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Work, Power & EnergyWork, Power & Energy
Chapter 4
Explaining the Causes of Explaining the Causes of Motion in a Different WayMotion in a Different Way
WorkWorkThe product of force and the amount
of displacement along the line of action of that force.
Units: ft . lbs (horsepower) Newton•meter (Joule) e
ntdisplacemeForceWork
Work = F x dWork = F x d
To calculate work done on an object, we need:
The ForceThe average magnitude of the force The direction of the forceThe DisplacementThe magnitude of the change of positionThe direction of the change of position
Calculate WorkCalculate WorkDuring the ascent phase of a rep of
the bench press, the lifter exerts an average vertical force of 1000 N against a barbell while the barbell moves 0.8 m upward
How much work did the lifter do to the barbell?
Calculate WorkCalculate Work
Table of Variables:Force = +1000 NDisplacement = +0.8 m
Force is positive due to pushing upwardDisplacement is positive due to moving
upward
Calculate WorkCalculate Work
Table of Variables:Force = +1000 NDisplacement = +0.8 mSelect the equation and solve:
JJouleNmWork
mNWork
ntdisplacemeForceWork
800800800
8.01000
- & + Work- & + WorkPositive work is performed
when the direction of the force and the direction of motion are the sameascent phase of the bench pressThrowing a ballpush off (upward) phase of a jump
Calculate WorkCalculate WorkDuring the descent phase of a rep of
the bench press, the lifter exerts an average vertical force of 1000 N against a barbell while the barbell moves 0.8 m downward
Calculate WorkCalculate Work
Table of VariablesForce = +1000 NDisplacement = -0.8 m
Force is positive due to pushing upwardDisplacement is negative due to
movement downward
Calculate WorkCalculate Work
Table of VariablesForce = +1000 NDisplacement = -0.8 mSelect the equation and solve:
JJouleNmWork
mNWork
ntdisplacemeForceWork
800800800
8.01000
- & + Work- & + WorkPositive work Negative work is performed when
the direction of the force and the direction of motion are the oppositedescent phase of the bench presscatching landing phase of a jump
ContemplateContemplateDuring negative work on the bar,
what is the dominant type of activity (contraction) occurring in the muscles?
When positive work is being performed on the bar?
EMG during the Bench PressEMG during the Bench Press
On elbow180
90
Work performed climbing Work performed climbing stairsstairs
Work = Fd Force
Subject weightFrom mass, ie 65 kg
Displacement Height of each step
Typical 8 inches (20cm)
Work per step 650N x 0.2 m = 130.0 Nm
Multiply by the number of steps
Work on a stair stepperWork on a stair stepper
Work = FdForce
Push on the step????
Displacement Step Height
8 inches
“Work” per step???N x .203 m = ???Nm
Work on a cycle ergometerWork on a cycle ergometer
Work = FdForce
belt friction on the flywheelmass (eg 3 kg)
Displacement revolution of the pedals
Monark: 6 m
“Work” per revolution
Work on a cycle ergometerWork on a cycle ergometer
Work = Fd Force
belt friction on the flywheelmass (eg 3 kg)
Displacement revolution of the pedals
Monark: 6 m
“Work” per revolution 3kg x 6 m = 18 kgm
Similar principle for Similar principle for wheelchairwheelchair
……and for handcycling and for handcycling ergometerergometer
EnergyEnergy Energy (E) is defined as the capacity to do
work (scalar) Many forms
No more created, only convertedchemical, sound, heat, nuclear, mechanical
Kinetic Energy (KE): energy due to motion
Potential Energy (PE): energy due to position or deformation
Kinetic EnergyKinetic EnergyEnergy due to motion reflects
the mass the velocity
of the object
KE = 1/2 mv2
Kinetic EnergyKinetic EnergyUnits: reflect the units of mass * v2
Units KE = Units work
NmKE
mssmkgKE
ssmmkgKE
smkgKE
mvKE
2
1
)//(2
1
//2
1
)/)((2
12
1
2
2
Calculate Kinetic Calculate Kinetic EnergyEnergy
How much KE in a 5 ounce baseball (145 g) thrown at 80 miles/hr (35.8 m/s)?
