Application Equipment and Calibration
G. S. Manual - Chap. 7Workbook - pp. 22-26
Application Calibration & Calculations
1998-99
Application Equipment and Calibration
Calibrating The Sprayer:Selecting Nozzle Size
Variables
1. Nozzle flow rate (GPM)
2. Ground speed (MPH)
3. Effective sprayed width (W)-inches
4. Application rate (GPA)
Application Equipment and Calibration
Measuring Ground Speed
Speed(MPH)Distance(ft) x 60
Time(seconds) x 88
Where 1 MPH = traveling 88 feet in 60
seconds
Application Equipment and Calibration
Application Rate Equation
GPAGPM X 5940
MPH X W
Equation # 1
• Calculates for application rate
• Represents total amount applied for an acre
• Calculates for application rate
• Represents total amount applied for an acre
Application Equipment and Calibration
Flow Rate Equation
GPMGPA x MPH x W
5940
Equation # 2
• Calculates for amount of flow from one nozzle
• Represents the size of nozzle to put on the sprayer
• Calculates for amount of flow from one nozzle
• Represents the size of nozzle to put on the sprayer
Application Equipment and Calibration
Where: gallons per acre
gallons per minute
miles per hour
GPA = ______________________
GPM = ______________________
MPH = ______________________
W = ______________________nozzle spacing - inches
5940 = a constant to convert gallons per minute, miles per hour,
and inches to gallons per acre
5940 = a constant to convert gallons per minute, miles per hour,
and inches to gallons per acre
Application Equipment and Calibration
Affect of variables on rate:
• Pressure • Pressure
How would the listed variables be adjusted to double the flow in gallons per minute from a spray nozzle or to double the application rate in gallons per acre?
Decrease by 1/2 (GPA)Decrease by 1/2 (GPA)
• Nozzle spacing • Nozzle spacing
Increase 4 times (GPM) Increase 4 times (GPM)
• Travel speed • Travel speed
Decrease by 1/2 (GPA)Decrease by 1/2 (GPA)
Application Equipment and Calibration
1. Select application ratefrom the label
2. Select an appropriate ground speed
3. Determine effective sprayed width
4. Determine the flow rate required
5. Select nozzle that will give the required flow rate
6. Convert flow rate from GPM to OPM
7. Collect the output from one or all nozzles
8. Determine the amount of pesticide needed - label
9. Operate the sprayer at speed from step 2
10. Check flow frequently- compare all nozzles
Calibration Steps:
Application Equipment and Calibration
4. Determining MPH Example #1:A sprayer takes 22 seconds for the first pass
and 24 seconds for the return pass to travel a measured course of 200 feet, what is the speed in MPH?
Speed(MPH)Distance(ft) x 60
Time(seconds) x 88
MPH= 88 X
60 X = SPEED
NDS SECO= 2
+ = TIME AVERAGE22 24
200
23
23
5.9
Application Equipment and Calibration
5. GPA Example #2:
• Your sprayer is set up with flat fan nozzles spaced at 20-inches and have a measured flow rate of .51 gpm at 35 psi. What would be the application rate when using these nozzles at 35 psi traveling 7 MPH?
• Which equation should you use?
• To calculate for application rate or flow rate?
Application Rate
Application Equipment and Calibration
GPA Example Solution:
GPA=?
GPAGPM X 5940
MPH X W
GPM=? MPH=? W=?GPA=? GPM=.51 MPH=7 W=20
Application Equipment and Calibration
GPA.51 X 5940
7 X 20
GPA Example Solution:
GPAGPM X 5940
MPH X W
Answer 21.6
Application Equipment and Calibration
6. GPM Example #3:
• You want to broadcast a soil applied herbicide at 15 GPA traveling 7 MPH using flooding nozzles on 40-inch spacing.
• Which equation should you use?
• To calculate for application rate or flow rate?
Flow Rate
Application Equipment and Calibration
GPA Example Solution:
GPM=? GPA=? MPH=? W=?GPM=? GPA=15 MPH=7 W=40
GPMGPA x MPH x W
5940
Application Equipment and Calibration
GPM Example Solution:
GPMGPA x MPH x W
5940
GPM15 x 7 x 40
5940
Answer .71
Application Equipment and Calibration
MIXING PROCEDURE
THE RECOMMENDED APPLICATION RATE OF A PESTICIDE IS GIVEN AS:
• Active ingredient (a.i.)
• Product or Formulation
Application Equipment and Calibration
MIXING PROCEDURE
THE RECOMMENDED APPLICATION RATE OF A PESTICIDE IS GIVEN AS:
• Active ingredient (a.i.)
• Product or Formulation
needs adjustment!
Application Equipment and Calibration
MIXING PROCEDURE:
THE RECOMMENDED APPLICATION RATE OF A PESTICIDE IS GIVEN AS:
• Active ingredient (a.i.)
• Product or Formulationready
to use!
Application Equipment and Calibration
8A.Dry Ingredient example #4:A recommendation of 2 lb. active ingredient
(a.i.) per acre is given for benefluralin. The sprayer has a 400-gallon tank and is calibrated to apply 75 GPA. Determine the amount of Balan 60DF to be added to the tank.
key word - active ingredient (a.i.)
How many acres per tank?
How much product per acre?
How much product per tank?
Application Equipment and Calibration
Acres / Tankful400 gal
75gpa5.3acres
2lbs./Acre100%60%
3.3lbs.
Answer
Dry ingredient example solution:
5.3 A/tank X 3.3 lbs. product/A = 17.5 lbs
Application Equipment and Calibration
8B. Liquid ingredient example #5:An applicator needs to apply a broadleaf herbicide using a 400 gallon sprayer at a rate of 2 pounds (a.i.) active ingredient per acre. A 4EC material will be used. With a calibrated rate of 20 gallons per acre - how much herbicide will be needed to be added to the spray tank?
key word - (a.i.)How many acres per tank?
How much product per acre?
How much product per tank?
Application Equipment and Calibration
Acres / Tankful400 gal
20 gpa20 acres
Liquid a.i. example solution:
Lbs.product / Albs a.i. recommended
lbs. a.i. purchased24
0.5 gpa
Answer
20 A/tank X 0.5 gpa product/A = 10 gal.
Application Equipment and Calibration
8C. Liquid formulation example #6:
You are to spray a 4EC herbicide to a 5 acreturf area. The rate to apply is 1.5 quarts formulation in 20 gallons of water per acre.
How much herbicide should be added to the tank?
keyword - formulation
Size of area? 5 acres
Application Equipment and Calibration
Solution:
What is the rate?
1.5 quarts/acre
1.5 quarts x 5 acres = 7.5 quarts
Application Equipment and Calibration
8D. Liquid formulation/area - #7:You have a product which is a 4E and
recommended at the rate of 3.2 qts. per acre. How much of this product is needed to treat an area measuring 250 ft. by 575 ft.?
_____ ft. X _____ ft. = ________ square feet_____ ft. X _____ ft. = ________ square feet250 575 143,750
es_______acr ft/a sq 43,560
ft sq 143,750
3.3
________ acres X 3.2 qts. =3.3 ______ qts10.56