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Class: SZ2-A JEE-MAIN MODEL Date: 07-06-2020
Time: 3hrs WTM-09 Max. Marks: 300
IMPORTANT INSTRUCTIONS
PHYSICS
Section Question Type +Ve
Marks - Ve
Marks No.of
Qs Total marks
Sec – I(Q.N : 1 – 20) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 21 – 25) Questions with Numerical Answer Type
(+/ - Decimal Numbers) 4 0 5 20
Total 25 100
CHEMISTRY
Section Question Type +Ve
Marks - Ve
Marks No.of
Qs Total marks
Sec – I(Q.N : 26 – 45) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 46 – 50) Questions with Numerical Answer Type
(+/ - Decimal Numbers) 4 0 5 20
Total 25 100
MATHEMATICS Section Question Type
+Ve Marks
- Ve Marks
No.of Qs
Total marks
Sec – I(Q.N : 51 – 70) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 71 – 75) Questions with Numerical Answer Type
(+/ - Decimal Numbers) 4 0 5 20
Total 25 100
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–:SZ2-A Jee-Main Exam Syllabus (07-06-20):–
TOPICS
PHYSICS
PRESENT WEEK 50%:
Projectile motion on an inclined plane, Applications, Relative motion
between projectiles, condition for collision between projectiles,
Applications.
PREVIOUS WEEK 50%:
Projectile motion - oblique projectile motion, Applications, Horizontal
projectile motion, Applications.
TOPICS
CHEMISTRY
PRESENT WEEK 50%:
Resonance, characteristics of resonance, Properties of covalent
compound,s Co - ordinate covalent bond (dative bond) Properties
of co - ordinate covalent bond, VBT
PREVIOUS WEEK 50%:
Crystal lattice energy, born Haber cycle, Fajans rules, Crystal lattice
of NaCl, CsCl, unit cell, coordination number, limiting radius ratio,
Properties of ionic compounds, Covalent bond, formation Lewis dot
structures, types, Co - valency, formal charge
TOPICS
MATHS
PRESENT WEEK 50%:
Transformations: Standard Formulae of Trigonometric
Transformations, Conditional Identities, Related Problems.
PREVIOUS WEEK 50%:
Important Standard Results On Multiple And Sub Multiple Angles,
Problems On Standard Results, Problems Related C±S<0 AND
C±S>0, Miscellaneous Problems.
SZ2-A _JEE-MAIN_WTM-09_QP_Dt.07-06-2020
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SECTION-I(1-20)
(Single Answer Type)
This section contains 20 multiple choice questions. Each question has 4 options
(1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.
01. If the horizontal components of velocities are equal, then path of a
projectile as observed from another projectile is
1) A hyperbola 2) A circle
3) A parabola 4) A straight line
02. An object is projected horizontally from a top of the tower of height
h. The line joining the point of projection and point of striking on
the ground makes an angle 45° with ground, Then with what
velocity the object strikes the ground
1) 11
2
gh 2)
9
2
gh 3)
7
2
gh 4)
5
2
gh
03. The horizontal and vertical displacements of a projectile are given
as x = at & y = bt-ct2. Then velocity of projection is
1) 2 2a b+ 2)
2 2b c+
3) 2 2a c+ 4)
2 2b c−
04. A ball is thrown with a velocity of u making an angle θ with the
horizontal. Its velocity vector normal to initial vector (u) after a time
interval of
1) sinu
g
2)
cos
u
g
3) sin
u
g 4)
cosu
g
05. Two bodies are projected at angle and ( )90− to the horizontal
with the same speed. The ratio of their times of flight is
1) 1:1 2) tan :1 3) 1: tan 4) 2tan :1
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06. Keeping the speed of projection constant, the angle of projection is
increased from 0 to 90 . Then the horizontal range of the projectile
1) Goes on increasing up to 90
2) Decreases up to 90
3) Increases up to 45 and decreases afterwards
4) Decreases up to 45 and increases afterwards
07. A particle is projected with a speed 7m / s at an angle above the
horizontal from foot of an inclined plane of inclination 30. If the
particle strikes the plane normally then the value of is
(g=10m/s2)
1) 0 1 330 tan
2
−
−
2) 0 1 330 tan
2
−
+
3) 0 1 360 tan
2
−
−
4) 0 1 230 tan
3
− +
08. A ball is projected horizontally with a speed 0v = 5 m/s from the top
of a hill for which = 37. (See the figure). Then (g=10m/s2)
A) Speed of the ball when its velocity vector is parallel to the hill is
2 ms−1
B) Speed of the ball when its velocity vector is parallel to the hill is
16.25ms−
C) Radius of curvature of the path is 4.9 m
D) Radius of curvature of the path is 6 m
Choose the correct options
1) BC 2) AC 3) CD 4) AD
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09. Two inclined planes OA and OB having inclinations 30 and 60
with the horizontal respectively intersect each other at O. A particle
is projected from P on OA with velocity 10 3 m/s perpendicular to
the plane OA. The particle strikes plane OB perpendicular to it at
Q with velocity v. Then time of flight is _____________sec.(g=10m/s2)
1) 2 3 2) 2 2 3) 2 4) 4 2
10. Two particles projected simultaneously from point (0, 0) and (1m,0)
with uniform velocity 10 m/s and v m/s respectively, as shown in
the figure. It is found that they collide after time t in space. Then
the value of velocity is
1) 5 m/sec 2) 5 2 m/sec 3) 25 m/sec 4) None
11. Two particles projected simultaneously from point (0, 0) and (1m,0)
with uniform velocity 10 m/s and v m/s respectively, as shown in
the figure. It is found that they collide after time t in space. Then
the value of time is ________sec.
