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M. Salman Khan Chapter-3 Scalars & Vector Q1. Differentiate between Scalars and Vectors. Scalars Vectors Physical Quantities which can be completely specified by a number with a suitable unit with out mention of direction are known as Scalars. Physical Quantities which can be completely specified by a number with a suitable unit and direction are called Vectors. Mass, Volume, Density, Temperature, Energy, Electric Potential, Charge, Time and Distance are the examples of Scalar Quantities. Acceleration, Force, Velocity, Displacement, Momentum and Electric Intensity are the examples of Vector Quantities. Scalars can be added, subtracted, multiplied and divided by simple arithmetical rules. Vectors can be added, subtracted, multiplied and divided by vector algebra. As the scalars are the simple numbers therefore they do not have any special representation like vectors. A vector quantity is represented by an arrow, length of the arrow is proportional to magnitude of the vector quantity, the direction of the arrow represent the direction of vector quantity. Q2. Define the following : 1. Head to Tail Rule 2. Negative of a vector 3. Null vector 4. Resultant vector 1

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Page 1: X Notes Complete

M. Salman Khan

Chapter-3

Scalars & Vector

Q1. Differentiate between Scalars and Vectors.

Scalars VectorsPhysical Quantities which can be

completely specified by a number with a

suitable unit with out mention of

direction are known as Scalars.

Physical Quantities which can be

completely specified by a number with a

suitable unit and direction are called

Vectors.

Mass, Volume, Density, Temperature,

Energy, Electric Potential, Charge, Time

and Distance are the examples of Scalar

Quantities.

Acceleration, Force, Velocity,

Displacement, Momentum and Electric

Intensity are the examples of Vector

Quantities.

Scalars can be added, subtracted,

multiplied and divided by simple

arithmetical rules.

Vectors can be added, subtracted,

multiplied and divided by vector

algebra.

As the scalars are the simple numbers

therefore they do not have any special

representation like vectors.

A vector quantity is represented by an

arrow, length of the arrow is

proportional to magnitude of the vector

quantity, the direction of the arrow

represent the direction of vector

quantity.

Q2. Define the following :1. Head to Tail Rule

2. Negative of a vector

3. Null vector

4. Resultant vector

I. HEAD TO TAIL RULE To add two or mote vectors by this method they are drawn on a suitable scale such that the

head of one vector coincides with the tail of other and so no. The resultant vector is obtained by

joining the tail of the first vector to the head of the last vector. It is directed from the tail of the

first vector to the head of the last vector. It is directed from the tail of the first vector to the head

of the last vector. The magnitude and the direction of the resultant are found by using ruler and

protractor.

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II. NEGATIVE OF A VECTOR Suppose we have a vector A, then its negative is define as

A vector having the same magnitude as that of given “Vector A” but opposite in direction

is called the negative vector of A and is denoted by “-A”.

III. NULL VECTOR

It is a vector having zero magnitude and orbiting direction. It is denoted by O.

IV. RESULTANT VECTOR When two or more than two vectors are added we get a single vector which has the same

effect as the combined effect of all the vectors to be added. This single vector is known as

the resultant vector.

The resultant of A and B is R. symbolically we can write as

R = A + B

Q3. Write note on the following Subtraction of vectors.

SUBTRACTION OF VECTORSThe subtraction of two vectors is just like addition of vectors. In order to subtract a A from

B, the negative of A (i.e. -A) is added to B, and the resultant vector R of –A and B is found

which gives the difference between B and A.

Q4. Explain graphically method of addition of vectors.

GRAPHICAL METHOD OF VECTOR’S ADDITION Addition of Vectors:

The process of combining two or more vectors to produce a single vector

(called resultants) is known as addition.

Graphical Method of Vector’s Addition

In this method the magnitude and direction of a resultant vector is found by ruler and protractor.

We can explain the given procedure as follows

1. First we chose a system of reference

2. Draw the second vector with suitable scale keeping in view its magnitude and

direction.

3. Draw the second vector using the same scale by placing the tail of second vector on

the Head of the first vector.

4. Join the “head” of the second vector with the tail of the first vector. The straight line

joining the tail of the first vector to the head of the second vector represented the

“Resultant Vector”2

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When three of more vectors to be added two vectors are added first, then the next one and

so on. This procedure could be extended to any number of vectors involved. Symbolically

R = A + B + C ……………………

Q5. Define resolution of a vector. Describe a method of resolving a vector in to its

rectangular components.

RESOLUTION OF VECTORThe process of splitting up of a single vector into a number of vectors is called “Resolution of

Vectors”.

RECTANGULAR COMPONENTSThe components of a vectors which are at right angles to each other are called rectangular

components.

RESOLVING A VECTOR INTO ITS COMPONENTS

1. Consider a vector A which makes an angles “O” with the x-axis, the vector A is

drawn by placing its tail at the origin of rectangular co-ordinate system.

2. From the head of the vector A perpendicular lines are drawn to the axis and drawn to

the axis and Ax and Ay are so formed are regarded as the components of A, By

parallelogram law of vector addition.

A = Ax + Ay

Ax is acting along the x-axis

Ay is acting along the y-axis

MAGNITUDES OF Ax and AyFor Ay

Consider right angled triangle OPQ Perp / Hyp = Sin

or Ay / A = Sin

or Ay / = A Sin

or Ay = A Sin

For Ax

Base / Hyp = Cos

or Ax / A = Cos

or Ax = A Cos

or Ax = A Cos

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Q6. Explain addition of two vector perpendicular to each other. (Addition of rectangular

component method).

Suppose these are two forces F1 and F2 are acting on a body and making an angle of 90o

with each other. We have to find the resultant force.

In the above figure OA and AB represent F1and F2 respectively and OB is the resultant

vector of these forces. OAB is and right angled triangle and we can use Pythagoras Theorem.

Hence,

(OB)2 = (OA)2 + (OB)2

or R2 = F12 + F22

or R = F12 + F22

The direction of “R” can be calculated by using trigonometric ratios.

Tan = F2/ F1 (Tan = Perp./Base)

= tan-1 F2/F1

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Chapter-4

Kinematics

Q1. Define the following: Rest

Motion

Translatory Motion

Rotatory Motion

Vibratory Motion

Displacement

RESTA body is said to be at rest when it does not change its position with respect to its

surrounding objects.

EXAMPLE OF RESTExamples of position of Rest are given below.

1- A book lying on a table.

2- A bird sitting on a wall.

MOTIONA body is said to be in motion when it changes its position with respect to its surrounding objects.

EXAMPLES OF MOTION Examples of position of Motion are given below.

1- A book lying on a table.

2- A bird sitting on a wall.

TRANSLATORY MOTIONIt is the motion which is associated with bodies moving in a straight line, e.g.; The motion of a car

on a straight road, the flying of an aeroplane, the falling of brick etc.

VIBRATORY MOTIONTo and for motion of an object about a mean position is called vibratory motion or oscillatory

motion. Motion of a swing, motion of the string of sitar or violin are the examples of vibratory

motion.

ROTATORY MOTIONWhen a body moves such that its distance from a fixed point remains constant, its motion is

said to be rotatory motion.

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Motion of the wheel of cycle, hands of clock and wing of a fan are the examples of rotatory

motion.

DISPLACEMENTIt is a vector quantity which signified the least distance between two points in a particular

direction.

Q2. Write note on the following: Speed

Velocity

Uniform and Variable Velocity

Acceleration

Deceleration

Uniform Acceleration

Acceleration due to Gravity

SPEED“Rate of change of distance is called speed”. It is measured by the distance traveled by a

body in unit time. If covered distance denoted by “S” and time taken by “t” and speed by “v” then

Speed = Distance Covered / Time

or Vav = S/ t S.I unit of speed is meter/second

or m/s or ms-1

VELOCITY“Rate of change of displacement is called velocity”

or

“Speed of a body in specified direction is called velocity

The average velocity of a moving body is given by the displacement divided by the time elapsed.

Average Velocity = Displacement / Time Elapsed

or Vav = d / t

S.I. unit velocity is meter/second or ms-1

UNIFORM VELOCITYThe velocity of a body is said to be uniform if it covers equal distance in equal intervals of

time in a specified direction.

VARIABLE VELOCITYThe value of velocity may change due to a change in magnitude or change in direction or in both.

Thus a body is said to posses a variable velocity if its speed or its direction changes continuously.

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ACCELERATION“Rate of change of velocity is called acceleration”. The word change may imply an alteration in

direction or in magnitude or in both.

Suppose Vi is the initial velocity and Vf is the final velocity, then (Vf )

Change in velocity = Vf -Vi

If this change occurs in time “t” then

Rate of change of velocity = a = (Vf - Vi ) / t a = ( Vf - Vi ) / t

or aav = V / t

unit of acceleration m/s2 or ms-2

DECELERATIONIf the rate of change of velocity is negative then it called deceleration or retardation.

UNIFORM ACCELERATION If velocity changes uniformly in equal intervals of time, however short the interval may be, in a

straight line the acceleration so produced is called uniform acceleration.

ACCELERATION DUE TO GRAVITYAll bodies irrespective of their masses, while falling freely under gravity experience the same

acceleration called acceleration due to gravity. Average value of this acceleration is found to be 9.8

ms-2. It is denoted by “g”.

Q3. Drive the following Vf = Vi + at

S = Vit + ½ at2

2as = Vf2 - Vi

2

Answer :

S = Vit + ½ at2

PROOF :Suppose initial velocity of a body = Vi

Final velocity of a body = Vf

Average velocity Va = (Vi + Vf ) / 2

Distance covered by a body in time “t”

S = Vav x t (1)

From equation of motion Vf = Vi + at, Substituting the value of Vf in eq.1

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S = ( Vi + Vi + at ) / 2 x t

or S = ( 2Vi + at ) / 2 x t

or S = 2Vit + at2 / 2

or S = 2 Vit/2 + at2/ 2

S = Vit + ½ at2

2as = Vf2 - Vi

2

Suppose initial velocity of a body = Vi

Final Velocity of a body = Vf

Average Velocity = Vav = ( Vf + Vi )/2

Let the body moves with average velocity till the time “t” then covered distance

S = Vav x t (1)

Substituting the value of Vav in eq. (1)

S = ( Vf + Vi ) / 2 x t (2)

From equation of motion Vf = Vi + at,

Substituting the value of “t” in eq. (2)

S = ( Vf + Vi ) / 2 x ( Vf - Vi ) / a

S = (Vf ) 2 - (Vi) 2 /2a

or 2as = Vf 2 - Vi 2

2as = Vf 2 - Vi 2

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Chapter -6

Static

Q1. Write a note on “Torque”.

Definition:“The turning effect of a force about the axis of rotation is called torque or moment of that force”.

We can measure it by the product of force and moment arm.

Mathematical Representation:The torque is represented by a Greek letter Tau () symbolically

= F x r

where “r” is the moment arm.

Magnitude of torque = = F r Sin

or = Fr Sin

Where “” is angle between F and r.

UNITS OF TORQUEForce is measured in Newton and moment arm in meter, then unit of torque is “Newton

Meter” or “Nm”.

DIRECTION OF TORQUEThe direction of torque is always normal to the plane formed by F and r. The torque causing

anticlockwise rotation is regarded as a vector directed along the axis outward from the page.

Similarly torque causing clockwise rotation is regarded as vector directed along the axis into

the page and conventionally taken to be -ve.

MOMENT ARMThe perpendicular distance b/w the line of action of force and axis of rotation is called moment

arm.

FACTORS UPON WHICH THE TORQUE DEPENS Torque depends upon the following factors.

a) Magnitude of the force. Torque and magnitude of force are directly proportional to each other.

b) Magnitude of the moment arm. Torque and moment arm also directly proportional to each other.

POSITIVE TORQUEThe torque which tends to rotate a body in counter clockwise rotation is given a positive sign.

NEGATIVE TORQUE The torque which tens to rotate a body is clockwise rotation is given as negative.

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Counter Clockwise Rotation

is out of the paper.

is taken positive.

Clockwise Rotation

is into the paper.

is taken negative.

MINIMUM & MAXIMUM VALUES OF TORQUETorque is zero when

Moment arm is zero i.e. r = 0

Angle b/w F and r is zero i.e. = 0

= F r Sin = F r x 0 = 0

Torque is maximum when

Maximum force is applied

Maximum possible length of moment arm.

Angle b/w F and r is a right angle i.e. ( = 90o)

Q2.a) Define centre of gravity?

b) Find the centre of gravity of the fall Objects sphere, Uniform Road, Circular Plate, Plate

(Square, Rectangular, Parallelogram Shaped)

c) Explain how would you locate the centre of gravity of an irregular piece of metal shape?

a) CENTRE OF GRAVITY “The point inside or outside the body, where the whole weight of body appears to act is

called centre of gravity”.

b) CENTRE OF GRAVITY OF SOME OBJECTS

S.No. Name Of Object Position Of Centre Of Gravity

1. Sphere Centre Of Sphere

2. Uniform Rod Centre Of Rod

3. Circular Plate Centre Of Plate

4. Plate ( Square, Rect., or

Parallelogram in Shape

Interaction Of Diagonals

5. Triangular Plate Intersection Of Medians

6. Cylinder Mid Point Of Axis

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c) CENTRE OF GRAVITY OF AN IRREGULAR SHAPED BODY The centre of gravity of an irregular shape body cannot be found by simple geometrical

method, but a simple experiment can help to determine it.

To find the centre of gravity of an irregular shaped body drill a small hole “A” near the edge of

the cardboard.

