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MECHANICS OF MATERIALS Fifth SI Edition Ferdinand P. Beer E. Russell Johnston, Jr. John T. DeWolf David F. Mazurek Lecture Notes: J. Walt Oler Texas Tech University CHAPTER © 2009 The McGraw-Hill Companies, Inc. All rights reserved 6 Shearing Stresses in Beams and Thin-Walled Members

WK11 Shearing Stresses(010111)

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Page 1: WK11 Shearing Stresses(010111)

MECHANICS OF MATERIALS

Fifth SI Edition

Ferdinand P. BeerE. Russell Johnston, Jr.John T. DeWolfDavid F. Mazurek

Lecture Notes:J. Walt OlerTexas Tech University

CHAPTER

© 2009 The McGraw-Hill Companies, Inc. All rights reserved.

6Shearing Stresses in

Beams and Thin-Walled Members

Page 2: WK11 Shearing Stresses(010111)

© 2009 The McGraw-Hill Companies, Inc. All rights reserved.

MECHANICS OF MATERIALSFifthEdition

Beer • Johnston • DeWolf • Mazurek

6- 2

Contents

IntroductionShear on the Horizontal Face of a Beam ElementExample 6.01Determination of the Shearing Stress in a BeamShearing Stresses txy in Common Types of BeamsFurther Discussion of the Distribution of Stresses in a ...Sample Problem 6.2Longitudinal Shear on a Beam Element of Arbitrary ShapeExample 6.04Example 6.04Shearing Stresses in Thin-Walled MembersPlastic DeformationsSample Problem 6.3Unsymmetric Loading of Thin-Walled MembersExample 6.05Example 6.06

Page 3: WK11 Shearing Stresses(010111)

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MECHANICS OF MATERIALSFifthEdition

Beer • Johnston • DeWolf • Mazurek

6- 3

Introduction

MyMdAFdAzMVdAF

dAzyMdAF

xzxzz

xyxyy

xyxzxxx

stst

tts

00

00

• Distribution of normal and shearing stresses satisfies

• Transverse loading applied to a beam results in normal and shearing stresses in transverse sections.

• Longitudinal shearing stresses must exist in any member subjected to transverse loading.

• When shearing stresses are exerted on the vertical faces of an element, equal stresses must be exerted on the horizontal faces

Page 4: WK11 Shearing Stresses(010111)

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MECHANICS OF MATERIALSFifthEdition

Beer • Johnston • DeWolf • Mazurek

6- 4

Shear on the Horizontal Face of a Beam Element

• Consider prismatic beam

• For equilibrium of beam element

A

CD

ACDx

dAyIMMH

dAHF

ss0

xVxdxdMMM

dAyQ

CD

A

• Note,

flowshearI

VQxHq

xI

VQH

• Substituting,

Page 5: WK11 Shearing Stresses(010111)

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MECHANICS OF MATERIALSFifthEdition

Beer • Johnston • DeWolf • Mazurek

6- 5

Shear on the Horizontal Face of a Beam Element

• where

section cross full ofmoment second

above area ofmoment first

'

21

AA

A

dAyI

y

dAyQ

• Same result found for lower area

HH

QQ

qIQV

xHq

axis neutral torespect h moment witfirst

0

flowshearI

VQxHq

• Shear flow,

Page 6: WK11 Shearing Stresses(010111)

© 2009 The McGraw-Hill Companies, Inc. All rights reserved.

MECHANICS OF MATERIALSFifthEdition

Beer • Johnston • DeWolf • Mazurek

6- 6

Example 6.01

A beam is made of three planks, nailed together. Knowing that the spacing between nails is 25 mm and that the vertical shear in the beam is V = 500 N, determine the shear force in each nail.

SOLUTION:

• Determine the horizontal force per unit length or shear flow q on the lower surface of the upper plank.

• Calculate the corresponding shear force in each nail.

Page 7: WK11 Shearing Stresses(010111)

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MECHANICS OF MATERIALSFifthEdition

Beer • Johnston • DeWolf • Mazurek

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Example 6.01

46

2

3121

3121

36

m1020.16

]m060.0m100.0m020.0

m020.0m100.0[2

m100.0m020.0

m10120

m060.0m100.0m020.0

I

yAQ

SOLUTION:

• Determine the horizontal force per unit length or shear flow q on the lower surface of the upper plank.

mN3704

m1016.20)m10120)(N500(

46-

36

IVQq

• Calculate the corresponding shear force in each nail for a nail spacing of 25 mm.

mNqF 3704)(m025.0()m025.0(

N6.92F

Page 8: WK11 Shearing Stresses(010111)

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MECHANICS OF MATERIALSFifthEdition

Beer • Johnston • DeWolf • Mazurek

6- 8

Determination of the Shearing Stress in a Beam

• The average shearing stress on the horizontal face of the element is obtained by dividing the shearing force on the element by the area of the face.

ItVQ

xtx

IVQ

Axq

AH

ave

t

• If the width of the beam is comparable or large relative to its depth, the shearing stresses at D1 and D2 are significantly higher than at D.

• On the upper and lower surfaces of the beam, tyx= 0. It follows that txy= 0 on the upper and lower edges of the transverse sections.

Page 9: WK11 Shearing Stresses(010111)

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6- 9

Shearing Stresses txy in Common Types of Beams

• For a narrow rectangular beam,

AV

cy

AV

IbVQ

xy

23

123

max

2

2

t

t

• For American Standard (S-beam) and wide-flange (W-beam) beams

web

ave

AV

ItVQ

maxt

t

Page 10: WK11 Shearing Stresses(010111)

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Beer • Johnston • DeWolf • Mazurek

6- 15

Sample Problem 6.2

A timber beam is to support the three concentrated loads shown. Knowing that for the grade of timber used,

MPa8.0MPa12 allall ts

determine the minimum required depth d of the beam.

SOLUTION:

• Develop shear and bending moment diagrams. Identify the maximums.

• Determine the beam depth based on allowable normal stress.

• Determine the beam depth based on allowable shear stress.

• Required beam depth is equal to the larger of the two depths found.

Page 11: WK11 Shearing Stresses(010111)

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MECHANICS OF MATERIALSFifthEdition

Beer • Johnston • DeWolf • Mazurek

6- 16

Sample Problem 6.2

SOLUTION:

Develop shear and bending moment diagrams. Identify the maximums.

kNm95.10kN5.14

max

max

MV

Page 12: WK11 Shearing Stresses(010111)

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MECHANICS OF MATERIALSFifthEdition

Beer • Johnston • DeWolf • Mazurek

6- 17

Sample Problem 6.2

2

261

261

3121

m015.0

m09.0

d

d

dbcIS

dbI

• Determine the beam depth based on allowable normal stress.

mm246m246.0

m015.0Nm1095.10Pa 1012 2

36

max

dd

SM

alls

• Determine the beam depth based on allowable shear stress.

mm322m322.0

m0.0914500

23Pa108.0

23

6

max

dd

AV

allt

• Required beam depth is equal to the larger of the two. mm322d