Calculate Kinetic Calculate Kinetic EnergyEnergy
Table of VariablesMass = 145 g 0.145 kgVelocity = 35.8 m/s
Calculate Kinetic Calculate Kinetic EnergyEnergyTable of VariablesMass = 145 g 0.145 kgVelocity = 35.8 m/sSelect the equation and solve:KE = ½ m v2
KE = ½ (0.145 kg)(35.8 m/s)2
KE = ½ (0.145 kg)(1281.54 m/s/s)KE = ½ (185.8 kg m/s/s)KE = 92.9 kg m/s/s, or 92.9 Nm, or 92.9J
Calculate Kinetic Calculate Kinetic EnergyEnergy
How much KE possessed by a 150 pound female volleyball player moving downward at 3.2 m/s after a block?
Calculate Kinetic EnergyCalculate Kinetic Energy
Table of Variables 150 lbs = 68.18 kg of mass -3.2 m/sSelect the equation and solve:KE = ½ m v2
KE = ½ (68.18 kg)(-3.2 m/s)2
KE = ½ (68.18 kg)(10.24 m/s/s) KE = ½ (698.16 kg m/s/s) KE = 349.08 Nm or J
Calculate Kinetic Calculate Kinetic EnergyEnergy
Compare KE possessed by: a 220 pound (100 kg) running back
moving forward at 4.0 m/s a 385 pound (175 kg) lineman
moving forward at 3.75 m/s
Bonus: calculate the momentumof each player
Calculate Kinetic EnergyCalculate Kinetic Energy
Table of Variablesm = 100 Kgv = 4.0 m/sSelect the equation
and solve:KE = ½ m v2
KE = ½ (100 kg)(4.0 m/s)2
KE = 800 Nm or J
Table of Variablesm = 175 kgv = 3.75 m/sSelect the equation
and solve:KE = ½ m v2
KE = ½ (175)(3.75)2
KE = 1230 Nm or J
Calculate Momentumomentum
Momentum = mass times velocity
Player 1 = 100 kg * 4.0 m/sPlayer 1 = 400 kg m/s
Player 2 = 175 * 3.75 m/sPlayer 2 = 656.25
Potential EnergyPotential Energy
Two forms of PE:Gravitational PE:
energy due to an object’s position relative to the earth
Strain PE:due to the deformation of an object
Gravitational PEGravitational PEAffected by the object’s
weight mg
elevation (height) above reference point ground or some other surfaceh
GPE = mgh
Units = Nm or J (why?)
Calculate GPECalculate GPE
How much gravitational potential energy in a 45 kg gymnast when she is 4m above the mat of the trampoline?
Take a look at the energetics of a roller coaster
Calculate GPECalculate GPE
How much gravitational potential energy in a 45 kg gymnast when she is 4m above the mat of the trampoline?
Trampoline mat is 1.25 mabove the ground
Calculate GPECalculate GPE
GPE relative to mat Table of Variables m = 45 kgg = -9.81 m/s/sh = 4 mPE = mghPE = 45kg * -9.81
m/s/s * 4 mPE = - 1765.8 J
GPE relative to groundTable of Variablesm = 45 kgg = -9.81 m/s/sh = 5.25 mPE = mghPE = 45m * -9.81
m/s/s * 5.25 mPE = 2317.6 J
Conversion of KE to GPE and Conversion of KE to GPE and GPE to KE and KE to GPE and GPE to KE and KE to GPE and ……
Strain PEStrain PEAffected by the object’samount of deformation
greater deformation = greater SE x2 = change in length or deformation of the
object from its undeformed positionstiffness
resistance to being deformedk = stiffness or spring constant of material
SE = 1/2 kx2
Strain EnergyStrain EnergyWhen a fiberglass vaulting pole
bends, strain energy is stored in the bent pole
Pole vault explosion
Strain EnergyStrain EnergyWhen a fiberglass vaulting pole
bends, strain energy is stored in the bent pole
Bungee jumping
Strain EnergyStrain EnergyWhen a fiberglass vaulting pole
bends, strain energy is stored in the bent pole
Bungee jumpingHockey sticks
Strain EnergyStrain Energy When a fiberglass vaulting pole bends, strain energy is
stored in the bent pole Bungee jumping When a tendon/ligament/muscle is stretched, strain
energy is stored in the elongated elastin fibers (Fukunaga et al, 2001, ref#5332) k = 10000 n /m x = 0.007 m (7 mm), Achilles tendon in
walking When a floor/shoe sole is deformed, energy is stored in
the material
.