Use this hole to hang the cardboard from a nail.

With the help of plumb line draw a line “Aa” on the cardboard.

Repeat this experiment using the holes “B” & “C” respectively, and draw Bb and Cc. These lines

intersect each other at a point “G”. The centre of gravity lies at their point of interaction “G”.

Q3.a) Define equilibrium

b) State the two conditions of equilibrium

c) Define the types of equilibrium.

d) Distinguish the three types of Equilibrium.

a) EQULIBRIUM When two or more than two forces act on a body simultaneously in such a manner that there is no

change, either in it’s translational motion on in it’s rotational motion, the body is said to be in

Equilibrium.

b) FIRST CONDITION OF EQULIBRIUMAccording to this condition if the resultant of all forces acting on a body is zero, the body is in

equilibrium.

i.e. F = O ( Sigma, stands for summation)

In general case, the forces are resolved into rectangular components i.e. x-components and y-

components. If forces are resolved into their components, then according to first condition.

If the sum of all forces acting along the x-axis is zero, the body is in equilibrium i.e. Fx = 0.

If the sum of all forces acting along the y-axis is zero, the body is in equilibrium i.e. Fy = 0.

If a body satisfies first condition of equilibrium, it’s translational acceleration is zero and the body is

said to be in Translational Equilibrium.

SECOND CONDITION OF EQULIBRIUMConsider a body which can rotate about a fixed point and there are some forces acting upon it,

then if the algebraic sum of all the torque on the body is zero, then it is in equilibrium.

If the second condition of equilibrium is satisfied then there is no angular acceleration and the

body is said to be in Rotational Equilibrium.

d) STATES OF EQULIBRIUM

STABLE EQULIBRIUM UNSTABLE

EQULIBRIUM

NEUTRAL

EQULIBRIUM

Centre of gravity of the Centre of Gravity of the Centre of Gravity of the

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body lies below the point

of support or suspension.

body lies above the point

of support or suspension.

body lies at point of

support or suspension

If we give a slight jerk, to

the body , the centre of

gravity rises.

If we give a slight jerk to

the body, the centre of

gravity of the body is

lowered.

If we give a slight jerk to

the body, it’s centre of

gravity neither rises nor

lowered.

If a book is lifted from one

edge and then allowed to

fall, it will come back to

it’s original position.

If a pencil standing

vertically is slightly

distributed from it’s

position, it will not come

back to it’s original

position.

If a ball is pushed slightly

to roll, it will neither come

back to it’s original

position nor it will gain a

new position.

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Chapter-5

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Force And Motion

Q1. Define the following:

Force, Inertia, Coefficient of friction unit of force (Newton)

FORCEForce is that agent which changes or tends to change the state of rest or of uniform velocity of a

body.

INERTIAThe property of matter by virtue of which a body is incapable of changing its state of rest or of

uniform motion along a straight line.

COEFFICIENT OF FRICTIONIt is the ratio between limiting friction and normal reaction. It is denoted by

= Limiting friction / Normal reaction

= F / R

Unit Of Force (Newton):

One Newton is that amount of force which is required to produce an acceleration of 1m/s2 in a

body of mass 1 Kg.

Q2.a) State Newton’s first law of motion.

b) Explain the law and give the definition of force.

c) Give at least two examples from the daily life which explain the Newton’s first law.

a) STATEMENT“Every body continues in the state of rest or of uniform motion in a straight line unless it is

compelled to change that state by an external force.”

b) THIS LAW CONSIST OF TWO PARTSThe first part state that “A body at rest will remain at rest unless it is compelled to change that

state by an external force”. It is very easy to understand, it is our common observation that a book

lying on a table will continue to remain there until we displace it, This means an external

force is needed to change the state of rest. The second part state that, “A body in motion in a

straight line with a uniform velocity until it is acted upon by an external force”. According to

second part,

If we roll a ball on the ground, with some velocity it some keep on rolling forever.

If a bullet is fired from a short gun, it should keep on moving forever.

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But common observation seems to contradict these statements, we know that a ball rolling on the

ground and a bullet fired from a gun, stop after some time actually

there are three forces which stops the motion of bodies, these forces are the force of friction, force

of gravity and air resistance. Rolling ball stops due to force of gravity and air resistance. Moving

bullet stops due to force of gravity, air resistance. This means that if we could get rid of all these

forces the bodies will continue moving in a straight line.

c) EXAMPLES 1. The fireman in a railway engine, Swiftly moves the coal rod near the furnace and suddenly

stop the rod, in this process the rod comes to rest suddenly and coal already in motion

continues to move in the same direction and falls into the furnace.

2. A boy riding a push bike along a level road does not comes to rest immediately when he stop

pedaling. The push bike continues to move forwards, but eventually it comes to rest as the

result of opposing action of the air resistance and road friction.

Q3. State Newton’s Third Law Of Motion and give at least three examples

from your daily life.

STATEMENT“If one body exert a force on the second body, the second body exert an equal but opposite

force on the first”.

OR

“To every action there is an equal and opposite reaction”.

MathematicallyF . action = - F. reaction

The minus sign indicates that the two forces are acting in opposite directions.

Examples The birds while flying, push the air downward with their wings (action). The air exert an equal

and opposite force on the birds in the upward direction (reaction).

The swimmer pushes the water in the backward direction with a certain force (action), water

pushes the man forwards with an equal and opposite force (reaction).

The blades of the helicopter revolve in horizontal direction and pushes the air downwards

(action). The air lifts the helicopter vertically upward (reaction).

Q4. Define Inertia and give at least two examples from your daily life.

INERTIA“The property of matter by virtue of which a body is incapable of changing its state of rest

or of uniform motion in a straight line on its own accord is describe as Inertia”.

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A passenger in a bus falls backward when the bus suddenly starts moving, when the bus

starts moving the lower portion of the body share the motion of the bus, where the upper portion

is still at rest. Due to this reason passenger falls backward when the bus start.

A passenger falls forward when the bus in motion suddenly stops. When the bus in motion

the passenger sharing the motion of the bus, when bus stop the lower portion of the bus comes to

rest. The upper portion of the body is in motion, hence he fall forward.

Q5. Differentiate b/w Mass and Weight

MASS WEIGHT

The quantity of matter in a body is

called mass.

Weight is the force with which earth

attracts a body towards its centre.

It is the property of a body which

determines the acceleration produce in it

under the influence of a gravitational

force i.e. a= F/m

It is the measurement of gravitational force

between earth and the body

i.e. W=mg

It is a non-directional quantity. It is a directional quantity, and always

directed towards centre of the earth.

The mass of a body remain constant

every where.

The value of weight is different at different

distances from the centre of the earth.

Mass can be determined by ordinary

balance.

Weight is often measured by a spring

balance.

6/5

Q6. State Newton’s second law of motion and prove that F = ma.

STATEMENTWhenever a net force acts on an object it produces an acceleration in its own direction which is

directly proportional to net force and inversely proportional to mass of the object.

ExplanationIt is our common observation that if there is no change in the mass of the object, acceleration will

increase with the increase of net force on the object mathematically we can write it as

a F (mass is constant)

Similarly if the applied force remains the same, there by increasing mass of the object the

acceleration will decrease, mathematically we can write it as

a 1 / m (for a constant force)

By combining the above two relations

a F/m

or a = k F/m

Where k is the constant of proportionality.15

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If 1 N force is applied on an object of mass 1 kg which produces an acceleration of 1 m/s2, then by

substituting these values we get.

1 = k 1/1

or k = 1

Substituting the value of ‘k’ in e.g.

a = k F/m

or a = (1) F/m

a = F/m

F = ma

Q7. Define momentum and

a) Write its Mathematical Form

b) State law of conservation of momentum and give it mathematical form

MOMENTUMA physical quantity that decides how easy or difficult it will be to stop a moving body is known as

momentum of the body.

Mathematically it can be calculated by the product of mass and velocity.

So momentum = mass x velocity

If momentum is denoted by ‘P’ then

P = mV

UnitAs mass is measured in ‘kg’ and velocity in m/s, therefore unit of momentum is Kg m/s or Ns

STATEMENT OF LAW OF CONSERVATION OF MOMENTUMIn an isolated system total momentum before and after collision remains the same.

ExplanationConsider an isolated system in which two bodies ‘A’ and ‘B’ are moving with the velocities ‘U1’

and ‘U2’ respectively suppose ‘U1’ > ‘U2’ and both are moving in the same line and same direction.

Momentum of body A = m1u1

Momentum of body B = m2u2

Total momentum of the system = m1u1 + m2u2

Suppose after time t they collide with each other, and their velocities becomes ‘V1’and ‘V2’

After collision momentum of body A = m1v1momentum of body

B = m2v2

Total momentum of the system after collision = m1v1 = m2v2

According to law of conservation of momentum

Momentum before collision = Momentum after collision

So,

m1u1 + m2u2 = m1v1 + m2v2

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Q8.

a) Define friction, give its mathematical form

b) Define the following

Coefficient of friction

Rolling friction

c) Advantages and Disadvantages of friction,

d) Methods of reducing the friction.

a) FRICTIONWhen a body slides or rolls on a surface it experience a force in a direction opposite to its motion.

Which resist the motion of the body. This resisting force is called Force Of Friction.

ExplanationSuppose a body of weight ‘W’ placed on a surface is drag by Force ‘F’. It experiences a force in a

direction opposite to its motion, when we increase the amount of applied force the value of

frictional force also increases up to some extent . From the experiments its is proved that force of

friction has the ability to increase its value with the increase of applied force till reaches the

maximum value. Due to this strange nature, force of friction is called self adjusting force. The

maximum value of friction is called limiting friction. When the applied force is exceed from the

limiting friction the body starts sliding. Experiments show that the limiting friction is proportional

to weight of the body. i.e. f w

or w = R

Therefore f R where “R” is the normal reaction

f = R

Here “” is the coefficient of friction, and it is dimension less constant.

b) CO-EFFICIENT OF FRICTION Coefficient of friction is the ratio b/w limiting friction and normal reaction, i.e.

= f / R

It depends upon nature of the surface and as it is dimension less constant.

c) Rolling FrictionIf we rolled a heavy spherical ball on smooth surface, an opposing force which try to stop the

motion of rolling ball is called Rolling friction.

DISADVANTAGES OF FRICTION Wear and tear of the machinery is due to excessive friction.

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A large amount of power is wasted in over coming friction and the efficiency of machine

decreases considerably.

ADVANTAGES OF FRICTION Without friction between feet and ground it is not possible to walk.

In the absence of friction, the brakes of motor car can not work.

METHODS OF REDUCING THE FRICTIONFriction can be reduced by the following methods:

The various part of the machine which are moving over one another are properly lubricated.

In machine the sliding of various parts is usually replaced by rolling and its is done by casing

ball bearing.

Where sliding is unavoidable a thick layer of greasing material is used between the sliding

surfaces.

The front part of fast moving objects is cars and aeroplanes are made obliged to decrease air

friction.

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Chapter -6

CIRCULAR MOTION AND GRAVITATION

Q 1. Define centripetal acceleration and give its mathematical form and on what

factors it depends.

DefinitionWhen a body moves in a circle, its direction changes continuously due to which an

acceleration is produce which is directed towards the centre of the circle. This

acceleration is called centripetal acceleration.

MATHEMATICAL FORMCentripetal acceleration = ac = v2/r

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Where ‘V’ is the speed of the body and ‘r’ is the radius of circle in which body

is moving.

Q2. a) Define Centripetal force.

b) Derive Fc =m2/r

c) On what factors Centripetal force depends.

d) Give some examples of Centripetal force from your daily life.

a) DefinitionWhen a body moves in a circle with uniform speed, the force required to keep it moving in

a circular path is called Centripetal force. This force is always directed towards the centre of the

circle.

b) MATHEMATICAL FORMSuppose a body of mass ‘m’ is moving in a circular path of radius ‘r’ with a

speed of “V m/s”.

According to Newton’s second law of motion

F = ma

or Fc = m ac

As we know that ac = v2/r

therefore Fc = mv2/r

Hence

Centripetal force Fc = mv2/r

c) FACTORS UPON WHICH CENTRIPETAL FORCE DEPENDSCentripetal force depends upon the following factor

Mass of the object Fc m Centripetal force is increases with the increase of mass of the

body and decreases by decreasing mass of the body.

Velocity of the object Fc x v2 Centripetal force is directly proportional to square of

the velocity. It increases with the increase of velocity.

Radius of circular path Fc x 1/r If radius of the circle in which body is moving increase,

Centripetal force will decrease.

EXAMPLES OF CENTRIPETAL FORCE FROM DAILY LIFE When a car moves along a round track, the force of friction between tyres and road provide

necessary centripetal force and keep the car on the curved path.

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Gravitational force between moon and earth provide centripetal force and keep the moon on a

circular path.

Q 3. Define centrifugal force and give some examples of centrifugal force from the

daily life.

CENTRIFUGAL FORCE Such a force which is produced by virtue of centripetal force is called centrifugal force.

It is a force of reaction of centripetal force. In case of motion of a stone whirled

in a circle, centripetal force acts on the stone and centrifugal force act on the hand.

MATHEMATICAL FORM As centrifugal force is the force of reaction, therefore its mathematical

representation is same as centripetal force but with negative sign.

Centrifugal force = - mv2/r

EXAMPLES FROM DAILY LIFE When we whirl a stone tied at the end of a string, we experiences an outward force on our

hand. This is centrifugal force.

Centrifuge system helps in separating honey from bees wax.

