Chapter 11
Properties of Solutions
Important Vocabulary
• Homogeneous means there is only one phase (compositions do not vary)
• Ex: Kool Aid, air, steel• Solute: Gets dissolved • Solvent: Does the dissolving• Solution: Homogeneous mixture
consisting of a solute and solvent
Dilute vs. Concentrated
• Can’t be used in calculations• Molarity, mass percent, and mole fraction
can be used to show solution concentrations
Molarity
• Moles of solute/liters of solution • Represented by M• Example: A solution was prepared by adding
5.84 g of formaldehyde, H2CO, to 100.0 g of water. The final volume of the solution was 104.0 mL. Calculate the molarity.
• Answer: 1.87 M H2CO
Mass Percent
• Percent by mass of the solute in the solution• Mass Percent = (mass of solute/mass of
solution) X 100%• Example: A solution was prepared by adding
5.84 g of formaldehyde, H2CO, to 100.0 g of water. The final volume of the solution was 104.0 mL. Calculate the mass percent.
• Answer: 5.52 % H2CO, 94.48% H2O
Mole Fraction• Represented by X• Moles of part/moles of solution X 100%
Mole Frac. A = XA = nA/(nA+nB)
• Example: A solution was prepared by adding 5.84 g of formaldehyde, H2CO, to 100.0 g of water. The final volume of the solution was 104.0 mL. Calculate the mole fraction.
• Answer: XH2CO = 0.0338, XH2O = 0.9662
Molality• Represented by m• Moles of solute per kilogram of solvent
Molality = moles of solute/kilogram of solvent
• Example: A solution was prepared by adding 5.84 g of formaldehyde, H2CO, to 100.0 g of water. The final volume of the solution was 104.0 mL. Calculate the molality.
• Answer: 1.94 m H2CO
Solubility
• Shows what will dissolve in what• “Like dissolves like” = polar solvents will
dissolve polar/ionic solutes and nonpolar solvents will dissolve nonpolar solutes
Factors Affecting Solubility
1. Structure2. Pressure3. Temperature
1. Structure Effects• Polarity of solute/solvent (like dissolves like)• Example: vitamins are fat-soluble and water-
soluble– Fat-soluble = nonpolar, hydrophobic (water-fearing),
build up/stored in fatty tissue, too much = hypervitaminosis
– Water-soluble = polar, hydrophilic (water-loving), extra are excreted by the body
2. Pressure Effects• Doesn’t affect liquids/solids, but has a large
affect on gases
• Gas solubility increases as the partial pressure of the gas above the solution increases
Henry’s Law
• Shows relationship between gas pressure and concentration of dissolved gas:
C = kP• C = concentration of dissolved gas• K = constant for particular solution• P = partial pressure of gas above solution• Works best with gases that don’t
dissociate in/react with solvent
Henry’s Law Example
• The solubility of O2 is 2.2 X 10-4 M at 0C and 0.10 atm. Calculate the solubility of O2 at 0C and 0.35 atm.
• Answer: 7.7 X 10-4 M O2
3. Temperature Effects• For most solids, solubility increases
as temperature increases• For most gases, solubility decreases
as temperature increases–Thermal Pollution in lakes: increase in
temp. lowers dissolved oxygen concentrations
Vapor Pressure of Solutions• If a solution contains a nonvolitile (not
easily vaporized) solute, its vapor pressure is LOWER than the pure solvent.
• Shells of water solvation make it so it’s harder for the solvent to vaporize
• Molecules that do not dissociate (break up) in water (solvent) have higher vapor pressures than ionic compounds that do dissociate
• The decrease in a solution’s vapor pressure is proportional to the number of particles the solute makes in solution.
Answer This…
• Which compound affects the vapor pressure of a solution the least: glucose, sodium chloride, or calcium chloride?
• Solutions with covalent compounds > Solutions with ionic compounds
Raoult’s Law• Calculates the expected vapor pressure of a
solution based on the solute/solvent
Psoln = XsolventP0solvent
• Psoln = observed vapor pressure of solution
• Xsolvent = mole fraction of solvent
• P0solvent = vapor pressure of the pure solvent
Example
• Glycerin, C3H8O3, is a nonvolatile liquid. What is the vapor pressure of a solution made by adding 164 g of glycerin to 338 mL of H2O at 39.8C? The vapor pressure of pure water at 39.8C is 54.74 torr and its density is 0.992 g/mL.
• Answer: 50.0 torr
Example #2
• What is the vapor pressure of a solution made by adding 52.9 g of CuCl2, a strong electrolyte, to 800.0 mL of water at 52.0C? The vapor pressure of water is 102.1 torr, and its density is 0.987 g/mL.
• Answer: 99.4 torr
Colligative Properties
• Depend on the number of solute particles, NOT their identity in an ideal solution1. Boiling-Point Elevation2. Freezing-Point Depression3. Osmotic Pressure
1. Boiling-Point Elevation• Review boiling point definition: when
vapor pressure = atmospheric pressure
• When solute is added to solvent, it lowers the vapor pressure.
• More kinetic energy must be added to bring the solution to boiling
• Boiling point is HIGHER in solutions than in pure solvents
• Antifreeze in car engines (solute) makes it so car engines don’t boil in high temperatures
• The more solute particles dissolved, the higher the boiling point (identity doesn’t matter)
Boiling-Point Elevation Calculation• Change in boiling point ∆Tb is the
difference between the boiling point of the solution and the pure solvent
• Unit: °C/m• Calculated using
∆Tb = Kb X msolute
Kb is a molal boiling-point elevation constant of the solvent found on pg. 517
Example
• What is the boiling point of a solution containing 96.7g of sucrose (C12H22O11) in 250.0g water at 1atm?
• Answer: 100.579°C
2. Freezing-Point Depression• When solute is present, the normal
molecular freezing pattern is disrupted• This makes it so the solution has to
lose more kinetic energy (get colder) in order to solidify
• Freezing point of the solution is LOWER than that of the pure solvent
• The more solute particles dissolved, the more the freezing point decreases (identity doesn’t matter)
• Sidewalk salt and car antifreeze work this way
Freezing-Point Depression Calculation
• Change in freezing point ∆Tf is the difference between the freezing point of the solution and the pure solvent
• Unit: °C/m• Calculated using
∆Tf = Kf X msolute
Kf is a molal freezing-point depression constant of the solvent found on pg. 517
Example
• Determine the freezing point of a solution made by adding 27.5 g of methanol (CH3OH) to 250.0 g of water.
• Answer: -6.39°C
Example
• Find the boiling point of a 1.50m solution of calcium chloride, CaCl2 and water.
• Answer: 2.30°C so the new boiling point would be 102.30°C.