Plyometrics
Work - Energy RelationshipWork - Energy Relationship
The work done by an external force acting on an object causes a change in the mechanical energy of the object
)(2
1 2ifif rrmgvvmFd
PEKEFd
EnergyFd
Work - Energy RelationshipWork - Energy Relationship
The work done by an external force acting on an object causes a change in the mechanical energy of the objectBench press ascent phase
initial position = 0.75 m; velocity = 0final position = 1.50 m; velocity = 0m = 100 kgg = -10 m/s/sWhat work was performed on the bar by lifter?What is GPE at the start & end of the press?
Work - Energy Work - Energy RelationshipRelationship
What work was performed on the bar by lifter? Fd = KE + PE Fd = ½ m(vf –vi)2 + mgh Fd = 100kg * - 10 m/s/s * 0.75 m Fd = 750 J W = Fd W = 100 kg * .75m W = 75 kg m W = 75 kg m (10) = 750 J
Work - Energy Work - Energy RelationshipRelationship
What is GPE at the start & end of the press? End (ascent) PE = mgh PE = 100 kg * -10 m/s/s * 1.50 m PE = 1500 J Start (ascent) PE = 100 kg * -10 m/s/s * 0.75m PE = 750 J
Work - Energy Work - Energy RelationshipRelationship
Of critical importanceSport and exercise = velocity
increasing and decreasing kinetic energy of a body
similar to the impulse-momentum relationship
)(2
1 2vivfif rrmgvvmFd
PEKEFd
EnergyFd
Ft = m (vf-vi)
Work - Energy RelationshipWork - Energy Relationship
If more work is done, greater energy greater average forcegreater displacement
Ex. Shot put technique (121-122).
If displacement is restricted, average force is __________ ? (increased/decreased)
“giving” with the ball landing hard vs soft
PowerPowerThe rate of doing work
Work = Fd
Units: Fd/s = J/s = watt
velocityForcePower
tFdPower
timeWorkPower
/
/
Calculate & compare Calculate & compare powerpower
During the ascent phase of a rep of the bench press, two lifters each exert an average vertical force of 1000 N against a barbell while the barbell moves 0.8 m upward
Lifter A: 0.50 secondsLifter B: 0.75 seconds
Calculate & compare Calculate & compare powerpower
Lifter ATable of VariablesF = 1000 Nd = 0.8 mt = 0.50 s
Lifter B
ws
JPower
s
mNPower
t
FdPower
160050.0
80050.0
8.01000
Power on a cycle Power on a cycle ergometerergometer
Work = Fd Force: 3kg Displacement: 6m /rev “Work” per revolution
3kg x 6 m = 18 kgm
60 rev/min
min/1080""
min/6018""
min/""
/""
kgmPower
kgmPower
revFdPower
tFdPower
Power on a cycle Power on a cycle ergometerergometer Work = Fd Force: 3kg Displacement: 6m /rev “Work” per revolution
3kg x 6 m = 18 kgm
60 rev/min
min/1080""
min/6018""
min/""
/""
kgmPower
kgmPower
revFdPower
tFdPower
1 Watt = 6.12 kgm/min
Compare “power” in Compare “power” in typical stair steppingtypical stair stepping
Work = Fd Force: Push on the step
constant setting
Displacement Step Height: 5” vs 10”
0.127 m vs 0.254 m
step rate 56.9 /min vs 28.8 /min
Time per step60s/step rate
Thesis data from Nikki Gegel and Michelle Molnar
Compare “power” in Compare “power” in typical stair steppingtypical stair stepping
Work = Fd Force: Push on the step
constant setting
Displacement Step Height: 5” vs 10”
0.127 m vs 0.254 m
step rate 56.9 /min vs 28.8 /min
)08.2/254(.
)05.1/127(.
10
5
smFPower
smFPower
vFPower
inch
inch
Compare “power” in Compare “power” in typical stair steppingtypical stair stepping
Work = Fd Force: Push on the step
constant setting
Displacement Step Height: 5” vs 10”
0.127 m vs 0.254 m
step rate 56.9 /min vs 28.8 /min
smFPower
smFPower
vFPower
inch
inch
/122.0
/121.0
10
5
Results: VO2 similar fast/short steps vs slow/deep steps