Q 4. State Newton’s law of gravitation and prove that F = G m1m2/d2.

STATEMENTEverybody in this universe l attracts every other body with a force which is directly

proportional to the product of their masses and inversely proportional to the square of the

distance between their centers.

MATHEMATICAL REPRESENTATIONSuppose two bodies A and B of masses ‘m1’ and ‘m2’ respectively and ‘d’ is

the distance between their centres.

As force of attraction between the bodies is directly proportional to product of their

masses, i.e. F m1 m2 -------- 1

This force is inversely proportional to square of the distance between their centres,

i.e. F 1/d2------- 2

Combining the relations 1and 2 we got

F = G x m1 m2 /d2

OR F = G m1 m2 /d2

When G is the gravitational constant.

Its value is G = 6.67x 10-11 N m2/kg2

Q 4. Derive an equation for mass of the earth, by applying law of gravitation.20

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Consider a body of mass ‘m’ place on the surface of the earth.

Suppose mass of the earth is Me then the force of attraction between the body and

earth is given by gravitational law

F = G m Me / Re2 -- 1

(Neglecting the distance between centre of the body and earth’s surface).

But we know that the force with witch earth attracts a body towards its centre is

weight i.e. F = W = mg ---- 2

By comparing 1 and 2 we get

mg = G m Me / Re2

or mg Re2 /Gm = Me

or gRe2/G = Me

or Me = gRe2 /G

With the help of above relation we can calculate the value of mass of the earth..

Q5. Calculate Mass of the earth.

With the help of gravitational law, we have derived a relation for mass of the earth,

i.e. Me = Re2g / G

We know that in S.I. Units Re = 6.4x106 m

g = 9.8 m/s2

G = 6.67x10-11 N m2/kg2

Substituting the values , we got

Me = (6.4x106)2 x 9.8 / 6.67 x 10-11

Me = 40.96 x 1012 x9.8 / 6.67 x 10-11

= 401.40 x 1012 + 11 / 6.67

= 60.1 x 1023

= 6.01 x 1024

Me = 6 x 1024 kg

Q6. Differentiate between g and G.

g GIt is the acceleration due to gravity It is gravitational constant

In S.I. units its value is 9.8 m/ s2 In S.I. units its value is 6.67 x 10-11 Nm2 /

Kg2

Its value increases by decreasing altitude

and vice versa

Its value is constant for whole universe

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Q7. Explain the variation of “g” with altitude.Value of “g” is not a constant gravity, its value depends upon the distance of the body from the centre

of the earth. The value of “g” varies inversly as the square of this distance, i.e.

g 1 / r2

Where “r” is the distance b/w centre of considering body and centre of the earth.

Therefore, at the earth, value of “g” is less at equator then pole because equatorial distance is more at

poles.

Differentiate b/w centripetal and centrifugal forces.

CENTRIPETAL FORCE CENTIFUGAL FORCE

It is a centre seeking force. It is centre fleeing force.

This force acts on the body making

circular motion

This force acts on the body providing

centripetal force

This force is a force of action This force is a force of reaction

**********************************************

Chapter-8

WORK ENERGY & POWER

Q1.a) Define work and it’s units?

b) Evaluate work when force and displacement are not in one direction?

a) WORK Work is said to be done when a force “F” causes a displacement “d” in the body on which it

acts.

EXPLANATIONIf the displacement of the body takes place under the action of a constant force in the

direction of force, the work done is given by the product of the magnitude of force and that of the

displacement.

MATHEMATICAL FORMWork = ( Force ) ( Displacement )

or W = F S

UNITS OF WORKJOULE:

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In S.I units, the unit of work is Joule. It is defined as “the work done by a force of one

Newton in moving a body through a distance of one meter in the direction of force.

ERG:

In C.G.S. system the unit of work is ERG. It is defined as “the work done by a force of one

dyne while moving a body through a distance of one centimeter in the direction of force”.

FOOT POUND:

In British Engineering system the unit of work is Foot Pound. It is defined as “the work

done when a force of one pound moves a body through a distance of foot in a direction of force.

EVALUATE WORK WHEN FORCE AND DISPLACEMENT ARE NOT IN ONE

DIRECTIONIf force makes an angle with the direction of displacement then we calculate work by resolving

force into two components “Fx”, which acts along the direction of displacement “Fy”, which acts

perpendicular to the ground .

then, Fx = F Cos

Fy = F Sin

As the body is moving along the horizontal direction therefore the component Fx is doing

work, whereas the component Fy is not effective because no work is done along this direction

therefore.

Work = ( Fx ) (d)

or Work = (F Cos ) (d)

or Work = F d Cos

FACTORS ON WHICH WORK DEPENDS Displacement ( d )

Angle Between Force And Displacement

Q2. Define Potential Energy, Derive a formula of Potential Energy?

POTENTIAL ENERGYPotential Energy of a body is define as the energy due to position of a body.

Gravitational Potential EnergyIf a body is lifted to a position higher than it’s initial position in the gravitational field of

the earth, the work is done on it. This work is stored in this body as

potential energy. Such potential energy is called Gravitational Potential Energy. This energy is

recovered if the body is allowed to fall..

Magnitude Of P.E:

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Suppose a body of mass ‘m’ is situated at some point in a gravitational field of the earth. It

is lifted with very small speed vertically through a distance ‘h’. The force required to raise the

body is just equal and opposite to its weight (W=mg) of the body.

This work done on the body is, therefore, given by

Work = Force x Displacement

Work = W x h

Work = mgh

This work is equal to potential energy

P.E = mgh

Factors On Which Potential Energy DependsPotential energy depends upon the following factors.

Mass of the body

Height from initial point.

Value of acceleration due to gravity

Potential Energy is directly proportional to mass and height .

Q3. Define Kinetic Energy and derive the formula K.E =1/2 mv2 .

DEFINITION Energy possessed by a body by virtue of its motion is called the Kinetic Energy.

EXPLANATION It is the energy possessed by a moving body. A moving body is capable of doing work. The

work which a moving body can do is equal to its Kinetic Energy..

This energy has many practical application.

1) Generation of electricity from moving water is used to drive turbines.

2) Wind mills.

MAGNITUDE OF KINETIC ENERGYSuppose a body of mass “m” placed on a horizontal friction less table. Suppose force “F” is

applied on the body which accelerates the body in the direction of force, then according to

Newton’s Second law of motion, applied force

F = ma

Suppose the body starts its motion from rest and after covering “S” its final velocity

becomes “V”.

Using the equation of motion 2aS = Vf2 – Vi

2

Substituting the values, we get

2aS = V2 - 02

2aS = V2

S = V2 / 2a

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Work Done by the force

W= F x S

Or W= (ma) (V2 / 2a)

W= mv2 / 2

This work is appeared in the form of Kinetic Energy

Therefore K.E. =1/2 mv2

FACTORS ON WHICH K.E. DEPENDSKinetic Energy depends upon two factors.

1) MASS OF THE BODY

2) VELOCITY OF THE BODY

Kinetic Energy is directly proportional to mass of the body.

Kinetic Energy is directly proportional to square of the velocity.

Q: State the law of conservation of energy and explain this law for a freely

falling body.

LAW OF CONSERVATION OF ENERGY“Energy can neither be created nor it can be destroyed but it can changed from one form of energy to

another form of energy”.

EXPLANATIONConsider a body of mass ‘m’ lying at a height ‘h’ from the ground. When we release this body it will move

towards the ground and its potential energy decreases but Kinetic energy increases at the same time.

During this motion from A to C its potential energy changes into K.E. we will calculate P.E and K.E

at different points and total energy.

AT POINT A:K.E = 0 (body is at rest therefore, its velocity = 0)

P.E = mgh

Total Energy = P.E. + K.E.

= mgh + 0 = mgh

Total energy = P.E + K.E.

= mgh + 0 = mgh

AT POINT C:Distance covered by the body from A to C = x

Height from the ground = h-x

P.E at C = mg (h-x)

Initial velocity at A = vi =0

Final velocity at C = vf = v

By using the equation of motion.

2gh = Vf2 -Vi

2

2gx = V2 -(0)2

2gx = V2

K.E at C = ½ m V2

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= mgx

Hence total energy at C = E = P.E + K.E

E = mg (h-x) + mgx

E = mgh - mgx + mgx

E = mgh.

AT POINT B:P.E = 0 (h =0)

K.E = mgh

E = mgh + 0

E = mgh

During the motion from A to B potential energy is converted into Kinetic energy and Kinetic

energy is converted into potential energy, but total energy remains the same.

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Chapter-9

MACHINEQ1. Define the following.

Effort

Load

Mechanical advantage

Out put

Input

Efficiency.

EFFORT ‘P’It is a force directly applied to a machine for ding work. It is denoted by ‘P’.

LOAD ‘W’ The weight lifted or resistance overcome by a machine is known as weight and it is denoted by

‘W’.

MECHANICAL ADVANTAGEIf a weight ‘W’ is raised by a machine when an effort ‘P’ is applied, the ratio of load and effort is

called mechanical advantage of the machine, Hence

Mechanical Advantage = Weight or resistance overcome by a machine

Force applied on machine

M.A. = W P

INPUT If an effort ‘P’ acts through a distance ‘d’ then work done on machine is called Input, Thus

Input = effort x distance through which the effort acts.

Input = Pd

OUT PUTIf a machine moves a load ‘W’ through a distance ‘h’ then useful work done by machine is called out

put, thus

Out put = Load x distance through which the load moves

Out put = Wh

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The ratio between useful work done by the machine to the work done on the machine is called the

efficiency of the machine.

It is denoted by a Greek letter ‘’ (eta).

Efficiency = = useful work done by the machine

useful work done on the machine

Efficiency always expressed in percentage.

= Output x 100

Input

or = W x h x100

p x d

Q2.

Define lever.

On what principle it works.

Calculate its mechanical advantage.

Write down the types with some example.

a) DEFINITION :Lever is a straight rigid ban which can rotate about a fixed point. This point is called

Fulcrum.

b) ON WHAT PRINCIPE LEVER WORKSLever works on principle of moment i.e.

Moment of effort = moment of weight

OR effort x effort arm = weight x weight arm

c) MECHANICAL ADVANTAGEAs a lever works on principle of moment, therefore we can calculate the mechanical

advantage with the help of this principle i.e.

effort x effort arm = Weight x Weight

OR P X OA = W X OB

OR OA / OB = W / P

OR M.A. = W/P = OA / OB

M.A. = Effort Arm / Word Arm

Mechanical advantage of lever can be increased by increasing effort arm or by decreasing load arm,

to a minimum possible limit.

d) TYPES OF LEVER Lever is divided into three classes depending on different positions of fulcr relative to the point of

application of the force and resistance or weight.

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1. Lever Of The First Kind

In the lever of the first kind, fulcrum ‘F’ is in between effort ‘P’ and weight ‘W’.

Examples: Common balance, pair of scissors, Sea-Saw are the examples of the first kind of

lever.

2. Lever Of The Second Kind

In the lever of the second kind, weight ‘W” is in between Fulcrum ‘F’ and effort ‘P’.

Examples: Wheel barrow, nut crackers are the examples of second kind.

3. Lever Of Third Kind

In the third kind of lever, effort ‘P’ is in between weight ‘W’ and fulcrum ‘F’

Examples: Human arm and fire tongue are its examples.

Q: Write note on the following.

Pulley

Inclined plane

Wedge

Screw Jack

Wheel and axle.

PULLEYConstruction :

It consist of a grooved wheel which can carry a string, rope or chain passing round it.

The wheel mounted on an axle which is fixed to a frame work called Block.

The pulley used in two ways.

Fixed pulley

Moveable pulley

Fixed Pulley

If the block of the pulley is fixed it is called fixed pulley.

Working:

Load is attached at one end and effort is applied on the other end in downward direction to lift the

load.

Mechanical Advantage:If we ignore the weight of the rope and force of friction between the rope and wheel then from

principle of lever.

Effort x Effort arm = Weight x Weight arm

P x OA = W x OB

OA / OB = W / P

MA =W / P = OA / OB = r / r (where ‘r’ is the radius of wheel)

M.A. = 1

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Such pulleys used to change the direction of force. The advantage of fixed pulley is the force can

be applied in downward direction, which is more convenient.

Moveable pulleyArrangement And Working:

In this pulley, one end of the rope which is passing round the pulley is tied to a firm support ‘O’

and effort ‘P’ is applied at its other end. The load ‘W’ to be lifted, is hung from the hook of the block.

Mechanical Advantage:In each segment of the rope tension is equal to applied effort. As the weight is supported by the

two segments of the rope, the upward effort acting on weight ‘W’ is ‘2P’.

For equilibrium condition position.

W = 2P OR W/P = 2 OR MA = 2

INCLINED PLANE

Definition Inclined plane is a plane surface making a certain angle with the horizontal.

Use: It is used up to help us in raising heavy loads.

Mechanical Advantage:

Suppose AB is an inclined plane having length ‘l’’ height ‘h’ and the angle of inclination is

.

Suppose weight ‘W’ is being pulled up by a force ‘P’ parallel to plane surface. As

the weight ‘W’ is acting vertically downward, therefore it is resolved into its components.

W Cos which is balanced by normal reaction R.

W Sin which tend to pull the body parallel to plane surface. The force ‘P’ acting against

this force. If force of friction is neglected then for an equilibrium.

W Sin = P

OR W / P = 1/Sin ---- (1)

IN ABC,

Sin = h / l

Substituting this value in (1)

W / P = 1

h / l

OR M.A. = l / h

OR M.A. = length of inclined plane

height of inclined plane

M.A. of inclined plane can be increased by increasing length or by decreasing

height of inclined plane.