1) ( )
1
5 3 1− 2) 1 3) 4 4) 2
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12. A shot is fired with a velocity u at angle ( )+ with the horizon from
the foot of an incline plane of angle through the point of
projection. If it hits the plane horizontally then tan=
1) 2
tan
1 2 tan
+ 2) 2tan
3) 2
2 tan
1 2 tan
+ 4)
2
2
tan
1 2 tan
+
13. The range of a projectile fired at an angle of 015 is 50 m. If it is fired
with the same speed at an angle of 045 , its range will be (nearly)
1) 25 m 2) 37 m 3) 50 m 4) 100 m
14. Two projectiles A and B are projected with angle of projection 015
for the projectile A and 045 for the projectile B. If AR and BR be the
horizontal range for the two projectiles, then
1) A BR R 2) A BR R= 3) A BR R
4) The information is insufficient to decide the relation of AR and
BR
15. A particle A is projected from the ground with an initial velocity of
110 ms− at an angle of 060 with horizontal. At the same instant,
another particle B is projected horizontally with velocity 15ms− from
height h above A so that both the particles collide at point C on the
ground. Taking 210 ,g ms−= then
1) 10h m= 2) 30h m= 3) 15h m= 4) None
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16. A projectile is fired with a velocity u at right angle to the slope
which is inclined at an angle with the horizontal. The expression
for R is
1) 22
tanu
g 2)
22sec
u
g
3) 2
2tanu
g 4)
22tan sec
u
g
17. A particle is projected at an angle 060 with speed 10 3 /m s from the
point A, as shown in the figure. At the same time the wedge is made
to move with speed 10 3 /m s towards right as shown in figure. Then
the time after which particle strike with wedge is
1) 2s 2) 2 3s 3) 4
3s 4) None
18. Two bodies A and B are projected from the same place in same
vertical plane with velocities 1v and 2.v From a long inclined plane
as shown the ratio of their times of flight is
1) 1
2
sinv
v
2) 1
2
2 sinv
v
3) 1
2
sin
2
v
v
4) None
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19. A particle P is projected from a point on the surface of smooth
inclined plane. Simultaneously another particle Q is released on the
smooth inclined plane from the same position. P and Q collide on
the inclined plane after t=4 second. The speed of projection of P is
(Take g=10 2/m s )
1) 5 m/s 2) 10 m/s 3) 15 m/s 4) 20 m/s
20. In the direction shown in figure with velocities 20 /Av m s= and
10 /Bv m s= respectively. They collide in air after 1
.2
s Then the
distance x is
1) 2 3m 2) 5 3m 3) 4 3m 4) None
SECTION-II(21-25)
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical values comprising of positive or negative decimal numbers (place value
ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.
21. In the direction shown in figure with velocities 20 /Av m s= and
10 /Bv m s= respectively. They collide in air after 1
.2
s Then the value
of is ______________degree.
SZ2-A _JEE-MAIN_WTM-09_QP_Dt.07-06-2020
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22. In the figure shown, the two projectiles are fired simultaneously.
The minimum distance between them during their flight is
____________m.
23. Number of correct statements are __________
I) For a projectile, w.r.t stationary frame path (or) trajectory is a
parabola
II) For a projectile, w.r.t stationary frame path (or) trajectory is a
ellipse
III) Acceleration of a projectile relative to another projective is zero
IV) Path of projectile w.r.t frame of another projectile is a straight
line
24. The number of correct statements are ___________
I) Path of the horizontal projectile is parabola
II) Path of the horizontal projectile is straight line
III) When a body is projected horizontally with a velocity from a
point above the ground level, it is called a horizontal projectile
IV) When a body is projected horizontally with a velocity from a
point above the ground level, it is called a inclined projectile
25. A particle is projected from the ground with an initial speed v at an
angle with horizontal. The average velocity of the particle between
its point of projection and highest point of trajectory is
21 cos .V
PN
+ Then the value of N P+ is
SZ2-A_JEE-MAIN_WTM-09_QP_Dt.07-06-2020
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SECTION-I(26-45)
(Single Answer Type)
This section contains 20 multiple choice questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be
correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.
