F = 12F/11=1.09 F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J
Capacitance
1 = 1 + 1 + 1 Cseries C1 C2 C3
2F 4F 6F
1/C = 1/2F 1/4F + 1/6F
1/C = 11/12F = 12F/11= 1.09 F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J
Capacitance
1 = 1 + 1 + 1 Cseries C1 C2 C3
2F 4F 6F
1/C = 1/2F 1/4F + 1/6F
1/C = 11/12F = 12F/11= 1.09 F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J
Capacitance
1 = 1 + 1 + 1 Cseries C1 C2 C3
2F 4F 6F
1/C = 1/2F 1/4F + 1/6F
1/C = 11/12F = 12F/11= 1.09 F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J
Capacitance
1 = 1 + 1 + 1 Cseries C1 C2 C3
2F 4F 6F
1/C = 1/2F 1/4F + 1/6F
1/C = 11/12F = 12F/11= 1.09 F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J
Capacitance
1 = 1 + 1 + 1 Cseries C1 C2 C3
2F 4F 6F
1/C = 1/2F 1/4F + 1/6F
1/C = 11/12F = 12F/11= 1.09 F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J
Capacitance
1 = 1 + 1 + 1 Cseries C1 C2 C3
2F 4F 6F
1/C = 1/2F 1/4F + 1/6F
1/C = 11/12F = 12F/11= 1.09 F
3 V
What is the total charge stored in the system? C = Q VCV = Q = 1.09x10-6F (3V) = 3.27x10-6C
What is the energy stored in the system?U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 =U=1.47x10-5 J