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WEDGE:DefinitionWedge is a simple machine made up of two inclined planes.Use.

Used as fulcrum in levers.

Used to split wood into small pieces.

Mechanical Advantage

Suppose a wedge is penetrated into a wooden log by a force ‘P’ . R1, R2 are two

reacting forces acting normally on the inclined planes.,

Consider the equilibrium position of Wedge and neglecting the frictional force.

R1, R2 and ‘P’ forms a triangle XYZ. Such that XY, YZ and XZ show P,

R1 and R2 respectively. As ABC and XYZ are two similar triangles therefore

ZX / XY = AC/BC (Ratio of the sides of similar triangles are equal)

OR R/P =AC/BC (ZX =R, XY =P) (R1 =R2 =R)

We know that

M.A. = Weight or resistance /Effort.

Is M.A. = R/P = length of inclined plane / Thickness of Wedge

CONCLUSIONM.A. of a wedge can be increased by increasing length of inclined plane and by

decreasing thickness of wedge.

SCREW

DefinitionScrew is a simple machine consists of a threaded rod with a circular head, called screw head.

UseIt is used to hold different parts of machines together.

Construction

It consist of two main parts.

A cylinder on which continuous threads are wrapped/

A circular grooved head on the top of a screw.

The distance b/w two consecutive threads is called pitch, and it is denote by “h”.

WorkingWhen an effort “P” is applied on the head of the screw, It completes one revolution and

moves through a distance equal to pitch of the screw.

Mechanical Advantage

When the screw completes one revolution, the effort “P” is applied for one

complete revolution and covered a distance equal to circumference of the circular head i.e. 2r

Where ‘r’ is radius of circular head; so the Input = P x 2r .

Where the screw moves for wand, It may be used to raise weights or over come

resistance applied to its ends a distance equal to pitch of the screw.

Therefore out put = W x h

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For an ideal condition,

Out put = Input

W x h = Px2r

W/P = 2r/h

Or MA = 2r/h

Hence MA can be increased by increasing radius of circular head or by decreasing

pitch of the screw.

Screw JackA Screw Jack is a simple machine usually used to lift car or other heavy automobile

when need arise.

ConstructionIt consist of a long Screw rod passing through a threaded block ‘B’ and a handle it

to turn the threaded block ‘B’.

WorkingWhen the effort is applied to the handle ‘H’ and the handle covers a distance equal to

circumference of the circle of radius ‘r’ where ‘r’ is equal to length of the handle. Due to this

effort the block moves equal to pitch of the screw and raised a load ‘W’.

Mechanical Advantage

For an ideal Screw Jack

Input = out put

P x 2r = W h

Or W/P = 2r / h

For a large mechanical advantage pitch of the screw should be small as compared to length

of the rod.

Wheel and AxleIt is a very simple machine used for lifting heavy loads, such as pulling bucket of water

from well.

ConstructionIt consist of two wheels, one is large having radius ‘R’ and the other wheel is small

having radius ‘r’. Both the wheels are fixed on the same shaft and are called wheel and axle.

WorkingThe effort is applied on the rim of the wheel and load is raised by a string wound round the

axle.

If effort ‘P’ is applied for one complete rotation of larger wheel having radius equal to ‘R’

then Input = P x 2R

Load is raised through a distance equal to circumference of axle, then Output = W x 2r

For an ideal condition

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Input = Out put

P x 2R = W x 2 r

Or W/P = 2R / 2r

Or W/P = R/r

M.A = R/r

M.A of wheel and axle is increased by increasing R or by decreasing r.

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Chapter-16

REFRACTION OF LIGHTQ1. Define refraction of light and state the laws of refraction?

REFRACTION:Refraction is the bending of light which occurs when it passes from one transparent medium

(material) to another.

i = angle of incidence. (angle b/w incident ray and normal)

r = angle of refraction (angle b/w refracted ray and normal)

e = angle of emergence (angle b/w emergent ray and normal)

LAWS OF REFRACTION:

First Law :

The incident ray, refracted ray and the normal at the point of incidence all lie in the same plane.

Angle of Deviation :

The angle with which incident ray deviates from its original path is called Angle of Deviation.Angle of Minimum Deviation :

The last value of angle of deviation after which it increases with the increase of angle of incidence is called Angle of Minimum Deviation.Second Law :

For light rays passing from one transparent medium to another, the sine of angle of incidence and

the sine of angle of refraction are in constant ratio. This constant is known as ‘Refractive Index’

and denoted by a Greek Symbol ‘’.

Mathematically = Sin i / Sin r

i = 20o Sin < i = 0.34 ‘n’ = Sin i / Sin r = 1.5

r = 13o Sin < r = 0.22

i = 30o Sin < i = 0.50 ‘n’ = Sin i / Sin r = 1.5

r = 19o Sin < r = 0.33

i = 40o Sin < i = 0.64 ‘n’ = Sin i / Sin r = 1.5

r = 25o Sin < r = 0.42

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Q2. Define refractive Index ? Describe different methods by which you can

calculate the refractive index of a medium ?

REFRACTIVE INDEX:It is the bending ability of a light ray in the second medium with respect to first, and it is different

in different medium. It is denoted by Greek symbol ‘n’.

Refractive index can be calculated by following different methods.

Refractive index is the ratio between sine of angle of incidence to sine of angle of refraction

Mathematically ‘n’ Sin i / Sin r

Refractive index can be calculate by dividing the speed of light in air to speed of light in second

medium

If V1 = Speed of light in air.

V2 = Speed of light in second medium (sup glass)

Then Refractive Index = ‘n’ = Sin i / Sin r

The refractive index of glass by prism can be calculated by the formula.

n = Sin (A+Dm) / 2

Sin A / 2

Where ‘A ‘ is the angle of prism.

‘Dm’ is the angle of minimum deviation.

The refractive index of a medium can be calculated by the formula n = 1/Sin C

Where ’C’ is the critical angle of that medium.

Q3) Define critical angle.

Define total internal reflection.

Explain the phenomena of total internal reflection?

Find a relation between the critical angle and the refractive index of the medium?

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CRITICAL ANGLE:

We know that when a ray of light passes from a denser medium to a rarer medium , the

refracted ray bends away from the normal. If now the angle of incidence “i” is slowly increased

the angle of refraction becomes 90o, then the refracted ray grazes along the boundary of the

media. This particular angle of incidence for which the angle of refraction become 90o is called

critical angle.

TOTAL INTERNAL REFLECTION:

When light passes from a denser medium to rarer medium it bends away from the normal

and having a small angle of incidence “i” and a weak internally reflected ray is produced as well

as a refracted ray . The angle of refraction is greater than the angle of incidence “i”. It follows that

if the angle of incidence is increased it will reach the critical value where the angle of refraction is

equal to 90o.

If the angle of incidence is further increased, become grater than the critical angle (i > c) it is

impossible for the angle of refraction to exceed 90o. Now no light emerges and the light is totally

internally reflected, The inside surface of denser medium behaves like a perfect mirror. This

phenomena is known as Total Internal Reflection.

Conditions For Total Internal Reflection:There are two conditions for total internal reflection.

The ray of light should incident from a denser medium to a rarer medium.

The angle of incidence should be greater than the critical angle.

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Q5. Write note on the following: Total reflecting prism.

Periscope.

TOTALLY REFLECTING PRISM:

A prism with one 90o corner and two 45o corners can be used to turn a ray of light through

90o. In fig. ray PQ is totally internally reflected, because the angle of incidence “i” = 45o is greater

than the critical angle for glass to air, angle C=42. The ray is deviated by 90o.

Use:

Totally reflecting prism is used in some periscope in preference to a plane mirror because there is

no exposed silvered surface to become damaged and no multiple reflections.

PERISCOPE:Introduction:

It is an optical instrument which is used to see the objects on the surface of the sea by an observer

in a submarine under water.

Construction:

It consist of two right angled triangle prism and three convex lenses. The first is fixed at the top

and the second prism P2 is fixed at the bottom of a vertical tube which bent at right angle at the

lower end. There is also a lens system in the tube.

Working:

The rays from the distant objects are reflected at right angles by the upper prism into the vertical

tube. The rays pass through a system of lenses and fall on the second prism P2. This prism bends

rays again and the rays then fall on an eye piece that forms a final enlarged image which can be

viewed by the observer.

Q6. Explain in detail the refraction of light through prism ?

INTRODUCTION:Prism is a transparent refracting medium bounded by two triangular and three rectangular

surfaces. Triangular section of the prism is called

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“Principle Section”. The angles of the triangle is called “Angle Of the Prism”.

Let PQ is the ray incident on the face “AB” of the prism at “Q”, refraction at Q takes place from

air to glass , the refracted ray QR bends towards the normal, when QR

reaches “R” refraction takes place again from glass to air, So the refracted ray bends away from

the normal “OM” at “R”. This ray is called a emergent ray.

Here refraction takes place two times, firstly when light ray enter into the prism, secondly when

light travel from glass to air.

Q8. Describe the changes in the position, nature and size of the image formed by convex lens

when the object is brought from infinity to optical centre of the lens. Draw the ray

diagram?

Case I : When An Object Placed At Infinity:

When an object is at infinity, the image is formed at principal focus. It is real, inverted and

extremely diminished.

Case II : When An Object Placed Beyond “2F” :

When an object is beyond “2F”, the image is formed between principal focus and “2F”. It is real,

inverted and smaller in size.

Case III : When An Object Placed At “2F” :

When an object placed at “2F” the image is formed at “2F”. This image will be real, inverted and

same in size.

Case IV : When An Object Placed b/w “F” and “2F” :

When an object placed b/w “F” and “2F”. This image will be real, inverted and magnified.

Case V: When An Object Placed At “F” :When an object is placed at “F” it’s image will be formed at infinity. This image will be real,

inverted and highly magnified.

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Case VI : When An Object With In The Focal Length:

When an object is placed within the focal length, it’s image is formed on the same side of the

object. This image is erect, virtual and magnified.

Q9: Draw a labelled diagram showing the structure of eye. Explain the functions of different

parts of the eye?

SCLEROTIC:It is the opaque coating of the eye.

CORNEA: The front portion of the sclerotic is slightly more convex than the rest of the eye ball, and is called

the Cornea.

CHOROID:

Inside the sclerotic is a blank opaque membrane called Choroid.

IRIS:

The front portion is a coloured diaphragm, called the iris.

PUPIL OF THE EYE: The iris contains a central aperture called the Pupil Of The Eye.

RETINA:The third coating inside the eye is called Retina.

OPTIC NERVES:This nerve carries the impression to the brain where it is translated into the mysterious

phenomena called “sight”.

LENS OF THE EYE:It is a convex lens, made of hard transparent gelatinous water.

AQUEOUS HUMOR:It is transparent matter filled b/w cornea and lens.

VITROUS HUMOR:It is highly transparent matter filled b/w lens and rating.

CILLARY MUSCLES:These muscles perform an important role. These muscles control the lens in

adjustment for seeing far off or a near by objects.

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Functions Of Parts Of Eye:SCLEROTIC:

It is hard coating to protect the eye

CHOROID:

It is a layer of tissue which supplies blood to the eye and also contains black colouring which

reduces reflection of light with in the eye.

RETINA:

It contains light sensitive cello and nerves fibres. Light falling on the retina produces chemical

changes in the cells which then send electrical impulses along the nerve fibres via optic nerve to

the brain.

LENS:

The lens forms a real, inverted and diminished image on the retina.

CILIARY MUSCLES:

It controls the shape of the lens. These muscles contract or relax so the thickness of the lens

changes

IRIS:

The iris is a coloured ring, which has a circular hole in it’s centre called the pupil, By adjusting

the size of the pupil, the iris can control the amount of light reaching the retina.

AQUEOUS AND VITREOUS HUMOR:

The eye is roughly spherical and keeps it’s shape due to liquid inside it called Aqueous And

Vitreous Humour.

Q10. What are the main defects of the eye? How are they removed? Following are the main

defects of the eye Short-Sightedness or Mypia

Long Sightedness or Hypermetropia

Astigmatism

Presbypia

Short-Sightedness Or Myopia:If a person cannot see distant objects but can see near objects, he is suffering from disease called

short sightedness.

Cause :In this case the eye ball of the person is too converging or the eye ball is too long as a result

of the image of distant objects is formed in front of the rating.

Removal:

This defect of the eye is corrected by using a concave lens of suitable focal.

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Long Sightedness:If a person cannot see near objects, but can see clearly the distant objects, he is said to be suffering

from long sightedness.

Cause:

In this case the eye ball of the person in less converging or the eye-ball is too short. For such a

person the rays from near objects are focussed beyond the retina.

Removal:

In order to bring the image at the retina a convex lens of suitable focal length is used which is in

front of the eye.

Q11. Write a note on Compound Microscope ?

COMPOUND MICROSCOPE:It is an optical instrument by which a small object can be seen very much large.

Construction:

It consists of two convex lenses of short focal length at one end of two tubes, one of these tubes can

be moved into the other, so that the distance between the lenses can be changed. The lens near the

object is called objective and the other near the eye is called Eye-Piece.

Objective:

This lens faces the object; it has short focal length or high power or small aperture.

Eye Piece:This lens faces the eye-piece. It has large focal length as compared to objective. It has large

aperture.

Working:The small object AB is viewed is placed in front of the objective at a distance slightly greater than

the focal length of the objective “O”, So that a real, inverted and enlarged image A’ B’ is formed.