26. Lattice energy depends on
1) Only radius of cation
2) Only radius of anion
3) Cation to anion radius ratio
4) Sum of the radii of cation and anion
27. Which of the following factors favours the Formation of Covalent
Bond?
1) Small size of cation
2) Large size of anion
3) Large charge on cation and Anion
4) All of these
28. Among the following the maximum covalent character is shown by
the compound [MAINS 2011]
1) 2MgCl 2) 2FeCl
3) 3AlCl 4) 2SnCl
29. According to Fajans rule covalent bond is favoured by
1) Small cation and large anion 2) Small cation and small anion
3) Large cation and large anion 4) Large cation and small anion
30. Which of the following is correct?
1) Resonance stabilises the molecule
2) More the number of resonating structures more will be the
stabiltiy of the molecule
3) Because of resonance all the bond lengths become same
4) All of these
SZ2-A _JEE-MAIN_WTM-09_QP_Dt.07-06-2020
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31. Co-ordinate covalent bond is formed by
1) Transfer of electrons 2) donation of electrons
3) Sharing of electrons 4) All of these
32. Sigma (σ) bond is formed by the
1) end to end overlap
2) head on overlap
3) Both (1) & (2)
4) sidewise overlapping
33. -bond is formed by the overlapping of
1) p - porbitals perpendicular to their axis
2) s - porbitals along the axis of p - orbital
3) p - porbitals along their axis
4) s - sorbitals
34. The bond between two identical non-metal atoms has a pair of
electrons
1) Unequally shared between them
2) Transfered fully from one atom to the other atom
3) With identical spins
4) Equally shared between them
35. Polarization power of a cation increases when
1) Charge on the cation increases
2) Size of the cation increases
3) Charge on the cation decreases
4) Has no relation to its size or charge
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36. 3NH and 3BF form an adduct readily because they form
1) A co-ordinate covalent bond 2) A covalent bond
3) An ionic bond 4) A hydrogen bond
37. Which of the following is not correct?
1) A double bond is stronger than a single bond
2) A sigma bond is stronger than pi bond
3) A sigma bond is weaker than pi bond
4) A double bond between two atoms is shorter than a single bond
between the same atoms
38. In the coordinate covalence
1) Electrons are equally shared by the atoms
2) Electrons of one atom are shared between the two atoms
3) Hydrogen bond is formed
4) All of these
39. Valence bond theory is based on the knowledge of
1) Atomic orbitals
2) electronic configurations of elements
3) overlap criteria of atomic orbitals
4) All of these
40. In Covalence
1) Transfer of electrons takes place
2) Sharing of electrons takes place
3) Sharing of electrons by one atom only
4) None of these take place
41. Strongest bond is formed by the head on overlapping of:
1) 2s and 2p orbitals 2) 2p and 2p orbitals
3) 2s and 2s orbitals 4) All of these
42. Covalent substances have low melting and boiling points. Except
1) Diamond 2) Carborundum (SiC)
3) Silica (SiO2) 4) All of these
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43. Which one of the following is an incorrect statement?
1) A bond is formed when a sigma already exists
2) A bond may be formed by the overlapping of ‘p’ or ‘d’ orbitals
3) A bond is formed by the overlapping of hybrid orbitals
4) A bond is formed by the lateral overlapping of atomic orbitals
44. Resonance is represented by
1) a double headed arrow 2) a single headed arrow
3) a curved arrow 4) All of these
45. Which of the following is the lewis dot structure of corresponding
elements
1) H • 2) B•
• •
3) Li • 4) All of these
SECTION-II(46-50)
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical values comprising of positive or negative decimal numbers (place value
ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -
123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.
46. In 34PO − ion the formal charge on the oxygen atom of P–O bond is
47. Covalence of nitrogen in Ammonium ion is
48. The number of resonance structures of ozone ( 3O ) is
49. Formal charge on central oxygen atoms of ozone is
50. The number of canonical forms of 2CO is
SZ2-A_JEE-MAIN_WTM-09_QP_Dt.07-06-2020
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SECTION-I (51-70)
(Single Answer Type)
This section contains 20 multiple choice questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be
correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.
51. ( )2
2 4
4 tan 1 tan
1 6 tan tan
x x
x x
−=
− +
1) tan x 2) tan2x 3) tan3x 4) tan4x
52. If sin cos
,a b
= then sin2 cos2a b+ =
1) b 2) a 3) 1
a 4)
1
b
53. 1 cos sin
1 cos sin
− + =
+ +
1) cot2
2) tan
2
3) tan 4) cot
54. For , R ( ) ( )2 2 2cos cos sin sin cos ,
2
− + + + =
then is
equal to
1) 1 2) 2 3) 3 4) 4
55. If 0 090 180 , then 1 cos 2 1 cos 2
1 cos 2 1 cos 2
+ + − =
+ − −
1) tan4
+
2) tan
4
−
3) 5
cot4
−
4) tan
56. If 12
tan5
− = and lies in II quadrant, then cos
2
=
1) 3
13 2)
2
13 3)
1
13 4)
4
13
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57. If 2
2
1cos 2
1
a
a
− =
+ and 0 00 90 , then
1tan 3
3for a
=
1) 3
2
3
1 3
a a
a
−
− 2)
3
2
3
1 3
a a
a
+
− 3)
3
2
3
1 3
a a
a
−
− 4)
2
2
1
a
a−
58. In a triangle ABC,
( ) ( ) ( ) ( )sin 2 3 2 .cos 2 cos 2 3 2 .sin 2A B C A B C A B C A B C+ + + + + + + + + =
1) sin 2B 2) cos2B 3) sin2B− 4) cos 2ec A
59. 2
cos8 cos 4 2
cos 2
− −=
1) 2cos4 3− 2) 4cos4 6−
3) 2cos4 3+ 4) 4cos4 6+
60. If 0340 ,A = then 1 sin 1 sinA A− − + =
1) 2cos2
A 2) 2sin
2
A
3) 2cos2
A− 4) 2sin
2
A−
61. If ( )3sin 4sin 2 , = + then ( )tan
tan
+=
1) 1
2− 2) 7− 3)
1
7− 4) 2
62. If 3
sin sin ,4
+ = 3
cos cos ,8
+ = then tan2
+ =
1) 1
2 2) 2 3) 4 4)
1
4
63. If 0180 ,A B C+ + = then cos2 cos2 cos2 1A B C+ + + =
1) 4sin sin cosA B C− 2) 4cos cos cosA B C−
3) 4cos cos sinA B C− 4) 4sin cos sinA B C−
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64. The value of 2 0 2 0
0 0
cos 33 cos 57
sin 21 cos 21
−
− is equal to
1) 1
2− 2)
1
2 3)
1
2− 4)
1
2
65.
1997 1997sin sin B cos cos
cos cos sin sin
A A B
A B A B
− − + =
+ +
1) 52 tan2
A B+
2) 52 tan2
A B−
3) 52cot2
A B+
4) 0
66. If ( ) ( )0 0cos 60 ,cos ,cos 60− + are in H.P, then cos =
1) 2
3 2)
2
3 3)
3
2 4)
3
2
67. If 1
tan ,5
A = then sin 2 sin 4
cos 2 cos 4
A A
A A
+=
−
1) 1
5− 2)
1
5 3) 5− 4) 5
68. If cos 4 cos 2 1
sin 4 sin 2 3
A A
A A
+=
+ and
3 2A
then
2
2 tan
1 tan
A
A=
+
1) 0sin 35 2) 0sin 20 3) 0sin 40 4) 0sin 80
69. ( )22sin 1 2cos 4 − =
1) sin9 sin7+ 2) sin9 sin7−
3) sin7 sin9− 4) sin16
70. If sin 4 sin 2 sin 2
,cos3 x
− =
then 1 cos2+ =
1) 2
4
x 2)
2
2
x 3) 22x 4) 24x
SZ2-A _JEE-MAIN_WTM-09_QP_Dt.07-06-2020
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SECTION-II(71-75)
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical
values comprising of positive or negative decimal numbers (place value
ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.
71. If 2 4 8
tan 2 tan 4 tan 8cot tan ,7 7 7 7
+ + + = then sin7 is equal to
72. ( ) ( )2 2
2 2 2 2cos 3 4cos sin 3 4sin ,k k N − + − = , then 17k is equal to
73. If 2 4cos 2 cos 4 sin sin ,a b− = + then a b+
74. If sin 7 sin 5
,sin 6
k+
=
then cos
15cos
k
k
+
− is equal to
75. ( )18sec6 .sec4 cos10 cos2 + is equal to
" When you can't control what is happening, challenge yourself to control
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