The eye-piece is moved forward or backwards. So that A’ B’ falls within the focal length and final 41

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image A” B” is formed by the lens (eye- piece) at a distance of least district vision. A” B” is

inverted, virtual and magnified image of AB.

Q12. What do you know about magnifying glass Describe the function of magnifying glass?

MAGNIFYING GLASS OR SIMPLE MICROSCOPE:

When a convex lens is placed near a small object such that the distance between the lens and the

object is less than its focal length, a magnified erect and virtual image of the object is seen through

the convex, which is said to act as a simple microscope or magnifying glass.

Consider an object AB placed in front of a convex lens within the focal length. A ray which is

parallel to principal axis after passing through the lens, passes through the convex, another ray of

light which passes through optical centre undeviated. When these rays are produced backward

meet and formed an image A”B” where the object is placed.

This image on the same side of the lens, large in size, virtual and erect.

Q13. Write down the construction and working of an Astronomical Refracting Telescope?

Construction :

An Astronomical Telescope is comprised of two convex lenses. The lens facing the object is called

objective. It has a large focal length and wide aperture. The lens which is placed close to the eye is

called eye-piece. It has a short focal length.

Working :As these heavenly bodies are at a very large distance from the earth, so the rays coming from then

will be parallel so they are focused by the objective at its principal focus and image of the star is

formed. The image is real, inverted and small in size. The eye-piece is adjusted in such a way so

that the image formed by the objective is focussed within the focal length of eye-piece. The image

formed by eye-piece is virtual image which is highly magnified. This final image is inverted with

respect to real object but for astronomical objects it does not make any difference.

Used:It is used by Astronomer for seeing heavenly bodies

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Q14. Write down the construction and working of a photo graphic camera.

PHOTO GRAPHIC CAMERA:A photographic camera is comprised of a light proof box which has been blackend from the inside

so that stray light may be absorbed. In an ordinary camera a convex law is fitted on the front side

but in costly cameras a combination of lenses is used. The function of lens or combination of lenses

is to produce a real and inverted image of the object at the other end on light sensitive film or

plate. If we want to get a sharp image then the lens should be moved in or out with the help of

mechanical device. There is an arrangement of a diaphragm and shutter for controlling the light

which is allowed to enter the camera. A shutter of variable speed and a diaphragm of changing

aperture control the lens and amount of light entering into the camera when the camera is not in

use, the shutter remains closed. The shutter s allowed opening for a fraction of second when we

press the button for taking the photograph.

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Chapter-13

REFLECTION OF LIGHTREFLECTION:When a ray of light travelling in one medium meets the surface of another medium obliquely

some or all the light may be turned back into the first medium.

This is called “Reflection of Light”.

LAW OF REFLECTION:

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The two laws of reflection are.

The incident ray, the reflected ray and the normal at the point of incidence all lie in one plane.

The angle of incidence is equal to angle of reflection.

Q2. Differentiate between regular and irregular reflection?

Regular Reflection Irregular Reflection

Reflection of light from a smooth

surface is called regular reflection.

Reflection of light from a rough

surface is called irregular reflection.

All parallel rays of light reflected in

the same direction.

All parallel rays of light are

randomly reflected in different

directions.

Due to the regular reflection images

are formed.

Due to the irregular we can see non-

luminous object.

Reflecting surface is not visible. Reflecting surface is visible.

Q3. What are the importance of irregular reflection?Irregular reflection plays an important role in nature.

It is due to the irregular reflection that we are able to see the non-luminous objects.

It is due to this fact that sunlight reach us before sun rise and persists for some time even after

the sun set.

Q4. Describe the characteristics of an image formed by a plane mirror?

CHARACTERISTICS OF AN IMAGE FORMED BY A PLANE MIRROR:

Image formed by a plane mirror is erect and virtual.44

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Size of image formed by a plane mirror is equal to the size of the object.

Image formed by a plane mirror is laterally.

Image formed by a plane mirror is as far behind the mirror as the object in front of it.

Q5. Define the following? Spherical mirror, concave mirror, convex mirror, pole, radius of curvature, principal focus,

focal length & aperture

SPHERICAL MIRROR:

A spherical mirror is a portion of the surface of a polished hollow sphere.

CONCAVE MIRROR:

If the spherical mirror is polished from outside then this mirror is called concave mirror.

The centre of curvature lies in front of reflecting surface.

It converges the rays of light, therefore formed a real image.

CONVEX MIRROR:

If the spherical mirror is polished from inside then this mirror is called Convex Mirror.

Centre of curvature lie behind the reflecting surface.

It diverges the rays of light, therefore it is called diverging mirror.

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POLE:

The centre of the reflecting surface of the mirror is called “Pole” of the mirror.

CENTRE OF CURVATURE:

It is the centre of sphere of which the mirror is a part is called “Centre of Curvature”.

RADIUS OF CURVATURE:

Radius of that sphere of which the mirror is a part is called “Radius Of Curvature” .

PRINCIPAL FOCUS OR FOCUS:

It is the point where parallel beam of light after reflection from the mirror either actually

converges to that point or appears to diverge from that point. It is denoted by “F”.

Focus of concave mirror is called Real Focus.

Focus of convex mirror is called Virtual Focus.

FOCAL LENGTH:

The distance b/w the pole and focus is called “Focal Length” of the mirror. It is positive in concave

mirror and negative in convex mirror.

APERTURE:The diameter of the circular boundary of the spherical mirror is called aperture.

Q6. Differentiate b/w Real and Virtual image?

Real Image Virtual Image

An image is said to be real, if the rays

of light actually pass through it.

Virtual image is only visible to the

eye and a reflected ray of light

appears to come from that from that

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point.

It can be received on the screen. It cannot be received on the screen.

Real images are inverted. Virtual images are erect.

Distance of real image is taken

positive.

Distances of virtual images are taken

negative.

Q7. Explain with the help of a ray diagram, the nature, the size and the position of an image

formed by a concave mirror when an object moved from infinity to pole of the mirror?

Case I: When An Object Is Placed At Infinity:

Position of Image = the image is formed at focal point

Size of Image = extremely diminished

Nature of Image = Real and inverted

Case II : When An Object Is Placed Beyond “C”:

Position of Image = Image is formed b/w focal point and centre of curvature.

Size of Image = Small in size

Nature of Image = Real and inverted

Case III : When An Object Is Placed At “C”:

Position of Image = Image is formed at “C”

Size of Image = same in size

Nature of Image = Real and inverted

Case IV : When an Object is Placed between “F” & “C”:

Position of Image = Image is formed beyond “C”

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Size of Image = Image is magnified

Nature of Image = Real and inverted

Case V : When An Object is Placed at “F”:

Position of Image = Image is formed at infinity

Size of Image = Image is highly magnified

Nature of Image = Real and inverted

Case VI : When An Object Placed b/w “F” And Pole:

Position of Image = Image is formed behind the mirror

Size of Image = Magnified

Nature of Image = Virtual and Erect

Q8. Explain with the help of ray diagram, image formed by convex mirror?Position of Image = Image is formed behind the mirror

Size of the Image = Small in size

Nature of the Image = Virtual and erect

Q9. Derive the mirror equation 1 /f = 1/ p + 1/ q .

In order to derive a relation b/w focal length, object distance and image distance, consider an

object AB placed in front of a concave mirror b/w

Focus and centre of curvature. By considering two incident rays AO and AP reflected from the

mirror and formed an image A’B’.

In the above figure APB and A’PB’ are similar triangles, therefore

A’B’ = B’P

AB = BP

A’B’ = hi (Height Of The Image)

AB = ho (Height Of The Object)

hi = q ( B’P = q )

ho = p 1 ( BP = p )

As PFD and A’FB’ are also similar triangles is

A’B’ = B’F48

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PD PF

A’B’ = B’P - PF

PD PF

As PD = AB (Opposite sides of the rectangle)

hi = q-f

ho f

Comparing eq. 1 and 2 we get

q = q – f

p f

qf = p ( q – f )

qf = pq – pf

Dividing whole eq. By pqf

qf = pq - pf

pqf pqf

qf = pq - pf

pqf pqf pqf

1 = 1 - 1

p f q

1 + 1 = 1

p q f

1 = 1 + 1

f p q

Q10. Give some uses of spherical mirrors?There are several particles uses of spherical mirror some of which are mentioned below.

SHAVING MIRRORS:A concave mirror produces erect and magnified image when an object placed within the focal

length, therefore it is used as shaving mirror.

USE IN MEDICAL EXAMINATION OPHTHALOMOSCOPE:Doctors use concave mirrors for the examinations of ear, nose, throat and eyes of the patients in

ophthalmoscopes.

USE IN MICROSCOPE:Concave mirrors are used to throw light on the slides in a microscope so that the slides can be

viewed more clearly.

USE IN SEARCH LIGHTS AND HEAD LIGHTS:Concave mirrors are used to focus light in the case of search lights and head lights of automobiles.

USE IN TELESCOPE:

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The concave mirror are used as objective in big telescopes

USE FOR REAR VIEW:Due to the diverging property of a concave mirror is used in automobiles to have the rear view.

**********************************************

Chapter-12

“WAVES AND SOUND”Q1. Define Vibratory. Simple Harmonic motion and positive that a body attached to an

elastic spacing execute. Simple Harmonic Motion?

Simple Harmonic Motion:The periodic motion, in which acceleration is directly proportional to displacement and the

direction of the acceleration is towards the mean position is called Simple Harmonic Motion.

Explanation:Let an object of a mass “m” is attached to a horizontal spring is placed on a friction less surface as

shown in figure.

Let a force is applied, due to which the body is displaced by a distance x.

According to Hook’s Law Applied force

F x

According Force or F = k x

Where ‘k’ is spring constant.

But due to elasticity the spring, the spring opposes the applied force and this opposing force is

called Elastic Restoring Force.

The elastic restoring force (F) is equal to applied force but opposite in direction, therefore

Elastic Restoring force = - (Applied Force)

F = - k x i

If “a” is the acceleration of body and “m” is the mass of the body then according to Newton’s

second law of motion

F = ma ii

Comparing (1) and (2) ma = -k x

Therefore a = - k x

m

Since k / m is constant

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Therefore a = - (constant) x

Or a -- x

This shows that acceleration “a” of the body is directly proportional to its displacement and is

directed to mean position.

Hence the motion of body under elastic restoring force is S.H.M

Q2. Prove that vibratory motion of Simple Pendulum is Simple Harmonic Motion?

Simple Pendulum:An ideal Simple pendulum consists of a point mass suspended by a weight less and in extensible

string from a fixed point.

Pendulum As A Simple Harmonic Oscillator:When we displace a pendulums bob from its mean position “O” to a new position “A” and then

released it will move towards “O” and due to inertia it will not stop at “O” and moves towards a

new position “B”.

The whole process is repeated again and again. “A” and “B” are the extreme positions of bob and

potential energy is maximum it that points. This potential energy is converted into K.E. when bob

moves from “A” to “O” or “B” to “O” and therefore, K.E. is maximum at “O”.

At “A” or “B” K.E. of bob is zero and it is maximum at “O”, therefore the bob accelerates when

moves towards “O”.

If we increase the displacement of bob the acceleration of bob will also increase.

From the above discussion it is proved that acceleration is directly proportional to displacement

and the direction of acceleration is towards the mean point.

Conclusion:Vibratory motion of Simple pendulum is Simple harmonic motion.

Q3. Define resonance; give at least two examples from you daily life?

Resonance:When the frequency of driven force is exactly equal to the natural frequency of the oscillator, the

driven force imparts the maximum energy to the oscillator, resulting a considerable increase in

amplitude of vibration. This is called Resonance.

Examples Of Resonance:An interesting example of resonance is that of swing while enjoying a swing we apply force by the

special movement of our body at a particular position in every vibration. The result is increase in

the amplitude of swing.

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When an opera-singer sings at a very high pitch, glass are caused to break. This is because

frequency of the note is same as the frequency of glass, resulting an increase in amplitude of

particles of glass and the glass will break.

Q4. a)Define Wave Motion?

b) Define Transverse and Longitudinal Waves and Explain with the help of an example?

Wave Motion:The mechanism by which energy is transferred from one place to another is called “wave motion”.

Transverse Waves:Transverse waves are those waves in which the disturbance travels in a direction perpendicular to

the direction of oscillation of particles.

Examples:We can produce transverse waves in a rope by fastening the rope at one end, and holding the other

end.

If we give a sudden up and down jerk in a direction perpendicular to its length. A wave pulse travels

from the jerk end to the fixed end of string. This wave produces elevation and depressions called

crest and trough respectively.

The distance between two consecutive crest or trough is known as wave length and it is denoted by

Greek Symbol “” (Lambda).

Longitudinal Waves:Those waves in which particles of elastic medium are vibrating in the same direction in which wave

is travelling called Longitudinal Waves.

Examples:Consider a horizontal wave on a spring produced by waving the spring back and for with one’s

hand. This is longitudinal wave in which particles of the medium vibrate back and forth along the

direction of wave. The portions where the particles come closer are called compression and when

these particles come back to its original shape is rarefaction. The distance between two consecutive

compressions is called Wave Length.

Q5. Differentiate between Transverse and Longitudinal Waves.

Transverse Waves Longitudinal Waves

In transverse waves the particles of the medium

liberate in a direction perpendicular to the

direction of motion of waves.

In longitudinal waves the particles of the

medium vibrate in the direction of motion of

waves.

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Trough and Crest are produce in transverse

waves.

Compression and rarefaction are produced in

longitudinal waves.

In transverse waves the distance between two

identical positions of two consecutive troughs or

crests is known as Wave Length.

In Longitudinal waves, the distance between two

identical positions of two consecutive

compressions’ or rarefactions is known as Wave

Length.

It can be produced in solid, liquid and also in

space.

It can be produced in solid liquid and gas only

but not in vacuum.

Microwaves, Radio Waves, Waves on the surface

of water are examples of transverse waves.

Sound wave and compress ional waves in a

spring are examples of longitudinal waves.

Q6. Define the terms Wave Length, Frequency and Time Period and prove that V=f .

Wave Length:It is the distance between two consecutive crest and trough. It is denoted by a Greek symbol “”

(Lambda).

It is also defined as the distance between two particles which are in phase (having same frequency

and same direction of motion).

Frequency:It is number of vibrations executed by an oscillating body in one second is called frequency. Its S.I.

unit is vibration/s, cycles/s or hertz. Frequency and time period are reciprocal of each other i.e.

f = 1/T

Time Period:It is the time required to complete one vibration or one oscillation. It is denoted by “T”.

Time period and frequency are reciprocal of each other i.e. T = 1/f

Proof V= f : The velocity of wave (whether of transverse or of longitudinal) is defined as the distance through

which any part of the wave disturbance moves in unit time.

Consider a wave of wave length “” passing through a point in time “t” then

S =

Time = T

If “V” is representing speed of wave then: V = S /t Or V = / T

Or V = 1/ T.

As we know that reciprocal of time is frequency; therefore, V = f

The above relation is called wave equation. It is true for any types of wave. Such as water waves,

Sound waves and radio waves etc.

Q7. Define Interference, Constructive destructive interference of waves and stationary

waves?Interference:

It is the interaction of two waves passing through the same region of space at the time.

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Constructive Interference:

If two waves interfere in such a way that crest of one wave falls on crest 0of second wave or trough

of one wave falls on trough of second wave then their combined effect is greater than either of two,

waves this is called constructive interference.

Destructive Interference:

If two waves interfere in such a way that crest of one wave falls on trough of second wave then

they cancel the effect of each other and there is no wave will be observed on the surface of water.

This is called destructive interference.

Stationary Waves:

When two waves of same frequency and wave length travelling in the same medium in opposite

direction meet with each other, form a new wave, in which particles of the medium do not transfer

the energy from one point to another, These special waves are called stationary waves or standing

waves. These wave form nodes and Antinodes.

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Chapter #

SOUNDSound:Psychologically, sound is the sensation produced in ear. Physically, it is said to the stimulus, due to

vibratory sources, and capable of producing the sensation of hearing in the auditory system.

Therefore, sound waves are the longitudinal waves that are capable of producing the sensation of

hearing.

Conditions Necessary To Hear Sound:Sound is a form of energy which travels in the form of longitudinal waves but all the longitudinal

waves are not sound waves. There are few conditions that must be fulfilled to detect sound.

a) Condition Necessary For Producing Sound:

Sound is produced only if a body is vibratory i.e. there is a vibratory source to produce sound

waves.

b) Condition Necessary For Propagation Of Sound Waves:

Sound waves required material median for the propagation.

C) Condition Necessary For Receiving Sound Waves:

Sound waves are received only if there is an auditory system i.e. a receiver like ear in human

beings.

d) Condition Necessary For Detection Of Sound:

Proper frequency range is required to detect sound waves. This frequency range is known as

Audible Frequency Range. It has different values for human beings and for other receivers

(organisms). The audible frequency range for human ear is 20 Hz to 20000 Hz.

Audible Sound:Those sound waves which can be detected are known as Audible sound. For an average human ear

an average human ear cannot detect the audible sound frequency ranges from 20 Hz to 20000 Hz

i.e. greater than 20000Hz.

Infra Sonic:Theses longitudinal waves having frequency less than 20 Hz are known as Infrasonic. These waves

cannot be detected by a human ear but can be caught by some other organisms.

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Ultrasonic:Sound waves having frequency more than 20000 Hz are known as Ultrasonic. An average human

ear cannot detect them because eardrum cannot vibrate with such a high frequency. However,

many species like bat-bugs and dolphin can hear sound with frequency more than 20000 Hz. Bats

and Dolphins can hear sound with frequencies above 100000.

Q2. Describe an experiment to prove that sound waves are produced by a vibratory source?Sound is always produced by some vibrating body. As the source vibrates mechanically about a

fixed point, the medium in the vicinity is alternately compressed and rarefied. The vibratory

object may be the prongs of a tuning fork, skin of a drum, wire in a piano or violin, a reed in

harmonium, a gong of an electric bell, air column in the vocal cord of human being etc.

Experimental Verification:Consider electric bell connected to an electric surface where the switch is turned on, the hammer

connected in the bell strikes to the gong (metallic disc) and sound is heard. The vibrations of

ringing bell can be demonstrated by bringing a pitch-ball suspended by fine thread close to it. The

pith-ball is thrown off as soon as it touches the bell.

Result:The above experiment proves that the ringing bell is vibrating about its mean position producing

alternative compressions & rarefaction in the medium.

Q3. What is meant by propagation of sound waves? Prove by an experiment.Whenever a body is vibrating, it produces a disturbance in the surrounding air. This disturbance

reaches our ear in the form of waves thus producing the sensation of sound. If there is no medium

around the vibrating body, the sound waves will not reach our ear and we will hear any sound.

Let us perform an experiment.

Experiment:Suspended an electric bell in a jar by its wire through a cork fixed in its mouth as shown in Fig.

Switch on the bell. We will hear the sound of the bell. Now start-removing air from the jar with

the help of the bell will start decreasing ultimately, bell. This experiment shows that air is

necessary for the propagation of sound in fact a material medium such as air, water metals etc., is

needed for the sound to travel from one place to another. Thus three things are necessary for the

sound (i) vibrating body (ii) some material medium like air, water etc. and (iii) receiver like ear.

Q4. Why does the flash of lighting seen earlier than the sound of thunder?It is a matter of common experience that the flash of lighting is seen earlier than hearing the

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reason is that light travels much faster than sound. Due to its slow velocity sound lags behind and

so it is heard a little after seeing the flash.

Q5. How you calculate the velocity of sound?Select two stations at a distance of 8 Km. to 10 Km. such that there is no obstacle between them

which can hinder the view. Fire a gun at station A and ask your friend at station B to start a

stopwatch on seeing the flash. The stopwatch should be stopped on hearing the sound of the gun.

The distance S between the two stations is already known. So the velocity V of the sound can be

calculated by the formula:

V = S / t

The mean of these time intervals is calculated to find the exact value of velocity of sound. The

distance between the two stations A and B S.

Average Time t = t1 + t2 2

Velocity Of Sound V = S / t

The velocity of sound in air at 0oC is 330 m/s. The velocity of sound in water is 1450 m/s and in

iron it is 5130 m/s. The velocity of sound is increased with the increase in temperature.

Q6. What is the difference between musical sound and noise?

Musical Sound Noise

Musical sound which has a pleasant

effect on our ears.

Which has unpleasant and jarring effect

on our ear?

In musical sounds there is a regularity in

the variation of frequency and amplitude

Noise has abrupt changes in amplitude

and frequency and there is no regularity

in the variation of frequency.

Sound of different musical instrument,

which are operating in a right manner,

of a song of Mehdi Hassan or Noor

Jehan are some examples of musical

sound.

Barking of dogs, ratting of machines,

sound produced by rickshaws are some

examples of noise.

Q7. Describe the characteristic of musical sound?Characteristics of musical sound are as follows:

Loudness of Intensity:1. The characteristics of a sound by which a loud and a faint sound can be disguised are

called loudness.

2. Loudness depends upon intensity and also upon the sensitiveness of the ear.

Loudness or Intensity depends upon the following factors:

The Amplitude Of Vibrating Body:If the amplitude of the vibrating body is large, the sound will be loud. On the other hand if the

amplitude is small then the sound will be faint. When we beat a drum forcefully the membrane

vibrates with large amplitude and a loud sound is heard.

Area Of Vibrating Body:

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A louder sound is produced if the surface area of a vibrating body is large. The loudness of a school bell is more than

that of a house bell.

Distance Of Sounding Body:If we are standing near a rail road track we will hear a faint sound of a train which is far away from us. As it

approaches us the sound becomes louder and louder. The sound will be loudest when the train passes by us. After

passing by us, as the train moves away from us the sound will start becoming feeble and feeble again.

Pitch:It is a sensation that depends upon the frequency. A shrill sound is produced by a source of high frequency whereas

the pitch is lower if the frequency is lower. Pitch does not depend upon loudness or quality. The voice produced by

ladies and children has high pitch because the frequency is high.

Quality Or Timber :It depends on the presence of overtones. The quality of sounds enables us to distinguish between two sounds having

the same loudness and pitch. Nature has provided different overtones in the voice of different persons. The humming

of a mosquito or a bee has low amplitude but high frequency.

Q8. Differentiate between Pitch and Quality?

Pitch Quality

The characteristics of sound by which a shrill

sound can be distinguish from a grave one is

known as the sound.

It is that characteristics of sound, which enables

us to distinguish between two sounds of same

loudness.

Pitch of the sound depends upon the frequency of

the sound.

It depends upon the wave form of the waves.

Q9. What is an echo? How is it produced?

Echo: “The sound is heard after reflection from a surface is called an echo”.

The repetition of sound produced due to reflection by a distant extended surface like a cliff, hill, well, building etc, is

called an echo. The effect of sound on the human ear remains for 1/10 th of second. Suppose, a person produces sound

and this sound is reflected from an obstacle at a distance ‘D’. The time taken by the sound to travel to the obstacle and

back is ‘t’. Velocity of sound is 330 m/s.

therefore, D = Vt 2D = 33

2D = 330 x 1 D = 33 = 16.5 ≈ 17m

10 2

It means that if the distance between the source of sound and the obstacle is less than 17 meters

(56ft.)

Q10. What is meant by Beats?

Beats:When two sound waves that differ from one another in frequency by a very small number. Then

sometimes we hear a loud sound where the compressions of the two waves meet and at other time

we hear a faint sound where the one wave falls upon the rarefaction of the other wave. This

phenomenon is called beats. The number of times we hear the rise and fall of sound per second is

called the beat frequency. The beat frequency is equal to the difference in the frequencies of the

two sounds.

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Chapter-15

NATURE OF LIGHT & ELECTROMAGNETISM

Q: Write a note on the following:

Newton’s Corpuscular theory of light

Wave theory of light

Quantum theory of light

Newton’s Corpuscular Theory:Sir Isaac Newton in 1675 presented a theory regarding nature of light. It is known as

Newton’s corpuscular theory of light.

According to this theory “A luminous body like the sun, electric bulb etc. continuously

emits minute invisible particles called corpuscles in all direction these corpuscles posses following

properties.

1. Travel in a straight line with a very high speed without being affected by the earth’s

gravitation.

2. Penetrate into the transparent medium.

3. Produce the sensation of vision when they strike retina.

4. Reflect back from a polished surface.

Achievements of Corpuscular Theory:With the help of this theory. Newton explains the following:

1. Propagation of light in a straight line.

2. Shadow formation.

3. Bending of light in a denser medium.

Draw Backs of Corpuscular Theory:1. Newton assumed that speed of light is more in denser medium than a rarer medium.

Foucault Proved that Newton assumption is wrong.

2. Newton assumed that higher the temperature of luminous body higher the speed of light.

This assumption is also proved wrong.

Huygens Wave Theory:Huygens presented another theory regarding nature of light. According to the theory:

Light is emitted theory from a source in the form of waves which

continuously propagated away from source.

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Achievement of This Theory: Reflection and refraction was successfully explained.

Present explained the rectilinear propagation of light.

Interference of light also proved by this theory.

Draw Backs of This Theory:It was known during those days that a medium is essential for the propagation of waves

therefore it was assumed that whole universe is filled with hypothetical medium called ether.

Morley and Michelson with the help of an experiment proved the Ether did not exist.

Maxwell’s Electromagnetic Theory:According to Maxwell light waves are electromagnetic i.e. they are rapidly moving electric

and magnetic fields which are perpendicular to one another. The propagation of electromagnetic

waves does not require any material medium. He proved that electromagnetic waves are of

transverse type.

Draw Backs of This Theory: The Maxwell’s theory could not explain the phenomenon of photo-electric effect.

Plank’s Quantum Theory:Quantum theory is simply a sort of revival of Newton’s corpuscular theory. According to

this theory light is a form of energy and travels in the form of energy packets called Photons.

Energy of each photon is given by E=h where h is the plank’s constant and is the frequency of

light. The energy of photon depends upon the frequency. Einstein gave a simple explanation of

photo-electric effect on this theory. Neil Bohr also used this theory to explain the spectrum of

Hydrogen atom. Quantum theory could not explain interference and polarization.

Dispersion Of Light:When white light is allowed to pass through a prism it is decomposed into several colors

which appear as a band on the screen. The splitting up of light into it’s constituent colors is called

dispersion of light. The band of colors seen on the screen is called spectrum.

Monochromatic And Ordinary Light:Sunlight or white light is called ordinary light while the light which contains only one

colour or of simple frequency is called monochromatic light.

Rainbow:After rainfall tiny water droplets remain suspended in the air and they behave like prism and

disperse the sunlight fallen on to it into seven different colors. If the sun is at the bank of the observer and

light rays fall obliquely on the droplet then rainbow is seen. It is an spiral arc of colors which appear when

sunlight is dispersed by droplets.

Under favorable conditions several bows may be seen. The brightest bow is called primary bow it

shows brilliant colors of the spectrum of the sunlight. It is red on the outer and violet on it’s inner edge.

Visible and Invisible Spectrum:

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When whit light is allowed to pass through a glass prisms it gets split it into its constitute

colors and a bend of colors is seen on the screen. This color bend is called visible spectrum. But

there are several other types of waves in the spectrum at both the ends of visible spectrum

corresponding the waves whose frequency greater than violet waves is called “Ultra Violet” and

the portion of invisible spectrum corresponding the waves whose frequency less than that of red

are called “infrared”.

Emission Spectra:When a substance strongly heated it starts emitting radiation. Spectrum thus form the

radiation is called emission spectrum.

It is found that the substance in automatic state emits radiation which produced sharp and

district lines in the spectrum. Such a spectrum is called line spectrum.

When a temperature of a solid goes on increasing the number of lines seen in the spectrum

also increases. The solid becomes white hot it emits nearly all the colors and so we get what is

continuous spectrum.

Luminous gases or vapors when heated produced a spectrum in which we see groups of

closely packed lines on bends such a spectrum is called bend spectrum.

Photon:According to Quantum Theory, light is emitted and absorbed in the form of energy

packets. These energy packets are known as Photons. Energy of photons is given as follows:

E = h

Where “E” is energy, “h” is Plank’s constant and “” is the frequency.

Q Explain Electromagnetic Spectrum?When we get electromagnetic spectrum then we get the following wave length spectrum of light.

Radio Wave:These waves consist of a large range of wavelength form a few millimeters to several

meters.

Microwaves:These waves of shorter wave lengths between 1mm and 300m. It is used in radar and

microwaves ovens.

Infrared Waves:These waves are radiated by hot bodies at different temperature. Its wavelength is 10

micrometer to 10-5m.

Visible Waves:Their wavelength ranges from 380 nm down to 60 nm. These are emitted by hotter stars

having a mean temperature greater than 25000 oc.

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Ultra Violet Waves:Their wavelength ranges from 380 nm down to 60 nm. These are emitted by hotter stars

having a mean temperature greater than 25000 oc.

Gamma Rays:Their wavelength is less than 10-11 m. They are emitted by the nucleus of certain

radioactive substance.

Green House and Its Effect:

Definition:

Due to small amount of water vapour and carbon dioxide in the atmosphere, it is trapping

heat energy and this effect is called Green House Effect.

Explanation:

The major part of energy, which receives earth from the sun, is absorbed by the

atmosphere. Due to these gases of atmosphere and surface of water is heated. When earth is

heated, it radiates energy in the form of infrared waves of larger wavelength.

Dust and gas:

Molecules scatter some light to space. The small amount of water vapors and carbon dioxide in the

atmosphere is transparent to visible light, but lower part of atmosphere. An analogous effect takes place

in green houses where the glass of green house allows light to pass through and heat the enclosed ground.

Since glass is relatively opaque to infrared radiation, the heat is trapped in the green house. Sometimes

green house effect is so great that we can feel it. For example, in winter it is much warm at night in the

presence of thick cloud layers. If such layers dissipate and clean air moves in the temperature of the

surrounding, it is sure to drop as the ground radiates its heat energy unhindered into space.

**********************************

HEAT

Heat Temperature

Heat is a form of energy which is

transferred from one point to another

due to difference of temperature.

It is the measures of average Kinetic

Energy of molecules.

It is measured in Joules. Unit of temperature is Kelvin or oC or oF.

It is measured by Calorimeter. It is measured by thermometer.

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It depends upon amount of substance. It does not depend upon amount of

substance.

Q2. Write down the construction and working of the following.

Ordinary Liquid In Glass Thermometer.

Clinical Thermometer.

Maxima And Minima Thermometer.

Thermos Flask.

Ordinary Liquid-Glass Thermometer:The most common type of thermometer is the liquid in glass thermometer as shown in

figure it consists of a glass stem with a capillary tube, having a small bulb at one end. The bulb

and part of the capillary tube are filled with a liquid, usually mercury or alcohol colored with a

red dye to make it visible. The upper end of the capillary tube is sealed so that liquid will neither

spill nor evaporates from the tube. On heating, the liquid expands and rises in the tube. In order

that the liquid may expand freely in the upper part of the tube, air is removed from it before

sealing the upper end. A temperature scale is marked on the glass stem to indicate temperatures

corresponding to various levels of the liquid in the tube. The liquid –in-glass thermometer

commonly used in a laboratory.

Clinical Thermometer:Purpose Of Clinical Thermometer:

A clinical thermometer is used to find the temperature of human body by placing the bulb

under the tongue or in the arm pit. The normal body temperature is about 37oC. The temperature of

a sick person varies slightly from this value. For this reason a clinical thermometer has a limited range

of calibration usually 35oC to 43oC (95oF to 110oF)

Construction And Working:

The glass stem of the clinical thermometer has a narrow bend or constriction in its capillary bore

near the mercury bulb.

This helps to stop the mercury thread moving back towards the bulb after the thermometer

is removed from the patient’s mouth and the temperature can be read easily.

Maxima And Minima ThermometerConstruction:

This thermometer consist of a bulb “X”, completely filled with alcohol, a “U” tube “Y”,

contained mercury, another bulb “Z”, partially filled with alcohol, and two steel indexes “A1”

and “A2”. Temperature scales are provided against each limb of the U tube. The alcohol in “X”

has the largest volume compared to the volume of mercurying and alcohol in “Y” and “Z” respectively.

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Working:

When the temperature rises, the alcohol in “X” expands and pushes the mercury column

down, with the result that the index A2 is forced up by the mercury meniscus. Thus the lower end

of A2 indicates the maximum temperature reached, this being read from the scale. As the temperature

falls, the alcohol in X contracts and owing to the pressure of alcohol vapors in Z, the index A1 is forced

up by the mercury column. Thus the lower end of A1 indicates the minimum temperature reached.

Use:

It is use in green houses, food storage and methodological stations.

Thermos Flask:Definition Of Thermos Flask:

“Thermos Flask is a pot designed to prevent heat loss from the fluid inside it, due to all of the

three heat transfer mechanism. Similarly it prevents the heat from outside, getting into the material”.

Construction Of Thermos Flask:

It consists of double wall glassed vessel, which is silvered on the outer surface of the inner wall

and on the surface of the outer wall. The space between the walls is evacuated, and is then sealed. The

glass vessel is enclosed in a metal case such that it rests on a cork at the bottom of the case, and is

secured at the neck with a pad of felt or a ring of rubber.

Working Of Thermos Flask:

Glass is a relatively poor thermal conductor while cork, air are felt between the glass vessel

and the metal case are all bad conductors. Thus heat from a hot liquid kept in the glass vessel cannot

rapidly pass to the metal case. The cork in the neck of the vessel, and the cup over that, prevent loss of

heat by convection. Moreover, the silvering on the outside of the inner wall makes that wall a bad

radiator, while that on the inner surface of the outer wall tends to reflect back any heat that is

radiated. Consequently hot or cold drink in the thermos flask remains hot or cold for relatively long

time.

Q3: Define the following:

Conduction

Convection

Radiation

Thermal Conductivity

Conduction:Conduction is the transfer of heat energy through a solid body due to the molecular interactions.

Convection:Convection is the transfer of heat from one part of a fluid to another by the movement of the

fluid from the hotter to the colder part.

Radiation:

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In this process heat energy is transfer from hot place to cold place without any material

medium. The hot object emits radiation which carries away energy. When these radiation fall

on an object, their energy is transferred to the latter in the form of heat.

Energy transfer from sun to earth is an example of radiation.

Thermal ConductivityThermal conductivity can be quantitatively defined as the amount of heat conducted for one

second through a meter cube of the substance whose opposite faces are maintained at a temperature

difference of 1oC.

Mathematically

K=Q L / A T t

Its unit is J oC-1 m-1 s-1

Q4. Define Co-efficient of Linear Expansion and prove that L2=L1 {1+ T}

Co-efficient Of Linear Expansion:“It is the change in length per unit length per degree rise in temperature”.

It is denoted by “”.

Mathematically

= L / L1 T

L2 = L1 {1+T}

Consider an iron rod of length L1, at temperature T1 oC. It is heated to certain temperature

T2 and its length becomes L2.

Change in length = L = L2 – L1

Change in temperature = T = T2 – T1

Change in length per unit length per degree rise in temp = L2 - L1/L1T

Or = L / L1 T

Or L1 T = L

Or L = L1 T

Or L2 – L2 = L1 T

L2 = L1 + L1 T

L2 = L1 {1+ T}

Unit of Co-efficient of linear expansion is oC-1.

Q5. Define bimetallic strips and write note on the following

Bimetal Thermometer

Thermometer

Fire Alarm.

Bimetallic Strips:

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Before Heating After Heading

Brass

Iron

When two metallic strips of different thermal expansion are pasted together bimetallic strips

are formed i.e. Bimetallic strips of iron and brass.

Bimetallic Thermometer:As we know liquid glass thermometer have a low range of measurement because liquid

vaporize at low temperature and also glass melts. So it can not be used to measure high

temperature as above 500 oC. So bimetallic thermometer is used for the measure of higher

temperature.

Construction And Working Of Bimetal Thermometer:A bimetal strip can be used to make a simple thermometer which is tough but easy to read

as compared with liquid-in-glass thermometers. It consists of a bimetal strip in the form of a long spiral.

One end of the spiral is kept fixed while a light pointer is attached to the other, as shown in Fig.

When the temperature rises, the bimetal strip coils itself into an even tighter spiral due to different

expansion rates of the two metals which form the bimetal strip, and the pointer moves across the

temperature scale.

Thermostat:Thermostat are devices which control temperature in a certain space e.g. in refrigerators,

electric ovens, motor car engines etc. To maintain the temperature of air inside the room at a

comfortable level, thermostats are used with room heaters or air- conditioners.

Construction And Working Of Thermostats:The essential parts of a thermostat are shown in Fig. Suppose this thermostat is connected to

an electric room heater. As the temperature of air inside the room rises, the bimetal strip bends and

the electrical contact is disconnected. This switches off the heater. When the room temperature falls,

the bimetal strip cools and straightens. As the contacts touch each other, the heater is switched on

again. In this way the thermostat switches the heater on and off to keep the room at a more or less

steady temperature.

The desired temperature is selected by mean of a control knob. If the control knob is

screwed in wards, the bimetal strip has to bend further before the contacts disconnected. Thus

the room needs to be warmer before the heat is switched off.

Fire Alarm:Another very useful application of a bimetal strip is a fire alarm. A model fire alarm is shown

in fig. one end of a bimetal strip is firmly fixed while the other end is free. One terminal of a 6 volt

bulb or an electric bell. The other terminal of the battery is connected with a metallic contact which is

just above the free end of the strip. The heat energy given off when a fire starts raises the

temperature of the bimetal strip. The free end of the strip bends towards the contact and on

touching it electric current flows through the circuit. The bulb therefore, light up or in case of a bell, it

rings, to signal a warning about fire.

Q6. What do you know about?

a) Anomalous Expansion Of Water

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b) Why do fish and other aquatic animals in oceans and seas survive in extremely cold

water?

c) Why do water pipes burst in winter seasons in cold regions?

d) Why rocks do are break in cold regions.a) All the substances contract on freezing and expand on heating but water has a strange

behavior between 0oC to 4 oC. It expands when its temperature falls from 4oC to 0oC and contract

when it is heated from 0 oC to 4oC. This strange behaviors of water is called Anomalous Expansion of

water.

Effect Of Anomalous Expansion Of Water:The effect of anomalous expansion of water is important in nature & everyday life. Some of them

are discussed here briefly.

In Winter, the water ponds, lakes and seas in the area close to the north and south poles of the

earth cools down as the atmospheric in temperature falls. The cooler and denser water at the surface

initially flow to the bottom. When the temperature at the surface reaches 4oC, this downward flow

of water ceases. If the atmosphere temperature further falls below 4oC the water at the surface expands,

becomes lighter and therefore does not sink. As the water freezes at the surface it remains there

while water near bottom remains at 4 oC. This help fish and other forms of marine life to survive an

wither season.

During the rainy season, a lot of water seeps through the numerous cracks & fissures in rocks.

In winter expands freezing. The rocks are therefore subjected to high pressure and are broken up.

In colder climates, the water supplies pipes burst, when the atmosphere temperature falls

below 4oC. This is because water in the pipes expands, and exerts enormously pressure on the walls

causing damage to the pipes.

Q7. State and following law?Explain General Gas Equation and write its mathematical form.

Boyle’s Law:“Volume of a given mass of gas is inversely proportional to the pressure, if the temperature

is kept constant”.

Mathematical Representation:If “V” denotes the volume and “p” stands for pressure then

V 1 / P

Or V = (Constant) 1 / p

Or VP= Constant

Graphical Representation:The pressure volume graph is a curve line shows that they are inversely proportional

quantities.

Charles Law:

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Volume of a given mass of a gas is directly proportional to its absolute temperature, provided that

pressure is kept constant”.

Mathematical Representation:If “V” and “T” stands for volume and temperature receptively then

V T

Or V = (Constant) K

Or V/T = Constant

Graphical Representation:The relation between volume and temperature for a given mass of a gas on graph is straight line

which shows that they are directly proportional to each other.

Q12. What is refrigerator write down its construction and working?

Refrigerator:It is device which is used to cool things and to preserve for a certain period of time e.g. food,

fruits etc.

Construction:Refrigerator uses gases which liquefy under pressure at normal temperature usually Freon

gas is used as a refrigerant. Refrigerator consist of three parts

Condenser

Evaporator

Compressor

Working:The gas is first compressed and fed into the condenser. There it liquefies under pressure and is

then let through a valve into a evaporator. In evaporator Freon evaporates under normal pressure

absorbing heat from the area surrounding the evaporator, thus cooling

it down. It is again brought to the condenser with the help of compressor. Freon loses its

heat in condenser where it again liquefied. This process is continuously repeated in this way

temperature inside evaporator becomes lower and things are preserved for long time.

Expansion Of Liquid:When liquids are heated, they expand and their volumes increases and on cooling contraction

takes place. We know that liquids are always contained in some sort of container which is made up

of solid. So when liquid is heated, first heat is absorbed by the solid container and its cubical

expansion takes place. Then after sometimes the liquid inside starts getting heat and its cubical

expansion takes place. When the expansion of the solid vessel occurs, the level of liquid inside the

container lower due to increased capacity of the container. Then on further heating the liquid level

rises as it starts absorbing heat from the vessel.

Thus while studying expansion of liquids we come across two types of expansion.

The apparent expansion.

The real expansion.

Their coefficients are as defined as follows.

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1. The Coefficient Of Apparent Expansion: Its is the rate of apparent expansion or apparent change in volume per unit original volume per

degree rise in temperature its is denoted by Ya.

2. The Coefficient Of Real Expansion: It is the rate of real expansion, or the real increase in volume per unit original volume per

degree rise in temperature. It is denoted by Yr.

The coefficient of apparent expansion always slightly lower than the coefficient of real

expansion by rate of cubical expansion of the container.

Yr = Yc + Ya

Where Yc is the coefficient of cubical expansion of the container.

Specific Heat :It is the amount of heat absorbed or given out by one kg of a substance when it is heated or

cooled through 1oC.

Spht = Amount of heat absorbed / given out

Mass x rise / fall in temperature

C = Q / mt

Q = mCt

where c = Specific Heat

m = Mass of the Substance

t = rise or fall in temperature

The SI unit of specific heat is J/kg oC.

Calorie:It is the amount of heat absorbed/given out by 1gm of water through 1oC. It is equal to 4.2

Joules.

Kilo Calorie:It is the amount of absorbed / given out by 1Kg, of water when heated / cooled through 1oC.

It is equal to 4200 Joules.

There is another unit of heat called British thermal unit (BTU)

1 BTU =1054Joules.

The Law Of Heat Exchange:When two bodies at different temperature are brought in contact, heat starts flowing from a

body at higher temperature towards a body at lower temperature. In this way hot body loses heat

and cold body gains it. The law of heat exchange states that “Heat lost by hot body is equal to heat

gained by cold body.

Determined of specific heat of solid by method of mixture:

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In this method a special type of container called calorimeter and thermometer are used to note

the temperature of the contents.

In this method the solid of which the specific heat is required, is heated through a known

temperature in the test tube of hypsometer. In the mean time the empty calorimeter with stirrer is

weighted. 2/3 of volume of Colorimeter filled with water and then weight it. The difference gives mass

of water. The temperature of calorimeter is noted. Which is also the temp of water beside it. Hot

solid from the test tube proved with Colorimeter and stirred for some time to achieve a constant

temperature. The final temperature of the mixture is noted. Again after weight the Colorimeter and

y the following calculation find specific heat of solid.

The following data is obtained.

Mass Of Empty Calorimeter with stirrer = m1 kg.

Mass Of Calorimeter stirrer and water = m2 kg.

Mass of water = (m2 – m1) kg.

Mass of mixture = m3 kg.

Mass of solid = ( m3 – m2 ) Kg.

Initial temperature of Cabrimetre = t1 oC (Room Temperature)

Initial temperature of water = t1 oC (Room Temperature)

Initial temperature of solid = t2 oC (Temp in the Hypsometer)

Final temperature mixture = t3 oC

Fall of temp of solid = (t2 – t3) oC

Rise of temp of Colorimeter = (t3 – t1) oC

Rise in temp of water = (t3 – t1) oC

Specific Heat Water = 4200 J/Kg oC

Specific Heat Of Colorimeter = C1, J/Kg. oC (given)

Specific Heat Of solid = C =? (Required)

Heat lost by solid = sp heat of solid of x fall of colorimeter temp.

Ht lost by solid =

Heat gained by Calorimeter = spht x mass x rise in temp.

Ht gained by Calorimeter = c1 m1 (t3 – t1)

Heat gained by water = 4200 x (m2 – m1) x (t3 – t1)

According to law of heat exchange

Heat lost by solid = Ht gained by cm + heat gained by water.

( m3 – m2 ) C2 (t2 – t3) = C1m1 (t3 – t1) + (m2 – m1) 4200 (t3 – t1)

C2 = ( m2 – m1 ) x 4200 ( t3 – t1 ) x m1 C1 ( t3 – t1 )

(m3 – m2) (t2 – t3)

Melting Point:The temperature at which the melting of a solid to liquid occurs is called its melting point.

Latent Heat of Fusion:It is the amount of heat required to convert unit mass of a solid into liquid at its melting point

with out rise in temperature. Or

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Heat given out by unit mass of a liquid to change into solid at its freezing point with out fall in

temperature is called latent heat of fusion.

Lf = Q / m

When ever change of state occurs, there is no rise or fall in temperature.

Explanation On The Basis Of Kinetic Molecular Theory:

When a solid is heated its molecular motion is increases, a result the temperature rises. If the

solid continues to absorb heat, a stage come when the vibration of the molecule increases so much

that it over comes the intermolecular force of attraction which keeps the body bound together as solid.

At this point solid starts changing it state of liquid. Any further addition just helps in breaking up

the bonds of attraction between the molecules. The energy of the molecule does not increase on the

average the temperature remains constant till all the solids are broken.

Latent Heat of Vaporization:It is the amount of heat required to convert unit mass of a liquid into vapors at its boiling point

with out rising temperature. Or

The heat given out by unit mass of vapors to change into liquid at their point of condensation

with out fall in temperature.

Lv = Q / m

Explanation On The Basis Of Molecular Theory:When a liquid is heated its molecular motion increases in temperature. When the liquid

continues to absorb heat a stage come when the intermolecular force of attraction is over come and any

further addition of heat does not raise its temperature but change of state starts taking place till the

hole liquid change to vapor.

Effect Of Pressure On Melting Point (Regelation):Substance which expands on freezing when subjected to pressure, melt before their melting point

on removal of pressure they again freeze at their freezing point. This process is called regelation.

To illustrate we takes the ice block supported on stands a wire is passed over it with weight

changes on the earth end. The layer of ice just beneath the wire due to pressure melt and skins

down. As the wire skins the pressure is removed and that layer freezes again. This process

continues till the whole wire passes through it and the block does not cut in to two.

Effect Of Pressure On Boiling Point:The boiling point of a liquid increases with pressure and vice versa. Water boils at 100 oC

when the pressure 760 mm Hg. Its pressure is reduced the boiling point decreases.

To illustrate this we take a flask half filled with water and heat it till it starts boiling. Let it

boil for some time so that sufficient steam may produce. Then stop heating and cork the flask. The

flask is then inverted on a stand and cold water is poured over it.

As we pour cold water the water inside the flask again starts boiling although we have stop

heating. This explained as, “When the heating was stopped there was pressure of steam (vapors) also

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to water and reduced the pressure on water and the boiling point also decrease water starts boiling

again below its boiling point.

Evaporation:The process of converting a liquid into vapors without boiling it called evaporation. Evaporation

takes place at all temperature.

Explanation On The Basis Of Molecular Theory:According to kinetic molecular theory, the molecules of liquid are in continuous motion due to

motion, they posses kinetic energy. The energy of all the molecules are not same. The molecules which

are near the surface of liquid due to continuous collision with other molecule acquire so much energy

that they over came the inter molecular force of attraction of the liquid and escape out of the surface of

liquid, leaving behind a fall in temperature of the liquid. Due to fall in temperature the cooling

effects is experienced.

Factors upon which rate of evaporation Depends

Rate of evaporation depends upon the following factors.

Temperature of the liquid:If the surface temperature is high rate of evaporation increase. While ironing the cloths, wet

cloths dry out quickly as the water evaporates quickly.

Nature Of Liquid:Liquid having low boiling evaporate more quickly e.g. alcohol etc.

Surface Of The Liquid:Rate of evaporation increases with increase in surface area, we spread wet cloths to get them

dry quicker or the unwanted water is spread over larger area of quick evaporation.

Dryness Of Air:Rate of evaporation increases of air is drier. In rainy season the cloth take much time to dry as

rate of evaporation decreases due to moisture in the air.

Speed Of Wind:If speed of wind increases rate of evaporation is also increases. Because the wind carries the

vapor to other place leaving capacity for new vapors. So evaporation increase.

Air Pressure On The Surface If Liquid :If pressure is reduced the rate of evaporation increases. Because lowing of pressure reduces the

boiling point so rate of evaporation increases.

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Chapter-18

ELECTRONICS

Q: Define semi conductors. Give some examples.

Semi Conductors:Those materials which have conductivity between an insulator and a conductor are called

semi conductors. Crystals of germiniun and silicon are the examples of semi conductors.

Q: Define Doping.

Doping:Process by which the electrical conductivity of elements such as Silicon or Germiniun is

increased by adding in them a small amount of an element which has either three or five electrons

in its atom is called doping.

Q: Write two points of differences between n-type substances and p-type substances.

n – type substance p – type substance

If a tetravalent element is dopped with

a pentavalent element four out of five

electron form covalent bonds and the

fifth valence electron is free to move

about which makes the dopped element

a better conductor. Such a material is

known as n – type substance.

If a tetravalent element is dopped with

a trivalent element then three electrons

form covalent bond and a space known

as hole is left. Such a material is known

as P – type substance.

There is an excess of negative electrons.There is an excess of holes. (Positive

changes)

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Q: Write two points of differences between Forward Bias and Reverse Bias.

Forward Bias Reverse Bias

When a semiconductor diode is

connected to a D.C. Source in such a

way that p – side is connected to the

positive terminal and n – side to the

negative terminal and holes move from

the p – type to the n – type and

electrons move from the n – type to the

p – type material across the junction it

is called forward biased.

When a semiconductor diode is

connected to a D.C. Source in such a

way the p – side is connected to the

negative terminal and n – side to the

positive terminal and holes and

electrons move away form the junction

it is called reverse biased.

It has very low electrical resistance. It has very high electrical resistance.

Q: Define rectification. How a PN junction diode is used as a rectifier.

Rectification:The conversion of alternating current (A.C) to direct current (D.C) is called rectification.

Working of Diode as Rectifier:

During the positive half cycle of the A.C. the p – section of diode is positive which make it

forward bias and allow the flow of current through the load ‘R’. But during negative half cycle of

the A.C the p – section of diode is negative which make it reverse bias and stop the flow of current

across the junction. Thus only positive half cycle of the A.C. passes through diode and this

rectification is called half wave rectification.

Q: Define Transistor.

Transistor:

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Transistor is a semiconductor which consists of a thin central layer (3 – 5 µm) of one type

semiconductor material sandwiched between two relatively thick pieces of the other type.

Q: Write the types of transistor.

Types of Transistors:Transistors are of following two types.

1) npn – Transistor

2) pnp – Transistor

npn - Transistor:

The npn transistor has a thin piece of p – type material sandwiched between two pieces of n

– type material.

pnp - Transistor:

The pnp transistor has a thin piece of n – type material sandwiched between two pieces of p

– type material.

Q: How does a transistor works.

Working of Transistors:

A transistor consists of two junctions. One is the emitter base junction (EB) and the other is

collector base (CB). Generally the emitter base junction is forward biased, while the collector base

junction is reverse biased.

As the base emitter junction is forward biased, so its resistance gets very low and a stream

of electrons is injected from the emitter into the base. Thus current begins to flow through this

junction. As the base region is very thin, so practically almost all the electrons injected into the

base are attracted towards the collector due to its large positive potential and very few electrons

enter into the base circuit. In this way a current begins to flow in the collector circuit.

Q: Define amplifier. And how a transistor is used as an amplifier?

Amplifier:An amplifier is a device used to increase the amplitude of an input signal (current or

voltage) without changing the shape of wave.

Working of Transistor as an Amplifier:

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The importance of the transistor is based upon the fact that value of the collector current is

many times greater than the base current. If current is charged slightly, then the collector current

changes significantly. In this way the transistor acts as an amplifier.

Q: What are the advantages of transistor?

Advantages of Transistor:1) Transistors are small in size.

2) Transistors are light in weight.

3) Transistors are not easily broken.

4) Transistors produce little heat.

5) Transistors are very cheap.

6) Transistors use very little potential.

7) Transistors have long operating life.

Q: Define Radar.

Radar:

Radar stands for Radio Detection and Ranging.

Q: How many parts of radar?

Parts of Radar:Radar consists of following parts:

1) Transmitter

2) Receiver

3) Indicating devices

Q: What are the uses of Radar?

Uses of Radar:1) It is used to beware of surrounding ships, ice bergs hidden rocks under water

and hills hidden by mist and cloud.

2) It is used for air traffic control.

3) It helps in navigation in low visibility.

4) It helps to detect enemy planes.

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